Calculus Examples

$lim_{x \to 0} \frac{\sin^{3} (x)}{\sin (x^{3})}$

Step 1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 1.1

Take the limit of the numerator and the limit of the denominator.

$\frac{lim_{x \to 0} \sin^{3} (x)}{lim_{x \to 0} \sin (x^{3})}$

Step 1.2

Evaluate the limit of the numerator.

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Step 1.2.1

Evaluate the limit.

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Step 1.2.1.1

Move the exponent $3$ from $\sin^{3} (x)$ outside the limit using the Limits Power Rule.

$\frac{{(lim_{x \to 0} \sin (x))}^{3}}{lim_{x \to 0} \sin (x^{3})}$

Step 1.2.1.2

Move the limit inside the trig function because sine is continuous.

$\frac{\sin^{3} (lim_{x \to 0} x)}{lim_{x \to 0} \sin (x^{3})}$

Step 1.2.2

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{\sin^{3} (0)}{lim_{x \to 0} \sin (x^{3})}$

Step 1.2.3

Simplify the answer.

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Step 1.2.3.1

The exact value of $\sin (0)$ is $0$ .

$\frac{0^{3}}{lim_{x \to 0} \sin (x^{3})}$

Step 1.2.3.2

Raising $0$ to any positive power yields $0$ .

$\frac{0}{lim_{x \to 0} \sin (x^{3})}$

Step 1.3

Evaluate the limit of the denominator.

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Step 1.3.1

Evaluate the limit.

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Step 1.3.1.1

Move the limit inside the trig function because sine is continuous.

$\frac{0}{\sin (lim_{x \to 0} x^{3})}$

Step 1.3.1.2

Move the exponent $3$ from $x^{3}$ outside the limit using the Limits Power Rule.

$\frac{0}{\sin ({(lim_{x \to 0} x)}^{3})}$

Step 1.3.2

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{0}{\sin (0^{3})}$

Step 1.3.3

Simplify the answer.

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Step 1.3.3.1

Raising $0$ to any positive power yields $0$ .

$\frac{0}{\sin (0)}$

Step 1.3.3.2

The exact value of $\sin (0)$ is $0$ .

$\frac{0}{0}$

Step 1.3.3.3

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{0}{0}$

Step 1.3.4

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{0}{0}$

Step 1.4

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{0}{0}$

Step 2

Since $\frac{0}{0}$ is of indeterminate form, apply L'Hospital's Rule. L'Hospital's Rule states that the limit of a quotient of functions is equal to the limit of the quotient of their derivatives.

$lim_{x \to 0} \frac{\sin^{3} (x)}{\sin (x^{3})} = lim_{x \to 0} \frac{\frac{d}{d x} [\sin^{3} (x)]}{\frac{d}{d x} [\sin (x^{3})]}$

Step 3

Find the derivative of the numerator and denominator.

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Step 3.1

Differentiate the numerator and denominator.

$lim_{x \to 0} \frac{\frac{d}{d x} [\sin^{3} (x)]}{\frac{d}{d x} [\sin (x^{3})]}$

Step 3.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{3}$ and $g (x) = \sin (x)$ .

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Step 3.2.1

To apply the Chain Rule, set $u$ as $\sin (x)$ .

$lim_{x \to 0} \frac{\frac{d}{d u} [u^{3}] \frac{d}{d x} [\sin (x)]}{\frac{d}{d x} [\sin (x^{3})]}$

Step 3.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 3$ .

$lim_{x \to 0} \frac{3 u^{2} \frac{d}{d x} [\sin (x)]}{\frac{d}{d x} [\sin (x^{3})]}$

Step 3.2.3

Replace all occurrences of $u$ with $\sin (x)$ .

$lim_{x \to 0} \frac{3 \sin^{2} (x) \frac{d}{d x} [\sin (x)]}{\frac{d}{d x} [\sin (x^{3})]}$

Step 3.3

The derivative of $\sin (x)$ with respect to $x$ is $\cos (x)$ .

$lim_{x \to 0} \frac{3 \sin^{2} (x) \cos (x)}{\frac{d}{d x} [\sin (x^{3})]}$

Step 3.4

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = \sin (x)$ and $g (x) = x^{3}$ .

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Step 3.4.1

To apply the Chain Rule, set $u$ as $x^{3}$ .

$lim_{x \to 0} \frac{3 \sin^{2} (x) \cos (x)}{\frac{d}{d u} [\sin (u)] \frac{d}{d x} [x^{3}]}$

Step 3.4.2

The derivative of $\sin (u)$ with respect to $u$ is $\cos (u)$ .

$lim_{x \to 0} \frac{3 \sin^{2} (x) \cos (x)}{\cos (u) \frac{d}{d x} [x^{3}]}$

Step 3.4.3

Replace all occurrences of $u$ with $x^{3}$ .

$lim_{x \to 0} \frac{3 \sin^{2} (x) \cos (x)}{\cos (x^{3}) \frac{d}{d x} [x^{3}]}$

Step 3.5

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$lim_{x \to 0} \frac{3 \sin^{2} (x) \cos (x)}{\cos (x^{3}) (3 x^{2})}$

Step 3.6

Reorder the factors of $\cos (x^{3}) (3 x^{2})$ .

$lim_{x \to 0} \frac{3 \sin^{2} (x) \cos (x)}{3 x^{2} \cos (x^{3})}$

Step 4

Cancel the common factor of $3$ .

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Step 4.1

Cancel the common factor.

$lim_{x \to 0} \frac{3 \sin^{2} (x) \cos (x)}{3 x^{2} \cos (x^{3})}$

Step 4.2

Rewrite the expression.

$lim_{x \to 0} \frac{\sin^{2} (x) \cos (x)}{x^{2} \cos (x^{3})}$

Step 5

Apply L'Hospital's rule.

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Step 5.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 5.1.1

Take the limit of the numerator and the limit of the denominator.

$\frac{lim_{x \to 0} \sin^{2} (x) \cos (x)}{lim_{x \to 0} x^{2} \cos (x^{3})}$

Step 5.1.2

Evaluate the limit of the numerator.

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Step 5.1.2.1

Split the limit using the Product of Limits Rule on the limit as $x$ approaches $0$ .

$\frac{lim_{x \to 0} \sin^{2} (x) \cdot lim_{x \to 0} \cos (x)}{lim_{x \to 0} x^{2} \cos (x^{3})}$

Step 5.1.2.2

Move the exponent $2$ from $\sin^{2} (x)$ outside the limit using the Limits Power Rule.

$\frac{{(lim_{x \to 0} \sin (x))}^{2} \cdot lim_{x \to 0} \cos (x)}{lim_{x \to 0} x^{2} \cos (x^{3})}$

Step 5.1.2.3

Move the limit inside the trig function because sine is continuous.

$\frac{\sin^{2} (lim_{x \to 0} x) \cdot lim_{x \to 0} \cos (x)}{lim_{x \to 0} x^{2} \cos (x^{3})}$

Step 5.1.2.4

Move the limit inside the trig function because cosine is continuous.

$\frac{\sin^{2} (lim_{x \to 0} x) \cdot \cos (lim_{x \to 0} x)}{lim_{x \to 0} x^{2} \cos (x^{3})}$

Step 5.1.2.5

Evaluate the limits by plugging in $0$ for all occurrences of $x$ .

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Step 5.1.2.5.1

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{\sin^{2} (0) \cdot \cos (lim_{x \to 0} x)}{lim_{x \to 0} x^{2} \cos (x^{3})}$

Step 5.1.2.5.2

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{\sin^{2} (0) \cdot \cos (0)}{lim_{x \to 0} x^{2} \cos (x^{3})}$

Step 5.1.2.6

Simplify the answer.

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Step 5.1.2.6.1

The exact value of $\sin (0)$ is $0$ .

$\frac{0^{2} \cdot \cos (0)}{lim_{x \to 0} x^{2} \cos (x^{3})}$

Step 5.1.2.6.2

Raising $0$ to any positive power yields $0$ .

$\frac{0 \cdot \cos (0)}{lim_{x \to 0} x^{2} \cos (x^{3})}$

Step 5.1.2.6.3

The exact value of $\cos (0)$ is $1$ .

$\frac{0 \cdot 1}{lim_{x \to 0} x^{2} \cos (x^{3})}$

Step 5.1.2.6.4

Multiply $0$ by $1$ .

$\frac{0}{lim_{x \to 0} x^{2} \cos (x^{3})}$

Step 5.1.3

Evaluate the limit of the denominator.

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Step 5.1.3.1

Split the limit using the Product of Limits Rule on the limit as $x$ approaches $0$ .

$\frac{0}{lim_{x \to 0} x^{2} \cdot lim_{x \to 0} \cos (x^{3})}$

Step 5.1.3.2

Move the exponent $2$ from $x^{2}$ outside the limit using the Limits Power Rule.

