Calculus Examples

$y = \sqrt{x^{4} - 3 x + 5}$

Step 1

Write $y = \sqrt{x^{4} - 3 x + 5}$ as a function.

$f (x) = \sqrt{x^{4} - 3 x + 5}$

Step 2

Find the first derivative of the function.

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Step 2.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x^{4} - 3 x + 5}$ as ${(x^{4} - 3 x + 5)}^{\frac{1}{2}}$ .

$\frac{d}{d x} [{(x^{4} - 3 x + 5)}^{\frac{1}{2}}]$

Step 2.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{1}{2}}$ and $g (x) = x^{4} - 3 x + 5$ .

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Step 2.2.1

To apply the Chain Rule, set $u$ as $x^{4} - 3 x + 5$ .

$\frac{d}{d u} [u^{\frac{1}{2}}] \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 2.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = \frac{1}{2}$ .

$\frac{1}{2} u^{\frac{1}{2} - 1} \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 2.2.3

Replace all occurrences of $u$ with $x^{4} - 3 x + 5$ .

$\frac{1}{2} {(x^{4} - 3 x + 5)}^{\frac{1}{2} - 1} \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 2.3

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{1}{2} {(x^{4} - 3 x + 5)}^{\frac{1}{2} - 1 \cdot \frac{2}{2}} \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 2.4

Combine $- 1$ and $\frac{2}{2}$ .

$\frac{1}{2} {(x^{4} - 3 x + 5)}^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}} \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 2.5

Combine the numerators over the common denominator.

$\frac{1}{2} {(x^{4} - 3 x + 5)}^{\frac{1 - 1 \cdot 2}{2}} \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 2.6

Simplify the numerator.

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Step 2.6.1

Multiply $- 1$ by $2$ .

$\frac{1}{2} {(x^{4} - 3 x + 5)}^{\frac{1 - 2}{2}} \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 2.6.2

Subtract $2$ from $1$ .

$\frac{1}{2} {(x^{4} - 3 x + 5)}^{\frac{- 1}{2}} \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 2.7

Combine fractions.

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Step 2.7.1

Move the negative in front of the fraction.

$\frac{1}{2} {(x^{4} - 3 x + 5)}^{- \frac{1}{2}} \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 2.7.2

Combine $\frac{1}{2}$ and ${(x^{4} - 3 x + 5)}^{- \frac{1}{2}}$ .

$\frac{{(x^{4} - 3 x + 5)}^{- \frac{1}{2}}}{2} \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 2.7.3

Move ${(x^{4} - 3 x + 5)}^{- \frac{1}{2}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 2.8

By the Sum Rule, the derivative of $x^{4} - 3 x + 5$ with respect to $x$ is $\frac{d}{d x} [x^{4}] + \frac{d}{d x} [- 3 x] + \frac{d}{d x} [5]$ .

$\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} (\frac{d}{d x} [x^{4}] + \frac{d}{d x} [- 3 x] + \frac{d}{d x} [5])$

Step 2.9

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 4$ .

$\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} (4 x^{3} + \frac{d}{d x} [- 3 x] + \frac{d}{d x} [5])$

Step 2.10

Since $- 3$ is constant with respect to $x$ , the derivative of $- 3 x$ with respect to $x$ is $- 3 \frac{d}{d x} [x]$ .

$\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} (4 x^{3} - 3 \frac{d}{d x} [x] + \frac{d}{d x} [5])$

Step 2.11

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} (4 x^{3} - 3 \cdot 1 + \frac{d}{d x} [5])$

Step 2.12

Multiply $- 3$ by $1$ .

$\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} (4 x^{3} - 3 + \frac{d}{d x} [5])$

Step 2.13

Since $5$ is constant with respect to $x$ , the derivative of $5$ with respect to $x$ is $0$ .

$\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} (4 x^{3} - 3 + 0)$

Step 2.14

Add $4 x^{3} - 3$ and $0$ .

$\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} (4 x^{3} - 3)$

Step 2.15

Simplify.

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Step 2.15.1

Reorder the factors of $\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} (4 x^{3} - 3)$ .

$(4 x^{3} - 3) \frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}$

Step 2.15.2

Multiply $4 x^{3} - 3$ by $\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}$ .

$\frac{4 x^{3} - 3}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}$

Step 3

Find the second derivative of the function.

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Step 3.1

Since $\frac{1}{2}$ is constant with respect to $x$ , the derivative of $\frac{4 x^{3} - 3}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}$ with respect to $x$ is $\frac{1}{2} \frac{d}{d x} [\frac{4 x^{3} - 3}{{(x^{4} - 3 x + 5)}^{\frac{1}{2}}}]$ .

$f'' (x) = \frac{1}{2} \cdot \frac{d}{d x} (\frac{4 x^{3} - 3}{{(x^{4} - 3 x + 5)}^{\frac{1}{2}}})$

Step 3.2

Differentiate using the Quotient Rule which states that $\frac{d}{d x} [\frac{f (x)}{g (x)}]$ is $\frac{g (x) \frac{d}{d x} [f (x)] - f (x) \frac{d}{d x} [g (x)]}{{g (x)}^{2}}$ where $f (x) = 4 x^{3} - 3$ and $g (x) = {(x^{4} - 3 x + 5)}^{\frac{1}{2}}$ .

$f'' (x) = \frac{1}{2} \cdot \frac{{(x^{4} - 3 x + 5)}^{\frac{1}{2}} \frac{d}{d x} (4 x^{3} - 3) - (4 x^{3} - 3) \frac{d}{d x} {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}{{({(x^{4} - 3 x + 5)}^{\frac{1}{2}})}^{2}}$

Step 3.3

Multiply the exponents in ${({(x^{4} - 3 x + 5)}^{\frac{1}{2}})}^{2}$ .

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Step 3.3.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$f'' (x) = \frac{1}{2} \cdot \frac{{(x^{4} - 3 x + 5)}^{\frac{1}{2}} \frac{d}{d x} (4 x^{3} - 3) - (4 x^{3} - 3) \frac{d}{d x} {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}{{(x^{4} - 3 x + 5)}^{\frac{1}{2} \cdot 2}}$

Step 3.3.2

Cancel the common factor of $2$ .

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Step 3.3.2.1

Cancel the common factor.

Step 3.3.2.2

Rewrite the expression.

