Calculus Examples

$y = {(x^{2} - 25)}^{\frac{2}{3}}$

Step 1

Find the first derivative.

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Step 1.1

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{2}{3}}$ and $g (x) = x^{2} - 25$ .

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Step 1.1.1

To apply the Chain Rule, set $u$ as $x^{2} - 25$ .

$\frac{d}{d u} [u^{\frac{2}{3}}] \frac{d}{d x} [x^{2} - 25]$

Step 1.1.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = \frac{2}{3}$ .

$\frac{2}{3} u^{\frac{2}{3} - 1} \frac{d}{d x} [x^{2} - 25]$

Step 1.1.3

Replace all occurrences of $u$ with $x^{2} - 25$ .

$\frac{2}{3} {(x^{2} - 25)}^{\frac{2}{3} - 1} \frac{d}{d x} [x^{2} - 25]$

Step 1.2

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{2}{3} {(x^{2} - 25)}^{\frac{2}{3} - 1 \cdot \frac{3}{3}} \frac{d}{d x} [x^{2} - 25]$

Step 1.3

Combine $- 1$ and $\frac{3}{3}$ .

$\frac{2}{3} {(x^{2} - 25)}^{\frac{2}{3} + \frac{- 1 \cdot 3}{3}} \frac{d}{d x} [x^{2} - 25]$

Step 1.4

Combine the numerators over the common denominator.

$\frac{2}{3} {(x^{2} - 25)}^{\frac{2 - 1 \cdot 3}{3}} \frac{d}{d x} [x^{2} - 25]$

Step 1.5

Simplify the numerator.

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Step 1.5.1

Multiply $- 1$ by $3$ .

$\frac{2}{3} {(x^{2} - 25)}^{\frac{2 - 3}{3}} \frac{d}{d x} [x^{2} - 25]$

Step 1.5.2

Subtract $3$ from $2$ .

$\frac{2}{3} {(x^{2} - 25)}^{\frac{- 1}{3}} \frac{d}{d x} [x^{2} - 25]$

Step 1.6

Combine fractions.

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Step 1.6.1

Move the negative in front of the fraction.

$\frac{2}{3} {(x^{2} - 25)}^{- \frac{1}{3}} \frac{d}{d x} [x^{2} - 25]$

Step 1.6.2

Combine $\frac{2}{3}$ and ${(x^{2} - 25)}^{- \frac{1}{3}}$ .

$\frac{2 {(x^{2} - 25)}^{- \frac{1}{3}}}{3} \frac{d}{d x} [x^{2} - 25]$

Step 1.6.3

Move ${(x^{2} - 25)}^{- \frac{1}{3}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{2}{3 {(x^{2} - 25)}^{\frac{1}{3}}} \frac{d}{d x} [x^{2} - 25]$

Step 1.7

By the Sum Rule, the derivative of $x^{2} - 25$ with respect to $x$ is $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 25]$ .

$\frac{2}{3 {(x^{2} - 25)}^{\frac{1}{3}}} (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 25])$

Step 1.8

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$\frac{2}{3 {(x^{2} - 25)}^{\frac{1}{3}}} (2 x + \frac{d}{d x} [- 25])$

Step 1.9

Since $- 25$ is constant with respect to $x$ , the derivative of $- 25$ with respect to $x$ is $0$ .

$\frac{2}{3 {(x^{2} - 25)}^{\frac{1}{3}}} (2 x + 0)$

Step 1.10

Combine fractions.

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Step 1.10.1

Add $2 x$ and $0$ .

$\frac{2}{3 {(x^{2} - 25)}^{\frac{1}{3}}} (2 x)$

Step 1.10.2

Combine $2$ and $\frac{2}{3 {(x^{2} - 25)}^{\frac{1}{3}}}$ .

$\frac{2 \cdot 2}{3 {(x^{2} - 25)}^{\frac{1}{3}}} x$

Step 1.10.3

Multiply $2$ by $2$ .

$\frac{4}{3 {(x^{2} - 25)}^{\frac{1}{3}}} x$

Step 1.10.4

Combine $\frac{4}{3 {(x^{2} - 25)}^{\frac{1}{3}}}$ and $x$ .

$f' (x) = \frac{4 x}{3 {(x^{2} - 25)}^{\frac{1}{3}}}$

Step 2

Find the second derivative.

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Step 2.1

Since $\frac{4}{3}$ is constant with respect to $x$ , the derivative of $\frac{4 x}{3 {(x^{2} - 25)}^{\frac{1}{3}}}$ with respect to $x$ is $\frac{4}{3} \frac{d}{d x} [\frac{x}{{(x^{2} - 25)}^{\frac{1}{3}}}]$ .

$\frac{4}{3} \frac{d}{d x} [\frac{x}{{(x^{2} - 25)}^{\frac{1}{3}}}]$

Step 2.2

Differentiate using the Quotient Rule which states that $\frac{d}{d x} [\frac{f (x)}{g (x)}]$ is $\frac{g (x) \frac{d}{d x} [f (x)] - f (x) \frac{d}{d x} [g (x)]}{{g (x)}^{2}}$ where $f (x) = x$ and $g (x) = {(x^{2} - 25)}^{\frac{1}{3}}$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} \frac{d}{d x} [x] - x \frac{d}{d x} [{(x^{2} - 25)}^{\frac{1}{3}}]}{{({(x^{2} - 25)}^{\frac{1}{3}})}^{2}}$

Step 2.3

Differentiate using the Power Rule.

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Step 2.3.1

Multiply the exponents in ${({(x^{2} - 25)}^{\frac{1}{3}})}^{2}$ .

