Enter a problem...
Calculus Examples
Step 1
Write as a function.
Step 2
Step 2.1
Since is constant with respect to , the derivative of with respect to is .
Step 2.2
Differentiate using the chain rule, which states that is where and .
Step 2.2.1
To apply the Chain Rule, set as .
Step 2.2.2
The derivative of with respect to is .
Step 2.2.3
Replace all occurrences of with .
Step 2.3
Differentiate.
Step 2.3.1
Multiply by .
Step 2.3.2
Since is constant with respect to , the derivative of with respect to is .
Step 2.3.3
Simplify terms.
Step 2.3.3.1
Combine and .
Step 2.3.3.2
Multiply by .
Step 2.3.3.3
Combine and .
Step 2.3.3.4
Move the negative in front of the fraction.
Step 2.3.4
Differentiate using the Power Rule which states that is where .
Step 2.3.5
Multiply by .
Step 2.4
Simplify.
Step 2.4.1
Factor out of .
Step 2.4.2
Factor out of .
Step 2.4.3
Separate fractions.
Step 2.4.4
Divide by .
Step 2.4.5
Divide by .
Step 2.4.6
Multiply by .
Step 3
Step 3.1
Since is constant with respect to , the derivative of with respect to is .
Step 3.2
Differentiate using the chain rule, which states that is where and .
Step 3.2.1
To apply the Chain Rule, set as .
Step 3.2.2
The derivative of with respect to is .
Step 3.2.3
Replace all occurrences of with .
Step 3.3
Differentiate.
Step 3.3.1
Since is constant with respect to , the derivative of with respect to is .
Step 3.3.2
Simplify terms.
Step 3.3.2.1
Combine and .
Step 3.3.2.2
Multiply by .
Step 3.3.2.3
Combine and .
Step 3.3.2.4
Move the negative in front of the fraction.
Step 3.3.3
Differentiate using the Power Rule which states that is where .
Step 3.3.4
Multiply by .
Step 3.4
Simplify.
Step 3.4.1
Factor out of .
Step 3.4.2
Factor out of .
Step 3.4.3
Separate fractions.
Step 3.4.4
Divide by .
Step 3.4.5
Divide by .
Step 3.4.6
Multiply by .
Step 4
To find the local maximum and minimum values of the function, set the derivative equal to and solve.
Step 5
Step 5.1
Divide each term in by .
Step 5.2
Simplify the left side.
Step 5.2.1
Cancel the common factor of .
Step 5.2.1.1
Cancel the common factor.
Step 5.2.1.2
Divide by .
Step 5.3
Simplify the right side.
Step 5.3.1
Divide by .
Step 6
Take the inverse sine of both sides of the equation to extract from inside the sine.
Step 7
Step 7.1
The exact value of is .
Step 8
Set the numerator equal to zero.
Step 9
Step 9.1
Divide each term in by .
Step 9.2
Simplify the left side.
Step 9.2.1
Cancel the common factor of .
Step 9.2.1.1
Cancel the common factor.
Step 9.2.1.2
Divide by .
Step 9.3
Simplify the right side.
Step 9.3.1
Divide by .
Step 10
The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from to find the solution in the second quadrant.
Step 11
Step 11.1
Multiply both sides of the equation by .
Step 11.2
Simplify both sides of the equation.
Step 11.2.1
Simplify the left side.
Step 11.2.1.1
Simplify .
Step 11.2.1.1.1
Cancel the common factor of .
Step 11.2.1.1.1.1
Cancel the common factor.
Step 11.2.1.1.1.2
Rewrite the expression.
Step 11.2.1.1.2
Cancel the common factor of .
Step 11.2.1.1.2.1
Factor out of .
Step 11.2.1.1.2.2
Cancel the common factor.
Step 11.2.1.1.2.3
Rewrite the expression.
Step 11.2.2
Simplify the right side.
Step 11.2.2.1
Simplify .
Step 11.2.2.1.1
Subtract from .
Step 11.2.2.1.2
Cancel the common factor of .
Step 11.2.2.1.2.1
Cancel the common factor.
Step 11.2.2.1.2.2
Rewrite the expression.
Step 12
The solution to the equation .
Step 13
Evaluate the second derivative at . If the second derivative is positive, then this is a local minimum. If it is negative, then this is a local maximum.
Step 14
Step 14.1
Cancel the common factor of and .
Step 14.1.1
Factor out of .
Step 14.1.2
Cancel the common factors.
Step 14.1.2.1
Factor out of .
Step 14.1.2.2
Cancel the common factor.
Step 14.1.2.3
Rewrite the expression.
Step 14.1.2.4
Divide by .
Step 14.2
Multiply by .
Step 14.3
The exact value of is .
Step 14.4
Multiply by .
Step 15
is a local maximum because the value of the second derivative is negative. This is referred to as the second derivative test.
is a local maximum
Step 16
Step 16.1
Replace the variable with in the expression.
Step 16.2
Simplify the result.
Step 16.2.1
Cancel the common factor of and .
Step 16.2.1.1
Factor out of .
Step 16.2.1.2
Cancel the common factors.
Step 16.2.1.2.1
Factor out of .
Step 16.2.1.2.2
Cancel the common factor.
Step 16.2.1.2.3
Rewrite the expression.
Step 16.2.1.2.4
Divide by .
Step 16.2.2
Multiply by .
Step 16.2.3
The exact value of is .
Step 16.2.4
Multiply by .
Step 16.2.5
The final answer is .
Step 17
Evaluate the second derivative at . If the second derivative is positive, then this is a local minimum. If it is negative, then this is a local maximum.
Step 18
Step 18.1
Cancel the common factor of .
Step 18.1.1
Cancel the common factor.
Step 18.1.2
Divide by .
Step 18.2
Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because cosine is negative in the second quadrant.
Step 18.3
The exact value of is .
Step 18.4
Multiply .
Step 18.4.1
Multiply by .
Step 18.4.2
Multiply by .
Step 19
is a local minimum because the value of the second derivative is positive. This is referred to as the second derivative test.
is a local minimum
Step 20
Step 20.1
Replace the variable with in the expression.
Step 20.2
Simplify the result.
Step 20.2.1
Cancel the common factor of .
Step 20.2.1.1
Cancel the common factor.
Step 20.2.1.2
Divide by .
Step 20.2.2
Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because cosine is negative in the second quadrant.
Step 20.2.3
The exact value of is .
Step 20.2.4
Multiply .
Step 20.2.4.1
Multiply by .
Step 20.2.4.2
Multiply by .
Step 20.2.5
The final answer is .
Step 21
These are the local extrema for .
is a local maxima
is a local minima
Step 22