$f'' (x) = \frac{1}{2} \cdot \frac{{(x^{4} - 3 x + 5)}^{\frac{1}{2}} \frac{d}{d x} (4 x^{3} - 3) - (4 x^{3} - 3) \frac{d}{d x} {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}{x^{4} - 3 x + 5}$

Step 3.4

Simplify.

$f'' (x) = \frac{1}{2} \cdot \frac{{(x^{4} - 3 x + 5)}^{\frac{1}{2}} \frac{d}{d x} (4 x^{3} - 3) - (4 x^{3} - 3) \frac{d}{d x} {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}{x^{4} - 3 x + 5}$

Step 3.5

Differentiate.

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Step 3.5.1

By the Sum Rule, the derivative of $4 x^{3} - 3$ with respect to $x$ is $\frac{d}{d x} [4 x^{3}] + \frac{d}{d x} [- 3]$ .

$f'' (x) = \frac{1}{2} \cdot \frac{{(x^{4} - 3 x + 5)}^{\frac{1}{2}} (\frac{d}{d x} (4 x^{3}) + \frac{d}{d x} (- 3)) - (4 x^{3} - 3) \frac{d}{d x} {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}{x^{4} - 3 x + 5}$

Step 3.5.2

Since $4$ is constant with respect to $x$ , the derivative of $4 x^{3}$ with respect to $x$ is $4 \frac{d}{d x} [x^{3}]$ .

$f'' (x) = \frac{1}{2} \cdot \frac{{(x^{4} - 3 x + 5)}^{\frac{1}{2}} (4 \frac{d}{d x} (x^{3}) + \frac{d}{d x} (- 3)) - (4 x^{3} - 3) \frac{d}{d x} {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}{x^{4} - 3 x + 5}$

Step 3.5.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$f'' (x) = \frac{1}{2} \cdot \frac{{(x^{4} - 3 x + 5)}^{\frac{1}{2}} (4 (3 x^{2}) + \frac{d}{d x} (- 3)) - (4 x^{3} - 3) \frac{d}{d x} {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}{x^{4} - 3 x + 5}$

Step 3.5.4

Multiply $3$ by $4$ .

$f'' (x) = \frac{1}{2} \cdot \frac{{(x^{4} - 3 x + 5)}^{\frac{1}{2}} (12 x^{2} + \frac{d}{d x} (- 3)) - (4 x^{3} - 3) \frac{d}{d x} {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}{x^{4} - 3 x + 5}$

Step 3.5.5

Since $- 3$ is constant with respect to $x$ , the derivative of $- 3$ with respect to $x$ is $0$ .

$f'' (x) = \frac{1}{2} \cdot \frac{{(x^{4} - 3 x + 5)}^{\frac{1}{2}} (12 x^{2} + 0) - (4 x^{3} - 3) \frac{d}{d x} {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}{x^{4} - 3 x + 5}$

Step 3.5.6

Simplify the expression.

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Step 3.5.6.1

Add $12 x^{2}$ and $0$ .

$f'' (x) = \frac{1}{2} \cdot \frac{{(x^{4} - 3 x + 5)}^{\frac{1}{2}} (12 x^{2}) - (4 x^{3} - 3) \frac{d}{d x} {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}{x^{4} - 3 x + 5}$

Step 3.5.6.2

Move $12$ to the left of ${(x^{4} - 3 x + 5)}^{\frac{1}{2}}$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 \cdot ({(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2}) - (4 x^{3} - 3) \frac{d}{d x} {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}{x^{4} - 3 x + 5}$

Step 3.6

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{1}{2}}$ and $g (x) = x^{4} - 3 x + 5$ .

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Step 3.6.1

To apply the Chain Rule, set $u$ as $x^{4} - 3 x + 5$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - (4 x^{3} - 3) (\frac{d}{d u} (u^{\frac{1}{2}}) \frac{d}{d x} (x^{4} - 3 x + 5))}{x^{4} - 3 x + 5}$

Step 3.6.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = \frac{1}{2}$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - (4 x^{3} - 3) (\frac{1}{2} u^{\frac{1}{2} - 1} \frac{d}{d x} (x^{4} - 3 x + 5))}{x^{4} - 3 x + 5}$

Step 3.6.3

Replace all occurrences of $u$ with $x^{4} - 3 x + 5$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - (4 x^{3} - 3) (\frac{1}{2} \cdot {(x^{4} - 3 x + 5)}^{\frac{1}{2} - 1} \frac{d}{d x} (x^{4} - 3 x + 5))}{x^{4} - 3 x + 5}$

Step 3.7

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - (4 x^{3} - 3) (\frac{1}{2} \cdot {(x^{4} - 3 x + 5)}^{\frac{1}{2} - 1 \cdot \frac{2}{2}} \frac{d}{d x} (x^{4} - 3 x + 5))}{x^{4} - 3 x + 5}$

Step 3.8

Combine $- 1$ and $\frac{2}{2}$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - (4 x^{3} - 3) (\frac{1}{2} \cdot {(x^{4} - 3 x + 5)}^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}} \frac{d}{d x} (x^{4} - 3 x + 5))}{x^{4} - 3 x + 5}$

Step 3.9

Combine the numerators over the common denominator.

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - (4 x^{3} - 3) (\frac{1}{2} \cdot {(x^{4} - 3 x + 5)}^{\frac{1 - 1 \cdot 2}{2}} \frac{d}{d x} (x^{4} - 3 x + 5))}{x^{4} - 3 x + 5}$

Step 3.10

Simplify the numerator.

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Step 3.10.1

Multiply $- 1$ by $2$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - (4 x^{3} - 3) (\frac{1}{2} \cdot {(x^{4} - 3 x + 5)}^{\frac{1 - 2}{2}} \frac{d}{d x} (x^{4} - 3 x + 5))}{x^{4} - 3 x + 5}$

Step 3.10.2

Subtract $2$ from $1$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - (4 x^{3} - 3) (\frac{1}{2} \cdot {(x^{4} - 3 x + 5)}^{\frac{- 1}{2}} \frac{d}{d x} (x^{4} - 3 x + 5))}{x^{4} - 3 x + 5}$

Step 3.11

Combine fractions.

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Step 3.11.1

Move the negative in front of the fraction.

