Calculus Examples

$f (x) = 564 + t (36 t^{0.6} - 107)$

Step 1

By the Sum Rule, the derivative of $564 + t (36 t^{0.6} - 107)$ with respect to $t$ is $\frac{d}{d t} [564] + \frac{d}{d t} [t (36 t^{0.6} - 107)]$ .

$\frac{d}{d t} [564] + \frac{d}{d t} [t (36 t^{0.6} - 107)]$

Step 2

Since $564$ is constant with respect to $t$ , the derivative of $564$ with respect to $t$ is $0$ .

$0 + \frac{d}{d t} [t (36 t^{0.6} - 107)]$

Step 3

Add $0$ and $\frac{d}{d t} [t (36 t^{0.6} - 107)]$ .

$\frac{d}{d t} [t (36 t^{0.6} - 107)]$