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Step 2.3.1.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} \frac{d}{d x} [x] - x \frac{d}{d x} [{(x^{2} - 25)}^{\frac{1}{3}}]}{{(x^{2} - 25)}^{\frac{1}{3} \cdot 2}}$

Step 2.3.1.2

Combine $\frac{1}{3}$ and $2$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} \frac{d}{d x} [x] - x \frac{d}{d x} [{(x^{2} - 25)}^{\frac{1}{3}}]}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} \cdot 1 - x \frac{d}{d x} [{(x^{2} - 25)}^{\frac{1}{3}}]}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.3.3

Multiply ${(x^{2} - 25)}^{\frac{1}{3}}$ by $1$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} - x \frac{d}{d x} [{(x^{2} - 25)}^{\frac{1}{3}}]}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.4

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{1}{3}}$ and $g (x) = x^{2} - 25$ .

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Step 2.4.1

To apply the Chain Rule, set $u$ as $x^{2} - 25$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} - x (\frac{d}{d u} [u^{\frac{1}{3}}] \frac{d}{d x} [x^{2} - 25])}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.4.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = \frac{1}{3}$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} - x (\frac{1}{3} u^{\frac{1}{3} - 1} \frac{d}{d x} [x^{2} - 25])}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.4.3

Replace all occurrences of $u$ with $x^{2} - 25$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} - x (\frac{1}{3} {(x^{2} - 25)}^{\frac{1}{3} - 1} \frac{d}{d x} [x^{2} - 25])}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.5

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} - x (\frac{1}{3} {(x^{2} - 25)}^{\frac{1}{3} - 1 \cdot \frac{3}{3}} \frac{d}{d x} [x^{2} - 25])}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.6

Combine $- 1$ and $\frac{3}{3}$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} - x (\frac{1}{3} {(x^{2} - 25)}^{\frac{1}{3} + \frac{- 1 \cdot 3}{3}} \frac{d}{d x} [x^{2} - 25])}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.7

Combine the numerators over the common denominator.

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} - x (\frac{1}{3} {(x^{2} - 25)}^{\frac{1 - 1 \cdot 3}{3}} \frac{d}{d x} [x^{2} - 25])}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.8

Simplify the numerator.

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Step 2.8.1

Multiply $- 1$ by $3$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} - x (\frac{1}{3} {(x^{2} - 25)}^{\frac{1 - 3}{3}} \frac{d}{d x} [x^{2} - 25])}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.8.2

Subtract $3$ from $1$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} - x (\frac{1}{3} {(x^{2} - 25)}^{\frac{- 2}{3}} \frac{d}{d x} [x^{2} - 25])}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.9

Combine fractions.

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Step 2.9.1

Move the negative in front of the fraction.

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} - x (\frac{1}{3} {(x^{2} - 25)}^{- \frac{2}{3}} \frac{d}{d x} [x^{2} - 25])}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.9.2

Combine $\frac{1}{3}$ and ${(x^{2} - 25)}^{- \frac{2}{3}}$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} - x (\frac{{(x^{2} - 25)}^{- \frac{2}{3}}}{3} \frac{d}{d x} [x^{2} - 25])}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.9.3

Move ${(x^{2} - 25)}^{- \frac{2}{3}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} - x (\frac{1}{3 {(x^{2} - 25)}^{\frac{2}{3}}} \frac{d}{d x} [x^{2} - 25])}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.9.4

Combine $\frac{1}{3 {(x^{2} - 25)}^{\frac{2}{3}}}$ and $x$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} - \frac{x}{3 {(x^{2} - 25)}^{\frac{2}{3}}} \frac{d}{d x} [x^{2} - 25]}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.10

By the Sum Rule, the derivative of $x^{2} - 25$ with respect to $x$ is $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 25]$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} - \frac{x}{3 {(x^{2} - 25)}^{\frac{2}{3}}} (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 25])}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.11

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} - \frac{x}{3 {(x^{2} - 25)}^{\frac{2}{3}}} (2 x + \frac{d}{d x} [- 25])}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.12

Since $- 25$ is constant with respect to $x$ , the derivative of $- 25$ with respect to $x$ is $0$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} - \frac{x}{3 {(x^{2} - 25)}^{\frac{2}{3}}} (2 x + 0)}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.13

Combine fractions.

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Step 2.13.1

Add $2 x$ and $0$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} - \frac{x}{3 {(x^{2} - 25)}^{\frac{2}{3}}} (2 x)}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.13.2

Multiply $2$ by $- 1$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} - 2 \frac{x}{3 {(x^{2} - 25)}^{\frac{2}{3}}} x}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.13.3

Combine $- 2$ and $\frac{x}{3 {(x^{2} - 25)}^{\frac{2}{3}}}$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} + \frac{- 2 x}{3 {(x^{2} - 25)}^{\frac{2}{3}}} x}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.13.4

Combine $\frac{- 2 x}{3 {(x^{2} - 25)}^{\frac{2}{3}}}$ and $x$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} + \frac{- 2 x \cdot x}{3 {(x^{2} - 25)}^{\frac{2}{3}}}}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.14

Raise $x$ to the power of $1$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} + \frac{- 2 (x^{1} x)}{3 {(x^{2} - 25)}^{\frac{2}{3}}}}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.15

Raise $x$ to the power of $1$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} + \frac{- 2 (x^{1} x^{1})}{3 {(x^{2} - 25)}^{\frac{2}{3}}}}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.16

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} + \frac{- 2 x^{1 + 1}}{3 {(x^{2} - 25)}^{\frac{2}{3}}}}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.17

Add $1$ and $1$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} + \frac{- 2 x^{2}}{3 {(x^{2} - 25)}^{\frac{2}{3}}}}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.18

Move the negative in front of the fraction.

