Calculus Examples

$p (t) = 59.2 {(43)}^{0.6} - 104$

Step 1

Differentiate using the Sum Rule.

Tap for more steps...

Step 1.1

Raise $43$ to the power of $0.6$ .

$\frac{d}{d x} [59.2 \cdot 9.55170879 - 104]$

Step 1.2

By the Sum Rule, the derivative of $59.2 \cdot 9.55170879 - 104$ with respect to $x$ is $\frac{d}{d x} [59.2 \cdot 9.55170879] + \frac{d}{d x} [- 104]$ .

$\frac{d}{d x} [59.2 \cdot 9.55170879] + \frac{d}{d x} [- 104]$

Step 2

Evaluate $\frac{d}{d x} [59.2 \cdot 9.55170879]$ .

Tap for more steps...

Step 2.1

Multiply $59.2$ by $9.55170879$ .

$\frac{d}{d x} [565.46116039] + \frac{d}{d x} [- 104]$

Step 2.2

Since $565.46116039$ is constant with respect to $x$ , the derivative of $565.46116039$ with respect to $x$ is $0$ .

$0 + \frac{d}{d x} [- 104]$

Step 3

Differentiate using the Constant Rule.

Tap for more steps...

Step 3.1

Since $- 104$ is constant with respect to $x$ , the derivative of $- 104$ with respect to $x$ is $0$ .

$0 + 0$

Step 3.2

Add $0$ and $0$ .

$0$