Calculus Examples

$f (x) = - 4 x^{\frac{1}{2} + 2 x^{5}}$

Step 1

Since $- 4$ is constant with respect to $x$ , the derivative of $- 4 x^{\frac{1}{2} + 2 x^{5}}$ with respect to $x$ is $- 4 \frac{d}{d x} [x^{\frac{1}{2} + 2 x^{5}}]$ .

$- 4 \frac{d}{d x} [x^{\frac{1}{2} + 2 x^{5}}]$

Step 2

Use the properties of logarithms to simplify the differentiation.

Tap for more steps...

Step 2.1

Rewrite $x^{\frac{1}{2} + 2 x^{5}}$ as $e^{\ln (x^{\frac{1}{2} + 2 x^{5}})}$ .

$- 4 \frac{d}{d x} [e^{\ln (x^{\frac{1}{2} + 2 x^{5}})}]$

Step 2.2

Expand $\ln (x^{\frac{1}{2} + 2 x^{5}})$ by moving $\frac{1}{2} + 2 x^{5}$ outside the logarithm.

$- 4 \frac{d}{d x} [e^{(\frac{1}{2} + 2 x^{5}) \ln (x)}]$

Step 3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = e^{x}$ and $g (x) = (\frac{1}{2} + 2 x^{5}) \ln (x)$ .

Tap for more steps...

Step 3.1

To apply the Chain Rule, set $u$ as $(\frac{1}{2} + 2 x^{5}) \ln (x)$ .

$- 4 (\frac{d}{d u} [e^{u}] \frac{d}{d x} [(\frac{1}{2} + 2 x^{5}) \ln (x)])$

Step 3.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u} [a^{u}]$ is $a^{u} \ln (a)$ where $a$ = $e$ .

$- 4 (e^{u} \frac{d}{d x} [(\frac{1}{2} + 2 x^{5}) \ln (x)])$

Step 3.3

Replace all occurrences of $u$ with $(\frac{1}{2} + 2 x^{5}) \ln (x)$ .

$- 4 (e^{(\frac{1}{2} + 2 x^{5}) \ln (x)} \frac{d}{d x} [(\frac{1}{2} + 2 x^{5}) \ln (x)])$

Step 4

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = \frac{1}{2} + 2 x^{5}$ and $g (x) = \ln (x)$ .

$- 4 e^{(\frac{1}{2} + 2 x^{5}) \ln (x)} ((\frac{1}{2} + 2 x^{5}) \frac{d}{d x} [\ln (x)] + \ln (x) \frac{d}{d x} [\frac{1}{2} + 2 x^{5}])$

Step 5

The derivative of $\ln (x)$ with respect to $x$ is $\frac{1}{x}$ .

$- 4 e^{(\frac{1}{2} + 2 x^{5}) \ln (x)} ((\frac{1}{2} + 2 x^{5}) \frac{1}{x} + \ln (x) \frac{d}{d x} [\frac{1}{2} + 2 x^{5}])$

Step 6

Differentiate.

Tap for more steps...

Step 6.1

By the Sum Rule, the derivative of $\frac{1}{2} + 2 x^{5}$ with respect to $x$ is $\frac{d}{d x} [\frac{1}{2}] + \frac{d}{d x} [2 x^{5}]$ .

$- 4 e^{(\frac{1}{2} + 2 x^{5}) \ln (x)} ((\frac{1}{2} + 2 x^{5}) \frac{1}{x} + \ln (x) (\frac{d}{d x} [\frac{1}{2}] + \frac{d}{d x} [2 x^{5}]))$

Step 6.2

Since $\frac{1}{2}$ is constant with respect to $x$ , the derivative of $\frac{1}{2}$ with respect to $x$ is $0$ .

$- 4 e^{(\frac{1}{2} + 2 x^{5}) \ln (x)} ((\frac{1}{2} + 2 x^{5}) \frac{1}{x} + \ln (x) (0 + \frac{d}{d x} [2 x^{5}]))$

Step 6.3

Add $0$ and $\frac{d}{d x} [2 x^{5}]$ .

