Calculus Examples

$P (t) = \frac{1000 e^{0.12 t}}{19 + e^{0.12 t}}$

Step 1

Find the first derivative.

Tap for more steps...

Step 1.1

Since $1000$ is constant with respect to $t$ , the derivative of $\frac{1000 e^{0.12 t}}{19 + e^{0.12 t}}$ with respect to $t$ is $1000 \frac{d}{d t} [\frac{e^{0.12 t}}{19 + e^{0.12 t}}]$ .

$1000 \frac{d}{d t} [\frac{e^{0.12 t}}{19 + e^{0.12 t}}]$

Step 1.2

Differentiate using the Quotient Rule which states that $\frac{d}{d t} [\frac{f (t)}{g (t)}]$ is $\frac{g (t) \frac{d}{d t} [f (t)] - f (t) \frac{d}{d t} [g (t)]}{{g (t)}^{2}}$ where $f (t) = e^{0.12 t}$ and $g (t) = 19 + e^{0.12 t}$ .

$1000 \frac{(19 + e^{0.12 t}) \frac{d}{d t} [e^{0.12 t}] - e^{0.12 t} \frac{d}{d t} [19 + e^{0.12 t}]}{{(19 + e^{0.12 t})}^{2}}$

Step 1.3

Differentiate using the chain rule, which states that $\frac{d}{d t} [f (g (t))]$ is $f' (g (t)) g' (t)$ where $f (t) = e^{t}$ and $g (t) = 0.12 t$ .

Tap for more steps...

Step 1.3.1

To apply the Chain Rule, set $u_{1}$ as $0.12 t$ .

$1000 \frac{(19 + e^{0.12 t}) (\frac{d}{d u_{1}} [e^{u_{1}}] \frac{d}{d t} [0.12 t]) - e^{0.12 t} \frac{d}{d t} [19 + e^{0.12 t}]}{{(19 + e^{0.12 t})}^{2}}$

Step 1.3.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u_{1}} [a^{u_{1}}]$ is $a^{u_{1}} \ln (a)$ where $a$ = $e$ .

$1000 \frac{(19 + e^{0.12 t}) (e^{u_{1}} \frac{d}{d t} [0.12 t]) - e^{0.12 t} \frac{d}{d t} [19 + e^{0.12 t}]}{{(19 + e^{0.12 t})}^{2}}$

Step 1.3.3

Replace all occurrences of $u_{1}$ with $0.12 t$ .

$1000 \frac{(19 + e^{0.12 t}) (e^{0.12 t} \frac{d}{d t} [0.12 t]) - e^{0.12 t} \frac{d}{d t} [19 + e^{0.12 t}]}{{(19 + e^{0.12 t})}^{2}}$

Step 1.4

Differentiate.

Tap for more steps...

Step 1.4.1

Since $0.12$ is constant with respect to $t$ , the derivative of $0.12 t$ with respect to $t$ is $0.12 \frac{d}{d t} [t]$ .

$1000 \frac{(19 + e^{0.12 t}) e^{0.12 t} (0.12 \frac{d}{d t} [t]) - e^{0.12 t} \frac{d}{d t} [19 + e^{0.12 t}]}{{(19 + e^{0.12 t})}^{2}}$

Step 1.4.2

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 1$ .

$1000 \frac{(19 + e^{0.12 t}) e^{0.12 t} (0.12 \cdot 1) - e^{0.12 t} \frac{d}{d t} [19 + e^{0.12 t}]}{{(19 + e^{0.12 t})}^{2}}$

Step 1.4.3

Simplify the expression.

Tap for more steps...

Step 1.4.3.1

Multiply $0.12$ by $1$ .

$1000 \frac{(19 + e^{0.12 t}) e^{0.12 t} \cdot 0.12 - e^{0.12 t} \frac{d}{d t} [19 + e^{0.12 t}]}{{(19 + e^{0.12 t})}^{2}}$

Step 1.4.3.2

Move $0.12$ to the left of $(19 + e^{0.12 t}) e^{0.12 t}$ .

$1000 \frac{0.12 \cdot ((19 + e^{0.12 t}) e^{0.12 t}) - e^{0.12 t} \frac{d}{d t} [19 + e^{0.12 t}]}{{(19 + e^{0.12 t})}^{2}}$

Step 1.4.4

By the Sum Rule, the derivative of $19 + e^{0.12 t}$ with respect to $t$ is $\frac{d}{d t} [19] + \frac{d}{d t} [e^{0.12 t}]$ .

