Calculus Examples

$g (x) = \frac{- 3^{x}}{10^{2} + 90 x}$

Step 1

Simplify the expression.

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Step 1.1

Raise $10$ to the power of $2$ .

$\frac{d}{d x} [\frac{- 3^{x}}{100 + 90 x}]$

Step 1.2

Move the negative in front of the fraction.

$\frac{d}{d x} [- \frac{3^{x}}{100 + 90 x}]$

Step 2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = - 1$ and $g (x) = \frac{3^{x}}{100 + 90 x}$ .

$- \frac{d}{d x} [\frac{3^{x}}{100 + 90 x}] + \frac{3^{x}}{100 + 90 x} \frac{d}{d x} [- 1]$

Step 3

Differentiate using the Quotient Rule which states that $\frac{d}{d x} [\frac{f (x)}{g (x)}]$ is $\frac{g (x) \frac{d}{d x} [f (x)] - f (x) \frac{d}{d x} [g (x)]}{{g (x)}^{2}}$ where $f (x) = 3^{x}$ and $g (x) = 100 + 90 x$ .

$- \frac{(100 + 90 x) \frac{d}{d x} [3^{x}] - 3^{x} \frac{d}{d x} [100 + 90 x]}{{(100 + 90 x)}^{2}} + \frac{3^{x}}{100 + 90 x} \frac{d}{d x} [- 1]$

Step 4

Differentiate using the Exponential Rule which states that $\frac{d}{d x} [a^{x}]$ is $a^{x} \ln (a)$ where $a$ = $3$ .

$- \frac{(100 + 90 x) (3^{x} \ln (3)) - 3^{x} \frac{d}{d x} [100 + 90 x]}{{(100 + 90 x)}^{2}} + \frac{3^{x}}{100 + 90 x} \frac{d}{d x} [- 1]$

Step 5

Differentiate.

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Step 5.1

By the Sum Rule, the derivative of $100 + 90 x$ with respect to $x$ is $\frac{d}{d x} [100] + \frac{d}{d x} [90 x]$ .

$- \frac{(100 + 90 x) \cdot 3^{x} \ln (3) - 3^{x} (\frac{d}{d x} [100] + \frac{d}{d x} [90 x])}{{(100 + 90 x)}^{2}} + \frac{3^{x}}{100 + 90 x} \frac{d}{d x} [- 1]$

Step 5.2

Since $100$ is constant with respect to $x$ , the derivative of $100$ with respect to $x$ is $0$ .

$- \frac{(100 + 90 x) \cdot 3^{x} \ln (3) - 3^{x} (0 + \frac{d}{d x} [90 x])}{{(100 + 90 x)}^{2}} + \frac{3^{x}}{100 + 90 x} \frac{d}{d x} [- 1]$

Step 5.3

Add $0$ and $\frac{d}{d x} [90 x]$ .

$- \frac{(100 + 90 x) \cdot 3^{x} \ln (3) - 3^{x} \frac{d}{d x} [90 x]}{{(100 + 90 x)}^{2}} + \frac{3^{x}}{100 + 90 x} \frac{d}{d x} [- 1]$

Step 5.4

Since $90$ is constant with respect to $x$ , the derivative of $90 x$ with respect to $x$ is $90 \frac{d}{d x} [x]$ .

$- \frac{(100 + 90 x) \cdot 3^{x} \ln (3) - 3^{x} (90 \frac{d}{d x} [x])}{{(100 + 90 x)}^{2}} + \frac{3^{x}}{100 + 90 x} \frac{d}{d x} [- 1]$

Step 5.5

Multiply $90$ by $- 1$ .

$- \frac{(100 + 90 x) \cdot 3^{x} \ln (3) - 90 \cdot 3^{x} \frac{d}{d x} [x]}{{(100 + 90 x)}^{2}} + \frac{3^{x}}{100 + 90 x} \frac{d}{d x} [- 1]$

Step 5.6

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$- \frac{(100 + 90 x) \cdot 3^{x} \ln (3) - 90 \cdot 3^{x} \cdot 1}{{(100 + 90 x)}^{2}} + \frac{3^{x}}{100 + 90 x} \frac{d}{d x} [- 1]$

Step 5.7

Multiply $- 90$ by $1$ .

$- \frac{(100 + 90 x) \cdot 3^{x} \ln (3) - 90 \cdot 3^{x}}{{(100 + 90 x)}^{2}} + \frac{3^{x}}{100 + 90 x} \frac{d}{d x} [- 1]$

Step 5.8

Since $- 1$ is constant with respect to $x$ , the derivative of $- 1$ with respect to $x$ is $0$ .