$\frac{0}{{(lim_{x \to 0} x)}^{2} \cdot lim_{x \to 0} \cos (x^{3})}$

Step 5.1.3.3

Move the limit inside the trig function because cosine is continuous.

$\frac{0}{{(lim_{x \to 0} x)}^{2} \cdot \cos (lim_{x \to 0} x^{3})}$

Step 5.1.3.4

Move the exponent $3$ from $x^{3}$ outside the limit using the Limits Power Rule.

$\frac{0}{{(lim_{x \to 0} x)}^{2} \cdot \cos ({(lim_{x \to 0} x)}^{3})}$

Step 5.1.3.5

Evaluate the limits by plugging in $0$ for all occurrences of $x$ .

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Step 5.1.3.5.1

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{0}{0^{2} \cdot \cos ({(lim_{x \to 0} x)}^{3})}$

Step 5.1.3.5.2

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{0}{0^{2} \cdot \cos (0^{3})}$

Step 5.1.3.6

Simplify the answer.

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Step 5.1.3.6.1

Raising $0$ to any positive power yields $0$ .

$\frac{0}{0 \cdot \cos (0^{3})}$

Step 5.1.3.6.2

Raising $0$ to any positive power yields $0$ .

$\frac{0}{0 \cdot \cos (0)}$

Step 5.1.3.6.3

The exact value of $\cos (0)$ is $1$ .

$\frac{0}{0 \cdot 1}$

Step 5.1.3.6.4

Multiply $0$ by $1$ .

$\frac{0}{0}$

Step 5.1.3.6.5

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{0}{0}$

Step 5.1.3.7

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{0}{0}$

Step 5.1.4

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{0}{0}$

Step 5.2

Since $\frac{0}{0}$ is of indeterminate form, apply L'Hospital's Rule. L'Hospital's Rule states that the limit of a quotient of functions is equal to the limit of the quotient of their derivatives.

$lim_{x \to 0} \frac{\sin^{2} (x) \cos (x)}{x^{2} \cos (x^{3})} = lim_{x \to 0} \frac{\frac{d}{d x} [\sin^{2} (x) \cos (x)]}{\frac{d}{d x} [x^{2} \cos (x^{3})]}$

Step 5.3

Find the derivative of the numerator and denominator.

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Step 5.3.1

Differentiate the numerator and denominator.

$lim_{x \to 0} \frac{\frac{d}{d x} [\sin^{2} (x) \cos (x)]}{\frac{d}{d x} [x^{2} \cos (x^{3})]}$

Step 5.3.2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = \sin^{2} (x)$ and $g (x) = \cos (x)$ .

$lim_{x \to 0} \frac{\sin^{2} (x) \frac{d}{d x} [\cos (x)] + \cos (x) \frac{d}{d x} [\sin^{2} (x)]}{\frac{d}{d x} [x^{2} \cos (x^{3})]}$

Step 5.3.3

The derivative of $\cos (x)$ with respect to $x$ is $- \sin (x)$ .

$lim_{x \to 0} \frac{\sin^{2} (x) (- \sin (x)) + \cos (x) \frac{d}{d x} [\sin^{2} (x)]}{\frac{d}{d x} [x^{2} \cos (x^{3})]}$

Step 5.3.4

Multiply $\sin^{2} (x)$ by $\sin (x)$ by adding the exponents.

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Step 5.3.4.1

Move $\sin (x)$ .

$lim_{x \to 0} \frac{\sin (x) \sin^{2} (x) \cdot - 1 + \cos (x) \frac{d}{d x} [\sin^{2} (x)]}{\frac{d}{d x} [x^{2} \cos (x^{3})]}$

Step 5.3.4.2

Multiply $\sin (x)$ by $\sin^{2} (x)$ .

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Step 5.3.4.2.1

Raise $\sin (x)$ to the power of $1$ .

$lim_{x \to 0} \frac{\sin^{1} (x) \sin^{2} (x) \cdot - 1 + \cos (x) \frac{d}{d x} [\sin^{2} (x)]}{\frac{d}{d x} [x^{2} \cos (x^{3})]}$

Step 5.3.4.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$lim_{x \to 0} \frac{{\sin (x)}^{1 + 2} \cdot - 1 + \cos (x) \frac{d}{d x} [\sin^{2} (x)]}{\frac{d}{d x} [x^{2} \cos (x^{3})]}$

Step 5.3.4.3

Add $1$ and $2$ .

$lim_{x \to 0} \frac{\sin^{3} (x) \cdot - 1 + \cos (x) \frac{d}{d x} [\sin^{2} (x)]}{\frac{d}{d x} [x^{2} \cos (x^{3})]}$

Step 5.3.5

Move $- 1$ to the left of $\sin^{3} (x)$ .

$lim_{x \to 0} \frac{- 1 \cdot \sin^{3} (x) + \cos (x) \frac{d}{d x} [\sin^{2} (x)]}{\frac{d}{d x} [x^{2} \cos (x^{3})]}$

Step 5.3.6

Rewrite $- 1 \sin^{3} (x)$ as $- \sin^{3} (x)$ .

$lim_{x \to 0} \frac{- \sin^{3} (x) + \cos (x) \frac{d}{d x} [\sin^{2} (x)]}{\frac{d}{d x} [x^{2} \cos (x^{3})]}$

Step 5.3.7

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = \sin (x)$ .

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Step 5.3.7.1

To apply the Chain Rule, set $u$ as $\sin (x)$ .

$lim_{x \to 0} \frac{- \sin^{3} (x) + \cos (x) (\frac{d}{d u} [u^{2}] \frac{d}{d x} [\sin (x)])}{\frac{d}{d x} [x^{2} \cos (x^{3})]}$

Step 5.3.7.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 2$ .

$lim_{x \to 0} \frac{- \sin^{3} (x) + \cos (x) (2 u \frac{d}{d x} [\sin (x)])}{\frac{d}{d x} [x^{2} \cos (x^{3})]}$

Step 5.3.7.3

Replace all occurrences of $u$ with $\sin (x)$ .

$lim_{x \to 0} \frac{- \sin^{3} (x) + \cos (x) (2 \sin (x) \frac{d}{d x} [\sin (x)])}{\frac{d}{d x} [x^{2} \cos (x^{3})]}$

Step 5.3.8

Move $2$ to the left of $\cos (x)$ .

$lim_{x \to 0} \frac{- \sin^{3} (x) + 2 \cdot \cos (x) \sin (x) \frac{d}{d x} [\sin (x)]}{\frac{d}{d x} [x^{2} \cos (x^{3})]}$

Step 5.3.9

The derivative of $\sin (x)$ with respect to $x$ is $\cos (x)$ .

$lim_{x \to 0} \frac{- \sin^{3} (x) + 2 \cos (x) \sin (x) \cos (x)}{\frac{d}{d x} [x^{2} \cos (x^{3})]}$

Step 5.3.10

Raise $\cos (x)$ to the power of $1$ .

$lim_{x \to 0} \frac{- \sin^{3} (x) + 2 (\cos^{1} (x) \cos (x)) \sin (x)}{\frac{d}{d x} [x^{2} \cos (x^{3})]}$

Step 5.3.11

Raise $\cos (x)$ to the power of $1$ .

$lim_{x \to 0} \frac{- \sin^{3} (x) + 2 (\cos^{1} (x) \cos^{1} (x)) \sin (x)}{\frac{d}{d x} [x^{2} \cos (x^{3})]}$

Step 5.3.12

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$lim_{x \to 0} \frac{- \sin^{3} (x) + 2 {\cos (x)}^{1 + 1} \sin (x)}{\frac{d}{d x} [x^{2} \cos (x^{3})]}$

Step 5.3.13

Add $1$ and $1$ .

$lim_{x \to 0} \frac{- \sin^{3} (x) + 2 \cos^{2} (x) \sin (x)}{\frac{d}{d x} [x^{2} \cos (x^{3})]}$

Step 5.3.14

Reorder terms.

$lim_{x \to 0} \frac{2 \cos^{2} (x) \sin (x) - \sin^{3} (x)}{\frac{d}{d x} [x^{2} \cos (x^{3})]}$

Step 5.3.15

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x^{2}$ and $g (x) = \cos (x^{3})$ .

$lim_{x \to 0} \frac{2 \cos^{2} (x) \sin (x) - \sin^{3} (x)}{x^{2} \frac{d}{d x} [\cos (x^{3})] + \cos (x^{3}) \frac{d}{d x} [x^{2}]}$

Step 5.3.16

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = \cos (x)$ and $g (x) = x^{3}$ .

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Step 5.3.16.1

To apply the Chain Rule, set $u$ as $x^{3}$ .

