Calculus Examples

$\frac{x}{x^{2} - x + 25}$

Step 1

Write $\frac{x}{x^{2} - x + 25}$ as a function.

$f (x) = \frac{x}{x^{2} - x + 25}$

Step 2

Find the first derivative of the function.

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Step 2.1

Differentiate using the Quotient Rule which states that $\frac{d}{d x} [\frac{f (x)}{g (x)}]$ is $\frac{g (x) \frac{d}{d x} [f (x)] - f (x) \frac{d}{d x} [g (x)]}{{g (x)}^{2}}$ where $f (x) = x$ and $g (x) = x^{2} - x + 25$ .

$\frac{(x^{2} - x + 25) \frac{d}{d x} [x] - x \frac{d}{d x} [x^{2} - x + 25]}{{(x^{2} - x + 25)}^{2}}$

Step 2.2

Differentiate.

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Step 2.2.1

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{(x^{2} - x + 25) \cdot 1 - x \frac{d}{d x} [x^{2} - x + 25]}{{(x^{2} - x + 25)}^{2}}$

Step 2.2.2

Multiply $x^{2} - x + 25$ by $1$ .

$\frac{x^{2} - x + 25 - x \frac{d}{d x} [x^{2} - x + 25]}{{(x^{2} - x + 25)}^{2}}$

Step 2.2.3

By the Sum Rule, the derivative of $x^{2} - x + 25$ with respect to $x$ is $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [25]$ .

$\frac{x^{2} - x + 25 - x (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [25])}{{(x^{2} - x + 25)}^{2}}$

Step 2.2.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$\frac{x^{2} - x + 25 - x (2 x + \frac{d}{d x} [- x] + \frac{d}{d x} [25])}{{(x^{2} - x + 25)}^{2}}$

Step 2.2.5

Since $- 1$ is constant with respect to $x$ , the derivative of $- x$ with respect to $x$ is $- \frac{d}{d x} [x]$ .

$\frac{x^{2} - x + 25 - x (2 x - \frac{d}{d x} [x] + \frac{d}{d x} [25])}{{(x^{2} - x + 25)}^{2}}$

Step 2.2.6

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{x^{2} - x + 25 - x (2 x - 1 \cdot 1 + \frac{d}{d x} [25])}{{(x^{2} - x + 25)}^{2}}$

Step 2.2.7

Multiply $- 1$ by $1$ .

$\frac{x^{2} - x + 25 - x (2 x - 1 + \frac{d}{d x} [25])}{{(x^{2} - x + 25)}^{2}}$

Step 2.2.8

Since $25$ is constant with respect to $x$ , the derivative of $25$ with respect to $x$ is $0$ .

$\frac{x^{2} - x + 25 - x (2 x - 1 + 0)}{{(x^{2} - x + 25)}^{2}}$

Step 2.2.9

Add $2 x - 1$ and $0$ .

$\frac{x^{2} - x + 25 - x (2 x - 1)}{{(x^{2} - x + 25)}^{2}}$

Step 2.3

Simplify.

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Step 2.3.1

Apply the distributive property.

$\frac{x^{2} - x + 25 - x (2 x) - x \cdot - 1}{{(x^{2} - x + 25)}^{2}}$

Step 2.3.2

Simplify the numerator.

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Step 2.3.2.1

Simplify each term.

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Step 2.3.2.1.1

Rewrite using the commutative property of multiplication.

$\frac{x^{2} - x + 25 - 1 \cdot 2 x \cdot x - x \cdot - 1}{{(x^{2} - x + 25)}^{2}}$

Step 2.3.2.1.2

Multiply $x$ by $x$ by adding the exponents.

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Step 2.3.2.1.2.1

Move $x$ .

$\frac{x^{2} - x + 25 - 1 \cdot 2 (x \cdot x) - x \cdot - 1}{{(x^{2} - x + 25)}^{2}}$

Step 2.3.2.1.2.2

Multiply $x$ by $x$ .

$\frac{x^{2} - x + 25 - 1 \cdot 2 x^{2} - x \cdot - 1}{{(x^{2} - x + 25)}^{2}}$

Step 2.3.2.1.3

Multiply $- 1$ by $2$ .

$\frac{x^{2} - x + 25 - 2 x^{2} - x \cdot - 1}{{(x^{2} - x + 25)}^{2}}$

Step 2.3.2.1.4

Multiply $- x \cdot - 1$ .

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Step 2.3.2.1.4.1

Multiply $- 1$ by $- 1$ .

$\frac{x^{2} - x + 25 - 2 x^{2} + 1 x}{{(x^{2} - x + 25)}^{2}}$

Step 2.3.2.1.4.2

Multiply $x$ by $1$ .

$\frac{x^{2} - x + 25 - 2 x^{2} + x}{{(x^{2} - x + 25)}^{2}}$

Step 2.3.2.2

Combine the opposite terms in $x^{2} - x + 25 - 2 x^{2} + x$ .

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Step 2.3.2.2.1

Add $- x$ and $x$ .

$\frac{x^{2} + 25 - 2 x^{2} + 0}{{(x^{2} - x + 25)}^{2}}$

Step 2.3.2.2.2

Add $x^{2} + 25 - 2 x^{2}$ and $0$ .

$\frac{x^{2} + 25 - 2 x^{2}}{{(x^{2} - x + 25)}^{2}}$

Step 2.3.2.3

Subtract $2 x^{2}$ from $x^{2}$ .

$\frac{- x^{2} + 25}{{(x^{2} - x + 25)}^{2}}$

Step 2.3.3

Simplify the numerator.

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Step 2.3.3.1

Rewrite $25$ as $5^{2}$ .

$\frac{- x^{2} + 5^{2}}{{(x^{2} - x + 25)}^{2}}$

Step 2.3.3.2

Reorder $- x^{2}$ and $5^{2}$ .