$- \frac{(100 + 90 x) \cdot 3^{x} \ln (3) - 90 \cdot 3^{x}}{{(100 + 90 x)}^{2}} + \frac{3^{x}}{100 + 90 x} \cdot 0$

Step 5.9

Simplify the expression.

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Step 5.9.1

Multiply $\frac{3^{x}}{100 + 90 x}$ by $0$ .

$- \frac{(100 + 90 x) \cdot 3^{x} \ln (3) - 90 \cdot 3^{x}}{{(100 + 90 x)}^{2}} + 0$

Step 5.9.2

Add $- \frac{(100 + 90 x) \cdot 3^{x} \ln (3) - 90 \cdot 3^{x}}{{(100 + 90 x)}^{2}}$ and $0$ .

$- \frac{(100 + 90 x) \cdot 3^{x} \ln (3) - 90 \cdot 3^{x}}{{(100 + 90 x)}^{2}}$

Step 6

Simplify.

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Step 6.1

Apply the distributive property.

$- \frac{(100 \cdot 3^{x} + 90 x \cdot 3^{x}) \ln (3) - 90 \cdot 3^{x}}{{(100 + 90 x)}^{2}}$

Step 6.2

Apply the distributive property.

$- \frac{100 \cdot 3^{x} \ln (3) + 90 x \cdot 3^{x} \ln (3) - 90 \cdot 3^{x}}{{(100 + 90 x)}^{2}}$

Step 6.3

Simplify each term.

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Step 6.3.1

Simplify $100 \ln (3)$ by moving $100$ inside the logarithm.

$- \frac{3^{x} \ln (3^{100}) + 90 x \cdot 3^{x} \ln (3) - 90 \cdot 3^{x}}{{(100 + 90 x)}^{2}}$

Step 6.3.2

Simplify $90 \ln (3)$ by moving $90$ inside the logarithm.

$- \frac{3^{x} \ln (3^{100}) + x \cdot 3^{x} \ln (3^{90}) - 90 \cdot 3^{x}}{{(100 + 90 x)}^{2}}$

Step 6.4

Simplify the numerator.

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Step 6.4.1

Factor $3^{x}$ out of $3^{x} \ln (3^{100}) + x \cdot 3^{x} \ln (3^{90}) - 90 \cdot 3^{x}$ .

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Step 6.4.1.1

Factor $3^{x}$ out of $3^{x} \ln (3^{100})$ .

$- \frac{3^{x} (\ln (3^{100})) + x \cdot 3^{x} \ln (3^{90}) - 90 \cdot 3^{x}}{{(100 + 90 x)}^{2}}$

Step 6.4.1.2

Factor $3^{x}$ out of $x \cdot 3^{x} \ln (3^{90})$ .

$- \frac{3^{x} (\ln (3^{100})) + 3^{x} (x \ln (3^{90})) - 90 \cdot 3^{x}}{{(100 + 90 x)}^{2}}$

Step 6.4.1.3

Factor $3^{x}$ out of $- 90 \cdot 3^{x}$ .

$- \frac{3^{x} (\ln (3^{100})) + 3^{x} (x \ln (3^{90})) + 3^{x} \cdot - 90}{{(100 + 90 x)}^{2}}$

Step 6.4.1.4

Factor $3^{x}$ out of $3^{x} (\ln (3^{100})) + 3^{x} (x \ln (3^{90}))$ .

$- \frac{3^{x} (\ln (3^{100}) + x \ln (3^{90})) + 3^{x} \cdot - 90}{{(100 + 90 x)}^{2}}$

Step 6.4.1.5

Factor $3^{x}$ out of $3^{x} (\ln (3^{100}) + x \ln (3^{90})) + 3^{x} \cdot - 90$ .

$- \frac{3^{x} (\ln (3^{100}) + x \ln (3^{90}) - 90)}{{(100 + 90 x)}^{2}}$

Step 6.4.2

Reorder terms.

$- \frac{3^{x} (x \ln (3^{90}) + \ln (3^{100}) - 90)}{{(100 + 90 x)}^{2}}$

Step 6.5

Simplify the denominator.

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Step 6.5.1

Factor $10$ out of $100 + 90 x$ .

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Step 6.5.1.1

Factor $10$ out of $100$ .

$- \frac{3^{x} (x \ln (3^{90}) + \ln (3^{100}) - 90)}{{(10 (10) + 90 x)}^{2}}$

Step 6.5.1.2

Factor $10$ out of $90 x$ .