$1000 \frac{0.12 (19 + e^{0.12 t}) e^{0.12 t} - e^{0.12 t} (\frac{d}{d t} [19] + \frac{d}{d t} [e^{0.12 t}])}{{(19 + e^{0.12 t})}^{2}}$

Step 1.4.5

Since $19$ is constant with respect to $t$ , the derivative of $19$ with respect to $t$ is $0$ .

$1000 \frac{0.12 (19 + e^{0.12 t}) e^{0.12 t} - e^{0.12 t} (0 + \frac{d}{d t} [e^{0.12 t}])}{{(19 + e^{0.12 t})}^{2}}$

Step 1.4.6

Add $0$ and $\frac{d}{d t} [e^{0.12 t}]$ .

$1000 \frac{0.12 (19 + e^{0.12 t}) e^{0.12 t} - e^{0.12 t} \frac{d}{d t} [e^{0.12 t}]}{{(19 + e^{0.12 t})}^{2}}$

Step 1.5

Differentiate using the chain rule, which states that $\frac{d}{d t} [f (g (t))]$ is $f' (g (t)) g' (t)$ where $f (t) = e^{t}$ and $g (t) = 0.12 t$ .

Tap for more steps...

Step 1.5.1

To apply the Chain Rule, set $u_{2}$ as $0.12 t$ .

$1000 \frac{0.12 (19 + e^{0.12 t}) e^{0.12 t} - e^{0.12 t} (\frac{d}{d u_{2}} [e^{u_{2}}] \frac{d}{d t} [0.12 t])}{{(19 + e^{0.12 t})}^{2}}$

Step 1.5.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u_{2}} [a^{u_{2}}]$ is $a^{u_{2}} \ln (a)$ where $a$ = $e$ .

$1000 \frac{0.12 (19 + e^{0.12 t}) e^{0.12 t} - e^{0.12 t} (e^{u_{2}} \frac{d}{d t} [0.12 t])}{{(19 + e^{0.12 t})}^{2}}$

Step 1.5.3

Replace all occurrences of $u_{2}$ with $0.12 t$ .

$1000 \frac{0.12 (19 + e^{0.12 t}) e^{0.12 t} - e^{0.12 t} (e^{0.12 t} \frac{d}{d t} [0.12 t])}{{(19 + e^{0.12 t})}^{2}}$

Step 1.6

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$1000 \frac{0.12 (19 + e^{0.12 t}) e^{0.12 t} - e^{0.12 t + 0.12 t} \frac{d}{d t} [0.12 t]}{{(19 + e^{0.12 t})}^{2}}$

Step 1.7

Add $0.12 t$ and $0.12 t$ .

$1000 \frac{0.12 (19 + e^{0.12 t}) e^{0.12 t} - e^{0.24 t} \frac{d}{d t} [0.12 t]}{{(19 + e^{0.12 t})}^{2}}$

Step 1.8

Since $0.12$ is constant with respect to $t$ , the derivative of $0.12 t$ with respect to $t$ is $0.12 \frac{d}{d t} [t]$ .

$1000 \frac{0.12 (19 + e^{0.12 t}) e^{0.12 t} - e^{0.24 t} (0.12 \frac{d}{d t} [t])}{{(19 + e^{0.12 t})}^{2}}$

Step 1.9

Multiply $0.12$ by $- 1$ .

$1000 \frac{0.12 (19 + e^{0.12 t}) e^{0.12 t} - 0.12 e^{0.24 t} \frac{d}{d t} [t]}{{(19 + e^{0.12 t})}^{2}}$

Step 1.10

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 1$ .

$1000 \frac{0.12 (19 + e^{0.12 t}) e^{0.12 t} - 0.12 e^{0.24 t} \cdot 1}{{(19 + e^{0.12 t})}^{2}}$

Step 1.11

Combine fractions.

Tap for more steps...

Step 1.11.1

Multiply $- 0.12$ by $1$ .

