Calculus Examples

$z = \frac{A}{y^{13}} + B e^{y}$

Step 1

This derivative could not be completed using the chain rule. Mathway will use another method.

Step 2

By the Sum Rule, the derivative of $\frac{A}{y^{13}} + B e^{y}$ with respect to $z$ is $\frac{d}{d z} [\frac{A}{y^{13}}] + \frac{d}{d z} [B e^{y}]$ .

$\frac{d}{d z} [\frac{A}{y^{13}}] + \frac{d}{d z} [B e^{y}]$

Step 3

Since $\frac{A}{y^{13}}$ is constant with respect to $z$ , the derivative of $\frac{A}{y^{13}}$ with respect to $z$ is $0$ .

$0 + \frac{d}{d z} [B e^{y}]$

Step 4

Since $B e^{y}$ is constant with respect to $z$ , the derivative of $B e^{y}$ with respect to $z$ is $0$ .

$0 + 0$

Step 5

Add $0$ and $0$ .

$0$