Calculus Examples

$lim_{x \to \infty} e^{- 2 x} \cos (x)$

Step 1

Since $e^{- 2 x} \cdot - 1 \leq e^{- 2 x} \cos (x) \leq e^{- 2 x} \cdot 1$ and $lim_{x \to \infty} e^{- 2 x} \cdot - 1 = lim_{x \to \infty} e^{- 2 x} \cdot 1 = 0$ , apply the squeeze theorem.

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