$lim_{x \to 0} \frac{2 \cos^{2} (x) \sin (x) - \sin^{3} (x)}{x^{2} (\frac{d}{d u} [\cos (u)] \frac{d}{d x} [x^{3}]) + \cos (x^{3}) \frac{d}{d x} [x^{2}]}$

Step 5.3.16.2

The derivative of $\cos (u)$ with respect to $u$ is $- \sin (u)$ .

$lim_{x \to 0} \frac{2 \cos^{2} (x) \sin (x) - \sin^{3} (x)}{x^{2} (- \sin (u) \frac{d}{d x} [x^{3}]) + \cos (x^{3}) \frac{d}{d x} [x^{2}]}$

Step 5.3.16.3

Replace all occurrences of $u$ with $x^{3}$ .

$lim_{x \to 0} \frac{2 \cos^{2} (x) \sin (x) - \sin^{3} (x)}{x^{2} (- \sin (x^{3}) \frac{d}{d x} [x^{3}]) + \cos (x^{3}) \frac{d}{d x} [x^{2}]}$

Step 5.3.17

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$lim_{x \to 0} \frac{2 \cos^{2} (x) \sin (x) - \sin^{3} (x)}{x^{2} (- \sin (x^{3}) (3 x^{2})) + \cos (x^{3}) \frac{d}{d x} [x^{2}]}$

Step 5.3.18

Multiply $3$ by $- 1$ .

$lim_{x \to 0} \frac{2 \cos^{2} (x) \sin (x) - \sin^{3} (x)}{x^{2} (- 3 \sin (x^{3}) x^{2}) + \cos (x^{3}) \frac{d}{d x} [x^{2}]}$

Step 5.3.19

Multiply $x^{2}$ by $x^{2}$ by adding the exponents.

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Step 5.3.19.1

Move $x^{2}$ .

$lim_{x \to 0} \frac{2 \cos^{2} (x) \sin (x) - \sin^{3} (x)}{x^{2} x^{2} (- 3 \sin (x^{3})) + \cos (x^{3}) \frac{d}{d x} [x^{2}]}$

Step 5.3.19.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$lim_{x \to 0} \frac{2 \cos^{2} (x) \sin (x) - \sin^{3} (x)}{x^{2 + 2} (- 3 \sin (x^{3})) + \cos (x^{3}) \frac{d}{d x} [x^{2}]}$

Step 5.3.19.3

Add $2$ and $2$ .

$lim_{x \to 0} \frac{2 \cos^{2} (x) \sin (x) - \sin^{3} (x)}{x^{4} (- 3 \sin (x^{3})) + \cos (x^{3}) \frac{d}{d x} [x^{2}]}$

Step 5.3.20

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$lim_{x \to 0} \frac{2 \cos^{2} (x) \sin (x) - \sin^{3} (x)}{x^{4} (- 3 \sin (x^{3})) + \cos (x^{3}) (2 x)}$

Step 5.3.21

Reorder terms.

$lim_{x \to 0} \frac{2 \cos^{2} (x) \sin (x) - \sin^{3} (x)}{- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6

Apply L'Hospital's rule.

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Step 6.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 6.1.1

Take the limit of the numerator and the limit of the denominator.

$\frac{lim_{x \to 0} 2 \cos^{2} (x) \sin (x) - \sin^{3} (x)}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.2

Evaluate the limit of the numerator.

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Step 6.1.2.1

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $0$ .

$\frac{lim_{x \to 0} 2 \cos^{2} (x) \sin (x) - lim_{x \to 0} \sin^{3} (x)}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.2.2

Move the term $2$ outside of the limit because it is constant with respect to $x$ .

$\frac{2 lim_{x \to 0} \cos^{2} (x) \sin (x) - lim_{x \to 0} \sin^{3} (x)}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.2.3

Split the limit using the Product of Limits Rule on the limit as $x$ approaches $0$ .

$\frac{2 lim_{x \to 0} \cos^{2} (x) \cdot lim_{x \to 0} \sin (x) - lim_{x \to 0} \sin^{3} (x)}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.2.4

Move the exponent $2$ from $\cos^{2} (x)$ outside the limit using the Limits Power Rule.

$\frac{2 {(lim_{x \to 0} \cos (x))}^{2} \cdot lim_{x \to 0} \sin (x) - lim_{x \to 0} \sin^{3} (x)}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.2.5

Move the limit inside the trig function because cosine is continuous.

$\frac{2 \cos^{2} (lim_{x \to 0} x) \cdot lim_{x \to 0} \sin (x) - lim_{x \to 0} \sin^{3} (x)}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.2.6

Move the limit inside the trig function because sine is continuous.

$\frac{2 \cos^{2} (lim_{x \to 0} x) \cdot \sin (lim_{x \to 0} x) - lim_{x \to 0} \sin^{3} (x)}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.2.7

Move the exponent $3$ from $\sin^{3} (x)$ outside the limit using the Limits Power Rule.

$\frac{2 \cos^{2} (lim_{x \to 0} x) \cdot \sin (lim_{x \to 0} x) - {(lim_{x \to 0} \sin (x))}^{3}}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.2.8

Move the limit inside the trig function because sine is continuous.

$\frac{2 \cos^{2} (lim_{x \to 0} x) \cdot \sin (lim_{x \to 0} x) - \sin^{3} (lim_{x \to 0} x)}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.2.9

Evaluate the limits by plugging in $0$ for all occurrences of $x$ .

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Step 6.1.2.9.1

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{2 \cos^{2} (0) \cdot \sin (lim_{x \to 0} x) - \sin^{3} (lim_{x \to 0} x)}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.2.9.2

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{2 \cos^{2} (0) \cdot \sin (0) - \sin^{3} (lim_{x \to 0} x)}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.2.9.3

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{2 \cos^{2} (0) \cdot \sin (0) - \sin^{3} (0)}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.2.10

Simplify the answer.

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Step 6.1.2.10.1

Simplify each term.

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Step 6.1.2.10.1.1

The exact value of $\cos (0)$ is $1$ .

$\frac{2 \cdot 1^{2} \cdot \sin (0) - \sin^{3} (0)}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.2.10.1.2

One to any power is one.

$\frac{2 \cdot 1 \cdot \sin (0) - \sin^{3} (0)}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.2.10.1.3

Multiply $2$ by $1$ .

$\frac{2 \cdot \sin (0) - \sin^{3} (0)}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.2.10.1.4

The exact value of $\sin (0)$ is $0$ .

$\frac{2 \cdot 0 - \sin^{3} (0)}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.2.10.1.5

Multiply $2$ by $0$ .

$\frac{0 - \sin^{3} (0)}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.2.10.1.6

The exact value of $\sin (0)$ is $0$ .

$\frac{0 - 0^{3}}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.2.10.1.7

Raising $0$ to any positive power yields $0$ .

$\frac{0 - 0}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.2.10.1.8

Multiply $- 1$ by $0$ .

$\frac{0 + 0}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.2.10.2

Add $0$ and $0$ .

$\frac{0}{lim_{x \to 0} - 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})}$

Step 6.1.3

Evaluate the limit of the denominator.

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Step 6.1.3.1

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $0$ .

$\frac{0}{- lim_{x \to 0} 3 x^{4} \sin (x^{3}) + lim_{x \to 0} 2 x \cos (x^{3})}$

Step 6.1.3.2

Move the term $3$ outside of the limit because it is constant with respect to $x$ .

$\frac{0}{- 3 lim_{x \to 0} x^{4} \sin (x^{3}) + lim_{x \to 0} 2 x \cos (x^{3})}$

Step 6.1.3.3

Split the limit using the Product of Limits Rule on the limit as $x$ approaches $0$ .

$\frac{0}{- 3 lim_{x \to 0} x^{4} \cdot lim_{x \to 0} \sin (x^{3}) + lim_{x \to 0} 2 x \cos (x^{3})}$

Step 6.1.3.4

Move the exponent $4$ from $x^{4}$ outside the limit using the Limits Power Rule.

$\frac{0}{- 3 {(lim_{x \to 0} x)}^{4} \cdot lim_{x \to 0} \sin (x^{3}) + lim_{x \to 0} 2 x \cos (x^{3})}$

Step 6.1.3.5

Move the limit inside the trig function because sine is continuous.

$\frac{0}{- 3 {(lim_{x \to 0} x)}^{4} \cdot \sin (lim_{x \to 0} x^{3}) + lim_{x \to 0} 2 x \cos (x^{3})}$

Step 6.1.3.6

Move the exponent $3$ from $x^{3}$ outside the limit using the Limits Power Rule.

$\frac{0}{- 3 {(lim_{x \to 0} x)}^{4} \cdot \sin ({(lim_{x \to 0} x)}^{3}) + lim_{x \to 0} 2 x \cos (x^{3})}$

Step 6.1.3.7

Move the term $2$ outside of the limit because it is constant with respect to $x$ .

