Calculus Examples

$f (x) = 4 arccsc (\tan (e^{x}))$

Step 1

Since $4$ is constant with respect to $x$ , the derivative of $4 arccsc (\tan (e^{x}))$ with respect to $x$ is $4 \frac{d}{d x} [arccsc (\tan (e^{x}))]$ .

$4 \frac{d}{d x} [arccsc (\tan (e^{x}))]$

Step 2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = arccsc (x)$ and $g (x) = \tan (e^{x})$ .

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Step 2.1

To apply the Chain Rule, set $u_{1}$ as $\tan (e^{x})$ .

$4 (\frac{d}{d u_{1}} [arccsc (u_{1})] \frac{d}{d x} [\tan (e^{x})])$

Step 2.2

The derivative of $arccsc (u_{1})$ with respect to $u_{1}$ is $- \frac{1}{u_{1} \sqrt{{u_{1}}^{2} - 1}}$ .

$4 (- \frac{1}{u_{1} \sqrt{{u_{1}}^{2} - 1}} \frac{d}{d x} [\tan (e^{x})])$

Step 2.3

Replace all occurrences of $u_{1}$ with $\tan (e^{x})$ .

$4 (- \frac{1}{\tan (e^{x}) \sqrt{\tan^{2} (e^{x}) - 1}} \frac{d}{d x} [\tan (e^{x})])$

Step 3

Combine fractions.

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Step 3.1

Multiply $- 1$ by $4$ .

$- 4 (\frac{1}{\tan (e^{x}) \sqrt{\tan^{2} (e^{x}) - 1}} \frac{d}{d x} [\tan (e^{x})])$

Step 3.2

Combine $\frac{1}{\tan (e^{x}) \sqrt{\tan^{2} (e^{x}) - 1}}$ and $- 4$ .

$\frac{- 4}{\tan (e^{x}) \sqrt{\tan^{2} (e^{x}) - 1}} \frac{d}{d x} [\tan (e^{x})]$

Step 3.3

Move the negative in front of the fraction.

$- \frac{4}{\tan (e^{x}) \sqrt{\tan^{2} (e^{x}) - 1}} \frac{d}{d x} [\tan (e^{x})]$

Step 4

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = \tan (x)$ and $g (x) = e^{x}$ .

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Step 4.1

To apply the Chain Rule, set $u_{2}$ as $e^{x}$ .

$- \frac{4}{\tan (e^{x}) \sqrt{\tan^{2} (e^{x}) - 1}} (\frac{d}{d u_{2}} [\tan (u_{2})] \frac{d}{d x} [e^{x}])$

Step 4.2

The derivative of $\tan (u_{2})$ with respect to $u_{2}$ is $\sec^{2} (u_{2})$ .

$- \frac{4}{\tan (e^{x}) \sqrt{\tan^{2} (e^{x}) - 1}} (\sec^{2} (u_{2}) \frac{d}{d x} [e^{x}])$

Step 4.3

Replace all occurrences of $u_{2}$ with $e^{x}$ .

$- \frac{4}{\tan (e^{x}) \sqrt{\tan^{2} (e^{x}) - 1}} (\sec^{2} (e^{x}) \frac{d}{d x} [e^{x}])$

Step 5

Combine fractions.

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Step 5.1

Combine $\sec^{2} (e^{x})$ and $\frac{4}{\tan (e^{x}) \sqrt{\tan^{2} (e^{x}) - 1}}$ .

$- \frac{\sec^{2} (e^{x}) \cdot 4}{\tan (e^{x}) \sqrt{\tan^{2} (e^{x}) - 1}} \frac{d}{d x} [e^{x}]$

Step 5.2

Move $4$ to the left of $\sec^{2} (e^{x})$ .

$- \frac{4 \cdot \sec^{2} (e^{x})}{\tan (e^{x}) \sqrt{\tan^{2} (e^{x}) - 1}} \frac{d}{d x} [e^{x}]$

Step 6

Differentiate using the Exponential Rule which states that $\frac{d}{d x} [a^{x}]$ is $a^{x} \ln (a)$ where $a$ = $e$ .

$- \frac{4 \sec^{2} (e^{x})}{\tan (e^{x}) \sqrt{\tan^{2} (e^{x}) - 1}} e^{x}$

Step 7

Combine fractions.

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Step 7.1

Combine $e^{x}$ and $\frac{4 \sec^{2} (e^{x})}{\tan (e^{x}) \sqrt{\tan^{2} (e^{x}) - 1}}$ .

$- \frac{e^{x} (4 \sec^{2} (e^{x}))}{\tan (e^{x}) \sqrt{\tan^{2} (e^{x}) - 1}}$

Step 7.2

Rewrite using the commutative property of multiplication.

$- \frac{4 e^{x} \sec^{2} (e^{x})}{\tan (e^{x}) \sqrt{\tan^{2} (e^{x}) - 1}}$