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - (4 x^{3} - 3) (\frac{1}{2} \cdot {(x^{4} - 3 x + 5)}^{- \frac{1}{2}} \frac{d}{d x} (x^{4} - 3 x + 5))}{x^{4} - 3 x + 5}$

Step 3.11.2

Combine $\frac{1}{2}$ and ${(x^{4} - 3 x + 5)}^{- \frac{1}{2}}$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - (4 x^{3} - 3) (\frac{{(x^{4} - 3 x + 5)}^{- \frac{1}{2}}}{2} \cdot \frac{d}{d x} (x^{4} - 3 x + 5))}{x^{4} - 3 x + 5}$

Step 3.11.3

Move ${(x^{4} - 3 x + 5)}^{- \frac{1}{2}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - (4 x^{3} - 3) (\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} \cdot \frac{d}{d x} (x^{4} - 3 x + 5))}{x^{4} - 3 x + 5}$

Step 3.12

By the Sum Rule, the derivative of $x^{4} - 3 x + 5$ with respect to $x$ is $\frac{d}{d x} [x^{4}] + \frac{d}{d x} [- 3 x] + \frac{d}{d x} [5]$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - (4 x^{3} - 3) (\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} \cdot (\frac{d}{d x} (x^{4}) + \frac{d}{d x} (- 3 x) + \frac{d}{d x} (5)))}{x^{4} - 3 x + 5}$

Step 3.13

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 4$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - (4 x^{3} - 3) (\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} \cdot (4 x^{3} + \frac{d}{d x} (- 3 x) + \frac{d}{d x} (5)))}{x^{4} - 3 x + 5}$

Step 3.14

Since $- 3$ is constant with respect to $x$ , the derivative of $- 3 x$ with respect to $x$ is $- 3 \frac{d}{d x} [x]$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - (4 x^{3} - 3) (\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} \cdot (4 x^{3} - 3 \frac{d}{d x} x + \frac{d}{d x} (5)))}{x^{4} - 3 x + 5}$

Step 3.15

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - (4 x^{3} - 3) (\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} \cdot (4 x^{3} - 3 \cdot 1 + \frac{d}{d x} (5)))}{x^{4} - 3 x + 5}$

Step 3.16

Multiply $- 3$ by $1$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - (4 x^{3} - 3) (\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} \cdot (4 x^{3} - 3 + \frac{d}{d x} (5)))}{x^{4} - 3 x + 5}$

Step 3.17

Since $5$ is constant with respect to $x$ , the derivative of $5$ with respect to $x$ is $0$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - (4 x^{3} - 3) (\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} \cdot (4 x^{3} - 3 + 0))}{x^{4} - 3 x + 5}$

Step 3.18

Add $4 x^{3} - 3$ and $0$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - (4 x^{3} - 3) (\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} \cdot (4 x^{3} - 3))}{x^{4} - 3 x + 5}$

Step 3.19

Raise $4 x^{3} - 3$ to the power of $1$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - (4 x^{3} - 3) (4 x^{3} - 3) \frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}}{x^{4} - 3 x + 5}$

Step 3.20

Raise $4 x^{3} - 3$ to the power of $1$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - (4 x^{3} - 3) (4 x^{3} - 3) \frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}}{x^{4} - 3 x + 5}$

Step 3.21

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - {(4 x^{3} - 3)}^{1 + 1} \frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}}{x^{4} - 3 x + 5}$

Step 3.22

Add $1$ and $1$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - {(4 x^{3} - 3)}^{2} \frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}}{x^{4} - 3 x + 5}$

Step 3.23

Combine $\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}$ and ${(4 x^{3} - 3)}^{2}$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} - \frac{{(4 x^{3} - 3)}^{2}}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}}{x^{4} - 3 x + 5}$

Step 3.24

To write $12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2}$ as a fraction with a common denominator, multiply by $\frac{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}$ .

$f'' (x) = \frac{1}{2} \cdot \frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} \cdot \frac{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} - \frac{{(4 x^{3} - 3)}^{2}}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}}{x^{4} - 3 x + 5}$

Step 3.25

Combine $12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2}$ and $\frac{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}$ .

$f'' (x) = \frac{1}{2} \cdot \frac{\frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} (2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}})}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} - \frac{{(4 x^{3} - 3)}^{2}}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}}{x^{4} - 3 x + 5}$

Step 3.26

Combine the numerators over the common denominator.

$f'' (x) = \frac{1}{2} \cdot \frac{\frac{12 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} (2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}) - {(4 x^{3} - 3)}^{2}}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}}{x^{4} - 3 x + 5}$

Step 3.27

Multiply $2$ by $12$ .

$f'' (x) = \frac{1}{2} \cdot \frac{\frac{24 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} x^{2} {(x^{4} - 3 x + 5)}^{\frac{1}{2}} - {(4 x^{3} - 3)}^{2}}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}}{x^{4} - 3 x + 5}$

Step 3.28

Multiply ${(x^{4} - 3 x + 5)}^{\frac{1}{2}}$ by ${(x^{4} - 3 x + 5)}^{\frac{1}{2}}$ by adding the exponents.

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Step 3.28.1

Move ${(x^{4} - 3 x + 5)}^{\frac{1}{2}}$ .

$f'' (x) = \frac{1}{2} \cdot \frac{\frac{24 ({(x^{4} - 3 x + 5)}^{\frac{1}{2}} {(x^{4} - 3 x + 5)}^{\frac{1}{2}}) x^{2} - {(4 x^{3} - 3)}^{2}}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}}{x^{4} - 3 x + 5}$

Step 3.28.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f'' (x) = \frac{1}{2} \cdot \frac{\frac{24 {(x^{4} - 3 x + 5)}^{\frac{1}{2} + \frac{1}{2}} x^{2} - {(4 x^{3} - 3)}^{2}}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}}{x^{4} - 3 x + 5}$

Step 3.28.3

Combine the numerators over the common denominator.

$f'' (x) = \frac{1}{2} \cdot \frac{\frac{24 {(x^{4} - 3 x + 5)}^{\frac{1 + 1}{2}} x^{2} - {(4 x^{3} - 3)}^{2}}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}}{x^{4} - 3 x + 5}$

Step 3.28.4

Add $1$ and $1$ .

$f'' (x) = \frac{1}{2} \cdot \frac{\frac{24 {(x^{4} - 3 x + 5)}^{\frac{2}{2}} x^{2} - {(4 x^{3} - 3)}^{2}}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}}{x^{4} - 3 x + 5}$

Step 3.28.5

Divide $2$ by $2$ .

$f'' (x) = \frac{1}{2} \cdot \frac{\frac{24 (x^{4} - 3 x + 5) x^{2} - {(4 x^{3} - 3)}^{2}}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}}{x^{4} - 3 x + 5}$

Step 3.29

Simplify $24 {(x^{4} - 3 x + 5)}^{1} x^{2}$ .