$- \frac{3^{x} (x \ln (3^{90}) + \ln (3^{100}) - 90)}{{(10 (10) + 10 (9 x))}^{2}}$

Step 6.5.1.3

Factor $10$ out of $10 (10) + 10 (9 x)$ .

$- \frac{3^{x} (x \ln (3^{90}) + \ln (3^{100}) - 90)}{{(10 (10 + 9 x))}^{2}}$

Step 6.5.2

Apply the product rule to $10 (10 + 9 x)$ .

$- \frac{3^{x} (x \ln (3^{90}) + \ln (3^{100}) - 90)}{10^{2} {(10 + 9 x)}^{2}}$

Step 6.5.3

Raise $10$ to the power of $2$ .

$- \frac{3^{x} (x \ln (3^{90}) + \ln (3^{100}) - 90)}{100 {(10 + 9 x)}^{2}}$

Step 6.6

Expand $\ln (3^{90})$ by moving $90$ outside the logarithm.

$- \frac{3^{x} (x (90 \ln (3)) + \ln (3^{100}) - 90)}{100 {(10 + 9 x)}^{2}}$

Step 6.7

Expand $\ln (3^{100})$ by moving $100$ outside the logarithm.

$- \frac{3^{x} (x (90 \ln (3)) + 100 \ln (3) - 90)}{100 {(10 + 9 x)}^{2}}$

Step 6.8

Cancel the common factor of $x (90 \ln (3)) + 100 \ln (3) - 90$ and $100$ .

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Step 6.8.1

Factor $- 1$ out of $x (90 \ln (3))$ .

$- \frac{3^{x} (- (- x (90 \ln (3))) + 100 \ln (3) - 90)}{100 {(10 + 9 x)}^{2}}$

Step 6.8.2

Factor $- 1$ out of $100 \ln (3)$ .

$- \frac{3^{x} (- (- x (90 \ln (3))) - (- 100 \ln (3)) - 90)}{100 {(10 + 9 x)}^{2}}$

Step 6.8.3

Factor $- 1$ out of $- (- x (90 \ln (3))) - (- 100 \ln (3))$ .

$- \frac{3^{x} (- (- x (90 \ln (3)) - 100 \ln (3)) - 90)}{100 {(10 + 9 x)}^{2}}$

Step 6.8.4

Rewrite $- 90$ as $- 1 (90)$ .

$- \frac{3^{x} (- (- x (90 \ln (3)) - 100 \ln (3)) - 1 (90))}{100 {(10 + 9 x)}^{2}}$

Step 6.8.5

Factor $- 1$ out of $- (- x (90 \ln (3)) - 100 \ln (3)) - 1 (90)$ .

$- \frac{3^{x} (- (- x (90 \ln (3)) - 100 \ln (3) + 90))}{100 {(10 + 9 x)}^{2}}$

Step 6.8.6

Rewrite $- (- x (90 \ln (3)) - 100 \ln (3) + 90)$ as $- 1 (- x (90 \ln (3)) - 100 \ln (3) + 90)$ .

$- \frac{3^{x} (- 1 (- x (90 \ln (3)) - 100 \ln (3) + 90))}{100 {(10 + 9 x)}^{2}}$

Step 6.8.7

Factor $10$ out of $3^{x} (- 1 (- x \cdot 90 \ln (3) - 100 \ln (3) + 90))$ .

$- \frac{10 (3^{x} (- 1 (- x \cdot 9 \ln (3) - 10 \ln (3) + 9)))}{100 {(10 + 9 x)}^{2}}$

Step 6.8.8

Cancel the common factors.

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Step 6.8.8.1

Factor $10$ out of $100 {(10 + 9 x)}^{2}$ .

$- \frac{10 (3^{x} (- 1 (- x \cdot 9 \ln (3) - 10 \ln (3) + 9)))}{10 (10 {(10 + 9 x)}^{2})}$

Step 6.8.8.2

Cancel the common factor.

$- \frac{10 (3^{x} (- 1 (- x \cdot 9 \ln (3) - 10 \ln (3) + 9)))}{10 (10 {(10 + 9 x)}^{2})}$

Step 6.8.8.3

Rewrite the expression.

$- \frac{3^{x} (- 1 (- x \cdot 9 \ln (3) - 10 \ln (3) + 9))}{10 {(10 + 9 x)}^{2}}$

Step 6.9

Simplify the numerator.