$\frac{0}{- 3 {(lim_{x \to 0} x)}^{4} \cdot \sin ({(lim_{x \to 0} x)}^{3}) + 2 lim_{x \to 0} x \cos (x^{3})}$

Step 6.1.3.8

Split the limit using the Product of Limits Rule on the limit as $x$ approaches $0$ .

$\frac{0}{- 3 {(lim_{x \to 0} x)}^{4} \cdot \sin ({(lim_{x \to 0} x)}^{3}) + 2 lim_{x \to 0} x \cdot lim_{x \to 0} \cos (x^{3})}$

Step 6.1.3.9

Move the limit inside the trig function because cosine is continuous.

$\frac{0}{- 3 {(lim_{x \to 0} x)}^{4} \cdot \sin ({(lim_{x \to 0} x)}^{3}) + 2 lim_{x \to 0} x \cdot \cos (lim_{x \to 0} x^{3})}$

Step 6.1.3.10

Move the exponent $3$ from $x^{3}$ outside the limit using the Limits Power Rule.

$\frac{0}{- 3 {(lim_{x \to 0} x)}^{4} \cdot \sin ({(lim_{x \to 0} x)}^{3}) + 2 lim_{x \to 0} x \cdot \cos ({(lim_{x \to 0} x)}^{3})}$

Step 6.1.3.11

Evaluate the limits by plugging in $0$ for all occurrences of $x$ .

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Step 6.1.3.11.1

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{0}{- 3 \cdot 0^{4} \cdot \sin ({(lim_{x \to 0} x)}^{3}) + 2 lim_{x \to 0} x \cdot \cos ({(lim_{x \to 0} x)}^{3})}$

Step 6.1.3.11.2

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{0}{- 3 \cdot 0^{4} \cdot \sin (0^{3}) + 2 lim_{x \to 0} x \cdot \cos ({(lim_{x \to 0} x)}^{3})}$

Step 6.1.3.11.3

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{0}{- 3 \cdot 0^{4} \cdot \sin (0^{3}) + 2 \cdot 0 \cdot \cos ({(lim_{x \to 0} x)}^{3})}$

Step 6.1.3.11.4

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{0}{- 3 \cdot 0^{4} \cdot \sin (0^{3}) + 2 \cdot 0 \cdot \cos (0^{3})}$

Step 6.1.3.12

Simplify the answer.

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Step 6.1.3.12.1

Simplify each term.

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Step 6.1.3.12.1.1

Raising $0$ to any positive power yields $0$ .

$\frac{0}{- 3 \cdot 0 \cdot \sin (0^{3}) + 2 \cdot 0 \cdot \cos (0^{3})}$

Step 6.1.3.12.1.2

Multiply $- 3$ by $0$ .

$\frac{0}{0 \cdot \sin (0^{3}) + 2 \cdot 0 \cdot \cos (0^{3})}$

Step 6.1.3.12.1.3

Raising $0$ to any positive power yields $0$ .

$\frac{0}{0 \cdot \sin (0) + 2 \cdot 0 \cdot \cos (0^{3})}$

Step 6.1.3.12.1.4

The exact value of $\sin (0)$ is $0$ .

$\frac{0}{0 \cdot 0 + 2 \cdot 0 \cdot \cos (0^{3})}$

Step 6.1.3.12.1.5

Multiply $0$ by $0$ .

$\frac{0}{0 + 2 \cdot 0 \cdot \cos (0^{3})}$

Step 6.1.3.12.1.6

Multiply $2$ by $0$ .

$\frac{0}{0 + 0 \cdot \cos (0^{3})}$

Step 6.1.3.12.1.7

Raising $0$ to any positive power yields $0$ .

$\frac{0}{0 + 0 \cdot \cos (0)}$

Step 6.1.3.12.1.8

The exact value of $\cos (0)$ is $1$ .

$\frac{0}{0 + 0 \cdot 1}$

Step 6.1.3.12.1.9

Multiply $0$ by $1$ .

$\frac{0}{0 + 0}$

Step 6.1.3.12.2

Add $0$ and $0$ .

$\frac{0}{0}$

Step 6.1.3.12.3

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{0}{0}$

Step 6.1.3.13

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{0}{0}$

Step 6.1.4

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{0}{0}$

Step 6.2

Since $\frac{0}{0}$ is of indeterminate form, apply L'Hospital's Rule. L'Hospital's Rule states that the limit of a quotient of functions is equal to the limit of the quotient of their derivatives.

$lim_{x \to 0} \frac{2 \cos^{2} (x) \sin (x) - \sin^{3} (x)}{- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})} = lim_{x \to 0} \frac{\frac{d}{d x} [2 \cos^{2} (x) \sin (x) - \sin^{3} (x)]}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3

Find the derivative of the numerator and denominator.

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Step 6.3.1

Differentiate the numerator and denominator.

$lim_{x \to 0} \frac{\frac{d}{d x} [2 \cos^{2} (x) \sin (x) - \sin^{3} (x)]}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.2

By the Sum Rule, the derivative of $2 \cos^{2} (x) \sin (x) - \sin^{3} (x)$ with respect to $x$ is $\frac{d}{d x} [2 \cos^{2} (x) \sin (x)] + \frac{d}{d x} [- \sin^{3} (x)]$ .

$lim_{x \to 0} \frac{\frac{d}{d x} [2 \cos^{2} (x) \sin (x)] + \frac{d}{d x} [- \sin^{3} (x)]}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.3

Evaluate $\frac{d}{d x} [2 \cos^{2} (x) \sin (x)]$ .

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Step 6.3.3.1

Since $2$ is constant with respect to $x$ , the derivative of $2 \cos^{2} (x) \sin (x)$ with respect to $x$ is $2 \frac{d}{d x} [\cos^{2} (x) \sin (x)]$ .

$lim_{x \to 0} \frac{2 \frac{d}{d x} [\cos^{2} (x) \sin (x)] + \frac{d}{d x} [- \sin^{3} (x)]}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.3.2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = \cos^{2} (x)$ and $g (x) = \sin (x)$ .

$lim_{x \to 0} \frac{2 (\cos^{2} (x) \frac{d}{d x} [\sin (x)] + \sin (x) \frac{d}{d x} [\cos^{2} (x)]) + \frac{d}{d x} [- \sin^{3} (x)]}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.3.3

The derivative of $\sin (x)$ with respect to $x$ is $\cos (x)$ .

$lim_{x \to 0} \frac{2 (\cos^{2} (x) \cos (x) + \sin (x) \frac{d}{d x} [\cos^{2} (x)]) + \frac{d}{d x} [- \sin^{3} (x)]}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.3.4

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = \cos (x)$ .

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Step 6.3.3.4.1

To apply the Chain Rule, set $u_{1}$ as $\cos (x)$ .

$lim_{x \to 0} \frac{2 (\cos^{2} (x) \cos (x) + \sin (x) (\frac{d}{d u_{1}} [{u_{1}}^{2}] \frac{d}{d x} [\cos (x)])) + \frac{d}{d x} [- \sin^{3} (x)]}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.3.4.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{1}} [{u_{1}}^{n}]$ is $n {u_{1}}^{n - 1}$ where $n = 2$ .

$lim_{x \to 0} \frac{2 (\cos^{2} (x) \cos (x) + \sin (x) (2 u_{1} \frac{d}{d x} [\cos (x)])) + \frac{d}{d x} [- \sin^{3} (x)]}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.3.4.3

Replace all occurrences of $u_{1}$ with $\cos (x)$ .

$lim_{x \to 0} \frac{2 (\cos^{2} (x) \cos (x) + \sin (x) (2 \cos (x) \frac{d}{d x} [\cos (x)])) + \frac{d}{d x} [- \sin^{3} (x)]}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.3.5

The derivative of $\cos (x)$ with respect to $x$ is $- \sin (x)$ .

$lim_{x \to 0} \frac{2 (\cos^{2} (x) \cos (x) + \sin (x) (2 \cos (x) (- \sin (x)))) + \frac{d}{d x} [- \sin^{3} (x)]}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.3.6

Multiply $\cos^{2} (x)$ by $\cos (x)$ by adding the exponents.

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Step 6.3.3.6.1

Multiply $\cos^{2} (x)$ by $\cos (x)$ .

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Step 6.3.3.6.1.1

Raise $\cos (x)$ to the power of $1$ .

$lim_{x \to 0} \frac{2 (\cos^{2} (x) \cos^{1} (x) + \sin (x) (2 \cos (x) (- \sin (x)))) + \frac{d}{d x} [- \sin^{3} (x)]}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.3.6.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$lim_{x \to 0} \frac{2 ({\cos (x)}^{2 + 1} + \sin (x) (2 \cos (x) (- \sin (x)))) + \frac{d}{d x} [- \sin^{3} (x)]}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.3.6.2

Add $2$ and $1$ .