$\frac{5^{2} - x^{2}}{{(x^{2} - x + 25)}^{2}}$

Step 2.3.3.3

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 5$ and $b = x$ .

$\frac{(5 + x) (5 - x)}{{(x^{2} - x + 25)}^{2}}$

Step 3

Find the second derivative of the function.

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Step 3.1

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} \frac{d}{d x} ((5 + x) (5 - x)) - (5 + x) (5 - x) \frac{d}{d x} {(x^{2} - x + 25)}^{2}}{{({(x^{2} - x + 25)}^{2})}^{2}}$

Step 3.2

Multiply the exponents in ${({(x^{2} - x + 25)}^{2})}^{2}$ .

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Step 3.2.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} \frac{d}{d x} ((5 + x) (5 - x)) - (5 + x) (5 - x) \frac{d}{d x} {(x^{2} - x + 25)}^{2}}{{(x^{2} - x + 25)}^{2 \cdot 2}}$

Step 3.2.2

Multiply $2$ by $2$ .

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} \frac{d}{d x} ((5 + x) (5 - x)) - (5 + x) (5 - x) \frac{d}{d x} {(x^{2} - x + 25)}^{2}}{{(x^{2} - x + 25)}^{4}}$

Step 3.3

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = 5 + x$ and $g (x) = 5 - x$ .

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} ((5 + x) \frac{d}{d x} (5 - x) + (5 - x) \frac{d}{d x} (5 + x)) - (5 + x) (5 - x) \frac{d}{d x} {(x^{2} - x + 25)}^{2}}{{(x^{2} - x + 25)}^{4}}$

Step 3.4

Differentiate.

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Step 3.4.1

By the Sum Rule, the derivative of $5 - x$ with respect to $x$ is $\frac{d}{d x} [5] + \frac{d}{d x} [- x]$ .

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} ((5 + x) (\frac{d}{d x} (5) + \frac{d}{d x} (- x)) + (5 - x) \frac{d}{d x} (5 + x)) - (5 + x) (5 - x) \frac{d}{d x} {(x^{2} - x + 25)}^{2}}{{(x^{2} - x + 25)}^{4}}$

Step 3.4.2

Since $5$ is constant with respect to $x$ , the derivative of $5$ with respect to $x$ is $0$ .

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} ((5 + x) (0 + \frac{d}{d x} (- x)) + (5 - x) \frac{d}{d x} (5 + x)) - (5 + x) (5 - x) \frac{d}{d x} {(x^{2} - x + 25)}^{2}}{{(x^{2} - x + 25)}^{4}}$

Step 3.4.3

Add $0$ and $\frac{d}{d x} [- x]$ .

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} ((5 + x) \frac{d}{d x} (- x) + (5 - x) \frac{d}{d x} (5 + x)) - (5 + x) (5 - x) \frac{d}{d x} {(x^{2} - x + 25)}^{2}}{{(x^{2} - x + 25)}^{4}}$

Step 3.4.4

Since $- 1$ is constant with respect to $x$ , the derivative of $- x$ with respect to $x$ is $- \frac{d}{d x} [x]$ .

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} ((5 + x) (- \frac{d}{d x} x) + (5 - x) \frac{d}{d x} (5 + x)) - (5 + x) (5 - x) \frac{d}{d x} {(x^{2} - x + 25)}^{2}}{{(x^{2} - x + 25)}^{4}}$

Step 3.4.5

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} ((5 + x) (- 1 \cdot 1) + (5 - x) \frac{d}{d x} (5 + x)) - (5 + x) (5 - x) \frac{d}{d x} {(x^{2} - x + 25)}^{2}}{{(x^{2} - x + 25)}^{4}}$

Step 3.4.6

Simplify the expression.

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Step 3.4.6.1

Multiply $- 1$ by $1$ .

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} ((5 + x) \cdot - 1 + (5 - x) \frac{d}{d x} (5 + x)) - (5 + x) (5 - x) \frac{d}{d x} {(x^{2} - x + 25)}^{2}}{{(x^{2} - x + 25)}^{4}}$

Step 3.4.6.2

Move $- 1$ to the left of $5 + x$ .

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} (- 1 \cdot (5 + x) + (5 - x) \frac{d}{d x} (5 + x)) - (5 + x) (5 - x) \frac{d}{d x} {(x^{2} - x + 25)}^{2}}{{(x^{2} - x + 25)}^{4}}$

Step 3.4.6.3

Rewrite $- 1 (5 + x)$ as $- (5 + x)$ .

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} (- (5 + x) + (5 - x) \frac{d}{d x} (5 + x)) - (5 + x) (5 - x) \frac{d}{d x} {(x^{2} - x + 25)}^{2}}{{(x^{2} - x + 25)}^{4}}$

Step 3.4.7

By the Sum Rule, the derivative of $5 + x$ with respect to $x$ is $\frac{d}{d x} [5] + \frac{d}{d x} [x]$ .

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} (- (5 + x) + (5 - x) (\frac{d}{d x} (5) + \frac{d}{d x} (x))) - (5 + x) (5 - x) \frac{d}{d x} {(x^{2} - x + 25)}^{2}}{{(x^{2} - x + 25)}^{4}}$

Step 3.4.8

Since $5$ is constant with respect to $x$ , the derivative of $5$ with respect to $x$ is $0$ .

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} (- (5 + x) + (5 - x) (0 + \frac{d}{d x} (x))) - (5 + x) (5 - x) \frac{d}{d x} {(x^{2} - x + 25)}^{2}}{{(x^{2} - x + 25)}^{4}}$

Step 3.4.9

Add $0$ and $\frac{d}{d x} [x]$ .