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Step 6.9.1

Rewrite.

$- \frac{(100 + 90 x) \frac{d}{d x} [3^{x}] - 3^{x} \frac{d}{d x} [100 + 90 x]}{10 {(10 + 9 x)}^{2}}$

Step 6.9.2

Differentiate using the Exponential Rule which states that $\frac{d}{d x} [a^{x}]$ is $a^{x} \ln (a)$ where $a$ = $3$ .

$- \frac{(100 + 90 x) (3^{x} \ln (3)) - 3^{x} \frac{d}{d x} [100 + 90 x]}{10 {(10 + 9 x)}^{2}}$

Step 6.9.3

By the Sum Rule, the derivative of $100 + 90 x$ with respect to $x$ is $\frac{d}{d x} [100] + \frac{d}{d x} [90 x]$ .

$- \frac{(100 + 90 x) \cdot 3^{x} \ln (3) - 3^{x} (\frac{d}{d x} [100] + \frac{d}{d x} [90 x])}{10 {(10 + 9 x)}^{2}}$

Step 6.9.4

Since $100$ is constant with respect to $x$ , the derivative of $100$ with respect to $x$ is $0$ .

$- \frac{(100 + 90 x) \cdot 3^{x} \ln (3) - 3^{x} (0 + \frac{d}{d x} [90 x])}{10 {(10 + 9 x)}^{2}}$

Step 6.9.5

Add $0$ and $\frac{d}{d x} [90 x]$ .

$- \frac{(100 + 90 x) \cdot 3^{x} \ln (3) - 3^{x} \frac{d}{d x} [90 x]}{10 {(10 + 9 x)}^{2}}$

Step 6.9.6

Since $90$ is constant with respect to $x$ , the derivative of $90 x$ with respect to $x$ is $90 \frac{d}{d x} [x]$ .

$- \frac{(100 + 90 x) \cdot 3^{x} \ln (3) - 3^{x} (90 \frac{d}{d x} [x])}{10 {(10 + 9 x)}^{2}}$

Step 6.9.7

Multiply $90$ by $- 1$ .

$- \frac{(100 + 90 x) \cdot 3^{x} \ln (3) - 90 \cdot 3^{x} \frac{d}{d x} [x]}{10 {(10 + 9 x)}^{2}}$

Step 6.9.8

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$- \frac{(100 + 90 x) \cdot 3^{x} \ln (3) - 90 \cdot 3^{x} \cdot 1}{10 {(10 + 9 x)}^{2}}$

Step 6.9.9

Multiply $- 90$ by $1$ .

$- \frac{(100 + 90 x) \cdot 3^{x} \ln (3) - 90 \cdot 3^{x}}{10 {(10 + 9 x)}^{2}}$

Step 6.9.10

Apply the distributive property.

$- \frac{(100 \cdot 3^{x} + 90 x \cdot 3^{x}) \ln (3) - 90 \cdot 3^{x}}{10 {(10 + 9 x)}^{2}}$

Step 6.9.11

Apply the distributive property.

$- \frac{100 \cdot 3^{x} \ln (3) + 90 x \cdot 3^{x} \ln (3) - 90 \cdot 3^{x}}{10 {(10 + 9 x)}^{2}}$

Step 6.9.12

Simplify each term.

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Step 6.9.12.1

Simplify $100 \ln (3)$ by moving $100$ inside the logarithm.

$- \frac{3^{x} \ln (3^{100}) + 90 x \cdot 3^{x} \ln (3) - 90 \cdot 3^{x}}{10 {(10 + 9 x)}^{2}}$

Step 6.9.12.2

Simplify $90 \ln (3)$ by moving $90$ inside the logarithm.

$- \frac{3^{x} \ln (3^{100}) + x \cdot 3^{x} \ln (3^{90}) - 90 \cdot 3^{x}}{10 {(10 + 9 x)}^{2}}$

Step 6.9.13

Factor $3^{x}$ out of $3^{x} \ln (3^{100}) + x \cdot 3^{x} \ln (3^{90}) - 90 \cdot 3^{x}$ .

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Step 6.9.13.1

Factor $3^{x}$ out of $3^{x} \ln (3^{100})$ .

$- \frac{3^{x} (\ln (3^{100})) + x \cdot 3^{x} \ln (3^{90}) - 90 \cdot 3^{x}}{10 {(10 + 9 x)}^{2}}$

Step 6.9.13.2

Factor $3^{x}$ out of $x \cdot 3^{x} \ln (3^{90})$ .