$lim_{x \to 0} \frac{2 (\cos^{3} (x) + \sin (x) (2 \cos (x) (- \sin (x)))) + \frac{d}{d x} [- \sin^{3} (x)]}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.3.7

Multiply $- 1$ by $2$ .

$lim_{x \to 0} \frac{2 (\cos^{3} (x) + \sin (x) (- 2 \cos (x) \sin (x))) + \frac{d}{d x} [- \sin^{3} (x)]}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.3.8

Raise $\sin (x)$ to the power of $1$ .

$lim_{x \to 0} \frac{2 (\cos^{3} (x) - 2 \cos (x) (\sin^{1} (x) \sin (x))) + \frac{d}{d x} [- \sin^{3} (x)]}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.3.9

Raise $\sin (x)$ to the power of $1$ .

$lim_{x \to 0} \frac{2 (\cos^{3} (x) - 2 \cos (x) (\sin^{1} (x) \sin^{1} (x))) + \frac{d}{d x} [- \sin^{3} (x)]}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.3.10

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$lim_{x \to 0} \frac{2 (\cos^{3} (x) - 2 \cos (x) {\sin (x)}^{1 + 1}) + \frac{d}{d x} [- \sin^{3} (x)]}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.3.11

Add $1$ and $1$ .

$lim_{x \to 0} \frac{2 (\cos^{3} (x) - 2 \cos (x) \sin^{2} (x)) + \frac{d}{d x} [- \sin^{3} (x)]}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.4

Evaluate $\frac{d}{d x} [- \sin^{3} (x)]$ .

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Step 6.3.4.1

Since $- 1$ is constant with respect to $x$ , the derivative of $- \sin^{3} (x)$ with respect to $x$ is $- \frac{d}{d x} [\sin^{3} (x)]$ .

$lim_{x \to 0} \frac{2 (\cos^{3} (x) - 2 \cos (x) \sin^{2} (x)) - \frac{d}{d x} [\sin^{3} (x)]}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.4.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{3}$ and $g (x) = \sin (x)$ .

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Step 6.3.4.2.1

To apply the Chain Rule, set $u_{2}$ as $\sin (x)$ .

$lim_{x \to 0} \frac{2 (\cos^{3} (x) - 2 \cos (x) \sin^{2} (x)) - (\frac{d}{d u_{2}} [{u_{2}}^{3}] \frac{d}{d x} [\sin (x)])}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.4.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{2}} [{u_{2}}^{n}]$ is $n {u_{2}}^{n - 1}$ where $n = 3$ .

$lim_{x \to 0} \frac{2 (\cos^{3} (x) - 2 \cos (x) \sin^{2} (x)) - (3 {u_{2}}^{2} \frac{d}{d x} [\sin (x)])}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.4.2.3

Replace all occurrences of $u_{2}$ with $\sin (x)$ .

$lim_{x \to 0} \frac{2 (\cos^{3} (x) - 2 \cos (x) \sin^{2} (x)) - (3 \sin^{2} (x) \frac{d}{d x} [\sin (x)])}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.4.3

The derivative of $\sin (x)$ with respect to $x$ is $\cos (x)$ .

$lim_{x \to 0} \frac{2 (\cos^{3} (x) - 2 \cos (x) \sin^{2} (x)) - (3 \sin^{2} (x) \cos (x))}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.4.4

Multiply $3$ by $- 1$ .

$lim_{x \to 0} \frac{2 (\cos^{3} (x) - 2 \cos (x) \sin^{2} (x)) - 3 \sin^{2} (x) \cos (x)}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.5

Simplify.

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Step 6.3.5.1

Apply the distributive property.

$lim_{x \to 0} \frac{2 \cos^{3} (x) + 2 (- 2 \cos (x) \sin^{2} (x)) - 3 \sin^{2} (x) \cos (x)}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.5.2

Combine terms.

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Step 6.3.5.2.1

Multiply $- 2$ by $2$ .

$lim_{x \to 0} \frac{2 \cos^{3} (x) - 4 (\cos (x) \sin^{2} (x)) - 3 \sin^{2} (x) \cos (x)}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.5.2.2

Reorder the factors of $- 4 \cos (x) \sin^{2} (x)$ .

$lim_{x \to 0} \frac{2 \cos^{3} (x) - 4 \sin^{2} (x) \cos (x) - 3 \sin^{2} (x) \cos (x)}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.5.2.3

Subtract $3 \sin^{2} (x) \cos (x)$ from $- 4 \sin^{2} (x) \cos (x)$ .

$lim_{x \to 0} \frac{2 \cos^{3} (x) - 7 \sin^{2} (x) \cos (x)}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.5.3

Reorder terms.

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})]}$

Step 6.3.6

By the Sum Rule, the derivative of $- 3 x^{4} \sin (x^{3}) + 2 x \cos (x^{3})$ with respect to $x$ is $\frac{d}{d x} [- 3 x^{4} \sin (x^{3})] + \frac{d}{d x} [2 x \cos (x^{3})]$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{\frac{d}{d x} [- 3 x^{4} \sin (x^{3})] + \frac{d}{d x} [2 x \cos (x^{3})]}$

Step 6.3.7

Evaluate $\frac{d}{d x} [- 3 x^{4} \sin (x^{3})]$ .

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Step 6.3.7.1

Since $- 3$ is constant with respect to $x$ , the derivative of $- 3 x^{4} \sin (x^{3})$ with respect to $x$ is $- 3 \frac{d}{d x} [x^{4} \sin (x^{3})]$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 \frac{d}{d x} [x^{4} \sin (x^{3})] + \frac{d}{d x} [2 x \cos (x^{3})]}$

Step 6.3.7.2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x^{4}$ and $g (x) = \sin (x^{3})$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{4} \frac{d}{d x} [\sin (x^{3})] + \sin (x^{3}) \frac{d}{d x} [x^{4}]) + \frac{d}{d x} [2 x \cos (x^{3})]}$

Step 6.3.7.3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = \sin (x)$ and $g (x) = x^{3}$ .

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Step 6.3.7.3.1

To apply the Chain Rule, set $u_{1}$ as $x^{3}$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{4} (\frac{d}{d u_{1}} [\sin (u_{1})] \frac{d}{d x} [x^{3}]) + \sin (x^{3}) \frac{d}{d x} [x^{4}]) + \frac{d}{d x} [2 x \cos (x^{3})]}$

Step 6.3.7.3.2

The derivative of $\sin (u_{1})$ with respect to $u_{1}$ is $\cos (u_{1})$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{4} (\cos (u_{1}) \frac{d}{d x} [x^{3}]) + \sin (x^{3}) \frac{d}{d x} [x^{4}]) + \frac{d}{d x} [2 x \cos (x^{3})]}$

Step 6.3.7.3.3

Replace all occurrences of $u_{1}$ with $x^{3}$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{4} (\cos (x^{3}) \frac{d}{d x} [x^{3}]) + \sin (x^{3}) \frac{d}{d x} [x^{4}]) + \frac{d}{d x} [2 x \cos (x^{3})]}$

Step 6.3.7.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{4} (\cos (x^{3}) (3 x^{2})) + \sin (x^{3}) \frac{d}{d x} [x^{4}]) + \frac{d}{d x} [2 x \cos (x^{3})]}$

Step 6.3.7.5

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 4$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{4} (\cos (x^{3}) (3 x^{2})) + \sin (x^{3}) (4 x^{3})) + \frac{d}{d x} [2 x \cos (x^{3})]}$

Step 6.3.7.6

Multiply $x^{4}$ by $x^{2}$ by adding the exponents.

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Step 6.3.7.6.1

Move $x^{2}$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{2} x^{4} (\cos (x^{3}) \cdot (3)) + \sin (x^{3}) (4 x^{3})) + \frac{d}{d x} [2 x \cos (x^{3})]}$

Step 6.3.7.6.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{2 + 4} (\cos (x^{3}) \cdot (3)) + \sin (x^{3}) (4 x^{3})) + \frac{d}{d x} [2 x \cos (x^{3})]}$

Step 6.3.7.6.3

Add $2$ and $4$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{6} (\cos (x^{3}) \cdot (3)) + \sin (x^{3}) (4 x^{3})) + \frac{d}{d x} [2 x \cos (x^{3})]}$

Step 6.3.7.7

Move $3$ to the left of $\cos (x^{3})$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{6} (3 \cos (x^{3})) + \sin (x^{3}) (4 x^{3})) + \frac{d}{d x} [2 x \cos (x^{3})]}$

Step 6.3.8

Evaluate $\frac{d}{d x} [2 x \cos (x^{3})]$ .