$- 4 e^{(\frac{1}{2} + 2 x^{5}) \ln (x)} ((\frac{1}{2} + 2 x^{5}) \frac{1}{x} + \ln (x) \frac{d}{d x} [2 x^{5}])$

Step 6.4

Since $2$ is constant with respect to $x$ , the derivative of $2 x^{5}$ with respect to $x$ is $2 \frac{d}{d x} [x^{5}]$ .

$- 4 e^{(\frac{1}{2} + 2 x^{5}) \ln (x)} ((\frac{1}{2} + 2 x^{5}) \frac{1}{x} + \ln (x) (2 \frac{d}{d x} [x^{5}]))$

Step 6.5

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 5$ .

$- 4 e^{(\frac{1}{2} + 2 x^{5}) \ln (x)} ((\frac{1}{2} + 2 x^{5}) \frac{1}{x} + \ln (x) (2 (5 x^{4})))$

Step 6.6

Multiply $5$ by $2$ .

$- 4 e^{(\frac{1}{2} + 2 x^{5}) \ln (x)} ((\frac{1}{2} + 2 x^{5}) \frac{1}{x} + \ln (x) (10 x^{4}))$

Step 7

Simplify.

Tap for more steps...

Step 7.1

Apply the distributive property.

$- 4 e^{\frac{1}{2} \ln (x) + 2 x^{5} \ln (x)} ((\frac{1}{2} + 2 x^{5}) \frac{1}{x} + \ln (x) (10 x^{4}))$

Step 7.2

Apply the distributive property.

$- 4 e^{\frac{1}{2} \ln (x) + 2 x^{5} \ln (x)} (\frac{1}{2} \cdot \frac{1}{x} + 2 x^{5} \frac{1}{x} + \ln (x) (10 x^{4}))$

Step 7.3

Combine terms.

Tap for more steps...

Step 7.3.1

Combine $\frac{1}{2}$ and $\ln (x)$ .

$- 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\frac{1}{2} \cdot \frac{1}{x} + 2 x^{5} \frac{1}{x} + \ln (x) (10 x^{4}))$

Step 7.3.2

Multiply $\frac{1}{2}$ by $\frac{1}{x}$ .

$- 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\frac{1}{2 x} + 2 x^{5} \frac{1}{x} + \ln (x) (10 x^{4}))$

Step 7.3.3

Combine $2$ and $\frac{1}{x}$ .

$- 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\frac{1}{2 x} + x^{5} \frac{2}{x} + \ln (x) (10 x^{4}))$

Step 7.3.4

Combine $x^{5}$ and $\frac{2}{x}$ .

$- 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\frac{1}{2 x} + \frac{x^{5} \cdot 2}{x} + \ln (x) (10 x^{4}))$

Step 7.3.5

Move $2$ to the left of $x^{5}$ .

$- 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\frac{1}{2 x} + \frac{2 \cdot x^{5}}{x} + \ln (x) (10 x^{4}))$

Step 7.3.6

Cancel the common factor of $x^{5}$ and $x$ .

Tap for more steps...

Step 7.3.6.1

Factor $x$ out of $2 x^{5}$ .

$- 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\frac{1}{2 x} + \frac{x (2 x^{4})}{x} + \ln (x) (10 x^{4}))$

Step 7.3.6.2

Cancel the common factors.

Tap for more steps...

Step 7.3.6.2.1

Raise $x$ to the power of $1$ .

$- 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\frac{1}{2 x} + \frac{x (2 x^{4})}{x^{1}} + \ln (x) (10 x^{4}))$

Step 7.3.6.2.2

Factor $x$ out of $x^{1}$ .

$- 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\frac{1}{2 x} + \frac{x (2 x^{4})}{x \cdot 1} + \ln (x) (10 x^{4}))$

Step 7.3.6.2.3

Cancel the common factor.

$- 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\frac{1}{2 x} + \frac{x (2 x^{4})}{x \cdot 1} + \ln (x) (10 x^{4}))$

Step 7.3.6.2.4

Rewrite the expression.

$- 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\frac{1}{2 x} + \frac{2 x^{4}}{1} + \ln (x) (10 x^{4}))$

Step 7.3.6.2.5

Divide $2 x^{4}$ by $1$ .

$- 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\frac{1}{2 x} + 2 x^{4} + \ln (x) (10 x^{4}))$

Step 7.4

Rewrite using the commutative property of multiplication.