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} (- (5 + x) + (5 - x) \frac{d}{d x} (x)) - (5 + x) (5 - x) \frac{d}{d x} {(x^{2} - x + 25)}^{2}}{{(x^{2} - x + 25)}^{4}}$

Step 3.4.10

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} (- (5 + x) + (5 - x) \cdot 1) - (5 + x) (5 - x) \frac{d}{d x} {(x^{2} - x + 25)}^{2}}{{(x^{2} - x + 25)}^{4}}$

Step 3.4.11

Multiply $5 - x$ by $1$ .

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} (- (5 + x) + 5 - x) - (5 + x) (5 - x) \frac{d}{d x} {(x^{2} - x + 25)}^{2}}{{(x^{2} - x + 25)}^{4}}$

Step 3.5

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = x^{2} - x + 25$ .

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Step 3.5.1

To apply the Chain Rule, set $u$ as $x^{2} - x + 25$ .

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} (- (5 + x) + 5 - x) - (5 + x) (5 - x) (\frac{d}{d u} (u^{2}) \frac{d}{d x} (x^{2} - x + 25))}{{(x^{2} - x + 25)}^{4}}$

Step 3.5.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 2$ .

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} (- (5 + x) + 5 - x) - (5 + x) (5 - x) (2 u \frac{d}{d x} (x^{2} - x + 25))}{{(x^{2} - x + 25)}^{4}}$

Step 3.5.3

Replace all occurrences of $u$ with $x^{2} - x + 25$ .

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} (- (5 + x) + 5 - x) - (5 + x) (5 - x) (2 (x^{2} - x + 25) \frac{d}{d x} (x^{2} - x + 25))}{{(x^{2} - x + 25)}^{4}}$

Step 3.6

Simplify with factoring out.

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Step 3.6.1

Multiply $2$ by $- 1$ .

$f'' (x) = \frac{{(x^{2} - x + 25)}^{2} (- (5 + x) + 5 - x) - 2 (5 + x) (5 - x) ((x^{2} - x + 25) \frac{d}{d x} (x^{2} - x + 25))}{{(x^{2} - x + 25)}^{4}}$

Step 3.6.2

Factor $x^{2} - x + 25$ out of ${(x^{2} - x + 25)}^{2} (- (5 + x) + 5 - x) - 2 (5 + x) (5 - x) ((x^{2} - x + 25) \frac{d}{d x} [x^{2} - x + 25])$ .

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Step 3.6.2.1

Factor $x^{2} - x + 25$ out of ${(x^{2} - x + 25)}^{2} (- (5 + x) + 5 - x)$ .

$f'' (x) = \frac{(x^{2} - x + 25) ((x^{2} - x + 25) (- (5 + x) + 5 - x)) - 2 (5 + x) (5 - x) ((x^{2} - x + 25) \frac{d}{d x} (x^{2} - x + 25))}{{(x^{2} - x + 25)}^{4}}$

Step 3.6.2.2

Factor $x^{2} - x + 25$ out of $- 2 (5 + x) (5 - x) ((x^{2} - x + 25) \frac{d}{d x} [x^{2} - x + 25])$ .

$f'' (x) = \frac{(x^{2} - x + 25) ((x^{2} - x + 25) (- (5 + x) + 5 - x)) + (x^{2} - x + 25) (- 2 (5 + x) (5 - x) (\frac{d}{d x} (x^{2} - x + 25)))}{{(x^{2} - x + 25)}^{4}}$

Step 3.6.2.3

Factor $x^{2} - x + 25$ out of $(x^{2} - x + 25) ((x^{2} - x + 25) (- (5 + x) + 5 - x)) + (x^{2} - x + 25) (- 2 (5 + x) (5 - x) (\frac{d}{d x} [x^{2} - x + 25]))$ .

$f'' (x) = \frac{(x^{2} - x + 25) ((x^{2} - x + 25) (- (5 + x) + 5 - x) - 2 (5 + x) (5 - x) (\frac{d}{d x} (x^{2} - x + 25)))}{{(x^{2} - x + 25)}^{4}}$

Step 3.7

Cancel the common factors.

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Step 3.7.1

Factor $x^{2} - x + 25$ out of ${(x^{2} - x + 25)}^{4}$ .

$f'' (x) = \frac{(x^{2} - x + 25) ((x^{2} - x + 25) (- (5 + x) + 5 - x) - 2 (5 + x) (5 - x) (\frac{d}{d x} (x^{2} - x + 25)))}{(x^{2} - x + 25) {(x^{2} - x + 25)}^{3}}$

Step 3.7.2

Cancel the common factor.

$f'' (x) = \frac{(x^{2} - x + 25) ((x^{2} - x + 25) (- (5 + x) + 5 - x) - 2 (5 + x) (5 - x) (\frac{d}{d x} (x^{2} - x + 25)))}{(x^{2} - x + 25) {(x^{2} - x + 25)}^{3}}$

Step 3.7.3

Rewrite the expression.

$f'' (x) = \frac{(x^{2} - x + 25) (- (5 + x) + 5 - x) - 2 (5 + x) (5 - x) (\frac{d}{d x} (x^{2} - x + 25))}{{(x^{2} - x + 25)}^{3}}$

Step 3.8

By the Sum Rule, the derivative of $x^{2} - x + 25$ with respect to $x$ is $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [25]$ .

$f'' (x) = \frac{(x^{2} - x + 25) (- (5 + x) + 5 - x) - 2 (5 + x) (5 - x) (\frac{d}{d x} (x^{2}) + \frac{d}{d x} (- x) + \frac{d}{d x} (25))}{{(x^{2} - x + 25)}^{3}}$

Step 3.9

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$f'' (x) = \frac{(x^{2} - x + 25) (- (5 + x) + 5 - x) - 2 (5 + x) (5 - x) (2 x + \frac{d}{d x} (- x) + \frac{d}{d x} (25))}{{(x^{2} - x + 25)}^{3}}$

Step 3.10

Since $- 1$ is constant with respect to $x$ , the derivative of $- x$ with respect to $x$ is $- \frac{d}{d x} [x]$ .