$1000 \frac{0.12 (19 + e^{0.12 t}) e^{0.12 t} - 0.12 e^{0.24 t}}{{(19 + e^{0.12 t})}^{2}}$

Step 1.11.2

Combine $1000$ and $\frac{0.12 (19 + e^{0.12 t}) e^{0.12 t} - 0.12 e^{0.24 t}}{{(19 + e^{0.12 t})}^{2}}$ .

$\frac{1000 (0.12 (19 + e^{0.12 t}) e^{0.12 t} - 0.12 e^{0.24 t})}{{(19 + e^{0.12 t})}^{2}}$

Step 1.12

Simplify.

Tap for more steps...

Step 1.12.1

Apply the distributive property.

$\frac{1000 ((0.12 \cdot 19 + 0.12 e^{0.12 t}) e^{0.12 t} - 0.12 e^{0.24 t})}{{(19 + e^{0.12 t})}^{2}}$

Step 1.12.2

Apply the distributive property.

$\frac{1000 (0.12 \cdot 19 e^{0.12 t} + 0.12 e^{0.12 t} e^{0.12 t} - 0.12 e^{0.24 t})}{{(19 + e^{0.12 t})}^{2}}$

Step 1.12.3

Apply the distributive property.

$\frac{1000 (0.12 \cdot 19 e^{0.12 t}) + 1000 (0.12 e^{0.12 t} e^{0.12 t}) + 1000 (- 0.12 e^{0.24 t})}{{(19 + e^{0.12 t})}^{2}}$

Step 1.12.4

Simplify the numerator.

Tap for more steps...

Step 1.12.4.1

Simplify each term.

Tap for more steps...

Step 1.12.4.1.1

Multiply $0.12$ by $19$ .

$\frac{1000 (2.28 e^{0.12 t}) + 1000 (0.12 e^{0.12 t} e^{0.12 t}) + 1000 (- 0.12 e^{0.24 t})}{{(19 + e^{0.12 t})}^{2}}$

Step 1.12.4.1.2

Multiply $2.28$ by $1000$ .

$\frac{2280 e^{0.12 t} + 1000 (0.12 e^{0.12 t} e^{0.12 t}) + 1000 (- 0.12 e^{0.24 t})}{{(19 + e^{0.12 t})}^{2}}$

Step 1.12.4.1.3

Multiply $e^{0.12 t}$ by $e^{0.12 t}$ by adding the exponents.

Tap for more steps...

Step 1.12.4.1.3.1

Move $e^{0.12 t}$ .

$\frac{2280 e^{0.12 t} + 1000 (0.12 (e^{0.12 t} e^{0.12 t})) + 1000 (- 0.12 e^{0.24 t})}{{(19 + e^{0.12 t})}^{2}}$

Step 1.12.4.1.3.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2280 e^{0.12 t} + 1000 (0.12 e^{0.12 t + 0.12 t}) + 1000 (- 0.12 e^{0.24 t})}{{(19 + e^{0.12 t})}^{2}}$

Step 1.12.4.1.3.3

Add $0.12 t$ and $0.12 t$ .

$\frac{2280 e^{0.12 t} + 1000 (0.12 e^{0.24 t}) + 1000 (- 0.12 e^{0.24 t})}{{(19 + e^{0.12 t})}^{2}}$

Step 1.12.4.1.4

Multiply $0.12$ by $1000$ .

$\frac{2280 e^{0.12 t} + 120 e^{0.24 t} + 1000 (- 0.12 e^{0.24 t})}{{(19 + e^{0.12 t})}^{2}}$

Step 1.12.4.1.5

Multiply $- 0.12$ by $1000$ .

$\frac{2280 e^{0.12 t} + 120 e^{0.24 t} - 120 e^{0.24 t}}{{(19 + e^{0.12 t})}^{2}}$

Step 1.12.4.2

Subtract $120 e^{0.24 t}$ from $120 e^{0.24 t}$ .

$\frac{2280 e^{0.12 t} + 0 e^{0.24 t}}{{(19 + e^{0.12 t})}^{2}}$

Step 1.12.4.3

Multiply $0$ by $e^{0.24 t}$ .

$\frac{2280 e^{0.12 t} + 0}{{(19 + e^{0.12 t})}^{2}}$

Step 1.12.4.4

Add $2280 e^{0.12 t}$ and $0$ .

$f' (t) = \frac{2280 e^{0.12 t}}{{(19 + e^{0.12 t})}^{2}}$

Step 2

Find the second derivative.

