Calculus Examples

$\frac{1000 e^{0.12 t}}{19 + e^{0.12 t}}$

Step 1

Since $\frac{1000 e^{0.12 t}}{19 + e^{0.12 t}}$ is constant with respect to $e$ , the derivative of $\frac{1000 e^{0.12 t}}{19 + e^{0.12 t}}$ with respect to $e$ is $0$ .

$f' (e) = 0$

Step 2

Since $0$ is constant with respect to $e$ , the derivative of $0$ with respect to $e$ is $0$ .

$f'' (e) = 0$