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Step 6.3.8.1

Since $2$ is constant with respect to $x$ , the derivative of $2 x \cos (x^{3})$ with respect to $x$ is $2 \frac{d}{d x} [x \cos (x^{3})]$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{6} (3 \cos (x^{3})) + \sin (x^{3}) (4 x^{3})) + 2 \frac{d}{d x} [x \cos (x^{3})]}$

Step 6.3.8.2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x$ and $g (x) = \cos (x^{3})$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{6} (3 \cos (x^{3})) + \sin (x^{3}) (4 x^{3})) + 2 (x \frac{d}{d x} [\cos (x^{3})] + \cos (x^{3}) \frac{d}{d x} [x])}$

Step 6.3.8.3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = \cos (x)$ and $g (x) = x^{3}$ .

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Step 6.3.8.3.1

To apply the Chain Rule, set $u_{2}$ as $x^{3}$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{6} (3 \cos (x^{3})) + \sin (x^{3}) (4 x^{3})) + 2 (x (\frac{d}{d u_{2}} [\cos (u_{2})] \frac{d}{d x} [x^{3}]) + \cos (x^{3}) \frac{d}{d x} [x])}$

Step 6.3.8.3.2

The derivative of $\cos (u_{2})$ with respect to $u_{2}$ is $- \sin (u_{2})$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{6} (3 \cos (x^{3})) + \sin (x^{3}) (4 x^{3})) + 2 (x (- \sin (u_{2}) \frac{d}{d x} [x^{3}]) + \cos (x^{3}) \frac{d}{d x} [x])}$

Step 6.3.8.3.3

Replace all occurrences of $u_{2}$ with $x^{3}$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{6} (3 \cos (x^{3})) + \sin (x^{3}) (4 x^{3})) + 2 (x (- \sin (x^{3}) \frac{d}{d x} [x^{3}]) + \cos (x^{3}) \frac{d}{d x} [x])}$

Step 6.3.8.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{6} (3 \cos (x^{3})) + \sin (x^{3}) (4 x^{3})) + 2 (x (- \sin (x^{3}) (3 x^{2})) + \cos (x^{3}) \frac{d}{d x} [x])}$

Step 6.3.8.5

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{6} (3 \cos (x^{3})) + \sin (x^{3}) (4 x^{3})) + 2 (x (- \sin (x^{3}) (3 x^{2})) + \cos (x^{3}) \cdot 1)}$

Step 6.3.8.6

Multiply $3$ by $- 1$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{6} (3 \cos (x^{3})) + \sin (x^{3}) (4 x^{3})) + 2 (x (- 3 \sin (x^{3}) x^{2}) + \cos (x^{3}) \cdot 1)}$

Step 6.3.8.7

Raise $x$ to the power of $1$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{6} (3 \cos (x^{3})) + \sin (x^{3}) (4 x^{3})) + 2 (x^{2} x^{1} (- 3 \sin (x^{3})) + \cos (x^{3}) \cdot 1)}$

Step 6.3.8.8

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{6} (3 \cos (x^{3})) + \sin (x^{3}) (4 x^{3})) + 2 (x^{2 + 1} (- 3 \sin (x^{3})) + \cos (x^{3}) \cdot 1)}$

Step 6.3.8.9

Add $2$ and $1$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{6} (3 \cos (x^{3})) + \sin (x^{3}) (4 x^{3})) + 2 (x^{3} (- 3 \sin (x^{3})) + \cos (x^{3}) \cdot 1)}$

Step 6.3.8.10

Multiply $\cos (x^{3})$ by $1$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{6} (3 \cos (x^{3})) + \sin (x^{3}) (4 x^{3})) + 2 (x^{3} (- 3 \sin (x^{3})) + \cos (x^{3}))}$

Step 6.3.9

Simplify.

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Step 6.3.9.1

Apply the distributive property.

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{6} (3 \cos (x^{3}))) - 3 (\sin (x^{3}) (4 x^{3})) + 2 (x^{3} (- 3 \sin (x^{3})) + \cos (x^{3}))}$

Step 6.3.9.2

Apply the distributive property.

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 3 (x^{6} (3 \cos (x^{3}))) - 3 (\sin (x^{3}) (4 x^{3})) + 2 (x^{3} (- 3 \sin (x^{3}))) + 2 \cos (x^{3})}$

Step 6.3.9.3

Combine terms.

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Step 6.3.9.3.1

Multiply $3$ by $- 3$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 9 (x^{6} (\cos (x^{3}))) - 3 (\sin (x^{3}) (4 x^{3})) + 2 (x^{3} (- 3 \sin (x^{3}))) + 2 \cos (x^{3})}$

Step 6.3.9.3.2

Multiply $4$ by $- 3$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 9 x^{6} \cos (x^{3}) - 12 (\sin (x^{3}) (x^{3})) + 2 (x^{3} (- 3 \sin (x^{3}))) + 2 \cos (x^{3})}$

Step 6.3.9.3.3

Multiply $- 3$ by $2$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 9 x^{6} \cos (x^{3}) - 12 \sin (x^{3}) x^{3} - 6 (x^{3} (\sin (x^{3}))) + 2 \cos (x^{3})}$

Step 6.3.9.3.4

Subtract $6 x^{3} \sin (x^{3})$ from $- 12 \sin (x^{3}) x^{3}$ .

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Step 6.3.9.3.4.1

Move $\sin (x^{3})$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 9 x^{6} \cos (x^{3}) - 12 x^{3} \sin (x^{3}) - 6 x^{3} \sin (x^{3}) + 2 \cos (x^{3})}$

Step 6.3.9.3.4.2

Subtract $6 x^{3} \sin (x^{3})$ from $- 12 x^{3} \sin (x^{3})$ .

$lim_{x \to 0} \frac{- 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{- 9 x^{6} \cos (x^{3}) - 18 x^{3} \sin (x^{3}) + 2 \cos (x^{3})}$

Step 7

Evaluate the limit.

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Step 7.1

Split the limit using the Limits Quotient Rule on the limit as $x$ approaches $0$ .

$\frac{lim_{x \to 0} - 7 \sin^{2} (x) \cos (x) + 2 \cos^{3} (x)}{lim_{x \to 0} - 9 x^{6} \cos (x^{3}) - 18 x^{3} \sin (x^{3}) + 2 \cos (x^{3})}$

Step 7.2

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $0$ .

$\frac{- lim_{x \to 0} 7 \sin^{2} (x) \cos (x) + lim_{x \to 0} 2 \cos^{3} (x)}{lim_{x \to 0} - 9 x^{6} \cos (x^{3}) - 18 x^{3} \sin (x^{3}) + 2 \cos (x^{3})}$

Step 7.3

Move the term $7$ outside of the limit because it is constant with respect to $x$ .

$\frac{- 7 lim_{x \to 0} \sin^{2} (x) \cos (x) + lim_{x \to 0} 2 \cos^{3} (x)}{lim_{x \to 0} - 9 x^{6} \cos (x^{3}) - 18 x^{3} \sin (x^{3}) + 2 \cos (x^{3})}$

Step 7.4

Split the limit using the Product of Limits Rule on the limit as $x$ approaches $0$ .

$\frac{- 7 lim_{x \to 0} \sin^{2} (x) \cdot lim_{x \to 0} \cos (x) + lim_{x \to 0} 2 \cos^{3} (x)}{lim_{x \to 0} - 9 x^{6} \cos (x^{3}) - 18 x^{3} \sin (x^{3}) + 2 \cos (x^{3})}$

Step 7.5

Move the exponent $2$ from $\sin^{2} (x)$ outside the limit using the Limits Power Rule.

$\frac{- 7 {(lim_{x \to 0} \sin (x))}^{2} \cdot lim_{x \to 0} \cos (x) + lim_{x \to 0} 2 \cos^{3} (x)}{lim_{x \to 0} - 9 x^{6} \cos (x^{3}) - 18 x^{3} \sin (x^{3}) + 2 \cos (x^{3})}$

Step 7.6

Move the limit inside the trig function because sine is continuous.

$\frac{- 7 \sin^{2} (lim_{x \to 0} x) \cdot lim_{x \to 0} \cos (x) + lim_{x \to 0} 2 \cos^{3} (x)}{lim_{x \to 0} - 9 x^{6} \cos (x^{3}) - 18 x^{3} \sin (x^{3}) + 2 \cos (x^{3})}$

Step 7.7

Move the limit inside the trig function because cosine is continuous.

$\frac{- 7 \sin^{2} (lim_{x \to 0} x) \cdot \cos (lim_{x \to 0} x) + lim_{x \to 0} 2 \cos^{3} (x)}{lim_{x \to 0} - 9 x^{6} \cos (x^{3}) - 18 x^{3} \sin (x^{3}) + 2 \cos (x^{3})}$

Step 7.8

Move the term $2$ outside of the limit because it is constant with respect to $x$ .