$f'' (x) = \frac{1}{2} \cdot \frac{\frac{24 (x^{4} - 3 x + 5) x^{2} - {(4 x^{3} - 3)}^{2}}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}}{x^{4} - 3 x + 5}$

Step 3.30

Rewrite $\frac{\frac{24 (x^{4} - 3 x + 5) x^{2} - {(4 x^{3} - 3)}^{2}}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}}{x^{4} - 3 x + 5}$ as a product.

$f'' (x) = \frac{1}{2} \cdot (\frac{24 (x^{4} - 3 x + 5) x^{2} - {(4 x^{3} - 3)}^{2}}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} \cdot \frac{1}{x^{4} - 3 x + 5})$

Step 3.31

Multiply $\frac{24 (x^{4} - 3 x + 5) x^{2} - {(4 x^{3} - 3)}^{2}}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}$ by $\frac{1}{x^{4} - 3 x + 5}$ .

$f'' (x) = \frac{1}{2} \cdot \frac{24 (x^{4} - 3 x + 5) x^{2} - {(4 x^{3} - 3)}^{2}}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}} (x^{4} - 3 x + 5)}$

Step 3.32

Raise $x^{4} - 3 x + 5$ to the power of $1$ .

$f'' (x) = \frac{1}{2} \cdot \frac{24 (x^{4} - 3 x + 5) x^{2} - {(4 x^{3} - 3)}^{2}}{2 ((x^{4} - 3 x + 5) {(x^{4} - 3 x + 5)}^{\frac{1}{2}})}$

Step 3.33

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f'' (x) = \frac{1}{2} \cdot \frac{24 (x^{4} - 3 x + 5) x^{2} - {(4 x^{3} - 3)}^{2}}{2 {(x^{4} - 3 x + 5)}^{1 + \frac{1}{2}}}$

Step 3.34

Simplify the expression.

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Step 3.34.1

Write $1$ as a fraction with a common denominator.

$f'' (x) = \frac{1}{2} \cdot \frac{24 (x^{4} - 3 x + 5) x^{2} - {(4 x^{3} - 3)}^{2}}{2 {(x^{4} - 3 x + 5)}^{\frac{2}{2} + \frac{1}{2}}}$

Step 3.34.2

Combine the numerators over the common denominator.

$f'' (x) = \frac{1}{2} \cdot \frac{24 (x^{4} - 3 x + 5) x^{2} - {(4 x^{3} - 3)}^{2}}{2 {(x^{4} - 3 x + 5)}^{\frac{2 + 1}{2}}}$

Step 3.34.3

Add $2$ and $1$ .

$f'' (x) = \frac{1}{2} \cdot \frac{24 (x^{4} - 3 x + 5) x^{2} - {(4 x^{3} - 3)}^{2}}{2 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.35

Multiply $\frac{1}{2}$ by $\frac{24 (x^{4} - 3 x + 5) x^{2} - {(4 x^{3} - 3)}^{2}}{2 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$ .

$f'' (x) = \frac{24 (x^{4} - 3 x + 5) x^{2} - {(4 x^{3} - 3)}^{2}}{2 (2 {(x^{4} - 3 x + 5)}^{\frac{3}{2}})}$

Step 3.36

Multiply $2$ by $2$ .

$f'' (x) = \frac{24 (x^{4} - 3 x + 5) x^{2} - {(4 x^{3} - 3)}^{2}}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37

Simplify.

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Step 3.37.1

Apply the distributive property.

$f'' (x) = \frac{(24 x^{4} + 24 (- 3 x) + 24 \cdot 5) x^{2} - {(4 x^{3} - 3)}^{2}}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.2

Apply the distributive property.

$f'' (x) = \frac{24 x^{4} x^{2} + 24 (- 3 x) x^{2} + 24 \cdot (5 x^{2}) - {(4 x^{3} - 3)}^{2}}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3

Simplify the numerator.

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Step 3.37.3.1

Simplify each term.

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Step 3.37.3.1.1

Multiply $x^{4}$ by $x^{2}$ by adding the exponents.

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Step 3.37.3.1.1.1

Move $x^{2}$ .

$f'' (x) = \frac{24 (x^{2} x^{4}) + 24 (- 3 x) x^{2} + 24 \cdot (5 x^{2}) - {(4 x^{3} - 3)}^{2}}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f'' (x) = \frac{24 x^{2 + 4} + 24 (- 3 x) x^{2} + 24 \cdot (5 x^{2}) - {(4 x^{3} - 3)}^{2}}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.1.3

Add $2$ and $4$ .

$f'' (x) = \frac{24 x^{6} + 24 (- 3 x) x^{2} + 24 \cdot (5 x^{2}) - {(4 x^{3} - 3)}^{2}}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.2

Multiply $x$ by $x^{2}$ by adding the exponents.

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Step 3.37.3.1.2.1

Move $x^{2}$ .

$f'' (x) = \frac{24 x^{6} + 24 (- 3 (x^{2} x)) + 24 \cdot (5 x^{2}) - {(4 x^{3} - 3)}^{2}}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.2.2

Multiply $x^{2}$ by $x$ .

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Step 3.37.3.1.2.2.1

Raise $x$ to the power of $1$ .

$f'' (x) = \frac{24 x^{6} + 24 (- 3 (x^{2} x)) + 24 \cdot (5 x^{2}) - {(4 x^{3} - 3)}^{2}}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.2.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f'' (x) = \frac{24 x^{6} + 24 (- 3 x^{2 + 1}) + 24 \cdot (5 x^{2}) - {(4 x^{3} - 3)}^{2}}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.2.3

Add $2$ and $1$ .

$f'' (x) = \frac{24 x^{6} + 24 (- 3 x^{3}) + 24 \cdot (5 x^{2}) - {(4 x^{3} - 3)}^{2}}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.3

Multiply $- 3$ by $24$ .

$f'' (x) = \frac{24 x^{6} - 72 x^{3} + 24 \cdot (5 x^{2}) - {(4 x^{3} - 3)}^{2}}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.4

Multiply $24$ by $5$ .

$f'' (x) = \frac{24 x^{6} - 72 x^{3} + 120 x^{2} - {(4 x^{3} - 3)}^{2}}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.5

Rewrite ${(4 x^{3} - 3)}^{2}$ as $(4 x^{3} - 3) (4 x^{3} - 3)$ .

