Calculus Examples

$lim_{x \to \infty} \frac{\cos^{2} (2 x)}{x - 2 x}$

Step 1

Since $\frac{1}{x - 2 x} \leq \frac{\cos^{2} (2 x)}{x - 2 x} \leq \frac{0}{x - 2 x}$ and $lim_{x \to \infty} \frac{1}{x - 2 x} = lim_{x \to \infty} \frac{0}{x - 2 x} = 0$ , apply the squeeze theorem.

$0$