$f'' (x) = \frac{(x^{2} - x + 25) (- (5 + x) + 5 - x) - 2 (5 + x) (5 - x) (2 x - \frac{d}{d x} x + \frac{d}{d x} (25))}{{(x^{2} - x + 25)}^{3}}$

Step 3.11

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$f'' (x) = \frac{(x^{2} - x + 25) (- (5 + x) + 5 - x) - 2 (5 + x) (5 - x) (2 x - 1 \cdot 1 + \frac{d}{d x} (25))}{{(x^{2} - x + 25)}^{3}}$

Step 3.12

Multiply $- 1$ by $1$ .

$f'' (x) = \frac{(x^{2} - x + 25) (- (5 + x) + 5 - x) - 2 (5 + x) (5 - x) (2 x - 1 + \frac{d}{d x} (25))}{{(x^{2} - x + 25)}^{3}}$

Step 3.13

Since $25$ is constant with respect to $x$ , the derivative of $25$ with respect to $x$ is $0$ .

$f'' (x) = \frac{(x^{2} - x + 25) (- (5 + x) + 5 - x) - 2 (5 + x) (5 - x) (2 x - 1 + 0)}{{(x^{2} - x + 25)}^{3}}$

Step 3.14

Add $2 x - 1$ and $0$ .

$f'' (x) = \frac{(x^{2} - x + 25) (- (5 + x) + 5 - x) - 2 (5 + x) (5 - x) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15

Simplify.

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Step 3.15.1

Apply the distributive property.

$f'' (x) = \frac{(x^{2} - x + 25) (- 1 \cdot 5 - x + 5 - x) - 2 (5 + x) (5 - x) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.2

Apply the distributive property.

$f'' (x) = \frac{(x^{2} - x + 25) (- 1 \cdot 5 - x + 5 - x) + (- 2 \cdot 5 - 2 x) (5 - x) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3

Simplify the numerator.

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Step 3.15.3.1

Simplify each term.

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Step 3.15.3.1.1

Multiply $- 1$ by $5$ .

$f'' (x) = \frac{(x^{2} - x + 25) (- 5 - x + 5 - x) + (- 2 \cdot 5 - 2 x) (5 - x) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.2

Combine the opposite terms in $- 5 - x + 5 - x$ .

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Step 3.15.3.1.2.1

Add $- 5$ and $5$ .

$f'' (x) = \frac{(x^{2} - x + 25) (- x + 0 - x) + (- 2 \cdot 5 - 2 x) (5 - x) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.2.2

Add $- x$ and $0$ .

$f'' (x) = \frac{(x^{2} - x + 25) (- x - x) + (- 2 \cdot 5 - 2 x) (5 - x) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.3

Subtract $x$ from $- x$ .

$f'' (x) = \frac{(x^{2} - x + 25) (- 2 x) + (- 2 \cdot 5 - 2 x) (5 - x) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.4

Apply the distributive property.

$f'' (x) = \frac{x^{2} (- 2 x) - x (- 2 x) + 25 (- 2 x) + (- 2 \cdot 5 - 2 x) (5 - x) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.5

Simplify.

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Step 3.15.3.1.5.1

Rewrite using the commutative property of multiplication.

$f'' (x) = \frac{- 2 x^{2} x - x (- 2 x) + 25 (- 2 x) + (- 2 \cdot 5 - 2 x) (5 - x) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.5.2

Rewrite using the commutative property of multiplication.

$f'' (x) = \frac{- 2 x^{2} x - 1 \cdot (- 2 x \cdot x) + 25 (- 2 x) + (- 2 \cdot 5 - 2 x) (5 - x) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.5.3

Multiply $- 2$ by $25$ .

$f'' (x) = \frac{- 2 x^{2} x - 1 \cdot (- 2 x \cdot x) - 50 x + (- 2 \cdot 5 - 2 x) (5 - x) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.6

Simplify each term.

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Step 3.15.3.1.6.1

Multiply $x^{2}$ by $x$ by adding the exponents.

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Step 3.15.3.1.6.1.1

Move $x$ .

$f'' (x) = \frac{- 2 (x \cdot x^{2}) - 1 \cdot (- 2 x \cdot x) - 50 x + (- 2 \cdot 5 - 2 x) (5 - x) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.6.1.2

Multiply $x$ by $x^{2}$ .

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Step 3.15.3.1.6.1.2.1

Raise $x$ to the power of $1$ .

$f'' (x) = \frac{- 2 (x \cdot x^{2}) - 1 \cdot (- 2 x \cdot x) - 50 x + (- 2 \cdot 5 - 2 x) (5 - x) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.6.1.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f'' (x) = \frac{- 2 x^{1 + 2} - 1 \cdot (- 2 x \cdot x) - 50 x + (- 2 \cdot 5 - 2 x) (5 - x) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.6.1.3

Add $1$ and $2$ .

$f'' (x) = \frac{- 2 x^{3} - 1 \cdot (- 2 x \cdot x) - 50 x + (- 2 \cdot 5 - 2 x) (5 - x) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.6.2

Multiply $x$ by $x$ by adding the exponents.

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Step 3.15.3.1.6.2.1

Move $x$ .

$f'' (x) = \frac{- 2 x^{3} - 1 \cdot (- 2 (x \cdot x)) - 50 x + (- 2 \cdot 5 - 2 x) (5 - x) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.6.2.2

Multiply $x$ by $x$ .

$f'' (x) = \frac{- 2 x^{3} - 1 \cdot (- 2 x^{2}) - 50 x + (- 2 \cdot 5 - 2 x) (5 - x) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.6.3

Multiply $- 1$ by $- 2$ .