Tap for more steps...

Step 2.1

Since $2280$ is constant with respect to $t$ , the derivative of $\frac{2280 e^{0.12 t}}{{(19 + e^{0.12 t})}^{2}}$ with respect to $t$ is $2280 \frac{d}{d t} [\frac{e^{0.12 t}}{{(19 + e^{0.12 t})}^{2}}]$ .

$2280 \frac{d}{d t} [\frac{e^{0.12 t}}{{(19 + e^{0.12 t})}^{2}}]$

Step 2.2

$2280 \frac{{(19 + e^{0.12 t})}^{2} \frac{d}{d t} [e^{0.12 t}] - e^{0.12 t} \frac{d}{d t} [{(19 + e^{0.12 t})}^{2}]}{{({(19 + e^{0.12 t})}^{2})}^{2}}$

Step 2.3

Multiply the exponents in ${({(19 + e^{0.12 t})}^{2})}^{2}$ .

Tap for more steps...

Step 2.3.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$2280 \frac{{(19 + e^{0.12 t})}^{2} \frac{d}{d t} [e^{0.12 t}] - e^{0.12 t} \frac{d}{d t} [{(19 + e^{0.12 t})}^{2}]}{{(19 + e^{0.12 t})}^{2 \cdot 2}}$

Step 2.3.2

Multiply $2$ by $2$ .

$2280 \frac{{(19 + e^{0.12 t})}^{2} \frac{d}{d t} [e^{0.12 t}] - e^{0.12 t} \frac{d}{d t} [{(19 + e^{0.12 t})}^{2}]}{{(19 + e^{0.12 t})}^{4}}$

Step 2.4

Differentiate using the chain rule, which states that $\frac{d}{d t} [f (g (t))]$ is $f' (g (t)) g' (t)$ where $f (t) = e^{t}$ and $g (t) = 0.12 t$ .

Tap for more steps...

Step 2.4.1

To apply the Chain Rule, set $u_{1}$ as $0.12 t$ .

$2280 \frac{{(19 + e^{0.12 t})}^{2} (\frac{d}{d u_{1}} [e^{u_{1}}] \frac{d}{d t} [0.12 t]) - e^{0.12 t} \frac{d}{d t} [{(19 + e^{0.12 t})}^{2}]}{{(19 + e^{0.12 t})}^{4}}$

Step 2.4.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u_{1}} [a^{u_{1}}]$ is $a^{u_{1}} \ln (a)$ where $a$ = $e$ .

$2280 \frac{{(19 + e^{0.12 t})}^{2} (e^{u_{1}} \frac{d}{d t} [0.12 t]) - e^{0.12 t} \frac{d}{d t} [{(19 + e^{0.12 t})}^{2}]}{{(19 + e^{0.12 t})}^{4}}$

Step 2.4.3

Replace all occurrences of $u_{1}$ with $0.12 t$ .

$2280 \frac{{(19 + e^{0.12 t})}^{2} (e^{0.12 t} \frac{d}{d t} [0.12 t]) - e^{0.12 t} \frac{d}{d t} [{(19 + e^{0.12 t})}^{2}]}{{(19 + e^{0.12 t})}^{4}}$

Step 2.5

Differentiate.

Tap for more steps...

Step 2.5.1

Since $0.12$ is constant with respect to $t$ , the derivative of $0.12 t$ with respect to $t$ is $0.12 \frac{d}{d t} [t]$ .

$2280 \frac{{(19 + e^{0.12 t})}^{2} e^{0.12 t} (0.12 \frac{d}{d t} [t]) - e^{0.12 t} \frac{d}{d t} [{(19 + e^{0.12 t})}^{2}]}{{(19 + e^{0.12 t})}^{4}}$

Step 2.5.2

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 1$ .

$2280 \frac{{(19 + e^{0.12 t})}^{2} e^{0.12 t} (0.12 \cdot 1) - e^{0.12 t} \frac{d}{d t} [{(19 + e^{0.12 t})}^{2}]}{{(19 + e^{0.12 t})}^{4}}$

Step 2.5.3

Simplify the expression.

Tap for more steps...

Step 2.5.3.1

Multiply $0.12$ by $1$ .