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} - \frac{2 x^{2}}{3 {(x^{2} - 25)}^{\frac{2}{3}}}}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.19

To write ${(x^{2} - 25)}^{\frac{1}{3}}$ as a fraction with a common denominator, multiply by $\frac{3 {(x^{2} - 25)}^{\frac{2}{3}}}{3 {(x^{2} - 25)}^{\frac{2}{3}}}$ .

$\frac{4}{3} \cdot \frac{{(x^{2} - 25)}^{\frac{1}{3}} \cdot \frac{3 {(x^{2} - 25)}^{\frac{2}{3}}}{3 {(x^{2} - 25)}^{\frac{2}{3}}} - \frac{2 x^{2}}{3 {(x^{2} - 25)}^{\frac{2}{3}}}}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.20

Combine ${(x^{2} - 25)}^{\frac{1}{3}}$ and $\frac{3 {(x^{2} - 25)}^{\frac{2}{3}}}{3 {(x^{2} - 25)}^{\frac{2}{3}}}$ .

$\frac{4}{3} \cdot \frac{\frac{{(x^{2} - 25)}^{\frac{1}{3}} (3 {(x^{2} - 25)}^{\frac{2}{3}})}{3 {(x^{2} - 25)}^{\frac{2}{3}}} - \frac{2 x^{2}}{3 {(x^{2} - 25)}^{\frac{2}{3}}}}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.21

Combine the numerators over the common denominator.

$\frac{4}{3} \cdot \frac{\frac{{(x^{2} - 25)}^{\frac{1}{3}} (3 {(x^{2} - 25)}^{\frac{2}{3}}) - 2 x^{2}}{3 {(x^{2} - 25)}^{\frac{2}{3}}}}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.22

Multiply ${(x^{2} - 25)}^{\frac{1}{3}}$ by ${(x^{2} - 25)}^{\frac{2}{3}}$ by adding the exponents.

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Step 2.22.1

Move ${(x^{2} - 25)}^{\frac{2}{3}}$ .

$\frac{4}{3} \cdot \frac{\frac{{(x^{2} - 25)}^{\frac{2}{3}} {(x^{2} - 25)}^{\frac{1}{3}} \cdot 3 - 2 x^{2}}{3 {(x^{2} - 25)}^{\frac{2}{3}}}}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.22.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{4}{3} \cdot \frac{\frac{{(x^{2} - 25)}^{\frac{2}{3} + \frac{1}{3}} \cdot 3 - 2 x^{2}}{3 {(x^{2} - 25)}^{\frac{2}{3}}}}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.22.3

Combine the numerators over the common denominator.

$\frac{4}{3} \cdot \frac{\frac{{(x^{2} - 25)}^{\frac{2 + 1}{3}} \cdot 3 - 2 x^{2}}{3 {(x^{2} - 25)}^{\frac{2}{3}}}}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.22.4

Add $2$ and $1$ .

$\frac{4}{3} \cdot \frac{\frac{{(x^{2} - 25)}^{\frac{3}{3}} \cdot 3 - 2 x^{2}}{3 {(x^{2} - 25)}^{\frac{2}{3}}}}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.22.5

Divide $3$ by $3$ .

$\frac{4}{3} \cdot \frac{\frac{{(x^{2} - 25)}^{1} \cdot 3 - 2 x^{2}}{3 {(x^{2} - 25)}^{\frac{2}{3}}}}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.23

Simplify ${(x^{2} - 25)}^{1} \cdot 3$ .

$\frac{4}{3} \cdot \frac{\frac{(x^{2} - 25) \cdot 3 - 2 x^{2}}{3 {(x^{2} - 25)}^{\frac{2}{3}}}}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.24

Move $3$ to the left of $x^{2} - 25$ .

$\frac{4}{3} \cdot \frac{\frac{3 \cdot (x^{2} - 25) - 2 x^{2}}{3 {(x^{2} - 25)}^{\frac{2}{3}}}}{{(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.25

Rewrite $\frac{\frac{3 (x^{2} - 25) - 2 x^{2}}{3 {(x^{2} - 25)}^{\frac{2}{3}}}}{{(x^{2} - 25)}^{\frac{2}{3}}}$ as a product.

$\frac{4}{3} (\frac{3 (x^{2} - 25) - 2 x^{2}}{3 {(x^{2} - 25)}^{\frac{2}{3}}} \cdot \frac{1}{{(x^{2} - 25)}^{\frac{2}{3}}})$

Step 2.26

Multiply $\frac{3 (x^{2} - 25) - 2 x^{2}}{3 {(x^{2} - 25)}^{\frac{2}{3}}}$ by $\frac{1}{{(x^{2} - 25)}^{\frac{2}{3}}}$ .

$\frac{4}{3} \cdot \frac{3 (x^{2} - 25) - 2 x^{2}}{3 {(x^{2} - 25)}^{\frac{2}{3}} {(x^{2} - 25)}^{\frac{2}{3}}}$

Step 2.27

Multiply ${(x^{2} - 25)}^{\frac{2}{3}}$ by ${(x^{2} - 25)}^{\frac{2}{3}}$ by adding the exponents.

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Step 2.27.1

Move ${(x^{2} - 25)}^{\frac{2}{3}}$ .