$- 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\frac{1}{2 x} + 2 x^{4} + 10 \ln (x) x^{4})$

Step 7.5

Apply the distributive property.

$- 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} \frac{1}{2 x} - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (2 x^{4}) - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (10 \ln (x) x^{4})$

Step 7.6

Simplify.

Tap for more steps...

Step 7.6.1

Cancel the common factor of $2$ .

Tap for more steps...

Step 7.6.1.1

Factor $2$ out of $- 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)}$ .

$2 (- 2 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)}) \frac{1}{2 x} - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (2 x^{4}) - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (10 \ln (x) x^{4})$

Step 7.6.1.2

Factor $2$ out of $2 x$ .

$2 (- 2 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)}) \frac{1}{2 (x)} - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (2 x^{4}) - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (10 \ln (x) x^{4})$

Step 7.6.1.3

Cancel the common factor.

$2 (- 2 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)}) \frac{1}{2 x} - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (2 x^{4}) - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (10 \ln (x) x^{4})$

Step 7.6.1.4

Rewrite the expression.

$- 2 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} \frac{1}{x} - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (2 x^{4}) - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (10 \ln (x) x^{4})$

Step 7.6.2

Combine $\frac{1}{x}$ and $- 2$ .

$\frac{- 2}{x} e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (2 x^{4}) - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (10 \ln (x) x^{4})$

Step 7.6.3

Combine $\frac{- 2}{x}$ and $e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)}$ .

$\frac{- 2 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)}}{x} - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (2 x^{4}) - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (10 \ln (x) x^{4})$

Step 7.6.4

Rewrite using the commutative property of multiplication.

$\frac{- 2 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)}}{x} - 4 \cdot 2 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4} - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (10 \ln (x) x^{4})$

Step 7.6.5

Multiply $10$ by $- 4$ .

$\frac{- 2 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)}}{x} - 4 \cdot 2 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.7

Simplify each term.

Tap for more steps...

Step 7.7.1

Simplify the numerator.

Tap for more steps...

Step 7.7.1.1

To write $2 x^{5} \ln (x)$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{- 2 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x) \cdot \frac{2}{2}}}{x} - 4 \cdot 2 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.7.1.2

Combine $2 x^{5} \ln (x)$ and $\frac{2}{2}$ .

$\frac{- 2 e^{\frac{\ln (x)}{2} + \frac{2 x^{5} \ln (x) \cdot 2}{2}}}{x} - 4 \cdot 2 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.7.1.3

Combine the numerators over the common denominator.

$\frac{- 2 e^{\frac{\ln (x) + 2 x^{5} \ln (x) \cdot 2}{2}}}{x} - 4 \cdot 2 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.7.1.4

Simplify the numerator.

Tap for more steps...

Step 7.7.1.4.1

Factor $\ln (x)$ out of $\ln (x) + 2 x^{5} \ln (x) \cdot 2$ .

Tap for more steps...

Step 7.7.1.4.1.1

Multiply by $1$ .

$\frac{- 2 e^{\frac{\ln (x) \cdot 1 + 2 x^{5} \ln (x) \cdot 2}{2}}}{x} - 4 \cdot 2 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.7.1.4.1.2

Factor $\ln (x)$ out of $2 x^{5} \ln (x) \cdot 2$ .

$\frac{- 2 e^{\frac{\ln (x) \cdot 1 + \ln (x) (2 x^{5} \cdot 2)}{2}}}{x} - 4 \cdot 2 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.7.1.4.1.3

Factor $\ln (x)$ out of $\ln (x) \cdot 1 + \ln (x) (2 x^{5} \cdot 2)$ .

$\frac{- 2 e^{\frac{\ln (x) (1 + 2 x^{5} \cdot 2)}{2}}}{x} - 4 \cdot 2 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.7.1.4.2

Multiply $2$ by $2$ .

$\frac{- 2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}}{x} - 4 \cdot 2 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.7.2

Move the negative in front of the fraction.

$- \frac{2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}}{x} - 4 \cdot 2 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.7.3

Multiply $- 4$ by $2$ .

$- \frac{2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}}{x} - 8 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.8

To write $- 8 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4}$ as a fraction with a common denominator, multiply by $\frac{x}{x}$ .