$2280 \frac{{(19 + e^{0.12 t})}^{2} e^{0.12 t} \cdot 0.12 - e^{0.12 t} \frac{d}{d t} [{(19 + e^{0.12 t})}^{2}]}{{(19 + e^{0.12 t})}^{4}}$

Step 2.5.3.2

Move $0.12$ to the left of ${(19 + e^{0.12 t})}^{2} e^{0.12 t}$ .

$2280 \frac{0.12 \cdot ({(19 + e^{0.12 t})}^{2} e^{0.12 t}) - e^{0.12 t} \frac{d}{d t} [{(19 + e^{0.12 t})}^{2}]}{{(19 + e^{0.12 t})}^{4}}$

Step 2.6

Differentiate using the chain rule, which states that $\frac{d}{d t} [f (g (t))]$ is $f' (g (t)) g' (t)$ where $f (t) = t^{2}$ and $g (t) = 19 + e^{0.12 t}$ .

Tap for more steps...

Step 2.6.1

To apply the Chain Rule, set $u_{2}$ as $19 + e^{0.12 t}$ .

$2280 \frac{0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t} - e^{0.12 t} (\frac{d}{d u_{2}} [{u_{2}}^{2}] \frac{d}{d t} [19 + e^{0.12 t}])}{{(19 + e^{0.12 t})}^{4}}$

Step 2.6.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{2}} [{u_{2}}^{n}]$ is $n {u_{2}}^{n - 1}$ where $n = 2$ .

$2280 \frac{0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t} - e^{0.12 t} (2 u_{2} \frac{d}{d t} [19 + e^{0.12 t}])}{{(19 + e^{0.12 t})}^{4}}$

Step 2.6.3

Replace all occurrences of $u_{2}$ with $19 + e^{0.12 t}$ .

$2280 \frac{0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t} - e^{0.12 t} (2 (19 + e^{0.12 t}) \frac{d}{d t} [19 + e^{0.12 t}])}{{(19 + e^{0.12 t})}^{4}}$

Step 2.7

Differentiate.

Tap for more steps...

Step 2.7.1

Multiply $2$ by $- 1$ .

$2280 \frac{0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t} - 2 e^{0.12 t} ((19 + e^{0.12 t}) \frac{d}{d t} [19 + e^{0.12 t}])}{{(19 + e^{0.12 t})}^{4}}$

Step 2.7.2

By the Sum Rule, the derivative of $19 + e^{0.12 t}$ with respect to $t$ is $\frac{d}{d t} [19] + \frac{d}{d t} [e^{0.12 t}]$ .

$2280 \frac{0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t} - 2 e^{0.12 t} ((19 + e^{0.12 t}) (\frac{d}{d t} [19] + \frac{d}{d t} [e^{0.12 t}]))}{{(19 + e^{0.12 t})}^{4}}$

Step 2.7.3

Since $19$ is constant with respect to $t$ , the derivative of $19$ with respect to $t$ is $0$ .

$2280 \frac{0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t} - 2 e^{0.12 t} ((19 + e^{0.12 t}) (0 + \frac{d}{d t} [e^{0.12 t}]))}{{(19 + e^{0.12 t})}^{4}}$

Step 2.7.4

Add $0$ and $\frac{d}{d t} [e^{0.12 t}]$ .

$2280 \frac{0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t} - 2 e^{0.12 t} ((19 + e^{0.12 t}) \frac{d}{d t} [e^{0.12 t}])}{{(19 + e^{0.12 t})}^{4}}$

Step 2.8

Differentiate using the chain rule, which states that $\frac{d}{d t} [f (g (t))]$ is $f' (g (t)) g' (t)$ where $f (t) = e^{t}$ and $g (t) = 0.12 t$ .

Tap for more steps...

Step 2.8.1

To apply the Chain Rule, set $u_{3}$ as $0.12 t$ .

$2280 \frac{0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t} - 2 e^{0.12 t} ((19 + e^{0.12 t}) (\frac{d}{d u_{3}} [e^{u_{3}}] \frac{d}{d t} [0.12 t]))}{{(19 + e^{0.12 t})}^{4}}$

Step 2.8.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u_{3}} [a^{u_{3}}]$ is $a^{u_{3}} \ln (a)$ where $a$ = $e$ .