$- \frac{3^{x} (\ln (3^{100})) + 3^{x} (x \ln (3^{90})) - 90 \cdot 3^{x}}{10 {(10 + 9 x)}^{2}}$

Step 6.9.13.3

Factor $3^{x}$ out of $- 90 \cdot 3^{x}$ .

$- \frac{3^{x} (\ln (3^{100})) + 3^{x} (x \ln (3^{90})) + 3^{x} \cdot - 90}{10 {(10 + 9 x)}^{2}}$

Step 6.9.13.4

Factor $3^{x}$ out of $3^{x} (\ln (3^{100})) + 3^{x} (x \ln (3^{90}))$ .

$- \frac{3^{x} (\ln (3^{100}) + x \ln (3^{90})) + 3^{x} \cdot - 90}{10 {(10 + 9 x)}^{2}}$

Step 6.9.13.5

Factor $3^{x}$ out of $3^{x} (\ln (3^{100}) + x \ln (3^{90})) + 3^{x} \cdot - 90$ .

$- \frac{3^{x} (\ln (3^{100}) + x \ln (3^{90}) - 90)}{10 {(10 + 9 x)}^{2}}$

Step 6.9.14

Reorder terms.

$- \frac{3^{x} (x \ln (3^{90}) + \ln (3^{100}) - 90)}{10 {(10 + 9 x)}^{2}}$

Step 6.9.15

Expand $\ln (3^{90})$ by moving $90$ outside the logarithm.

$- \frac{3^{x} (x (90 \ln (3)) + \ln (3^{100}) - 90)}{10 {(10 + 9 x)}^{2}}$

Step 6.9.16

Expand $\ln (3^{100})$ by moving $100$ outside the logarithm.

$- \frac{3^{x} (x (90 \ln (3)) + 100 \ln (3) - 90)}{10 {(10 + 9 x)}^{2}}$

Step 6.9.17

Factor $- 1$ out of $x (90 \ln (3))$ .

$- \frac{3^{x} (- (- x (90 \ln (3))) + 100 \ln (3) - 90)}{10 {(10 + 9 x)}^{2}}$

Step 6.9.18

Factor $- 1$ out of $100 \ln (3)$ .

$- \frac{3^{x} (- (- x (90 \ln (3))) - (- 100 \ln (3)) - 90)}{10 {(10 + 9 x)}^{2}}$

Step 6.9.19

Factor $- 1$ out of $- (- x (90 \ln (3))) - (- 100 \ln (3))$ .

$- \frac{3^{x} (- (- x (90 \ln (3)) - 100 \ln (3)) - 90)}{10 {(10 + 9 x)}^{2}}$

Step 6.9.20

Rewrite $- 90$ as $- 1 (90)$ .

$- \frac{3^{x} (- (- x (90 \ln (3)) - 100 \ln (3)) - 1 (90))}{10 {(10 + 9 x)}^{2}}$

Step 6.9.21

Factor $- 1$ out of $- (- x (90 \ln (3)) - 100 \ln (3)) - 1 (90)$ .

$- \frac{3^{x} (- (- x (90 \ln (3)) - 100 \ln (3) + 90))}{10 {(10 + 9 x)}^{2}}$

Step 6.9.22

Rewrite $- (- x (90 \ln (3)) - 100 \ln (3) + 90)$ as $- 1 (- x (90 \ln (3)) - 100 \ln (3) + 90)$ .

$- \frac{3^{x} (- 1 (- x (90 \ln (3)) - 100 \ln (3) + 90))}{10 {(10 + 9 x)}^{2}}$

Step 6.9.23

Factor $10$ out of $- x \cdot 90 \ln (3)$ .

$- \frac{3^{x} (- 1 (10 (- x \cdot 9 \ln (3)) - 100 \ln (3) + 90))}{10 {(10 + 9 x)}^{2}}$

Step 6.9.24

Factor $10$ out of $- 100 \ln (3)$ .

$- \frac{3^{x} (- 1 (10 (- x \cdot 9 \ln (3)) + 10 (- 10 \ln (3)) + 90))}{10 {(10 + 9 x)}^{2}}$

Step 6.9.25

Factor $10$ out of $10 (- x \cdot 9 \ln (3)) + 10 (- 10 \ln (3))$ .

$- \frac{3^{x} (- 1 (10 (- x \cdot 9 \ln (3) - 10 \ln (3)) + 90))}{10 {(10 + 9 x)}^{2}}$

Step 6.9.26

Factor $10$ out of $90$ .