$f'' (x) = \frac{24 x^{6} - 72 x^{3} + 120 x^{2} - ((4 x^{3} - 3) (4 x^{3} - 3))}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.6

Expand $(4 x^{3} - 3) (4 x^{3} - 3)$ using the FOIL Method.

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Step 3.37.3.1.6.1

Apply the distributive property.

$f'' (x) = \frac{24 x^{6} - 72 x^{3} + 120 x^{2} - (4 x^{3} (4 x^{3} - 3) - 3 (4 x^{3} - 3))}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.6.2

Apply the distributive property.

$f'' (x) = \frac{24 x^{6} - 72 x^{3} + 120 x^{2} - (4 x^{3} (4 x^{3}) + 4 x^{3} \cdot - 3 - 3 (4 x^{3} - 3))}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.6.3

Apply the distributive property.

$f'' (x) = \frac{24 x^{6} - 72 x^{3} + 120 x^{2} - (4 x^{3} (4 x^{3}) + 4 x^{3} \cdot - 3 - 3 (4 x^{3}) - 3 \cdot - 3)}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.7

Simplify and combine like terms.

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Step 3.37.3.1.7.1

Simplify each term.

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Step 3.37.3.1.7.1.1

Rewrite using the commutative property of multiplication.

$f'' (x) = \frac{24 x^{6} - 72 x^{3} + 120 x^{2} - (4 \cdot (4 x^{3} x^{3}) + 4 x^{3} \cdot - 3 - 3 (4 x^{3}) - 3 \cdot - 3)}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.7.1.2

Multiply $x^{3}$ by $x^{3}$ by adding the exponents.

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Step 3.37.3.1.7.1.2.1

Move $x^{3}$ .

$f'' (x) = \frac{24 x^{6} - 72 x^{3} + 120 x^{2} - (4 \cdot (4 (x^{3} x^{3})) + 4 x^{3} \cdot - 3 - 3 (4 x^{3}) - 3 \cdot - 3)}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.7.1.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f'' (x) = \frac{24 x^{6} - 72 x^{3} + 120 x^{2} - (4 \cdot (4 x^{3 + 3}) + 4 x^{3} \cdot - 3 - 3 (4 x^{3}) - 3 \cdot - 3)}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.7.1.2.3

Add $3$ and $3$ .

$f'' (x) = \frac{24 x^{6} - 72 x^{3} + 120 x^{2} - (4 \cdot (4 x^{6}) + 4 x^{3} \cdot - 3 - 3 (4 x^{3}) - 3 \cdot - 3)}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.7.1.3

Multiply $4$ by $4$ .

$f'' (x) = \frac{24 x^{6} - 72 x^{3} + 120 x^{2} - (16 x^{6} + 4 x^{3} \cdot - 3 - 3 (4 x^{3}) - 3 \cdot - 3)}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.7.1.4

Multiply $- 3$ by $4$ .

$f'' (x) = \frac{24 x^{6} - 72 x^{3} + 120 x^{2} - (16 x^{6} - 12 x^{3} - 3 (4 x^{3}) - 3 \cdot - 3)}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.7.1.5

Multiply $4$ by $- 3$ .

$f'' (x) = \frac{24 x^{6} - 72 x^{3} + 120 x^{2} - (16 x^{6} - 12 x^{3} - 12 x^{3} - 3 \cdot - 3)}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.7.1.6

Multiply $- 3$ by $- 3$ .

$f'' (x) = \frac{24 x^{6} - 72 x^{3} + 120 x^{2} - (16 x^{6} - 12 x^{3} - 12 x^{3} + 9)}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.7.2

Subtract $12 x^{3}$ from $- 12 x^{3}$ .

$f'' (x) = \frac{24 x^{6} - 72 x^{3} + 120 x^{2} - (16 x^{6} - 24 x^{3} + 9)}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.8

Apply the distributive property.

$f'' (x) = \frac{24 x^{6} - 72 x^{3} + 120 x^{2} - (16 x^{6}) - (- 24 x^{3}) - 1 \cdot 9}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.9

Simplify.

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Step 3.37.3.1.9.1

Multiply $16$ by $- 1$ .

$f'' (x) = \frac{24 x^{6} - 72 x^{3} + 120 x^{2} - 16 x^{6} - (- 24 x^{3}) - 1 \cdot 9}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.9.2

Multiply $- 24$ by $- 1$ .

$f'' (x) = \frac{24 x^{6} - 72 x^{3} + 120 x^{2} - 16 x^{6} + 24 x^{3} - 1 \cdot 9}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.1.9.3

Multiply $- 1$ by $9$ .

$f'' (x) = \frac{24 x^{6} - 72 x^{3} + 120 x^{2} - 16 x^{6} + 24 x^{3} - 9}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.2

Subtract $16 x^{6}$ from $24 x^{6}$ .

$f'' (x) = \frac{8 x^{6} - 72 x^{3} + 120 x^{2} + 24 x^{3} - 9}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 3.37.3.3

Add $- 72 x^{3}$ and $24 x^{3}$ .

$f'' (x) = \frac{8 x^{6} - 48 x^{3} + 120 x^{2} - 9}{4 {(x^{4} - 3 x + 5)}^{\frac{3}{2}}}$

Step 4

To find the local maximum and minimum values of the function, set the derivative equal to $0$ and solve.

$\frac{4 x^{3} - 3}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} = 0$

Step 5

Find the first derivative.

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Step 5.1

Find the first derivative.

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Step 5.1.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x^{4} - 3 x + 5}$ as ${(x^{4} - 3 x + 5)}^{\frac{1}{2}}$ .

$\frac{d}{d x} [{(x^{4} - 3 x + 5)}^{\frac{1}{2}}]$

Step 5.1.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{1}{2}}$ and $g (x) = x^{4} - 3 x + 5$ .

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Step 5.1.2.1

To apply the Chain Rule, set $u$ as $x^{4} - 3 x + 5$ .

$\frac{d}{d u} [u^{\frac{1}{2}}] \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 5.1.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = \frac{1}{2}$ .

$\frac{1}{2} u^{\frac{1}{2} - 1} \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 5.1.2.3

Replace all occurrences of $u$ with $x^{4} - 3 x + 5$ .

$\frac{1}{2} {(x^{4} - 3 x + 5)}^{\frac{1}{2} - 1} \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 5.1.3

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{1}{2} {(x^{4} - 3 x + 5)}^{\frac{1}{2} - 1 \cdot \frac{2}{2}} \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 5.1.4

Combine $- 1$ and $\frac{2}{2}$ .