$\frac{4}{3} \cdot \frac{3 (x^{2} - 25) - 2 x^{2}}{3 ({(x^{2} - 25)}^{\frac{2}{3}} {(x^{2} - 25)}^{\frac{2}{3}})}$

Step 2.27.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{4}{3} \cdot \frac{3 (x^{2} - 25) - 2 x^{2}}{3 {(x^{2} - 25)}^{\frac{2}{3} + \frac{2}{3}}}$

Step 2.27.3

Combine the numerators over the common denominator.

$\frac{4}{3} \cdot \frac{3 (x^{2} - 25) - 2 x^{2}}{3 {(x^{2} - 25)}^{\frac{2 + 2}{3}}}$

Step 2.27.4

Add $2$ and $2$ .

$\frac{4}{3} \cdot \frac{3 (x^{2} - 25) - 2 x^{2}}{3 {(x^{2} - 25)}^{\frac{4}{3}}}$

Step 2.28

Multiply $\frac{4}{3}$ by $\frac{3 (x^{2} - 25) - 2 x^{2}}{3 {(x^{2} - 25)}^{\frac{4}{3}}}$ .

$\frac{4 (3 (x^{2} - 25) - 2 x^{2})}{3 (3 {(x^{2} - 25)}^{\frac{4}{3}})}$

Step 2.29

Multiply $3$ by $3$ .

$\frac{4 (3 (x^{2} - 25) - 2 x^{2})}{9 {(x^{2} - 25)}^{\frac{4}{3}}}$

Step 2.30

Simplify.

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Step 2.30.1

Apply the distributive property.

$\frac{4 (3 x^{2} + 3 \cdot - 25 - 2 x^{2})}{9 {(x^{2} - 25)}^{\frac{4}{3}}}$

Step 2.30.2

Apply the distributive property.

$\frac{4 (3 x^{2}) + 4 (3 \cdot - 25) + 4 (- 2 x^{2})}{9 {(x^{2} - 25)}^{\frac{4}{3}}}$

Step 2.30.3

Simplify the numerator.

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Step 2.30.3.1

Simplify each term.

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Step 2.30.3.1.1

Multiply $3$ by $4$ .

$\frac{12 x^{2} + 4 (3 \cdot - 25) + 4 (- 2 x^{2})}{9 {(x^{2} - 25)}^{\frac{4}{3}}}$

Step 2.30.3.1.2

Multiply $4 (3 \cdot - 25)$ .

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Step 2.30.3.1.2.1

Multiply $3$ by $- 25$ .

$\frac{12 x^{2} + 4 \cdot - 75 + 4 (- 2 x^{2})}{9 {(x^{2} - 25)}^{\frac{4}{3}}}$

Step 2.30.3.1.2.2

Multiply $4$ by $- 75$ .

$\frac{12 x^{2} - 300 + 4 (- 2 x^{2})}{9 {(x^{2} - 25)}^{\frac{4}{3}}}$

Step 2.30.3.1.3

Multiply $- 2$ by $4$ .

$\frac{12 x^{2} - 300 - 8 x^{2}}{9 {(x^{2} - 25)}^{\frac{4}{3}}}$

Step 2.30.3.2

Subtract $8 x^{2}$ from $12 x^{2}$ .

$\frac{4 x^{2} - 300}{9 {(x^{2} - 25)}^{\frac{4}{3}}}$

Step 2.30.4

Factor $4$ out of $4 x^{2} - 300$ .

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Step 2.30.4.1

Factor $4$ out of $4 x^{2}$ .

$\frac{4 (x^{2}) - 300}{9 {(x^{2} - 25)}^{\frac{4}{3}}}$

Step 2.30.4.2

Factor $4$ out of $- 300$ .

$\frac{4 x^{2} + 4 \cdot - 75}{9 {(x^{2} - 25)}^{\frac{4}{3}}}$

Step 2.30.4.3

Factor $4$ out of $4 x^{2} + 4 \cdot - 75$ .

$f'' (x) = \frac{4 (x^{2} - 75)}{9 {(x^{2} - 25)}^{\frac{4}{3}}}$

Step 3

Find the third derivative.

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Step 3.1

Since $\frac{4}{9}$ is constant with respect to $x$ , the derivative of $\frac{4 (x^{2} - 75)}{9 {(x^{2} - 25)}^{\frac{4}{3}}}$ with respect to $x$ is $\frac{4}{9} \frac{d}{d x} [\frac{x^{2} - 75}{{(x^{2} - 25)}^{\frac{4}{3}}}]$ .

$\frac{4}{9} \frac{d}{d x} [\frac{x^{2} - 75}{{(x^{2} - 25)}^{\frac{4}{3}}}]$

Step 3.2

$\frac{4}{9} \cdot \frac{{(x^{2} - 25)}^{\frac{4}{3}} \frac{d}{d x} [x^{2} - 75] - (x^{2} - 75) \frac{d}{d x} [{(x^{2} - 25)}^{\frac{4}{3}}]}{{({(x^{2} - 25)}^{\frac{4}{3}})}^{2}}$

Step 3.3

Differentiate.

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Step 3.3.1

Multiply the exponents in ${({(x^{2} - 25)}^{\frac{4}{3}})}^{2}$ .

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Step 3.3.1.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{4}{9} \cdot \frac{{(x^{2} - 25)}^{\frac{4}{3}} \frac{d}{d x} [x^{2} - 75] - (x^{2} - 75) \frac{d}{d x} [{(x^{2} - 25)}^{\frac{4}{3}}]}{{(x^{2} - 25)}^{\frac{4}{3} \cdot 2}}$

Step 3.3.1.2

Multiply $\frac{4}{3} \cdot 2$ .

