Calculus Examples

$g (x) = 5 \tan (3 x)$

Step 1

Since $5$ is constant with respect to $x$ , the derivative of $5 \tan (3 x)$ with respect to $x$ is $5 \frac{d}{d x} [\tan (3 x)]$ .

$5 \frac{d}{d x} [\tan (3 x)]$

Step 2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = \tan (x)$ and $g (x) = 3 x$ .

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Step 2.1

To apply the Chain Rule, set $u$ as $3 x$ .

$5 (\frac{d}{d u} [\tan (u)] \frac{d}{d x} [3 x])$

Step 2.2

The derivative of $\tan (u)$ with respect to $u$ is $\sec^{2} (u)$ .

$5 (\sec^{2} (u) \frac{d}{d x} [3 x])$

Step 2.3

Replace all occurrences of $u$ with $3 x$ .

$5 (\sec^{2} (3 x) \frac{d}{d x} [3 x])$

Step 3

Differentiate.

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Step 3.1

Since $3$ is constant with respect to $x$ , the derivative of $3 x$ with respect to $x$ is $3 \frac{d}{d x} [x]$ .

$5 \sec^{2} (3 x) (3 \frac{d}{d x} [x])$

Step 3.2

Multiply $3$ by $5$ .

$15 \sec^{2} (3 x) \frac{d}{d x} [x]$

Step 3.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$15 \sec^{2} (3 x) \cdot 1$

Step 3.4

Multiply $15$ by $1$ .

$15 \sec^{2} (3 x)$