Calculus Examples

$g (x) = \frac{e^{2 x} - 1}{e^{x} + 1}$

Step 1

Differentiate using the Quotient Rule which states that $\frac{d}{d x} [\frac{f (x)}{g (x)}]$ is $\frac{g (x) \frac{d}{d x} [f (x)] - f (x) \frac{d}{d x} [g (x)]}{{g (x)}^{2}}$ where $f (x) = e^{2 x} - 1$ and $g (x) = e^{x} + 1$ .

$\frac{(e^{x} + 1) \frac{d}{d x} [e^{2 x} - 1] - (e^{2 x} - 1) \frac{d}{d x} [e^{x} + 1]}{{(e^{x} + 1)}^{2}}$

Step 2

By the Sum Rule, the derivative of $e^{2 x} - 1$ with respect to $x$ is $\frac{d}{d x} [e^{2 x}] + \frac{d}{d x} [- 1]$ .

$\frac{(e^{x} + 1) (\frac{d}{d x} [e^{2 x}] + \frac{d}{d x} [- 1]) - (e^{2 x} - 1) \frac{d}{d x} [e^{x} + 1]}{{(e^{x} + 1)}^{2}}$

Step 3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = e^{x}$ and $g (x) = 2 x$ .

Tap for more steps...

Step 3.1

To apply the Chain Rule, set $u$ as $2 x$ .

$\frac{(e^{x} + 1) (\frac{d}{d u} [e^{u}] \frac{d}{d x} [2 x] + \frac{d}{d x} [- 1]) - (e^{2 x} - 1) \frac{d}{d x} [e^{x} + 1]}{{(e^{x} + 1)}^{2}}$

Step 3.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u} [a^{u}]$ is $a^{u} \ln (a)$ where $a$ = $e$ .

$\frac{(e^{x} + 1) (e^{u} \frac{d}{d x} [2 x] + \frac{d}{d x} [- 1]) - (e^{2 x} - 1) \frac{d}{d x} [e^{x} + 1]}{{(e^{x} + 1)}^{2}}$

Step 3.3

Replace all occurrences of $u$ with $2 x$ .

$\frac{(e^{x} + 1) (e^{2 x} \frac{d}{d x} [2 x] + \frac{d}{d x} [- 1]) - (e^{2 x} - 1) \frac{d}{d x} [e^{x} + 1]}{{(e^{x} + 1)}^{2}}$

Step 4

Differentiate.

Tap for more steps...

Step 4.1

Since $2$ is constant with respect to $x$ , the derivative of $2 x$ with respect to $x$ is $2 \frac{d}{d x} [x]$ .

$\frac{(e^{x} + 1) (e^{2 x} (2 \frac{d}{d x} [x]) + \frac{d}{d x} [- 1]) - (e^{2 x} - 1) \frac{d}{d x} [e^{x} + 1]}{{(e^{x} + 1)}^{2}}$

Step 4.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{(e^{x} + 1) (e^{2 x} (2 \cdot 1) + \frac{d}{d x} [- 1]) - (e^{2 x} - 1) \frac{d}{d x} [e^{x} + 1]}{{(e^{x} + 1)}^{2}}$

Step 4.3

Simplify the expression.

Tap for more steps...

Step 4.3.1

Multiply $2$ by $1$ .

$\frac{(e^{x} + 1) (e^{2 x} \cdot 2 + \frac{d}{d x} [- 1]) - (e^{2 x} - 1) \frac{d}{d x} [e^{x} + 1]}{{(e^{x} + 1)}^{2}}$

Step 4.3.2

Move $2$ to the left of $e^{2 x}$ .

$\frac{(e^{x} + 1) (2 \cdot e^{2 x} + \frac{d}{d x} [- 1]) - (e^{2 x} - 1) \frac{d}{d x} [e^{x} + 1]}{{(e^{x} + 1)}^{2}}$

Step 4.4

Since $- 1$ is constant with respect to $x$ , the derivative of $- 1$ with respect to $x$ is $0$ .

$\frac{(e^{x} + 1) (2 e^{2 x} + 0) - (e^{2 x} - 1) \frac{d}{d x} [e^{x} + 1]}{{(e^{x} + 1)}^{2}}$

Step 4.5

Simplify the expression.

Tap for more steps...

Step 4.5.1

Add $2 e^{2 x}$ and $0$ .

$\frac{(e^{x} + 1) (2 e^{2 x}) - (e^{2 x} - 1) \frac{d}{d x} [e^{x} + 1]}{{(e^{x} + 1)}^{2}}$

Step 4.5.2

Move $2$ to the left of $e^{x} + 1$ .

$\frac{2 \cdot (e^{x} + 1) e^{2 x} - (e^{2 x} - 1) \frac{d}{d x} [e^{x} + 1]}{{(e^{x} + 1)}^{2}}$

Step 4.6

By the Sum Rule, the derivative of $e^{x} + 1$ with respect to $x$ is $\frac{d}{d x} [e^{x}] + \frac{d}{d x} [1]$ .