$\frac{- 7 \sin^{2} (lim_{x \to 0} x) \cdot \cos (lim_{x \to 0} x) + 2 lim_{x \to 0} \cos^{3} (x)}{lim_{x \to 0} - 9 x^{6} \cos (x^{3}) - 18 x^{3} \sin (x^{3}) + 2 \cos (x^{3})}$

Step 7.9

Move the exponent $3$ from $\cos^{3} (x)$ outside the limit using the Limits Power Rule.

$\frac{- 7 \sin^{2} (lim_{x \to 0} x) \cdot \cos (lim_{x \to 0} x) + 2 {(lim_{x \to 0} \cos (x))}^{3}}{lim_{x \to 0} - 9 x^{6} \cos (x^{3}) - 18 x^{3} \sin (x^{3}) + 2 \cos (x^{3})}$

Step 7.10

Move the limit inside the trig function because cosine is continuous.

$\frac{- 7 \sin^{2} (lim_{x \to 0} x) \cdot \cos (lim_{x \to 0} x) + 2 \cos^{3} (lim_{x \to 0} x)}{lim_{x \to 0} - 9 x^{6} \cos (x^{3}) - 18 x^{3} \sin (x^{3}) + 2 \cos (x^{3})}$

Step 7.11

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $0$ .

$\frac{- 7 \sin^{2} (lim_{x \to 0} x) \cdot \cos (lim_{x \to 0} x) + 2 \cos^{3} (lim_{x \to 0} x)}{- lim_{x \to 0} 9 x^{6} \cos (x^{3}) - lim_{x \to 0} 18 x^{3} \sin (x^{3}) + lim_{x \to 0} 2 \cos (x^{3})}$

Step 7.12

Move the term $9$ outside of the limit because it is constant with respect to $x$ .

$\frac{- 7 \sin^{2} (lim_{x \to 0} x) \cdot \cos (lim_{x \to 0} x) + 2 \cos^{3} (lim_{x \to 0} x)}{- 9 lim_{x \to 0} x^{6} \cos (x^{3}) - lim_{x \to 0} 18 x^{3} \sin (x^{3}) + lim_{x \to 0} 2 \cos (x^{3})}$

Step 7.13

Split the limit using the Product of Limits Rule on the limit as $x$ approaches $0$ .

$\frac{- 7 \sin^{2} (lim_{x \to 0} x) \cdot \cos (lim_{x \to 0} x) + 2 \cos^{3} (lim_{x \to 0} x)}{- 9 lim_{x \to 0} x^{6} \cdot lim_{x \to 0} \cos (x^{3}) - lim_{x \to 0} 18 x^{3} \sin (x^{3}) + lim_{x \to 0} 2 \cos (x^{3})}$

Step 7.14

Move the exponent $6$ from $x^{6}$ outside the limit using the Limits Power Rule.

$\frac{- 7 \sin^{2} (lim_{x \to 0} x) \cdot \cos (lim_{x \to 0} x) + 2 \cos^{3} (lim_{x \to 0} x)}{- 9 {(lim_{x \to 0} x)}^{6} \cdot lim_{x \to 0} \cos (x^{3}) - lim_{x \to 0} 18 x^{3} \sin (x^{3}) + lim_{x \to 0} 2 \cos (x^{3})}$

Step 7.15

Move the limit inside the trig function because cosine is continuous.

$\frac{- 7 \sin^{2} (lim_{x \to 0} x) \cdot \cos (lim_{x \to 0} x) + 2 \cos^{3} (lim_{x \to 0} x)}{- 9 {(lim_{x \to 0} x)}^{6} \cdot \cos (lim_{x \to 0} x^{3}) - lim_{x \to 0} 18 x^{3} \sin (x^{3}) + lim_{x \to 0} 2 \cos (x^{3})}$

Step 7.16

Move the exponent $3$ from $x^{3}$ outside the limit using the Limits Power Rule.

$\frac{- 7 \sin^{2} (lim_{x \to 0} x) \cdot \cos (lim_{x \to 0} x) + 2 \cos^{3} (lim_{x \to 0} x)}{- 9 {(lim_{x \to 0} x)}^{6} \cdot \cos ({(lim_{x \to 0} x)}^{3}) - lim_{x \to 0} 18 x^{3} \sin (x^{3}) + lim_{x \to 0} 2 \cos (x^{3})}$

Step 7.17

Move the term $18$ outside of the limit because it is constant with respect to $x$ .

$\frac{- 7 \sin^{2} (lim_{x \to 0} x) \cdot \cos (lim_{x \to 0} x) + 2 \cos^{3} (lim_{x \to 0} x)}{- 9 {(lim_{x \to 0} x)}^{6} \cdot \cos ({(lim_{x \to 0} x)}^{3}) - 18 lim_{x \to 0} x^{3} \sin (x^{3}) + lim_{x \to 0} 2 \cos (x^{3})}$

Step 7.18

Split the limit using the Product of Limits Rule on the limit as $x$ approaches $0$ .

Step 7.19

Move the exponent $3$ from $x^{3}$ outside the limit using the Limits Power Rule.

$\frac{- 7 \sin^{2} (lim_{x \to 0} x) \cdot \cos (lim_{x \to 0} x) + 2 \cos^{3} (lim_{x \to 0} x)}{- 9 {(lim_{x \to 0} x)}^{6} \cdot \cos ({(lim_{x \to 0} x)}^{3}) - 18 {(lim_{x \to 0} x)}^{3} \cdot lim_{x \to 0} \sin (x^{3}) + lim_{x \to 0} 2 \cos (x^{3})}$

Step 7.20

Move the limit inside the trig function because sine is continuous.

$\frac{- 7 \sin^{2} (lim_{x \to 0} x) \cdot \cos (lim_{x \to 0} x) + 2 \cos^{3} (lim_{x \to 0} x)}{- 9 {(lim_{x \to 0} x)}^{6} \cdot \cos ({(lim_{x \to 0} x)}^{3}) - 18 {(lim_{x \to 0} x)}^{3} \cdot \sin (lim_{x \to 0} x^{3}) + lim_{x \to 0} 2 \cos (x^{3})}$

Step 7.21

Move the exponent $3$ from $x^{3}$ outside the limit using the Limits Power Rule.

$\frac{- 7 \sin^{2} (lim_{x \to 0} x) \cdot \cos (lim_{x \to 0} x) + 2 \cos^{3} (lim_{x \to 0} x)}{- 9 {(lim_{x \to 0} x)}^{6} \cdot \cos ({(lim_{x \to 0} x)}^{3}) - 18 {(lim_{x \to 0} x)}^{3} \cdot \sin ({(lim_{x \to 0} x)}^{3}) + lim_{x \to 0} 2 \cos (x^{3})}$

Step 7.22

Move the term $2$ outside of the limit because it is constant with respect to $x$ .

$\frac{- 7 \sin^{2} (lim_{x \to 0} x) \cdot \cos (lim_{x \to 0} x) + 2 \cos^{3} (lim_{x \to 0} x)}{- 9 {(lim_{x \to 0} x)}^{6} \cdot \cos ({(lim_{x \to 0} x)}^{3}) - 18 {(lim_{x \to 0} x)}^{3} \cdot \sin ({(lim_{x \to 0} x)}^{3}) + 2 lim_{x \to 0} \cos (x^{3})}$

Step 7.23

Move the limit inside the trig function because cosine is continuous.

$\frac{- 7 \sin^{2} (lim_{x \to 0} x) \cdot \cos (lim_{x \to 0} x) + 2 \cos^{3} (lim_{x \to 0} x)}{- 9 {(lim_{x \to 0} x)}^{6} \cdot \cos ({(lim_{x \to 0} x)}^{3}) - 18 {(lim_{x \to 0} x)}^{3} \cdot \sin ({(lim_{x \to 0} x)}^{3}) + 2 \cos (lim_{x \to 0} x^{3})}$

Step 7.24

Move the exponent $3$ from $x^{3}$ outside the limit using the Limits Power Rule.

$\frac{- 7 \sin^{2} (lim_{x \to 0} x) \cdot \cos (lim_{x \to 0} x) + 2 \cos^{3} (lim_{x \to 0} x)}{- 9 {(lim_{x \to 0} x)}^{6} \cdot \cos ({(lim_{x \to 0} x)}^{3}) - 18 {(lim_{x \to 0} x)}^{3} \cdot \sin ({(lim_{x \to 0} x)}^{3}) + 2 \cos ({(lim_{x \to 0} x)}^{3})}$

Step 8

Evaluate the limits by plugging in $0$ for all occurrences of $x$ .