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x + (- 2 \cdot 5 - 2 x) (5 - x) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.7

Multiply $- 2$ by $5$ .

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x + (- 10 - 2 x) (5 - x) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.8

Expand $(- 10 - 2 x) (5 - x)$ using the FOIL Method.

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Step 3.15.3.1.8.1

Apply the distributive property.

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x + (- 10 (5 - x) - 2 x (5 - x)) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.8.2

Apply the distributive property.

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x + (- 10 \cdot 5 - 10 (- x) - 2 x (5 - x)) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.8.3

Apply the distributive property.

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x + (- 10 \cdot 5 - 10 (- x) - 2 x \cdot 5 - 2 x (- x)) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.9

Simplify and combine like terms.

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Step 3.15.3.1.9.1

Simplify each term.

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Step 3.15.3.1.9.1.1

Multiply $- 10$ by $5$ .

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x + (- 50 - 10 (- x) - 2 x \cdot 5 - 2 x (- x)) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.9.1.2

Multiply $- 1$ by $- 10$ .

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x + (- 50 + 10 x - 2 x \cdot 5 - 2 x (- x)) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.9.1.3

Multiply $5$ by $- 2$ .

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x + (- 50 + 10 x - 10 x - 2 x (- x)) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.9.1.4

Rewrite using the commutative property of multiplication.

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x + (- 50 + 10 x - 10 x - 2 \cdot (- 1 x \cdot x)) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.9.1.5

Multiply $x$ by $x$ by adding the exponents.

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Step 3.15.3.1.9.1.5.1

Move $x$ .

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x + (- 50 + 10 x - 10 x - 2 \cdot (- 1 (x \cdot x))) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.9.1.5.2

Multiply $x$ by $x$ .

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x + (- 50 + 10 x - 10 x - 2 \cdot (- 1 x^{2})) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.9.1.6

Multiply $- 2$ by $- 1$ .

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x + (- 50 + 10 x - 10 x + 2 x^{2}) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.9.2

Subtract $10 x$ from $10 x$ .

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x + (- 50 + 0 + 2 x^{2}) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.9.3

Add $- 50$ and $0$ .

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x + (- 50 + 2 x^{2}) (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.10

Expand $(- 50 + 2 x^{2}) (2 x - 1)$ using the FOIL Method.

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Step 3.15.3.1.10.1

Apply the distributive property.

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x - 50 (2 x - 1) + 2 x^{2} (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.10.2

Apply the distributive property.

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x - 50 (2 x) - 50 \cdot - 1 + 2 x^{2} (2 x - 1)}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.10.3

Apply the distributive property.

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x - 50 (2 x) - 50 \cdot - 1 + 2 x^{2} (2 x) + 2 x^{2} \cdot - 1}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.11

Simplify each term.

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Step 3.15.3.1.11.1

Multiply $2$ by $- 50$ .

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x - 100 x - 50 \cdot - 1 + 2 x^{2} (2 x) + 2 x^{2} \cdot - 1}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.11.2

Multiply $- 50$ by $- 1$ .

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x - 100 x + 50 + 2 x^{2} (2 x) + 2 x^{2} \cdot - 1}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.11.3

Rewrite using the commutative property of multiplication.

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x - 100 x + 50 + 2 \cdot (2 x^{2} x) + 2 x^{2} \cdot - 1}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.11.4

Multiply $x^{2}$ by $x$ by adding the exponents.

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Step 3.15.3.1.11.4.1

Move $x$ .

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x - 100 x + 50 + 2 \cdot (2 (x \cdot x^{2})) + 2 x^{2} \cdot - 1}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.11.4.2

Multiply $x$ by $x^{2}$ .

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Step 3.15.3.1.11.4.2.1

Raise $x$ to the power of $1$ .

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x - 100 x + 50 + 2 \cdot (2 (x \cdot x^{2})) + 2 x^{2} \cdot - 1}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.11.4.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x - 100 x + 50 + 2 \cdot (2 x^{1 + 2}) + 2 x^{2} \cdot - 1}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.11.4.3

Add $1$ and $2$ .

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x - 100 x + 50 + 2 \cdot (2 x^{3}) + 2 x^{2} \cdot - 1}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.11.5

Multiply $2$ by $2$ .

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x - 100 x + 50 + 4 x^{3} + 2 x^{2} \cdot - 1}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.1.11.6

Multiply $- 1$ by $2$ .

$f'' (x) = \frac{- 2 x^{3} + 2 x^{2} - 50 x - 100 x + 50 + 4 x^{3} - 2 x^{2}}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.2

Combine the opposite terms in $- 2 x^{3} + 2 x^{2} - 50 x - 100 x + 50 + 4 x^{3} - 2 x^{2}$ .

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Step 3.15.3.2.1

Subtract $2 x^{2}$ from $2 x^{2}$ .

$f'' (x) = \frac{- 2 x^{3} - 50 x - 100 x + 50 + 4 x^{3} + 0}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.2.2

Add $- 2 x^{3} - 50 x - 100 x + 50 + 4 x^{3}$ and $0$ .

$f'' (x) = \frac{- 2 x^{3} - 50 x - 100 x + 50 + 4 x^{3}}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.3

Add $- 2 x^{3}$ and $4 x^{3}$ .

$f'' (x) = \frac{2 x^{3} - 50 x - 100 x + 50}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.3.4

Subtract $100 x$ from $- 50 x$ .

$f'' (x) = \frac{2 x^{3} - 150 x + 50}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.4

Factor $2$ out of $2 x^{3} - 150 x + 50$ .

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Step 3.15.4.1

Factor $2$ out of $2 x^{3}$ .

$f'' (x) = \frac{2 (x^{3}) - 150 x + 50}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.4.2

Factor $2$ out of $- 150 x$ .

$f'' (x) = \frac{2 (x^{3}) + 2 (- 75 x) + 50}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.4.3

Factor $2$ out of $50$ .