$\frac{2 (e^{x} + 1) e^{2 x} - (e^{2 x} - 1) (\frac{d}{d x} [e^{x}] + \frac{d}{d x} [1])}{{(e^{x} + 1)}^{2}}$

Step 5

Differentiate using the Exponential Rule which states that $\frac{d}{d x} [a^{x}]$ is $a^{x} \ln (a)$ where $a$ = $e$ .

$\frac{2 (e^{x} + 1) e^{2 x} - (e^{2 x} - 1) (e^{x} + \frac{d}{d x} [1])}{{(e^{x} + 1)}^{2}}$

Step 6

Differentiate using the Constant Rule.

Tap for more steps...

Step 6.1

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$\frac{2 (e^{x} + 1) e^{2 x} - (e^{2 x} - 1) (e^{x} + 0)}{{(e^{x} + 1)}^{2}}$

Step 6.2

Add $e^{x}$ and $0$ .

$\frac{2 (e^{x} + 1) e^{2 x} - (e^{2 x} - 1) e^{x}}{{(e^{x} + 1)}^{2}}$

Step 7

Simplify.

Tap for more steps...

Step 7.1

Apply the distributive property.

$\frac{(2 e^{x} + 2 \cdot 1) e^{2 x} - (e^{2 x} - 1) e^{x}}{{(e^{x} + 1)}^{2}}$

Step 7.2

Apply the distributive property.

$\frac{2 e^{x} e^{2 x} + 2 \cdot 1 e^{2 x} - (e^{2 x} - 1) e^{x}}{{(e^{x} + 1)}^{2}}$

Step 7.3

Apply the distributive property.

$\frac{2 e^{x} e^{2 x} + 2 \cdot 1 e^{2 x} + (- e^{2 x} - - 1) e^{x}}{{(e^{x} + 1)}^{2}}$

Step 7.4

Apply the distributive property.

$\frac{2 e^{x} e^{2 x} + 2 \cdot 1 e^{2 x} - e^{2 x} e^{x} - - 1 e^{x}}{{(e^{x} + 1)}^{2}}$

Step 7.5

Simplify the numerator.

Tap for more steps...

Step 7.5.1

Simplify each term.

Tap for more steps...

Step 7.5.1.1

Multiply $e^{x}$ by $e^{2 x}$ by adding the exponents.

Tap for more steps...

Step 7.5.1.1.1

Move $e^{2 x}$ .

$\frac{2 (e^{2 x} e^{x}) + 2 \cdot 1 e^{2 x} - e^{2 x} e^{x} - - 1 e^{x}}{{(e^{x} + 1)}^{2}}$

Step 7.5.1.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 e^{2 x + x} + 2 \cdot 1 e^{2 x} - e^{2 x} e^{x} - - 1 e^{x}}{{(e^{x} + 1)}^{2}}$

Step 7.5.1.1.3

Add $2 x$ and $x$ .

$\frac{2 e^{3 x} + 2 \cdot 1 e^{2 x} - e^{2 x} e^{x} - - 1 e^{x}}{{(e^{x} + 1)}^{2}}$

Step 7.5.1.2

Multiply $2$ by $1$ .

$\frac{2 e^{3 x} + 2 e^{2 x} - e^{2 x} e^{x} - - 1 e^{x}}{{(e^{x} + 1)}^{2}}$

Step 7.5.1.3

Multiply $e^{2 x}$ by $e^{x}$ by adding the exponents.

Tap for more steps...

Step 7.5.1.3.1

Move $e^{x}$ .

$\frac{2 e^{3 x} + 2 e^{2 x} - (e^{x} e^{2 x}) - - 1 e^{x}}{{(e^{x} + 1)}^{2}}$

Step 7.5.1.3.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{2 e^{3 x} + 2 e^{2 x} - e^{x + 2 x} - - 1 e^{x}}{{(e^{x} + 1)}^{2}}$

Step 7.5.1.3.3

Add $x$ and $2 x$ .

$\frac{2 e^{3 x} + 2 e^{2 x} - e^{3 x} - - 1 e^{x}}{{(e^{x} + 1)}^{2}}$

Step 7.5.1.4

Multiply $- 1$ by $- 1$ .

$\frac{2 e^{3 x} + 2 e^{2 x} - e^{3 x} + 1 e^{x}}{{(e^{x} + 1)}^{2}}$

Step 7.5.1.5

Multiply $e^{x}$ by $1$ .

$\frac{2 e^{3 x} + 2 e^{2 x} - e^{3 x} + e^{x}}{{(e^{x} + 1)}^{2}}$

Step 7.5.2

Subtract $e^{3 x}$ from $2 e^{3 x}$ .

$\frac{2 e^{2 x} + e^{3 x} + e^{x}}{{(e^{x} + 1)}^{2}}$