$- \frac{2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}}{x} - 8 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4} \cdot \frac{x}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.9

Combine $- 8 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4}$ and $\frac{x}{x}$ .

$- \frac{2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}}{x} + \frac{- 8 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4} x}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.10

Combine the numerators over the common denominator.

$\frac{- 2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 8 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4} x}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11

Simplify the numerator.

Tap for more steps...

Step 7.11.1

Factor $2$ out of $- 2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 8 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4} x$ .

Tap for more steps...

Step 7.11.1.1

Factor $2$ out of $- 2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}) - 8 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4} x}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.1.2

Factor $2$ out of $- 8 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4} x$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}) + 2 (- 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4} x)}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.1.3

Factor $2$ out of $2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}) + 2 (- 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4} x)$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{4} x)}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.2

Multiply $x^{4}$ by $x$ by adding the exponents.

Tap for more steps...

Step 7.11.2.1

Move $x$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (x \cdot x^{4}))}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.2.2

Multiply $x$ by $x^{4}$ .

Tap for more steps...

Step 7.11.2.2.1

Raise $x$ to the power of $1$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (x^{1} x^{4}))}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.2.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{1 + 4})}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.2.3

Add $1$ and $4$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} x^{5})}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.3

Simplify each term.

Tap for more steps...

Step 7.11.3.1

To write $2 x^{5} \ln (x)$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x) \cdot \frac{2}{2}} x^{5})}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.3.2

Combine $2 x^{5} \ln (x)$ and $\frac{2}{2}$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x)}{2} + \frac{2 x^{5} \ln (x) \cdot 2}{2}} x^{5})}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.3.3

Combine the numerators over the common denominator.

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x) + 2 x^{5} \ln (x) \cdot 2}{2}} x^{5})}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.3.4

Simplify the numerator.

Tap for more steps...

Step 7.11.3.4.1

Factor $\ln (x)$ out of $\ln (x) + 2 x^{5} \ln (x) \cdot 2$ .

Tap for more steps...

Step 7.11.3.4.1.1

Multiply by $1$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x) \cdot 1 + 2 x^{5} \ln (x) \cdot 2}{2}} x^{5})}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.3.4.1.2

Factor $\ln (x)$ out of $2 x^{5} \ln (x) \cdot 2$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x) \cdot 1 + \ln (x) (2 x^{5} \cdot 2)}{2}} x^{5})}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.3.4.1.3

Factor $\ln (x)$ out of $\ln (x) \cdot 1 + \ln (x) (2 x^{5} \cdot 2)$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x) (1 + 2 x^{5} \cdot 2)}{2}} x^{5})}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.3.4.2

Multiply $2$ by $2$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} x^{5})}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.4

Factor $e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}$ out of $- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} x^{5}$ .

Tap for more steps...

Step 7.11.4.1

Reorder the expression.

Tap for more steps...

Step 7.11.4.1.1

Reorder $1$ and $4 x^{5}$ .

$\frac{2 (- e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} - 4 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} x^{5})}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.4.1.2

Reorder $1$ and $4 x^{5}$ .

$\frac{2 (- e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} - 4 e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} x^{5})}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.4.1.3

Move $e^{\frac{\ln (x) (4 x^{5} + 1)}{2}}$ .

$\frac{2 (- e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} - 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1)}{2}})}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.4.2

Factor $e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}$ out of $- e^{\frac{\ln (x) (4 x^{5} + 1)}{2}}$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}}) - 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1)}{2}})}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.4.3

Factor $e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}$ out of $- 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1)}{2}}$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}}) + e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}}))}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.4.4

Factor $e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}$ out of $e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}}) + e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}})$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}} - 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}}))}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.5

Factor $e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}}$ out of $- e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}} - 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}}$ .

Tap for more steps...

Step 7.11.5.1

Reorder the expression.

Tap for more steps...

Step 7.11.5.1.1

Reorder $1$ and $4 x^{5}$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} - 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}}))}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.5.1.2

Reorder $1$ and $4 x^{5}$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} - 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}}))}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.5.2

Factor $e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}}$ out of $- e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}}$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} \cdot - 1 - 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}}))}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.5.3

Factor $e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}}$ out of $- 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}}$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} \cdot - 1 + e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} (- 4 x^{5})))}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.5.4

Factor $e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}}$ out of $e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} \cdot - 1 + e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} (- 4 x^{5})$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} (- 1 - 4 x^{5})))}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} (- 1 - 4 x^{5}))}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.6

Multiply $e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}$ by $e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}}$ by adding the exponents.