$2280 \frac{0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t} - 2 e^{0.12 t} ((19 + e^{0.12 t}) (e^{u_{3}} \frac{d}{d t} [0.12 t]))}{{(19 + e^{0.12 t})}^{4}}$

Step 2.8.3

Replace all occurrences of $u_{3}$ with $0.12 t$ .

$2280 \frac{0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t} - 2 e^{0.12 t} ((19 + e^{0.12 t}) (e^{0.12 t} \frac{d}{d t} [0.12 t]))}{{(19 + e^{0.12 t})}^{4}}$

Step 2.9

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$2280 \frac{0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t} - 2 e^{0.12 t + 0.12 t} ((19 + e^{0.12 t}) \frac{d}{d t} [0.12 t])}{{(19 + e^{0.12 t})}^{4}}$

Step 2.10

Add $0.12 t$ and $0.12 t$ .

$2280 \frac{0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t} - 2 e^{0.24 t} ((19 + e^{0.12 t}) \frac{d}{d t} [0.12 t])}{{(19 + e^{0.12 t})}^{4}}$

Step 2.11

Since $0.12$ is constant with respect to $t$ , the derivative of $0.12 t$ with respect to $t$ is $0.12 \frac{d}{d t} [t]$ .

$2280 \frac{0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t} - 2 e^{0.24 t} ((19 + e^{0.12 t}) (0.12 \frac{d}{d t} [t]))}{{(19 + e^{0.12 t})}^{4}}$

Step 2.12

Simplify the expression.

Tap for more steps...

Step 2.12.1

Move $0.12$ to the left of $19 + e^{0.12 t}$ .

$2280 \frac{0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t} - 2 e^{0.24 t} (0.12 \cdot (19 + e^{0.12 t}) \frac{d}{d t} [t])}{{(19 + e^{0.12 t})}^{4}}$

Step 2.12.2

Multiply $0.12$ by $- 2$ .

$2280 \frac{0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t} - 0.24 e^{0.24 t} ((19 + e^{0.12 t}) \frac{d}{d t} [t])}{{(19 + e^{0.12 t})}^{4}}$

Step 2.13

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 1$ .

$2280 \frac{0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t} - 0.24 e^{0.24 t} ((19 + e^{0.12 t}) \cdot 1)}{{(19 + e^{0.12 t})}^{4}}$

Step 2.14

Combine fractions.

Tap for more steps...

Step 2.14.1

Multiply $19 + e^{0.12 t}$ by $1$ .

$2280 \frac{0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t} - 0.24 e^{0.24 t} (19 + e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.14.2

Combine $2280$ and $\frac{0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t} - 0.24 e^{0.24 t} (19 + e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$ .

$\frac{2280 (0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t} - 0.24 e^{0.24 t} (19 + e^{0.12 t}))}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15

Simplify.

Tap for more steps...

Step 2.15.1

Apply the distributive property.

$\frac{2280 (0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t} - 0.24 e^{0.24 t} \cdot 19 - 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.2

Apply the distributive property.

$\frac{2280 (0.12 {(19 + e^{0.12 t})}^{2} e^{0.12 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3

Simplify the numerator.

Tap for more steps...

Step 2.15.3.1

Simplify each term.

Tap for more steps...

Step 2.15.3.1.1

Rewrite ${(19 + e^{0.12 t})}^{2}$ as $(19 + e^{0.12 t}) (19 + e^{0.12 t})$ .

$\frac{2280 (0.12 ((19 + e^{0.12 t}) (19 + e^{0.12 t})) e^{0.12 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.2

Expand $(19 + e^{0.12 t}) (19 + e^{0.12 t})$ using the FOIL Method.

Tap for more steps...

Step 2.15.3.1.2.1

Apply the distributive property.

$\frac{2280 (0.12 (19 (19 + e^{0.12 t}) + e^{0.12 t} (19 + e^{0.12 t})) e^{0.12 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.2.2

Apply the distributive property.

$\frac{2280 (0.12 (19 \cdot 19 + 19 e^{0.12 t} + e^{0.12 t} (19 + e^{0.12 t})) e^{0.12 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.2.3

Apply the distributive property.

$\frac{2280 (0.12 (19 \cdot 19 + 19 e^{0.12 t} + e^{0.12 t} \cdot 19 + e^{0.12 t} e^{0.12 t}) e^{0.12 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.3

Simplify and combine like terms.

Tap for more steps...

Step 2.15.3.1.3.1

Simplify each term.