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Step 3.3.1.2.1

Combine $\frac{4}{3}$ and $2$ .

$\frac{4}{9} \cdot \frac{{(x^{2} - 25)}^{\frac{4}{3}} \frac{d}{d x} [x^{2} - 75] - (x^{2} - 75) \frac{d}{d x} [{(x^{2} - 25)}^{\frac{4}{3}}]}{{(x^{2} - 25)}^{\frac{4 \cdot 2}{3}}}$

Step 3.3.1.2.2

Multiply $4$ by $2$ .

$\frac{4}{9} \cdot \frac{{(x^{2} - 25)}^{\frac{4}{3}} \frac{d}{d x} [x^{2} - 75] - (x^{2} - 75) \frac{d}{d x} [{(x^{2} - 25)}^{\frac{4}{3}}]}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.3.2

By the Sum Rule, the derivative of $x^{2} - 75$ with respect to $x$ is $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 75]$ .

$\frac{4}{9} \cdot \frac{{(x^{2} - 25)}^{\frac{4}{3}} (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 75]) - (x^{2} - 75) \frac{d}{d x} [{(x^{2} - 25)}^{\frac{4}{3}}]}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.3.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$\frac{4}{9} \cdot \frac{{(x^{2} - 25)}^{\frac{4}{3}} (2 x + \frac{d}{d x} [- 75]) - (x^{2} - 75) \frac{d}{d x} [{(x^{2} - 25)}^{\frac{4}{3}}]}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.3.4

Since $- 75$ is constant with respect to $x$ , the derivative of $- 75$ with respect to $x$ is $0$ .

$\frac{4}{9} \cdot \frac{{(x^{2} - 25)}^{\frac{4}{3}} (2 x + 0) - (x^{2} - 75) \frac{d}{d x} [{(x^{2} - 25)}^{\frac{4}{3}}]}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.3.5

Simplify the expression.

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Step 3.3.5.1

Add $2 x$ and $0$ .

$\frac{4}{9} \cdot \frac{{(x^{2} - 25)}^{\frac{4}{3}} (2 x) - (x^{2} - 75) \frac{d}{d x} [{(x^{2} - 25)}^{\frac{4}{3}}]}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.3.5.2

Move $2$ to the left of ${(x^{2} - 25)}^{\frac{4}{3}}$ .

$\frac{4}{9} \cdot \frac{2 \cdot {(x^{2} - 25)}^{\frac{4}{3}} x - (x^{2} - 75) \frac{d}{d x} [{(x^{2} - 25)}^{\frac{4}{3}}]}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.4

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{4}{3}}$ and $g (x) = x^{2} - 25$ .

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Step 3.4.1

To apply the Chain Rule, set $u$ as $x^{2} - 25$ .

$\frac{4}{9} \cdot \frac{2 {(x^{2} - 25)}^{\frac{4}{3}} x - (x^{2} - 75) (\frac{d}{d u} [u^{\frac{4}{3}}] \frac{d}{d x} [x^{2} - 25])}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.4.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = \frac{4}{3}$ .

$\frac{4}{9} \cdot \frac{2 {(x^{2} - 25)}^{\frac{4}{3}} x - (x^{2} - 75) (\frac{4}{3} u^{\frac{4}{3} - 1} \frac{d}{d x} [x^{2} - 25])}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.4.3

Replace all occurrences of $u$ with $x^{2} - 25$ .

$\frac{4}{9} \cdot \frac{2 {(x^{2} - 25)}^{\frac{4}{3}} x - (x^{2} - 75) (\frac{4}{3} {(x^{2} - 25)}^{\frac{4}{3} - 1} \frac{d}{d x} [x^{2} - 25])}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.5

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{4}{9} \cdot \frac{2 {(x^{2} - 25)}^{\frac{4}{3}} x - (x^{2} - 75) (\frac{4}{3} {(x^{2} - 25)}^{\frac{4}{3} - 1 \cdot \frac{3}{3}} \frac{d}{d x} [x^{2} - 25])}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.6

Combine $- 1$ and $\frac{3}{3}$ .

$\frac{4}{9} \cdot \frac{2 {(x^{2} - 25)}^{\frac{4}{3}} x - (x^{2} - 75) (\frac{4}{3} {(x^{2} - 25)}^{\frac{4}{3} + \frac{- 1 \cdot 3}{3}} \frac{d}{d x} [x^{2} - 25])}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.7

Combine the numerators over the common denominator.

$\frac{4}{9} \cdot \frac{2 {(x^{2} - 25)}^{\frac{4}{3}} x - (x^{2} - 75) (\frac{4}{3} {(x^{2} - 25)}^{\frac{4 - 1 \cdot 3}{3}} \frac{d}{d x} [x^{2} - 25])}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.8

Simplify the numerator.

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Step 3.8.1

Multiply $- 1$ by $3$ .

$\frac{4}{9} \cdot \frac{2 {(x^{2} - 25)}^{\frac{4}{3}} x - (x^{2} - 75) (\frac{4}{3} {(x^{2} - 25)}^{\frac{4 - 3}{3}} \frac{d}{d x} [x^{2} - 25])}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.8.2

Subtract $3$ from $4$ .

$\frac{4}{9} \cdot \frac{2 {(x^{2} - 25)}^{\frac{4}{3}} x - (x^{2} - 75) (\frac{4}{3} {(x^{2} - 25)}^{\frac{1}{3}} \frac{d}{d x} [x^{2} - 25])}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.9

Combine $\frac{4}{3}$ and ${(x^{2} - 25)}^{\frac{1}{3}}$ .