$\frac{1}{2} {(x^{4} - 3 x + 5)}^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}} \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 5.1.5

Combine the numerators over the common denominator.

$\frac{1}{2} {(x^{4} - 3 x + 5)}^{\frac{1 - 1 \cdot 2}{2}} \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 5.1.6

Simplify the numerator.

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Step 5.1.6.1

Multiply $- 1$ by $2$ .

$\frac{1}{2} {(x^{4} - 3 x + 5)}^{\frac{1 - 2}{2}} \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 5.1.6.2

Subtract $2$ from $1$ .

$\frac{1}{2} {(x^{4} - 3 x + 5)}^{\frac{- 1}{2}} \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 5.1.7

Combine fractions.

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Step 5.1.7.1

Move the negative in front of the fraction.

$\frac{1}{2} {(x^{4} - 3 x + 5)}^{- \frac{1}{2}} \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 5.1.7.2

Combine $\frac{1}{2}$ and ${(x^{4} - 3 x + 5)}^{- \frac{1}{2}}$ .

$\frac{{(x^{4} - 3 x + 5)}^{- \frac{1}{2}}}{2} \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 5.1.7.3

Move ${(x^{4} - 3 x + 5)}^{- \frac{1}{2}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} \frac{d}{d x} [x^{4} - 3 x + 5]$

Step 5.1.8

By the Sum Rule, the derivative of $x^{4} - 3 x + 5$ with respect to $x$ is $\frac{d}{d x} [x^{4}] + \frac{d}{d x} [- 3 x] + \frac{d}{d x} [5]$ .

$\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} (\frac{d}{d x} [x^{4}] + \frac{d}{d x} [- 3 x] + \frac{d}{d x} [5])$

Step 5.1.9

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 4$ .

$\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} (4 x^{3} + \frac{d}{d x} [- 3 x] + \frac{d}{d x} [5])$

Step 5.1.10

Since $- 3$ is constant with respect to $x$ , the derivative of $- 3 x$ with respect to $x$ is $- 3 \frac{d}{d x} [x]$ .

$\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} (4 x^{3} - 3 \frac{d}{d x} [x] + \frac{d}{d x} [5])$

Step 5.1.11

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} (4 x^{3} - 3 \cdot 1 + \frac{d}{d x} [5])$

Step 5.1.12

Multiply $- 3$ by $1$ .

$\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} (4 x^{3} - 3 + \frac{d}{d x} [5])$

Step 5.1.13

Since $5$ is constant with respect to $x$ , the derivative of $5$ with respect to $x$ is $0$ .

$\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} (4 x^{3} - 3 + 0)$

Step 5.1.14

Add $4 x^{3} - 3$ and $0$ .

$\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} (4 x^{3} - 3)$

Step 5.1.15

Simplify.

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Step 5.1.15.1

Reorder the factors of $\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} (4 x^{3} - 3)$ .

$(4 x^{3} - 3) \frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}$

Step 5.1.15.2

Multiply $4 x^{3} - 3$ by $\frac{1}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}$ .

$f' (x) = \frac{4 x^{3} - 3}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}$

Step 5.2

The first derivative of $f (x)$ with respect to $x$ is $\frac{4 x^{3} - 3}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}$ .

$\frac{4 x^{3} - 3}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}}$

Step 6

Set the first derivative equal to $0$ then solve the equation $\frac{4 x^{3} - 3}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} = 0$ .

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Step 6.1

Set the first derivative equal to $0$ .

$\frac{4 x^{3} - 3}{2 {(x^{4} - 3 x + 5)}^{\frac{1}{2}}} = 0$

Step 6.2

Set the numerator equal to zero.

$4 x^{3} - 3 = 0$

Step 6.3

Solve the equation for $x$ .

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Step 6.3.1

Add $3$ to both sides of the equation.

$4 x^{3} = 3$

Step 6.3.2

Divide each term in $4 x^{3} = 3$ by $4$ and simplify.

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Step 6.3.2.1

Divide each term in $4 x^{3} = 3$ by $4$ .

$\frac{4 x^{3}}{4} = \frac{3}{4}$

Step 6.3.2.2

Simplify the left side.

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Step 6.3.2.2.1

Cancel the common factor of $4$ .

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Step 6.3.2.2.1.1

Cancel the common factor.

$\frac{4 x^{3}}{4} = \frac{3}{4}$

Step 6.3.2.2.1.2

Divide $x^{3}$ by $1$ .

$x^{3} = \frac{3}{4}$

Step 6.3.3

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \sqrt[3]{\frac{3}{4}}$

Step 6.3.4

Simplify $\sqrt[3]{\frac{3}{4}}$ .

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Step 6.3.4.1

Rewrite $\sqrt[3]{\frac{3}{4}}$ as $\frac{\sqrt[3]{3}}{\sqrt[3]{4}}$ .

$x = \frac{\sqrt[3]{3}}{\sqrt[3]{4}}$

Step 6.3.4.2

Multiply $\frac{\sqrt[3]{3}}{\sqrt[3]{4}}$ by $\frac{{\sqrt[3]{4}}^{2}}{{\sqrt[3]{4}}^{2}}$ .

$x = \frac{\sqrt[3]{3}}{\sqrt[3]{4}} \cdot \frac{{\sqrt[3]{4}}^{2}}{{\sqrt[3]{4}}^{2}}$

Step 6.3.4.3

Combine and simplify the denominator.

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Step 6.3.4.3.1

Multiply $\frac{\sqrt[3]{3}}{\sqrt[3]{4}}$ by $\frac{{\sqrt[3]{4}}^{2}}{{\sqrt[3]{4}}^{2}}$ .

$x = \frac{\sqrt[3]{3} {\sqrt[3]{4}}^{2}}{\sqrt[3]{4} {\sqrt[3]{4}}^{2}}$

Step 6.3.4.3.2

Raise $\sqrt[3]{4}$ to the power of $1$ .

$x = \frac{\sqrt[3]{3} {\sqrt[3]{4}}^{2}}{{\sqrt[3]{4}}^{1} {\sqrt[3]{4}}^{2}}$

Step 6.3.4.3.3

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x = \frac{\sqrt[3]{3} {\sqrt[3]{4}}^{2}}{{\sqrt[3]{4}}^{1 + 2}}$

Step 6.3.4.3.4

Add $1$ and $2$ .