$f'' (x) = \frac{2 x^{3} + 2 (- 75 x) + 2 \cdot 25}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.4.4

Factor $2$ out of $2 x^{3} + 2 (- 75 x)$ .

$f'' (x) = \frac{2 (x^{3} - 75 x) + 2 \cdot 25}{{(x^{2} - x + 25)}^{3}}$

Step 3.15.4.5

Factor $2$ out of $2 (x^{3} - 75 x) + 2 \cdot 25$ .

$f'' (x) = \frac{2 (x^{3} - 75 x + 25)}{{(x^{2} - x + 25)}^{3}}$

Step 4

To find the local maximum and minimum values of the function, set the derivative equal to $0$ and solve.

$\frac{(5 + x) (5 - x)}{{(x^{2} - x + 25)}^{2}} = 0$

Step 5

Find the first derivative.

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Step 5.1

Find the first derivative.

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Step 5.1.1

$\frac{(x^{2} - x + 25) \frac{d}{d x} [x] - x \frac{d}{d x} [x^{2} - x + 25]}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.2

Differentiate.

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Step 5.1.2.1

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{(x^{2} - x + 25) \cdot 1 - x \frac{d}{d x} [x^{2} - x + 25]}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.2.2

Multiply $x^{2} - x + 25$ by $1$ .

$\frac{x^{2} - x + 25 - x \frac{d}{d x} [x^{2} - x + 25]}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.2.3

By the Sum Rule, the derivative of $x^{2} - x + 25$ with respect to $x$ is $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [25]$ .

$\frac{x^{2} - x + 25 - x (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [25])}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.2.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$\frac{x^{2} - x + 25 - x (2 x + \frac{d}{d x} [- x] + \frac{d}{d x} [25])}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.2.5

Since $- 1$ is constant with respect to $x$ , the derivative of $- x$ with respect to $x$ is $- \frac{d}{d x} [x]$ .

$\frac{x^{2} - x + 25 - x (2 x - \frac{d}{d x} [x] + \frac{d}{d x} [25])}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.2.6

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{x^{2} - x + 25 - x (2 x - 1 \cdot 1 + \frac{d}{d x} [25])}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.2.7

Multiply $- 1$ by $1$ .

$\frac{x^{2} - x + 25 - x (2 x - 1 + \frac{d}{d x} [25])}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.2.8

Since $25$ is constant with respect to $x$ , the derivative of $25$ with respect to $x$ is $0$ .

$\frac{x^{2} - x + 25 - x (2 x - 1 + 0)}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.2.9

Add $2 x - 1$ and $0$ .

$\frac{x^{2} - x + 25 - x (2 x - 1)}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.3

Simplify.

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Step 5.1.3.1

Apply the distributive property.

$\frac{x^{2} - x + 25 - x (2 x) - x \cdot - 1}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.3.2

Simplify the numerator.

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Step 5.1.3.2.1

Simplify each term.

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Step 5.1.3.2.1.1

Rewrite using the commutative property of multiplication.

$\frac{x^{2} - x + 25 - 1 \cdot 2 x \cdot x - x \cdot - 1}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.3.2.1.2

Multiply $x$ by $x$ by adding the exponents.

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Step 5.1.3.2.1.2.1

Move $x$ .

$\frac{x^{2} - x + 25 - 1 \cdot 2 (x \cdot x) - x \cdot - 1}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.3.2.1.2.2

Multiply $x$ by $x$ .

$\frac{x^{2} - x + 25 - 1 \cdot 2 x^{2} - x \cdot - 1}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.3.2.1.3

Multiply $- 1$ by $2$ .

$\frac{x^{2} - x + 25 - 2 x^{2} - x \cdot - 1}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.3.2.1.4

Multiply $- x \cdot - 1$ .

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Step 5.1.3.2.1.4.1

Multiply $- 1$ by $- 1$ .

$\frac{x^{2} - x + 25 - 2 x^{2} + 1 x}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.3.2.1.4.2

Multiply $x$ by $1$ .

$\frac{x^{2} - x + 25 - 2 x^{2} + x}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.3.2.2

Combine the opposite terms in $x^{2} - x + 25 - 2 x^{2} + x$ .

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Step 5.1.3.2.2.1

Add $- x$ and $x$ .

$\frac{x^{2} + 25 - 2 x^{2} + 0}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.3.2.2.2

Add $x^{2} + 25 - 2 x^{2}$ and $0$ .

$\frac{x^{2} + 25 - 2 x^{2}}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.3.2.3

Subtract $2 x^{2}$ from $x^{2}$ .

$\frac{- x^{2} + 25}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.3.3

Simplify the numerator.

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Step 5.1.3.3.1

Rewrite $25$ as $5^{2}$ .

$\frac{- x^{2} + 5^{2}}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.3.3.2

Reorder $- x^{2}$ and $5^{2}$ .

$\frac{5^{2} - x^{2}}{{(x^{2} - x + 25)}^{2}}$

Step 5.1.3.3.3

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 5$ and $b = x$ .

$f' (x) = \frac{(5 + x) (5 - x)}{{(x^{2} - x + 25)}^{2}}$

Step 5.2

The first derivative of $f (x)$ with respect to $x$ is $\frac{(5 + x) (5 - x)}{{(x^{2} - x + 25)}^{2}}$ .

$\frac{(5 + x) (5 - x)}{{(x^{2} - x + 25)}^{2}}$

Step 6

Set the first derivative equal to $0$ then solve the equation $\frac{(5 + x) (5 - x)}{{(x^{2} - x + 25)}^{2}} = 0$ .

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Step 6.1

Set the first derivative equal to $0$ .

$\frac{(5 + x) (5 - x)}{{(x^{2} - x + 25)}^{2}} = 0$

Step 6.2

Set the numerator equal to zero.