$\frac{4}{9} \cdot \frac{2 {(x^{2} - 25)}^{\frac{4}{3}} x - (x^{2} - 75) (\frac{4 {(x^{2} - 25)}^{\frac{1}{3}}}{3} \frac{d}{d x} [x^{2} - 25])}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.10

By the Sum Rule, the derivative of $x^{2} - 25$ with respect to $x$ is $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 25]$ .

$\frac{4}{9} \cdot \frac{2 {(x^{2} - 25)}^{\frac{4}{3}} x - (x^{2} - 75) (\frac{4 {(x^{2} - 25)}^{\frac{1}{3}}}{3} (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 25]))}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.11

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$\frac{4}{9} \cdot \frac{2 {(x^{2} - 25)}^{\frac{4}{3}} x - (x^{2} - 75) (\frac{4 {(x^{2} - 25)}^{\frac{1}{3}}}{3} (2 x + \frac{d}{d x} [- 25]))}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.12

Since $- 25$ is constant with respect to $x$ , the derivative of $- 25$ with respect to $x$ is $0$ .

$\frac{4}{9} \cdot \frac{2 {(x^{2} - 25)}^{\frac{4}{3}} x - (x^{2} - 75) (\frac{4 {(x^{2} - 25)}^{\frac{1}{3}}}{3} (2 x + 0))}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.13

Combine fractions.

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Step 3.13.1

Add $2 x$ and $0$ .

$\frac{4}{9} \cdot \frac{2 {(x^{2} - 25)}^{\frac{4}{3}} x - (x^{2} - 75) (\frac{4 {(x^{2} - 25)}^{\frac{1}{3}}}{3} (2 x))}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.13.2

Combine $2$ and $\frac{4 {(x^{2} - 25)}^{\frac{1}{3}}}{3}$ .

$\frac{4}{9} \cdot \frac{2 {(x^{2} - 25)}^{\frac{4}{3}} x - (x^{2} - 75) (\frac{2 (4 {(x^{2} - 25)}^{\frac{1}{3}})}{3} x)}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.13.3

Multiply $4$ by $2$ .

$\frac{4}{9} \cdot \frac{2 {(x^{2} - 25)}^{\frac{4}{3}} x - (x^{2} - 75) (\frac{8 {(x^{2} - 25)}^{\frac{1}{3}}}{3} x)}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.13.4

Combine $\frac{8 {(x^{2} - 25)}^{\frac{1}{3}}}{3}$ and $x$ .

$\frac{4}{9} \cdot \frac{2 {(x^{2} - 25)}^{\frac{4}{3}} x - (x^{2} - 75) \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x}{3}}{{(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.13.5

Multiply $\frac{4}{9}$ by $\frac{2 {(x^{2} - 25)}^{\frac{4}{3}} x - (x^{2} - 75) \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x}{3}}{{(x^{2} - 25)}^{\frac{8}{3}}}$ .

$\frac{4 (2 {(x^{2} - 25)}^{\frac{4}{3}} x - (x^{2} - 75) \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x}{3})}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14

Simplify.

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Step 3.14.1

Apply the distributive property.

$\frac{4 (2 {(x^{2} - 25)}^{\frac{4}{3}} x + (- x^{2} - - 75) \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x}{3})}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.2

Apply the distributive property.

$\frac{4 (2 {(x^{2} - 25)}^{\frac{4}{3}} x) + 4 ((- x^{2} - - 75) \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x}{3})}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3

Simplify the numerator.

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Step 3.14.3.1

Multiply $2$ by $4$ .

$\frac{8 ({(x^{2} - 25)}^{\frac{4}{3}} x) + 4 ((- x^{2} - - 75) \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x}{3})}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.2

Multiply $- 1$ by $- 75$ .

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 ((- x^{2} + 75) \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x}{3})}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.3

Apply the distributive property.

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 (- x^{2} \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x}{3} + 75 \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x}{3})}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.4

Multiply $- x^{2} \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x}{3}$ .

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Step 3.14.3.4.1

Combine $\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x}{3}$ and $x^{2}$ .

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 (- \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x \cdot x^{2}}{3} + 75 \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x}{3})}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.4.2

Multiply $x$ by $x^{2}$ by adding the exponents.

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Step 3.14.3.4.2.1

Move $x^{2}$ .

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 (- \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} (x^{2} x)}{3} + 75 \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x}{3})}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.4.2.2

Multiply $x^{2}$ by $x$ .

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Step 3.14.3.4.2.2.1

Raise $x$ to the power of $1$ .

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 (- \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} (x^{2} x^{1})}{3} + 75 \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x}{3})}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.4.2.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 (- \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x^{2 + 1}}{3} + 75 \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x}{3})}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.4.2.3

Add $2$ and $1$ .

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 (- \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x^{3}}{3} + 75 \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x}{3})}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.5

Cancel the common factor of $3$ .

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Step 3.14.3.5.1

Factor $3$ out of $75$ .

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 (- \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x^{3}}{3} + 3 (25) \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x}{3})}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.5.2

Cancel the common factor.

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 (- \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x^{3}}{3} + 3 \cdot 25 \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x}{3})}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.5.3

Rewrite the expression.

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 (- \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x^{3}}{3} + 25 (8 {(x^{2} - 25)}^{\frac{1}{3}} x))}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.6

Multiply $8$ by $25$ .