$- \frac{3^{x} (- 1 (10 (- x \cdot 9 \ln (3) - 10 \ln (3)) + 10 (9)))}{10 {(10 + 9 x)}^{2}}$

Step 6.9.27

Factor $10$ out of $10 (- x \cdot 9 \ln (3) - 10 \ln (3)) + 10 (9)$ .

$- \frac{3^{x} (- 1 (10 (- x \cdot 9 \ln (3) - 10 \ln (3) + 9)))}{10 {(10 + 9 x)}^{2}}$

Step 6.9.28

Rewrite.

$- \frac{3^{x} (- 1 (- x \cdot 9 \ln (3) - 10 \ln (3) + 9))}{10 {(10 + 9 x)}^{2}}$

Step 6.9.29

Remove unnecessary parentheses.

$- \frac{3^{x} \cdot - 1 (- x \cdot 9 \ln (3) - 10 \ln (3) + 9)}{10 {(10 + 9 x)}^{2}}$

Step 6.9.30

Combine exponents.

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Step 6.9.30.1

Factor out negative.

$- \frac{- (3^{x} (- x \cdot 9 \ln (3) - 10 \ln (3) + 9))}{10 {(10 + 9 x)}^{2}}$

Step 6.9.30.2

Multiply $9$ by $- 1$ .

$- \frac{- (3^{x} (- 9 x \ln (3) - 10 \ln (3) + 9))}{10 {(10 + 9 x)}^{2}}$

$- \frac{- 3^{x} (- 9 x \ln (3) - 10 \ln (3) + 9)}{10 {(10 + 9 x)}^{2}}$

Step 6.9.31

Reorder terms.

$- \frac{- 3^{x} (- 9 x \ln (3) + 9 - 10 \ln (3))}{10 {(10 + 9 x)}^{2}}$

Step 6.10

Move the negative in front of the fraction.

$- - \frac{3^{x} (- 9 x \ln (3) + 9 - 10 \ln (3))}{10 {(10 + 9 x)}^{2}}$

Step 6.11

Multiply $- - \frac{3^{x} (- 9 x \ln (3) + 9 - 10 \ln (3))}{10 {(10 + 9 x)}^{2}}$ .

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Step 6.11.1

Multiply $- 1$ by $- 1$ .

$1 \frac{3^{x} (- 9 x \ln (3) + 9 - 10 \ln (3))}{10 {(10 + 9 x)}^{2}}$

Step 6.11.2

Multiply $\frac{3^{x} (- 9 x \ln (3) + 9 - 10 \ln (3))}{10 {(10 + 9 x)}^{2}}$ by $1$ .

$\frac{3^{x} (- 9 x \ln (3) + 9 - 10 \ln (3))}{10 {(10 + 9 x)}^{2}}$

Step 6.12

Factor $- 1$ out of $- 9 x \ln (3)$ .

$\frac{3^{x} (- (9 x \ln (3)) + 9 - 10 \ln (3))}{10 {(10 + 9 x)}^{2}}$

Step 6.13

Rewrite $9$ as $- 1 (- 9)$ .

$\frac{3^{x} (- (9 x \ln (3)) - 1 (- 9) - 10 \ln (3))}{10 {(10 + 9 x)}^{2}}$

Step 6.14

Factor $- 1$ out of $- (9 x \ln (3)) - 1 (- 9)$ .

$\frac{3^{x} (- (9 x \ln (3) - 9) - 10 \ln (3))}{10 {(10 + 9 x)}^{2}}$

Step 6.15

Factor $- 1$ out of $- 10 \ln (3)$ .

$\frac{3^{x} (- (9 x \ln (3) - 9) - (10 \ln (3)))}{10 {(10 + 9 x)}^{2}}$

Step 6.16

Factor $- 1$ out of $- (9 x \ln (3) - 9) - (10 \ln (3))$ .

$\frac{3^{x} (- (9 x \ln (3) - 9 + 10 \ln (3)))}{10 {(10 + 9 x)}^{2}}$

Step 6.17

Rewrite $- (9 x \ln (3) - 9 + 10 \ln (3))$ as $- 1 (9 x \ln (3) - 9 + 10 \ln (3))$ .

$\frac{3^{x} (- 1 (9 x \ln (3) - 9 + 10 \ln (3)))}{10 {(10 + 9 x)}^{2}}$

Step 6.18

Move the negative in front of the fraction.

$- \frac{3^{x} (9 x \ln (3) - 9 + 10 \ln (3))}{10 {(10 + 9 x)}^{2}}$