Tap for more steps...

Step 7.11.6.1

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2} + \frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} (- 1 - 4 x^{5}))}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.6.2

Subtract $\ln (x) (4 x^{5} + 1)$ from $\ln (x) (4 x^{5} + 1)$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2} + \frac{0}{2}} (- 1 - 4 x^{5}))}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.6.3

Combine the opposite terms in $\frac{\ln (x) (1 + 4 x^{5})}{2} + \frac{0}{2}$ .

Tap for more steps...

Step 7.11.6.3.1

Divide $0$ by $2$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2} + 0} (- 1 - 4 x^{5}))}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.11.6.3.2

Add $\frac{\ln (x) (1 + 4 x^{5})}{2}$ and $0$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 1 - 4 x^{5}))}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

$\frac{2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 1 - 4 x^{5})}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$

Step 7.12

To write $- 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$ as a fraction with a common denominator, multiply by $\frac{x}{x}$ .

$\frac{2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 1 - 4 x^{5})}{x} - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4}) \cdot \frac{x}{x}$

Step 7.13

Combine $- 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4})$ and $\frac{x}{x}$ .

$\frac{2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 1 - 4 x^{5})}{x} + \frac{- 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4}) x}{x}$

Step 7.14

Combine the numerators over the common denominator.

$\frac{2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 1 - 4 x^{5}) - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4}) x}{x}$

Step 7.15

Simplify the numerator.

Tap for more steps...

Step 7.15.1

Factor $2$ out of $2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 1 - 4 x^{5}) - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4}) x$ .

Tap for more steps...

Step 7.15.1.1

Factor $2$ out of $2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 1 - 4 x^{5})$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 1 - 4 x^{5})) - 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4}) x}{x}$

Step 7.15.1.2

Factor $2$ out of $- 40 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4}) x$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 1 - 4 x^{5})) + 2 (- 20 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4}) x)}{x}$

Step 7.15.1.3

Factor $2$ out of $2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 1 - 4 x^{5})) + 2 (- 20 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4}) x)$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 1 - 4 x^{5}) - 20 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4}) x)}{x}$

Step 7.15.2

Apply the distributive property.

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} \cdot - 1 + e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 4 x^{5}) - 20 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4}) x)}{x}$

Step 7.15.3

Move $- 1$ to the left of $e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}$ .

$\frac{2 (- 1 \cdot e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} + e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 4 x^{5}) - 20 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4}) x)}{x}$

Step 7.15.4

Rewrite using the commutative property of multiplication.

$\frac{2 (- 1 \cdot e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} x^{5} - 20 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4}) x)}{x}$

Step 7.15.5

Rewrite $- 1 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}$ as $- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} x^{5} - 20 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{4}) x)}{x}$

Step 7.15.6

Multiply $x^{4}$ by $x$ by adding the exponents.

Tap for more steps...

Step 7.15.6.1

Move $x$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} x^{5} - 20 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) (x \cdot x^{4})))}{x}$

Step 7.15.6.2

Multiply $x$ by $x^{4}$ .

Tap for more steps...

Step 7.15.6.2.1

Raise $x$ to the power of $1$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} x^{5} - 20 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) (x^{1} x^{4})))}{x}$

Step 7.15.6.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} x^{5} - 20 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{1 + 4}))}{x}$

Step 7.15.6.3

Add $1$ and $4$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} x^{5} - 20 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x)} (\ln (x) x^{5}))}{x}$

Step 7.15.7

Simplify each term.

Tap for more steps...

Step 7.15.7.1

To write $2 x^{5} \ln (x)$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} x^{5} - 20 e^{\frac{\ln (x)}{2} + 2 x^{5} \ln (x) \cdot \frac{2}{2}} (\ln (x) x^{5}))}{x}$

Step 7.15.7.2

Combine $2 x^{5} \ln (x)$ and $\frac{2}{2}$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} x^{5} - 20 e^{\frac{\ln (x)}{2} + \frac{2 x^{5} \ln (x) \cdot 2}{2}} (\ln (x) x^{5}))}{x}$

Step 7.15.7.3

Combine the numerators over the common denominator.

