Calculus Examples

$p = \frac{7 + \sec (q)}{7 - \sec (q)}$

Step 1

This derivative could not be completed using the chain rule. Mathway will use another method.

Step 2

Differentiate using the Quotient Rule which states that $\frac{d}{d q} [\frac{f (q)}{g (q)}]$ is $\frac{g (q) \frac{d}{d q} [f (q)] - f (q) \frac{d}{d q} [g (q)]}{{g (q)}^{2}}$ where $f (q) = 7 + \sec (q)$ and $g (q) = 7 - \sec (q)$ .

$\frac{(7 - \sec (q)) \frac{d}{d q} [7 + \sec (q)] - (7 + \sec (q)) \frac{d}{d q} [7 - \sec (q)]}{{(7 - \sec (q))}^{2}}$

Step 3

Differentiate.

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Step 3.1

By the Sum Rule, the derivative of $7 + \sec (q)$ with respect to $q$ is $\frac{d}{d q} [7] + \frac{d}{d q} [\sec (q)]$ .

$\frac{(7 - \sec (q)) (\frac{d}{d q} [7] + \frac{d}{d q} [\sec (q)]) - (7 + \sec (q)) \frac{d}{d q} [7 - \sec (q)]}{{(7 - \sec (q))}^{2}}$

Step 3.2

Since $7$ is constant with respect to $q$ , the derivative of $7$ with respect to $q$ is $0$ .

$\frac{(7 - \sec (q)) (0 + \frac{d}{d q} [\sec (q)]) - (7 + \sec (q)) \frac{d}{d q} [7 - \sec (q)]}{{(7 - \sec (q))}^{2}}$

Step 3.3

Add $0$ and $\frac{d}{d q} [\sec (q)]$ .

$\frac{(7 - \sec (q)) \frac{d}{d q} [\sec (q)] - (7 + \sec (q)) \frac{d}{d q} [7 - \sec (q)]}{{(7 - \sec (q))}^{2}}$

Step 4

The derivative of $\sec (q)$ with respect to $q$ is $\sec (q) \tan (q)$ .

$\frac{(7 - \sec (q)) (\sec (q) \tan (q)) - (7 + \sec (q)) \frac{d}{d q} [7 - \sec (q)]}{{(7 - \sec (q))}^{2}}$

Step 5

Differentiate.

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Step 5.1

By the Sum Rule, the derivative of $7 - \sec (q)$ with respect to $q$ is $\frac{d}{d q} [7] + \frac{d}{d q} [- \sec (q)]$ .

$\frac{(7 - \sec (q)) \sec (q) \tan (q) - (7 + \sec (q)) (\frac{d}{d q} [7] + \frac{d}{d q} [- \sec (q)])}{{(7 - \sec (q))}^{2}}$

Step 5.2

Since $7$ is constant with respect to $q$ , the derivative of $7$ with respect to $q$ is $0$ .

$\frac{(7 - \sec (q)) \sec (q) \tan (q) - (7 + \sec (q)) (0 + \frac{d}{d q} [- \sec (q)])}{{(7 - \sec (q))}^{2}}$

Step 5.3

Add $0$ and $\frac{d}{d q} [- \sec (q)]$ .

$\frac{(7 - \sec (q)) \sec (q) \tan (q) - (7 + \sec (q)) \frac{d}{d q} [- \sec (q)]}{{(7 - \sec (q))}^{2}}$

Step 5.4

Since $- 1$ is constant with respect to $q$ , the derivative of $- \sec (q)$ with respect to $q$ is $- \frac{d}{d q} [\sec (q)]$ .

$\frac{(7 - \sec (q)) \sec (q) \tan (q) - (7 + \sec (q)) (- \frac{d}{d q} [\sec (q)])}{{(7 - \sec (q))}^{2}}$

Step 5.5

Multiply.

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Step 5.5.1

Multiply $- 1$ by $- 1$ .

$\frac{(7 - \sec (q)) \sec (q) \tan (q) + 1 (7 + \sec (q)) \frac{d}{d q} [\sec (q)]}{{(7 - \sec (q))}^{2}}$

Step 5.5.2

Multiply $7 + \sec (q)$ by $1$ .

$\frac{(7 - \sec (q)) \sec (q) \tan (q) + (7 + \sec (q)) \frac{d}{d q} [\sec (q)]}{{(7 - \sec (q))}^{2}}$

Step 6

The derivative of $\sec (q)$ with respect to $q$ is $\sec (q) \tan (q)$ .

$\frac{(7 - \sec (q)) \sec (q) \tan (q) + (7 + \sec (q)) (\sec (q) \tan (q))}{{(7 - \sec (q))}^{2}}$

Step 7

Simplify.

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Step 7.1

Apply the distributive property.

$\frac{(7 \sec (q) - \sec (q) \sec (q)) \tan (q) + (7 + \sec (q)) \sec (q) \tan (q)}{{(7 - \sec (q))}^{2}}$

Step 7.2

Apply the distributive property.

$\frac{7 \sec (q) \tan (q) - \sec (q) \sec (q) \tan (q) + (7 + \sec (q)) \sec (q) \tan (q)}{{(7 - \sec (q))}^{2}}$

Step 7.3

Apply the distributive property.

$\frac{7 \sec (q) \tan (q) - \sec (q) \sec (q) \tan (q) + (7 \sec (q) + \sec (q) \sec (q)) \tan (q)}{{(7 - \sec (q))}^{2}}$

Step 7.4

Apply the distributive property.

$\frac{7 \sec (q) \tan (q) - \sec (q) \sec (q) \tan (q) + 7 \sec (q) \tan (q) + \sec (q) \sec (q) \tan (q)}{{(7 - \sec (q))}^{2}}$

Step 7.5

Simplify the numerator.

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Step 7.5.1

Combine the opposite terms in $7 \sec (q) \tan (q) - \sec (q) \sec (q) \tan (q) + 7 \sec (q) \tan (q) + \sec (q) \sec (q) \tan (q)$ .

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Step 7.5.1.1

Add $- \sec (q) \sec (q) \tan (q)$ and $\sec (q) \sec (q) \tan (q)$ .

$\frac{7 \sec (q) \tan (q) + 7 \sec (q) \tan (q) + 0}{{(7 - \sec (q))}^{2}}$

Step 7.5.1.2

Add $7 \sec (q) \tan (q) + 7 \sec (q) \tan (q)$ and $0$ .

$\frac{7 \sec (q) \tan (q) + 7 \sec (q) \tan (q)}{{(7 - \sec (q))}^{2}}$

Step 7.5.2

Add $7 \sec (q) \tan (q)$ and $7 \sec (q) \tan (q)$ .

$\frac{14 \sec (q) \tan (q)}{{(7 - \sec (q))}^{2}}$