$x = \frac{\sqrt[3]{3} {\sqrt[3]{4}}^{2}}{{\sqrt[3]{4}}^{3}}$

Step 6.3.4.3.5

Rewrite ${\sqrt[3]{4}}^{3}$ as $4$ .

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Step 6.3.4.3.5.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[3]{4}$ as $4^{\frac{1}{3}}$ .

$x = \frac{\sqrt[3]{3} {\sqrt[3]{4}}^{2}}{{(4^{\frac{1}{3}})}^{3}}$

Step 6.3.4.3.5.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x = \frac{\sqrt[3]{3} {\sqrt[3]{4}}^{2}}{4^{\frac{1}{3} \cdot 3}}$

Step 6.3.4.3.5.3

Combine $\frac{1}{3}$ and $3$ .

$x = \frac{\sqrt[3]{3} {\sqrt[3]{4}}^{2}}{4^{\frac{3}{3}}}$

Step 6.3.4.3.5.4

Cancel the common factor of $3$ .

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Step 6.3.4.3.5.4.1

Cancel the common factor.

$x = \frac{\sqrt[3]{3} {\sqrt[3]{4}}^{2}}{4^{\frac{3}{3}}}$

Step 6.3.4.3.5.4.2

Rewrite the expression.

$x = \frac{\sqrt[3]{3} {\sqrt[3]{4}}^{2}}{4^{1}}$

Step 6.3.4.3.5.5

Evaluate the exponent.

$x = \frac{\sqrt[3]{3} {\sqrt[3]{4}}^{2}}{4}$

Step 6.3.4.4

Simplify the numerator.

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Step 6.3.4.4.1

Rewrite ${\sqrt[3]{4}}^{2}$ as $\sqrt[3]{4^{2}}$ .

$x = \frac{\sqrt[3]{3} \sqrt[3]{4^{2}}}{4}$

Step 6.3.4.4.2

Raise $4$ to the power of $2$ .

$x = \frac{\sqrt[3]{3} \sqrt[3]{16}}{4}$

Step 6.3.4.4.3

Rewrite $16$ as $2^{3} \cdot 2$ .

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Step 6.3.4.4.3.1

Factor $8$ out of $16$ .

$x = \frac{\sqrt[3]{3} \sqrt[3]{8 (2)}}{4}$

Step 6.3.4.4.3.2

Rewrite $8$ as $2^{3}$ .

$x = \frac{\sqrt[3]{3} \sqrt[3]{2^{3} \cdot 2}}{4}$

Step 6.3.4.4.4

Pull terms out from under the radical.

$x = \frac{\sqrt[3]{3} \cdot 2 \sqrt[3]{2}}{4}$

Step 6.3.4.4.5

Combine exponents.

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Step 6.3.4.4.5.1

Combine using the product rule for radicals.

$x = \frac{2 \sqrt[3]{3 \cdot 2}}{4}$

Step 6.3.4.4.5.2

Multiply $3$ by $2$ .

$x = \frac{2 \sqrt[3]{6}}{4}$

Step 6.3.4.5

Cancel the common factor of $2$ and $4$ .

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Step 6.3.4.5.1

Factor $2$ out of $2 \sqrt[3]{6}$ .

$x = \frac{2 (\sqrt[3]{6})}{4}$

Step 6.3.4.5.2

Cancel the common factors.

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Step 6.3.4.5.2.1

Factor $2$ out of $4$ .

$x = \frac{2 \sqrt[3]{6}}{2 \cdot 2}$

Step 6.3.4.5.2.2

Cancel the common factor.

$x = \frac{2 \sqrt[3]{6}}{2 \cdot 2}$

Step 6.3.4.5.2.3

Rewrite the expression.

$x = \frac{\sqrt[3]{6}}{2}$

Step 7

Find the values where the derivative is undefined.

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Step 7.1

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Step 8

Critical points to evaluate.

$x = \frac{\sqrt[3]{6}}{2}$

Step 9

Evaluate the second derivative at $x = \frac{\sqrt[3]{6}}{2}$ . If the second derivative is positive, then this is a local minimum. If it is negative, then this is a local maximum.

$\frac{8 {(\frac{\sqrt[3]{6}}{2})}^{6} - 48 {(\frac{\sqrt[3]{6}}{2})}^{3} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10

Evaluate the second derivative.

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Step 10.1

Simplify the numerator.

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Step 10.1.1

Apply the product rule to $\frac{\sqrt[3]{6}}{2}$ .

$\frac{8 \frac{{\sqrt[3]{6}}^{6}}{2^{6}} - 48 {(\frac{\sqrt[3]{6}}{2})}^{3} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.2

Simplify the numerator.

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Step 10.1.2.1

Rewrite ${\sqrt[3]{6}}^{6}$ as $6^{2}$ .

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Step 10.1.2.1.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[3]{6}$ as $6^{\frac{1}{3}}$ .

$\frac{8 \frac{{(6^{\frac{1}{3}})}^{6}}{2^{6}} - 48 {(\frac{\sqrt[3]{6}}{2})}^{3} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.2.1.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{8 \frac{6^{\frac{1}{3} \cdot 6}}{2^{6}} - 48 {(\frac{\sqrt[3]{6}}{2})}^{3} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.2.1.3

Combine $\frac{1}{3}$ and $6$ .

$\frac{8 \frac{6^{\frac{6}{3}}}{2^{6}} - 48 {(\frac{\sqrt[3]{6}}{2})}^{3} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.2.1.4

Cancel the common factor of $6$ and $3$ .

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Step 10.1.2.1.4.1

Factor $3$ out of $6$ .

$\frac{8 \frac{6^{\frac{3 \cdot 2}{3}}}{2^{6}} - 48 {(\frac{\sqrt[3]{6}}{2})}^{3} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.2.1.4.2

Cancel the common factors.

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Step 10.1.2.1.4.2.1

Factor $3$ out of $3$ .

$\frac{8 \frac{6^{\frac{3 \cdot 2}{3 (1)}}}{2^{6}} - 48 {(\frac{\sqrt[3]{6}}{2})}^{3} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.2.1.4.2.2

Cancel the common factor.

$\frac{8 \frac{6^{\frac{3 \cdot 2}{3 \cdot 1}}}{2^{6}} - 48 {(\frac{\sqrt[3]{6}}{2})}^{3} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.2.1.4.2.3

Rewrite the expression.