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} x^{5} - 20 e^{\frac{\ln (x) + 2 x^{5} \ln (x) \cdot 2}{2}} (\ln (x) x^{5}))}{x}$

Step 7.15.7.4

Simplify the numerator.

Tap for more steps...

Step 7.15.7.4.1

Factor $\ln (x)$ out of $\ln (x) + 2 x^{5} \ln (x) \cdot 2$ .

Tap for more steps...

Step 7.15.7.4.1.1

Multiply by $1$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} x^{5} - 20 e^{\frac{\ln (x) \cdot 1 + 2 x^{5} \ln (x) \cdot 2}{2}} (\ln (x) x^{5}))}{x}$

Step 7.15.7.4.1.2

Factor $\ln (x)$ out of $2 x^{5} \ln (x) \cdot 2$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} x^{5} - 20 e^{\frac{\ln (x) \cdot 1 + \ln (x) (2 x^{5} \cdot 2)}{2}} (\ln (x) x^{5}))}{x}$

Step 7.15.7.4.1.3

Factor $\ln (x)$ out of $\ln (x) \cdot 1 + \ln (x) (2 x^{5} \cdot 2)$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} x^{5} - 20 e^{\frac{\ln (x) (1 + 2 x^{5} \cdot 2)}{2}} (\ln (x) x^{5}))}{x}$

Step 7.15.7.4.2

Multiply $2$ by $2$ .

$\frac{2 (- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} x^{5} - 20 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (\ln (x) x^{5}))}{x}$

Step 7.15.8

Factor $e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}$ out of $- e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} - 4 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} x^{5} - 20 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (\ln (x) x^{5})$ .

Tap for more steps...

Step 7.15.8.1

Reorder the expression.

Tap for more steps...

Step 7.15.8.1.1

Reorder $1$ and $4 x^{5}$ .

$\frac{2 (- e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} - 4 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} x^{5} - 20 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (\ln (x) x^{5}))}{x}$

Step 7.15.8.1.2

Reorder $1$ and $4 x^{5}$ .

$\frac{2 (- e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} - 4 e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} x^{5} - 20 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (\ln (x) x^{5}))}{x}$

Step 7.15.8.1.3

Move $e^{\frac{\ln (x) (4 x^{5} + 1)}{2}}$ .

$\frac{2 (- e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} - 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} - 20 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (\ln (x) x^{5}))}{x}$

Step 7.15.8.1.4

Reorder $1$ and $4 x^{5}$ .

$\frac{2 (- e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} - 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} - 20 e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} (\ln (x) x^{5}))}{x}$

Step 7.15.8.1.5

Move $\ln (x)$ .

$\frac{2 (- e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} - 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} - 20 e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} x^{5} \ln (x))}{x}$

Step 7.15.8.1.6

Move $e^{\frac{\ln (x) (4 x^{5} + 1)}{2}}$ .

$\frac{2 (- e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} - 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} - 20 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} \ln (x))}{x}$

Step 7.15.8.2

Factor $e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}$ out of $- e^{\frac{\ln (x) (4 x^{5} + 1)}{2}}$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}}) - 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} - 20 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} \ln (x))}{x}$

Step 7.15.8.3

Factor $e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}$ out of $- 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1)}{2}}$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}}) + e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}}) - 20 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} \ln (x))}{x}$

Step 7.15.8.4

Factor $e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}$ out of $- 20 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1)}{2}} \ln (x)$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}}) + e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}}) + e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 20 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}} \ln (x)))}{x}$

Step 7.15.8.5

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}} - 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}}) + e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 20 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}} \ln (x)))}{x}$

Step 7.15.8.6

Factor $e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}$ out of $e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}} - 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}}) + e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 20 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}} \ln (x))$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}} - 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}} - 20 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}} \ln (x)))}{x}$

Step 7.15.9

Tap for more steps...

Step 7.15.9.1

Reorder the expression.

Tap for more steps...

