Calculus Examples

$- \ln ({| 1.5 - 0.8 y |}^{1.25}) = \ln ({| 0.5 + 0.8 x |}^{1.25})$

Step 1

Divide each term in $- \ln ({| 1.5 - 0.8 y |}^{1.25}) = \ln ({| 0.5 + 0.8 x |}^{1.25})$ by $- 1$ .

$\frac{- \ln ({| 1.5 - 0.8 y |}^{1.25})}{- 1} = \frac{\ln ({| 0.5 + 0.8 x |}^{1.25})}{- 1}$

Step 2

Simplify the left side.

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Step 2.1

Dividing two negative values results in a positive value.

$\frac{\ln ({| 1.5 - 0.8 y |}^{1.25})}{1} = \frac{\ln ({| 0.5 + 0.8 x |}^{1.25})}{- 1}$

Step 2.2

Divide $\ln ({| 1.5 - 0.8 y |}^{1.25})$ by $1$ .

$\ln ({| 1.5 - 0.8 y |}^{1.25}) = \frac{\ln ({| 0.5 + 0.8 x |}^{1.25})}{- 1}$

Step 3

Simplify the right side.

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Step 3.1

Move the negative one from the denominator of $\frac{\ln ({| 0.5 + 0.8 x |}^{1.25})}{- 1}$ .

$\ln ({| 1.5 - 0.8 y |}^{1.25}) = - 1 \cdot \ln ({| 0.5 + 0.8 x |}^{1.25})$

Step 3.2

Rewrite $- 1 \cdot \ln ({| 0.5 + 0.8 x |}^{1.25})$ as $- \ln ({| 0.5 + 0.8 x |}^{1.25})$ .

$\ln ({| 1.5 - 0.8 y |}^{1.25}) = - \ln ({| 0.5 + 0.8 x |}^{1.25})$