Tap for more steps...

Step 2.15.3.1.3.1.1

Multiply $19$ by $19$ .

$\frac{2280 (0.12 (361 + 19 e^{0.12 t} + e^{0.12 t} \cdot 19 + e^{0.12 t} e^{0.12 t}) e^{0.12 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.3.1.2

Move $19$ to the left of $e^{0.12 t}$ .

$\frac{2280 (0.12 (361 + 19 e^{0.12 t} + 19 \cdot e^{0.12 t} + e^{0.12 t} e^{0.12 t}) e^{0.12 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.3.1.3

Multiply $e^{0.12 t}$ by $e^{0.12 t}$ by adding the exponents.

Tap for more steps...

Step 2.15.3.1.3.1.3.1

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2280 (0.12 (361 + 19 e^{0.12 t} + 19 e^{0.12 t} + e^{0.12 t + 0.12 t}) e^{0.12 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.3.1.3.2

Add $0.12 t$ and $0.12 t$ .

$\frac{2280 (0.12 (361 + 19 e^{0.12 t} + 19 e^{0.12 t} + e^{0.24 t}) e^{0.12 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.3.2

Add $19 e^{0.12 t}$ and $19 e^{0.12 t}$ .

$\frac{2280 (0.12 (361 + 38 e^{0.12 t} + e^{0.24 t}) e^{0.12 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.4

Apply the distributive property.

$\frac{2280 ((0.12 \cdot 361 + 0.12 (38 e^{0.12 t}) + 0.12 e^{0.24 t}) e^{0.12 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.5

Simplify.

Tap for more steps...

Step 2.15.3.1.5.1

Multiply $0.12$ by $361$ .

$\frac{2280 ((43.32 + 0.12 (38 e^{0.12 t}) + 0.12 e^{0.24 t}) e^{0.12 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.5.2

Multiply $38$ by $0.12$ .

$\frac{2280 ((43.32 + 4.56 e^{0.12 t} + 0.12 e^{0.24 t}) e^{0.12 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.6

Apply the distributive property.

$\frac{2280 (43.32 e^{0.12 t} + 4.56 e^{0.12 t} e^{0.12 t} + 0.12 e^{0.24 t} e^{0.12 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.7

Simplify.

Tap for more steps...

Step 2.15.3.1.7.1

Multiply $e^{0.12 t}$ by $e^{0.12 t}$ by adding the exponents.

Tap for more steps...

Step 2.15.3.1.7.1.1

Move $e^{0.12 t}$ .

$\frac{2280 (43.32 e^{0.12 t} + 4.56 (e^{0.12 t} e^{0.12 t}) + 0.12 e^{0.24 t} e^{0.12 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.7.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2280 (43.32 e^{0.12 t} + 4.56 e^{0.12 t + 0.12 t} + 0.12 e^{0.24 t} e^{0.12 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.7.1.3

Add $0.12 t$ and $0.12 t$ .

$\frac{2280 (43.32 e^{0.12 t} + 4.56 e^{0.24 t} + 0.12 e^{0.24 t} e^{0.12 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.7.2

Multiply $e^{0.24 t}$ by $e^{0.12 t}$ by adding the exponents.

Tap for more steps...

Step 2.15.3.1.7.2.1

Move $e^{0.12 t}$ .

$\frac{2280 (43.32 e^{0.12 t} + 4.56 e^{0.24 t} + 0.12 (e^{0.12 t} e^{0.24 t})) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.7.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2280 (43.32 e^{0.12 t} + 4.56 e^{0.24 t} + 0.12 e^{0.12 t + 0.24 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.7.2.3

Add $0.12 t$ and $0.24 t$ .

$\frac{2280 (43.32 e^{0.12 t} + 4.56 e^{0.24 t} + 0.12 e^{0.36 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.8

Apply the distributive property.

$\frac{2280 (43.32 e^{0.12 t}) + 2280 (4.56 e^{0.24 t}) + 2280 (0.12 e^{0.36 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.9

Simplify.

Tap for more steps...

Step 2.15.3.1.9.1

Multiply $43.32$ by $2280$ .

$\frac{98769.6 e^{0.12 t} + 2280 (4.56 e^{0.24 t}) + 2280 (0.12 e^{0.36 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.9.2

Multiply $4.56$ by $2280$ .