$(5 + x) (5 - x) = 0$

Step 6.3

Solve the equation for $x$ .

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Step 6.3.1

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$5 + x = 0$

$5 - x = 0$

Step 6.3.2

Set $5 + x$ equal to $0$ and solve for $x$ .

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Step 6.3.2.1

Set $5 + x$ equal to $0$ .

$5 + x = 0$

Step 6.3.2.2

Subtract $5$ from both sides of the equation.

$x = - 5$

Step 6.3.3

Set $5 - x$ equal to $0$ and solve for $x$ .

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Step 6.3.3.1

Set $5 - x$ equal to $0$ .

$5 - x = 0$

Step 6.3.3.2

Solve $5 - x = 0$ for $x$ .

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Step 6.3.3.2.1

Subtract $5$ from both sides of the equation.

$- x = - 5$

Step 6.3.3.2.2

Divide each term in $- x = - 5$ by $- 1$ and simplify.

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Step 6.3.3.2.2.1

Divide each term in $- x = - 5$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 5}{- 1}$

Step 6.3.3.2.2.2

Simplify the left side.

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Step 6.3.3.2.2.2.1

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 5}{- 1}$

Step 6.3.3.2.2.2.2

Divide $x$ by $1$ .

$x = \frac{- 5}{- 1}$

Step 6.3.3.2.2.3

Simplify the right side.

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Step 6.3.3.2.2.3.1

Divide $- 5$ by $- 1$ .

$x = 5$

Step 6.3.4

The final solution is all the values that make $(5 + x) (5 - x) = 0$ true.

$x = - 5, 5$

Step 7

Find the values where the derivative is undefined.

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Step 7.1

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Step 8

Critical points to evaluate.

$x = - 5, 5$

Step 9

Evaluate the second derivative at $x = - 5$ . If the second derivative is positive, then this is a local minimum. If it is negative, then this is a local maximum.

$\frac{2 ({(- 5)}^{3} - 75 \cdot - 5 + 25)}{{({(- 5)}^{2} - (- 5) + 25)}^{3}}$

Step 10

Evaluate the second derivative.

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Step 10.1

Simplify the numerator.

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Step 10.1.1

Raise $- 5$ to the power of $3$ .

$\frac{2 (- 125 - 75 \cdot - 5 + 25)}{{({(- 5)}^{2} - (- 5) + 25)}^{3}}$

Step 10.1.2

Multiply $- 75$ by $- 5$ .

$\frac{2 (- 125 + 375 + 25)}{{({(- 5)}^{2} - (- 5) + 25)}^{3}}$

Step 10.1.3

Add $- 125$ and $375$ .

$\frac{2 (250 + 25)}{{({(- 5)}^{2} - (- 5) + 25)}^{3}}$

Step 10.1.4

Add $250$ and $25$ .

$\frac{2 \cdot 275}{{({(- 5)}^{2} - (- 5) + 25)}^{3}}$

Step 10.2

Simplify the denominator.

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Step 10.2.1

Raise $- 5$ to the power of $2$ .

$\frac{2 \cdot 275}{{(25 - (- 5) + 25)}^{3}}$

Step 10.2.2

Multiply $- 1$ by $- 5$ .

$\frac{2 \cdot 275}{{(25 + 5 + 25)}^{3}}$

Step 10.2.3

Add $25$ and $5$ .

$\frac{2 \cdot 275}{{(30 + 25)}^{3}}$

Step 10.2.4

Add $30$ and $25$ .

$\frac{2 \cdot 275}{55^{3}}$

Step 10.2.5

Raise $55$ to the power of $3$ .

$\frac{2 \cdot 275}{166375}$

Step 10.3

Reduce the expression by cancelling the common factors.

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Step 10.3.1

Multiply $2$ by $275$ .

$\frac{550}{166375}$

Step 10.3.2

Cancel the common factor of $550$ and $166375$ .

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Step 10.3.2.1

Factor $275$ out of $550$ .

$\frac{275 (2)}{166375}$

Step 10.3.2.2

Cancel the common factors.

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Step 10.3.2.2.1

Factor $275$ out of $166375$ .

$\frac{275 \cdot 2}{275 \cdot 605}$

Step 10.3.2.2.2

Cancel the common factor.

$\frac{275 \cdot 2}{275 \cdot 605}$

Step 10.3.2.2.3

Rewrite the expression.

$\frac{2}{605}$

Step 11

$x = - 5$ is a local minimum because the value of the second derivative is positive. This is referred to as the second derivative test.

$x = - 5$ is a local minimum

Step 12

Find the y-value when $x = - 5$ .

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Step 12.1

Replace the variable $x$ with $- 5$ in the expression.

$f (- 5) = \frac{- 5}{{(- 5)}^{2} - (- 5) + 25}$

Step 12.2

Simplify the result.

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Step 12.2.1

Simplify the denominator.

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Step 12.2.1.1

Raise $- 5$ to the power of $2$ .

$f (- 5) = \frac{- 5}{25 - (- 5) + 25}$

Step 12.2.1.2

Multiply $- 1$ by $- 5$ .

$f (- 5) = \frac{- 5}{25 + 5 + 25}$

Step 12.2.1.3

Add $25$ and $5$ .

$f (- 5) = \frac{- 5}{30 + 25}$

Step 12.2.1.4

Add $30$ and $25$ .

$f (- 5) = \frac{- 5}{55}$

Step 12.2.2

Reduce the expression by cancelling the common factors.

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Step 12.2.2.1

Cancel the common factor of $- 5$ and $55$ .

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Step 12.2.2.1.1

Factor $5$ out of $- 5$ .

$f (- 5) = \frac{5 (- 1)}{55}$

Step 12.2.2.1.2

Cancel the common factors.

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Step 12.2.2.1.2.1

Factor $5$ out of $55$ .

