Calculus Examples

$lim_{x \to \infty} \frac{\sin (x)}{e^{x} + \cos (x)}$

Step 1

Since $\frac{- 1}{e^{x} + \cos (x)} \leq \frac{\sin (x)}{e^{x} + \cos (x)} \leq \frac{1}{e^{x} + \cos (x)}$ and $lim_{x \to \infty} \frac{- 1}{e^{x} + \cos (x)} = lim_{x \to \infty} \frac{1}{e^{x} + \cos (x)} = 0$ , apply the squeeze theorem.

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