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Step 8.1

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{- 7 \sin^{2} (0) \cdot \cos (lim_{x \to 0} x) + 2 \cos^{3} (lim_{x \to 0} x)}{- 9 {(lim_{x \to 0} x)}^{6} \cdot \cos ({(lim_{x \to 0} x)}^{3}) - 18 {(lim_{x \to 0} x)}^{3} \cdot \sin ({(lim_{x \to 0} x)}^{3}) + 2 \cos ({(lim_{x \to 0} x)}^{3})}$

Step 8.2

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{- 7 \sin^{2} (0) \cdot \cos (0) + 2 \cos^{3} (lim_{x \to 0} x)}{- 9 {(lim_{x \to 0} x)}^{6} \cdot \cos ({(lim_{x \to 0} x)}^{3}) - 18 {(lim_{x \to 0} x)}^{3} \cdot \sin ({(lim_{x \to 0} x)}^{3}) + 2 \cos ({(lim_{x \to 0} x)}^{3})}$

Step 8.3

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{- 7 \sin^{2} (0) \cdot \cos (0) + 2 \cos^{3} (0)}{- 9 {(lim_{x \to 0} x)}^{6} \cdot \cos ({(lim_{x \to 0} x)}^{3}) - 18 {(lim_{x \to 0} x)}^{3} \cdot \sin ({(lim_{x \to 0} x)}^{3}) + 2 \cos ({(lim_{x \to 0} x)}^{3})}$

Step 8.4

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{- 7 \sin^{2} (0) \cdot \cos (0) + 2 \cos^{3} (0)}{- 9 \cdot 0^{6} \cdot \cos ({(lim_{x \to 0} x)}^{3}) - 18 {(lim_{x \to 0} x)}^{3} \cdot \sin ({(lim_{x \to 0} x)}^{3}) + 2 \cos ({(lim_{x \to 0} x)}^{3})}$

Step 8.5

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{- 7 \sin^{2} (0) \cdot \cos (0) + 2 \cos^{3} (0)}{- 9 \cdot 0^{6} \cdot \cos (0^{3}) - 18 {(lim_{x \to 0} x)}^{3} \cdot \sin ({(lim_{x \to 0} x)}^{3}) + 2 \cos ({(lim_{x \to 0} x)}^{3})}$

Step 8.6

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{- 7 \sin^{2} (0) \cdot \cos (0) + 2 \cos^{3} (0)}{- 9 \cdot 0^{6} \cdot \cos (0^{3}) - 18 \cdot 0^{3} \cdot \sin ({(lim_{x \to 0} x)}^{3}) + 2 \cos ({(lim_{x \to 0} x)}^{3})}$

Step 8.7

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{- 7 \sin^{2} (0) \cdot \cos (0) + 2 \cos^{3} (0)}{- 9 \cdot 0^{6} \cdot \cos (0^{3}) - 18 \cdot 0^{3} \cdot \sin (0^{3}) + 2 \cos ({(lim_{x \to 0} x)}^{3})}$

Step 8.8

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$\frac{- 7 \sin^{2} (0) \cdot \cos (0) + 2 \cos^{3} (0)}{- 9 \cdot 0^{6} \cdot \cos (0^{3}) - 18 \cdot 0^{3} \cdot \sin (0^{3}) + 2 \cos (0^{3})}$

Step 9

Simplify the answer.

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Step 9.1

Simplify the numerator.

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Step 9.1.1

The exact value of $\sin (0)$ is $0$ .

$\frac{- 7 \cdot 0^{2} \cdot \cos (0) + 2 \cos^{3} (0)}{- 9 \cdot 0^{6} \cdot \cos (0^{3}) - 18 \cdot 0^{3} \cdot \sin (0^{3}) + 2 \cos (0^{3})}$

Step 9.1.2

Raising $0$ to any positive power yields $0$ .

$\frac{- 7 \cdot 0 \cdot \cos (0) + 2 \cos^{3} (0)}{- 9 \cdot 0^{6} \cdot \cos (0^{3}) - 18 \cdot 0^{3} \cdot \sin (0^{3}) + 2 \cos (0^{3})}$

Step 9.1.3

Multiply $- 7$ by $0$ .

$\frac{0 \cdot \cos (0) + 2 \cos^{3} (0)}{- 9 \cdot 0^{6} \cdot \cos (0^{3}) - 18 \cdot 0^{3} \cdot \sin (0^{3}) + 2 \cos (0^{3})}$

Step 9.1.4

The exact value of $\cos (0)$ is $1$ .

$\frac{0 \cdot 1 + 2 \cos^{3} (0)}{- 9 \cdot 0^{6} \cdot \cos (0^{3}) - 18 \cdot 0^{3} \cdot \sin (0^{3}) + 2 \cos (0^{3})}$

Step 9.1.5

Multiply $0$ by $1$ .

$\frac{0 + 2 \cos^{3} (0)}{- 9 \cdot 0^{6} \cdot \cos (0^{3}) - 18 \cdot 0^{3} \cdot \sin (0^{3}) + 2 \cos (0^{3})}$

Step 9.1.6

The exact value of $\cos (0)$ is $1$ .

$\frac{0 + 2 \cdot 1^{3}}{- 9 \cdot 0^{6} \cdot \cos (0^{3}) - 18 \cdot 0^{3} \cdot \sin (0^{3}) + 2 \cos (0^{3})}$

Step 9.1.7

One to any power is one.

$\frac{0 + 2 \cdot 1}{- 9 \cdot 0^{6} \cdot \cos (0^{3}) - 18 \cdot 0^{3} \cdot \sin (0^{3}) + 2 \cos (0^{3})}$

Step 9.1.8

Multiply $2$ by $1$ .

$\frac{0 + 2}{- 9 \cdot 0^{6} \cdot \cos (0^{3}) - 18 \cdot 0^{3} \cdot \sin (0^{3}) + 2 \cos (0^{3})}$

Step 9.1.9

Add $0$ and $2$ .

$\frac{2}{- 9 \cdot 0^{6} \cdot \cos (0^{3}) - 18 \cdot 0^{3} \cdot \sin (0^{3}) + 2 \cos (0^{3})}$

Step 9.2

Simplify the denominator.

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Step 9.2.1

Raising $0$ to any positive power yields $0$ .

$\frac{2}{- 9 \cdot 0 \cdot \cos (0^{3}) - 18 \cdot 0^{3} \cdot \sin (0^{3}) + 2 \cos (0^{3})}$

Step 9.2.2

Multiply $- 9$ by $0$ .

$\frac{2}{0 \cdot \cos (0^{3}) - 18 \cdot 0^{3} \cdot \sin (0^{3}) + 2 \cos (0^{3})}$

Step 9.2.3

Raising $0$ to any positive power yields $0$ .

$\frac{2}{0 \cdot \cos (0) - 18 \cdot 0^{3} \cdot \sin (0^{3}) + 2 \cos (0^{3})}$

Step 9.2.4

The exact value of $\cos (0)$ is $1$ .

$\frac{2}{0 \cdot 1 - 18 \cdot 0^{3} \cdot \sin (0^{3}) + 2 \cos (0^{3})}$

Step 9.2.5

Multiply $0$ by $1$ .

$\frac{2}{0 - 18 \cdot 0^{3} \cdot \sin (0^{3}) + 2 \cos (0^{3})}$

Step 9.2.6

Raising $0$ to any positive power yields $0$ .

$\frac{2}{0 - 18 \cdot 0 \cdot \sin (0^{3}) + 2 \cos (0^{3})}$

Step 9.2.7

Multiply $- 18$ by $0$ .

$\frac{2}{0 + 0 \cdot \sin (0^{3}) + 2 \cos (0^{3})}$

Step 9.2.8

Raising $0$ to any positive power yields $0$ .

$\frac{2}{0 + 0 \cdot \sin (0) + 2 \cos (0^{3})}$

Step 9.2.9

The exact value of $\sin (0)$ is $0$ .

$\frac{2}{0 + 0 \cdot 0 + 2 \cos (0^{3})}$

Step 9.2.10

Multiply $0$ by $0$ .

$\frac{2}{0 + 0 + 2 \cos (0^{3})}$

Step 9.2.11

Raising $0$ to any positive power yields $0$ .

$\frac{2}{0 + 0 + 2 \cos (0)}$

Step 9.2.12

The exact value of $\cos (0)$ is $1$ .

$\frac{2}{0 + 0 + 2 \cdot 1}$

Step 9.2.13

Multiply $2$ by $1$ .

$\frac{2}{0 + 0 + 2}$

Step 9.2.14

Add $0$ and $0$ .

$\frac{2}{0 + 2}$

Step 9.2.15

Add $0$ and $2$ .

$\frac{2}{2}$

Step 9.3

Cancel the common factor of $2$ .

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Step 9.3.1

Cancel the common factor.

$\frac{2}{2}$

Step 9.3.2

Rewrite the expression.

$1$