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 (- \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x^{3}}{3} + 200 ({(x^{2} - 25)}^{\frac{1}{3}} x))}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.7

To write $200 {(x^{2} - 25)}^{\frac{1}{3}} x$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 (- \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x^{3}}{3} + 200 {(x^{2} - 25)}^{\frac{1}{3}} x \cdot \frac{3}{3})}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.8

Combine $200 {(x^{2} - 25)}^{\frac{1}{3}} x$ and $\frac{3}{3}$ .

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 (- \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x^{3}}{3} + \frac{200 {(x^{2} - 25)}^{\frac{1}{3}} x \cdot 3}{3})}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.9

Combine the numerators over the common denominator.

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 \frac{- 8 {(x^{2} - 25)}^{\frac{1}{3}} x^{3} + 200 {(x^{2} - 25)}^{\frac{1}{3}} x \cdot 3}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.10

Simplify the numerator.

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Step 3.14.3.10.1

Factor $8 {(x^{2} - 25)}^{\frac{1}{3}} x$ out of $- 8 {(x^{2} - 25)}^{\frac{1}{3}} x^{3} + 200 {(x^{2} - 25)}^{\frac{1}{3}} x \cdot 3$ .

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Step 3.14.3.10.1.1

Reorder the expression.

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Step 3.14.3.10.1.1.1

Move ${(x^{2} - 25)}^{\frac{1}{3}}$ .

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 \frac{- 8 x^{3} {(x^{2} - 25)}^{\frac{1}{3}} + 200 {(x^{2} - 25)}^{\frac{1}{3}} x \cdot 3}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.10.1.1.2

Move ${(x^{2} - 25)}^{\frac{1}{3}}$ .

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 \frac{- 8 x^{3} {(x^{2} - 25)}^{\frac{1}{3}} + 200 x \cdot 3 {(x^{2} - 25)}^{\frac{1}{3}}}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.10.1.1.3

Move $x$ .

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 \frac{- 8 x^{3} {(x^{2} - 25)}^{\frac{1}{3}} + 200 \cdot 3 x {(x^{2} - 25)}^{\frac{1}{3}}}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.10.1.2

Factor $8 {(x^{2} - 25)}^{\frac{1}{3}} x$ out of $- 8 x^{3} {(x^{2} - 25)}^{\frac{1}{3}}$ .

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (- x^{2}) + 200 \cdot 3 x {(x^{2} - 25)}^{\frac{1}{3}}}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.10.1.3

Factor $8 {(x^{2} - 25)}^{\frac{1}{3}} x$ out of $200 \cdot 3 x {(x^{2} - 25)}^{\frac{1}{3}}$ .

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (- x^{2}) + 8 {(x^{2} - 25)}^{\frac{1}{3}} x (25 \cdot 3)}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.10.1.4

Factor $8 {(x^{2} - 25)}^{\frac{1}{3}} x$ out of $8 {(x^{2} - 25)}^{\frac{1}{3}} x (- x^{2}) + 8 {(x^{2} - 25)}^{\frac{1}{3}} x (25 \cdot 3)$ .

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (- x^{2} + 25 \cdot 3)}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.10.2

Multiply $25$ by $3$ .

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + 4 \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (- x^{2} + 75)}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.11

Multiply $4 \frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (- x^{2} + 75)}{3}$ .

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Step 3.14.3.11.1

Combine $4$ and $\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (- x^{2} + 75)}{3}$ .

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + \frac{4 (8 {(x^{2} - 25)}^{\frac{1}{3}} x (- x^{2} + 75))}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.11.2

Multiply $8$ by $4$ .

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x + \frac{32 ({(x^{2} - 25)}^{\frac{1}{3}} x (- x^{2} + 75))}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.12

To write $8 {(x^{2} - 25)}^{\frac{4}{3}} x$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x \cdot \frac{3}{3} + \frac{32 {(x^{2} - 25)}^{\frac{1}{3}} x (- x^{2} + 75)}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.13

Combine $8 {(x^{2} - 25)}^{\frac{4}{3}} x$ and $\frac{3}{3}$ .

$\frac{\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x \cdot 3}{3} + \frac{32 {(x^{2} - 25)}^{\frac{1}{3}} x (- x^{2} + 75)}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.14

Combine the numerators over the common denominator.

$\frac{\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x \cdot 3 + 32 {(x^{2} - 25)}^{\frac{1}{3}} x (- x^{2} + 75)}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.15

Rewrite $\frac{8 {(x^{2} - 25)}^{\frac{4}{3}} x \cdot 3 + 32 {(x^{2} - 25)}^{\frac{1}{3}} x (- x^{2} + 75)}{3}$ in a factored form.

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Step 3.14.3.15.1

Factor $8 {(x^{2} - 25)}^{\frac{1}{3}} x$ out of $8 {(x^{2} - 25)}^{\frac{4}{3}} x \cdot 3 + 32 {(x^{2} - 25)}^{\frac{1}{3}} x (- x^{2} + 75)$ .

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Step 3.14.3.15.1.1

Reorder the expression.

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Step 3.14.3.15.1.1.1

Move ${(x^{2} - 25)}^{\frac{4}{3}}$ .

$\frac{\frac{8 x \cdot 3 {(x^{2} - 25)}^{\frac{4}{3}} + 32 {(x^{2} - 25)}^{\frac{1}{3}} x (- x^{2} + 75)}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.15.1.1.2

Move $x$ .

$\frac{\frac{8 \cdot 3 x {(x^{2} - 25)}^{\frac{4}{3}} + 32 {(x^{2} - 25)}^{\frac{1}{3}} x (- x^{2} + 75)}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.15.1.1.3

Move ${(x^{2} - 25)}^{\frac{1}{3}}$ .