$f (- 5) = \frac{5 \cdot - 1}{5 \cdot 11}$

Step 12.2.2.1.2.2

Cancel the common factor.

$f (- 5) = \frac{5 \cdot - 1}{5 \cdot 11}$

Step 12.2.2.1.2.3

Rewrite the expression.

$f (- 5) = \frac{- 1}{11}$

Step 12.2.2.2

Move the negative in front of the fraction.

$f (- 5) = - \frac{1}{11}$

Step 12.2.3

The final answer is $- \frac{1}{11}$ .

$y = - \frac{1}{11}$

Step 13

Evaluate the second derivative at $x = 5$ . If the second derivative is positive, then this is a local minimum. If it is negative, then this is a local maximum.

$\frac{2 ({(5)}^{3} - 75 \cdot 5 + 25)}{{({(5)}^{2} - (5) + 25)}^{3}}$

Step 14

Evaluate the second derivative.

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Step 14.1

Simplify the numerator.

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Step 14.1.1

Raise $5$ to the power of $3$ .

$\frac{2 (125 - 75 \cdot 5 + 25)}{{(5^{2} - (5) + 25)}^{3}}$

Step 14.1.2

Multiply $- 75$ by $5$ .

$\frac{2 (125 - 375 + 25)}{{(5^{2} - (5) + 25)}^{3}}$

Step 14.1.3

Subtract $375$ from $125$ .

$\frac{2 (- 250 + 25)}{{(5^{2} - (5) + 25)}^{3}}$

Step 14.1.4

Add $- 250$ and $25$ .

$\frac{2 \cdot - 225}{{(5^{2} - (5) + 25)}^{3}}$

Step 14.2

Simplify the denominator.

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Step 14.2.1

Raise $5$ to the power of $2$ .

$\frac{2 \cdot - 225}{{(25 - (5) + 25)}^{3}}$

Step 14.2.2

Multiply $- 1$ by $5$ .

$\frac{2 \cdot - 225}{{(25 - 5 + 25)}^{3}}$

Step 14.2.3

Subtract $5$ from $25$ .

$\frac{2 \cdot - 225}{{(20 + 25)}^{3}}$

Step 14.2.4

Add $20$ and $25$ .

$\frac{2 \cdot - 225}{45^{3}}$

Step 14.2.5

Raise $45$ to the power of $3$ .

$\frac{2 \cdot - 225}{91125}$

Step 14.3

Reduce the expression by cancelling the common factors.

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Step 14.3.1

Multiply $2$ by $- 225$ .

$\frac{- 450}{91125}$

Step 14.3.2

Cancel the common factor of $- 450$ and $91125$ .

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Step 14.3.2.1

Factor $225$ out of $- 450$ .

$\frac{225 (- 2)}{91125}$

Step 14.3.2.2

Cancel the common factors.

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Step 14.3.2.2.1

Factor $225$ out of $91125$ .

$\frac{225 \cdot - 2}{225 \cdot 405}$

Step 14.3.2.2.2

Cancel the common factor.

$\frac{225 \cdot - 2}{225 \cdot 405}$

Step 14.3.2.2.3

Rewrite the expression.

$\frac{- 2}{405}$

Step 14.3.3

Move the negative in front of the fraction.

$- \frac{2}{405}$

Step 15

$x = 5$ is a local maximum because the value of the second derivative is negative. This is referred to as the second derivative test.

$x = 5$ is a local maximum

Step 16

Find the y-value when $x = 5$ .

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Step 16.1

Replace the variable $x$ with $5$ in the expression.

$f (5) = \frac{5}{{(5)}^{2} - (5) + 25}$

Step 16.2

Simplify the result.

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Step 16.2.1

Cancel the common factor of $5$ and ${(5)}^{2} - (5) + 25$ .

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Step 16.2.1.1

Factor $5$ out of $5$ .

$f (5) = \frac{5 \cdot 1}{5^{2} - (5) + 25}$

Step 16.2.1.2

Cancel the common factors.

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Step 16.2.1.2.1

Factor $5$ out of $5^{2}$ .

$f (5) = \frac{5 \cdot 1}{5 \cdot 5 - (5) + 25}$

Step 16.2.1.2.2

Factor $5$ out of $- (5)$ .

$f (5) = \frac{5 \cdot 1}{5 \cdot 5 + 5 \cdot - 1 + 25}$

Step 16.2.1.2.3

Factor $5$ out of $5 \cdot 5 + 5 \cdot - 1$ .

$f (5) = \frac{5 \cdot 1}{5 \cdot (5 - 1) + 25}$

Step 16.2.1.2.4

Factor $5$ out of $25$ .

$f (5) = \frac{5 \cdot 1}{5 \cdot (5 - 1) + 5 (5)}$

Step 16.2.1.2.5

Factor $5$ out of $5 \cdot (5 - 1) + 5 (5)$ .

$f (5) = \frac{5 \cdot 1}{5 \cdot (5 - 1 + 5)}$

Step 16.2.1.2.6

Cancel the common factor.

$f (5) = \frac{5 \cdot 1}{5 \cdot (5 - 1 + 5)}$

Step 16.2.1.2.7

Rewrite the expression.

$f (5) = \frac{1}{5 - 1 + 5}$

Step 16.2.2

Simplify the denominator.

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Step 16.2.2.1

Subtract $1$ from $5$ .

$f (5) = \frac{1}{4 + 5}$

Step 16.2.2.2

Add $4$ and $5$ .

$f (5) = \frac{1}{9}$

Step 16.2.3

The final answer is $\frac{1}{9}$ .

$y = \frac{1}{9}$

Step 17

These are the local extrema for $f (x) = \frac{x}{x^{2} - x + 25}$ .

$(- 5, - \frac{1}{11})$ is a local minima

$(5, \frac{1}{9})$ is a local maxima

Step 18