$\frac{98769.6 e^{0.12 t} + 10396.8 e^{0.24 t} + 2280 (0.12 e^{0.36 t}) + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.9.3

Multiply $0.12$ by $2280$ .

$\frac{98769.6 e^{0.12 t} + 10396.8 e^{0.24 t} + 273.6 e^{0.36 t} + 2280 (- 0.24 e^{0.24 t} \cdot 19) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.10

Multiply $19$ by $- 0.24$ .

$\frac{98769.6 e^{0.12 t} + 10396.8 e^{0.24 t} + 273.6 e^{0.36 t} + 2280 (- 4.56 e^{0.24 t}) + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.11

Multiply $- 4.56$ by $2280$ .

$\frac{98769.6 e^{0.12 t} + 10396.8 e^{0.24 t} + 273.6 e^{0.36 t} - 10396.8 e^{0.24 t} + 2280 (- 0.24 e^{0.24 t} e^{0.12 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.12

Multiply $e^{0.24 t}$ by $e^{0.12 t}$ by adding the exponents.

Tap for more steps...

Step 2.15.3.1.12.1

Move $e^{0.12 t}$ .

$\frac{98769.6 e^{0.12 t} + 10396.8 e^{0.24 t} + 273.6 e^{0.36 t} - 10396.8 e^{0.24 t} + 2280 (- 0.24 (e^{0.12 t} e^{0.24 t}))}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.12.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{98769.6 e^{0.12 t} + 10396.8 e^{0.24 t} + 273.6 e^{0.36 t} - 10396.8 e^{0.24 t} + 2280 (- 0.24 e^{0.12 t + 0.24 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.12.3

Add $0.12 t$ and $0.24 t$ .

$\frac{98769.6 e^{0.12 t} + 10396.8 e^{0.24 t} + 273.6 e^{0.36 t} - 10396.8 e^{0.24 t} + 2280 (- 0.24 e^{0.36 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.1.13

Multiply $- 0.24$ by $2280$ .

$\frac{98769.6 e^{0.12 t} + 10396.8 e^{0.24 t} + 273.6 e^{0.36 t} - 10396.8 e^{0.24 t} - 547.2 e^{0.36 t}}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.2

Subtract $10396.8 e^{0.24 t}$ from $10396.8 e^{0.24 t}$ .

$\frac{98769.6 e^{0.12 t} + 273.6 e^{0.36 t} + 0 e^{0.24 t} - 547.2 e^{0.36 t}}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.3

Multiply $0$ by $e^{0.24 t}$ .

$\frac{98769.6 e^{0.12 t} + 273.6 e^{0.36 t} + 0 - 547.2 e^{0.36 t}}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.4

Add $98769.6 e^{0.12 t} + 273.6 e^{0.36 t}$ and $0$ .

$\frac{98769.6 e^{0.12 t} + 273.6 e^{0.36 t} - 547.2 e^{0.36 t}}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.3.5

Subtract $547.2 e^{0.36 t}$ from $273.6 e^{0.36 t}$ .

$\frac{98769.6 e^{0.12 t} - 273.6 e^{0.36 t}}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.4

Factor $273.6$ out of $98769.6 e^{0.12 t} - 273.6 e^{0.36 t}$ .

Tap for more steps...

Step 2.15.4.1

Factor $273.6$ out of $98769.6 e^{0.12 t}$ .

$\frac{273.6 (361 e^{0.12 t}) - 273.6 e^{0.36 t}}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.4.2

Factor $273.6$ out of $- 273.6 e^{0.36 t}$ .

$\frac{273.6 (361 e^{0.12 t}) + 273.6 (- e^{0.36 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 2.15.4.3

Factor $273.6$ out of $273.6 (361 e^{0.12 t}) + 273.6 (- e^{0.36 t})$ .

$f'' (t) = \frac{273.6 (361 e^{0.12 t} - e^{0.36 t})}{{(19 + e^{0.12 t})}^{4}}$

Step 3

The second derivative of $P (t)$ with respect to $t$ is $\frac{273.6 (361 e^{0.12 t} - e^{0.36 t})}{{(19 + e^{0.12 t})}^{4}}$ .

$\frac{273.6 (361 e^{0.12 t} - e^{0.36 t})}{{(19 + e^{0.12 t})}^{4}}$