$\frac{\frac{8 \cdot 3 x {(x^{2} - 25)}^{\frac{4}{3}} + 32 x {(x^{2} - 25)}^{\frac{1}{3}} (- x^{2} + 75)}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.15.1.2

Factor $8 {(x^{2} - 25)}^{\frac{1}{3}} x$ out of $8 \cdot 3 x {(x^{2} - 25)}^{\frac{4}{3}}$ .

$\frac{\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (3 {(x^{2} - 25)}^{\frac{3}{3}}) + 32 x {(x^{2} - 25)}^{\frac{1}{3}} (- x^{2} + 75)}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.15.1.3

Factor $8 {(x^{2} - 25)}^{\frac{1}{3}} x$ out of $32 x {(x^{2} - 25)}^{\frac{1}{3}} (- x^{2} + 75)$ .

$\frac{\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (3 {(x^{2} - 25)}^{\frac{3}{3}}) + 8 {(x^{2} - 25)}^{\frac{1}{3}} x (4 (- x^{2} + 75))}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.15.1.4

Factor $8 {(x^{2} - 25)}^{\frac{1}{3}} x$ out of $8 {(x^{2} - 25)}^{\frac{1}{3}} x (3 {(x^{2} - 25)}^{\frac{3}{3}}) + 8 {(x^{2} - 25)}^{\frac{1}{3}} x (4 (- x^{2} + 75))$ .

$\frac{\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (3 {(x^{2} - 25)}^{\frac{3}{3}} + 4 (- x^{2} + 75))}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.15.2

Divide $3$ by $3$ .

$\frac{\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (3 {(x^{2} - 25)}^{1} + 4 (- x^{2} + 75))}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.15.3

Simplify.

$\frac{\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (3 (x^{2} - 25) + 4 (- x^{2} + 75))}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.15.4

Apply the distributive property.

$\frac{\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (3 x^{2} + 3 \cdot - 25 + 4 (- x^{2} + 75))}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.15.5

Multiply $3$ by $- 25$ .

$\frac{\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (3 x^{2} - 75 + 4 (- x^{2} + 75))}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.15.6

Apply the distributive property.

$\frac{\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (3 x^{2} - 75 + 4 (- x^{2}) + 4 \cdot 75)}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.15.7

Multiply $- 1$ by $4$ .

$\frac{\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (3 x^{2} - 75 - 4 x^{2} + 4 \cdot 75)}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.15.8

Multiply $4$ by $75$ .

$\frac{\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (3 x^{2} - 75 - 4 x^{2} + 300)}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.15.9

Subtract $4 x^{2}$ from $3 x^{2}$ .

$\frac{\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (- x^{2} - 75 + 300)}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.15.10

Add $- 75$ and $300$ .

$\frac{\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (- x^{2} + 225)}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.15.11

Rewrite $- x^{2} + 225$ in a factored form.

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Step 3.14.3.15.11.1

Rewrite $225$ as $15^{2}$ .

$\frac{\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (- x^{2} + 15^{2})}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.15.11.2

Reorder $- x^{2}$ and $15^{2}$ .

$\frac{\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (15^{2} - x^{2})}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.3.15.11.3

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 15$ and $b = x$ .

$\frac{\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x ((15 + x) (15 - x))}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

$\frac{\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (15 + x) (15 - x)}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.4

Combine terms.

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Step 3.14.4.1

Rewrite $\frac{\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (15 + x) (15 - x)}{3}}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$ as a product.

$\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (15 + x) (15 - x)}{3} \cdot \frac{1}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.4.2

Multiply $\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (15 + x) (15 - x)}{3}$ by $\frac{1}{9 {(x^{2} - 25)}^{\frac{8}{3}}}$ .

$\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (15 + x) (15 - x)}{3 (9 {(x^{2} - 25)}^{\frac{8}{3}})}$

Step 3.14.4.3

Multiply $9$ by $3$ .

$\frac{8 {(x^{2} - 25)}^{\frac{1}{3}} x (15 + x) (15 - x)}{27 {(x^{2} - 25)}^{\frac{8}{3}}}$

Step 3.14.4.4

Move ${(x^{2} - 25)}^{\frac{1}{3}}$ to the denominator using the negative exponent rule $b^{n} = \frac{1}{b^{- n}}$ .

$\frac{8 x (15 + x) (15 - x)}{27 {(x^{2} - 25)}^{\frac{8}{3}} {(x^{2} - 25)}^{- \frac{1}{3}}}$

Step 3.14.4.5

Multiply ${(x^{2} - 25)}^{\frac{8}{3}}$ by ${(x^{2} - 25)}^{- \frac{1}{3}}$ by adding the exponents.

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Step 3.14.4.5.1

Move ${(x^{2} - 25)}^{- \frac{1}{3}}$ .

$\frac{8 x (15 + x) (15 - x)}{27 ({(x^{2} - 25)}^{- \frac{1}{3}} {(x^{2} - 25)}^{\frac{8}{3}})}$

Step 3.14.4.5.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{8 x (15 + x) (15 - x)}{27 {(x^{2} - 25)}^{- \frac{1}{3} + \frac{8}{3}}}$

Step 3.14.4.5.3

Combine the numerators over the common denominator.

$\frac{8 x (15 + x) (15 - x)}{27 {(x^{2} - 25)}^{\frac{- 1 + 8}{3}}}$

Step 3.14.4.5.4

Add $- 1$ and $8$ .

$f''' (x) = \frac{8 x (15 + x) (15 - x)}{27 {(x^{2} - 25)}^{\frac{7}{3}}}$