Step 7.15.9.1.1

Reorder $1$ and $4 x^{5}$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} - 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}} - 20 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}} \ln (x)))}{x}$

Step 7.15.9.1.2

Reorder $1$ and $4 x^{5}$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} - 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} - 20 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}} \ln (x)))}{x}$

Step 7.15.9.1.3

Reorder $1$ and $4 x^{5}$ .

Step 7.15.9.2

Factor $e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}}$ out of $- e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}}$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} \cdot - 1 - 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} - 20 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} \ln (x)))}{x}$

Step 7.15.9.3

Factor $e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}}$ out of $- 4 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}}$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} \cdot - 1 + e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} (- 4 x^{5}) - 20 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} \ln (x)))}{x}$

Step 7.15.9.4

Factor $e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (1 + 4 x^{5})}{2}}$ out of $- 20 x^{5} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} \ln (x)$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} \cdot - 1 + e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} (- 4 x^{5}) + e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} (- 20 x^{5} \ln (x))))}{x}$

Step 7.15.9.5

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} \cdot (- 1 - 4 x^{5}) + e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} (- 20 x^{5} \ln (x))))}{x}$

Step 7.15.9.6

Factor $e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}}$ out of $e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} \cdot (- 1 - 4 x^{5}) + e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} (- 20 x^{5} \ln (x))$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} (- 1 - 4 x^{5} - 20 x^{5} \ln (x))))}{x}$

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} (- 1 - 4 x^{5} - 20 x^{5} \ln (x)))}{x}$

Step 7.15.10

Multiply $e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}$ by $e^{\frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}}$ by adding the exponents.

Tap for more steps...

Step 7.15.10.1

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2} + \frac{\ln (x) (4 x^{5} + 1) - \ln (x) (4 x^{5} + 1)}{2}} (- 1 - 4 x^{5} - 20 x^{5} \ln (x)))}{x}$

Step 7.15.10.2

Subtract $\ln (x) (4 x^{5} + 1)$ from $\ln (x) (4 x^{5} + 1)$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2} + \frac{0}{2}} (- 1 - 4 x^{5} - 20 x^{5} \ln (x)))}{x}$

Step 7.15.10.3

Combine the opposite terms in $\frac{\ln (x) (1 + 4 x^{5})}{2} + \frac{0}{2}$ .

Tap for more steps...

Step 7.15.10.3.1

Divide $0$ by $2$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2} + 0} (- 1 - 4 x^{5} - 20 x^{5} \ln (x)))}{x}$

Step 7.15.10.3.2

Add $\frac{\ln (x) (1 + 4 x^{5})}{2}$ and $0$ .

$\frac{2 (e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 1 - 4 x^{5} - 20 x^{5} \ln (x)))}{x}$

$\frac{2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 1 - 4 x^{5} - 20 x^{5} \ln (x))}{x}$

Step 7.16

Rewrite $- 1$ as $- 1 (1)$ .

$\frac{2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 1 (1) - 4 x^{5} - 20 x^{5} \ln (x))}{x}$

Step 7.17

Factor $- 1$ out of $- 4 x^{5}$ .

$\frac{2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 1 (1) - (4 x^{5}) - 20 x^{5} \ln (x))}{x}$

Step 7.18

Factor $- 1$ out of $- 1 (1) - (4 x^{5})$ .

$\frac{2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 1 (1 + 4 x^{5}) - 20 x^{5} \ln (x))}{x}$

Step 7.19

Factor $- 1$ out of $- 20 x^{5} \ln (x)$ .

$\frac{2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 1 (1 + 4 x^{5}) - (20 x^{5} \ln (x)))}{x}$

Step 7.20

Factor $- 1$ out of $- 1 (1 + 4 x^{5}) - (20 x^{5} \ln (x))$ .

$\frac{2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (- 1 (1 + 4 x^{5} + 20 x^{5} \ln (x)))}{x}$

Step 7.21

Move the negative in front of the fraction.

$- \frac{(2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}) (1 + 4 x^{5} + 20 x^{5} \ln (x))}{x}$

Step 7.22

Reorder factors in $- \frac{(2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}}) (1 + 4 x^{5} + 20 x^{5} \ln (x))}{x}$ .

$- \frac{2 e^{\frac{\ln (x) (1 + 4 x^{5})}{2}} (1 + 4 x^{5} + 20 x^{5} \ln (x))}{x}$