$\frac{8 \frac{6^{\frac{2}{1}}}{2^{6}} - 48 {(\frac{\sqrt[3]{6}}{2})}^{3} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.2.1.4.2.4

Divide $2$ by $1$ .

$\frac{8 \frac{6^{2}}{2^{6}} - 48 {(\frac{\sqrt[3]{6}}{2})}^{3} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.2.2

Raise $6$ to the power of $2$ .

$\frac{8 \frac{36}{2^{6}} - 48 {(\frac{\sqrt[3]{6}}{2})}^{3} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.3

Raise $2$ to the power of $6$ .

$\frac{8 (\frac{36}{64}) - 48 {(\frac{\sqrt[3]{6}}{2})}^{3} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.4

Cancel the common factor of $8$ .

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Step 10.1.4.1

Factor $8$ out of $64$ .

$\frac{8 \frac{36}{8 (8)} - 48 {(\frac{\sqrt[3]{6}}{2})}^{3} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.4.2

Cancel the common factor.

$\frac{8 \frac{36}{8 \cdot 8} - 48 {(\frac{\sqrt[3]{6}}{2})}^{3} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.4.3

Rewrite the expression.

$\frac{\frac{36}{8} - 48 {(\frac{\sqrt[3]{6}}{2})}^{3} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.5

Cancel the common factor of $36$ and $8$ .

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Step 10.1.5.1

Factor $4$ out of $36$ .

$\frac{\frac{4 (9)}{8} - 48 {(\frac{\sqrt[3]{6}}{2})}^{3} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.5.2

Cancel the common factors.

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Step 10.1.5.2.1

Factor $4$ out of $8$ .

$\frac{\frac{4 \cdot 9}{4 \cdot 2} - 48 {(\frac{\sqrt[3]{6}}{2})}^{3} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.5.2.2

Cancel the common factor.

$\frac{\frac{4 \cdot 9}{4 \cdot 2} - 48 {(\frac{\sqrt[3]{6}}{2})}^{3} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.5.2.3

Rewrite the expression.

$\frac{\frac{9}{2} - 48 {(\frac{\sqrt[3]{6}}{2})}^{3} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.6

Apply the product rule to $\frac{\sqrt[3]{6}}{2}$ .

$\frac{\frac{9}{2} - 48 \frac{{\sqrt[3]{6}}^{3}}{2^{3}} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.7

Rewrite ${\sqrt[3]{6}}^{3}$ as $6$ .

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Step 10.1.7.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[3]{6}$ as $6^{\frac{1}{3}}$ .

$\frac{\frac{9}{2} - 48 \frac{{(6^{\frac{1}{3}})}^{3}}{2^{3}} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.7.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{\frac{9}{2} - 48 \frac{6^{\frac{1}{3} \cdot 3}}{2^{3}} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.7.3

Combine $\frac{1}{3}$ and $3$ .

$\frac{\frac{9}{2} - 48 \frac{6^{\frac{3}{3}}}{2^{3}} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.7.4

Cancel the common factor of $3$ .

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Step 10.1.7.4.1

Cancel the common factor.

$\frac{\frac{9}{2} - 48 \frac{6^{\frac{3}{3}}}{2^{3}} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.7.4.2

Rewrite the expression.

$\frac{\frac{9}{2} - 48 \frac{6^{1}}{2^{3}} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.7.5

Evaluate the exponent.

$\frac{\frac{9}{2} - 48 \frac{6}{2^{3}} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.8

Raise $2$ to the power of $3$ .

$\frac{\frac{9}{2} - 48 (\frac{6}{8}) + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.9

Cancel the common factor of $8$ .

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Step 10.1.9.1

Factor $8$ out of $- 48$ .

$\frac{\frac{9}{2} + 8 (- 6) \frac{6}{8} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.9.2

Cancel the common factor.

$\frac{\frac{9}{2} + 8 \cdot - 6 \frac{6}{8} + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.9.3

Rewrite the expression.

$\frac{\frac{9}{2} - 6 \cdot 6 + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.10

Multiply $- 6$ by $6$ .

$\frac{\frac{9}{2} - 36 + 120 {(\frac{\sqrt[3]{6}}{2})}^{2} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.11

Apply the product rule to $\frac{\sqrt[3]{6}}{2}$ .

$\frac{\frac{9}{2} - 36 + 120 \frac{{\sqrt[3]{6}}^{2}}{2^{2}} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.12

Simplify the numerator.

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Step 10.1.12.1

Rewrite ${\sqrt[3]{6}}^{2}$ as $\sqrt[3]{6^{2}}$ .

$\frac{\frac{9}{2} - 36 + 120 \frac{\sqrt[3]{6^{2}}}{2^{2}} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.12.2

Raise $6$ to the power of $2$ .

$\frac{\frac{9}{2} - 36 + 120 \frac{\sqrt[3]{36}}{2^{2}} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.13

Raise $2$ to the power of $2$ .

$\frac{\frac{9}{2} - 36 + 120 \frac{\sqrt[3]{36}}{4} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.14

Cancel the common factor of $4$ .

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Step 10.1.14.1

Factor $4$ out of $120$ .

$\frac{\frac{9}{2} - 36 + 4 (30) \frac{\sqrt[3]{36}}{4} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.14.2

Cancel the common factor.

$\frac{\frac{9}{2} - 36 + 4 \cdot 30 \frac{\sqrt[3]{36}}{4} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.14.3

Rewrite the expression.

$\frac{\frac{9}{2} - 36 + 30 \sqrt[3]{36} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.15

To write $- 36$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{\frac{9}{2} - 36 \cdot \frac{2}{2} + 30 \sqrt[3]{36} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.16

Combine $- 36$ and $\frac{2}{2}$ .

$\frac{\frac{9}{2} + \frac{- 36 \cdot 2}{2} + 30 \sqrt[3]{36} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.17

Combine the numerators over the common denominator.

$\frac{\frac{9 - 36 \cdot 2}{2} + 30 \sqrt[3]{36} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.18

Simplify the numerator.

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Step 10.1.18.1

Multiply $- 36$ by $2$ .

$\frac{\frac{9 - 72}{2} + 30 \sqrt[3]{36} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.18.2

Subtract $72$ from $9$ .

$\frac{\frac{- 63}{2} + 30 \sqrt[3]{36} - 9}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.19

To write $- 9$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{\frac{- 63}{2} - 9 \cdot \frac{2}{2} + 30 \sqrt[3]{36}}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.20

Combine $- 9$ and $\frac{2}{2}$ .

$\frac{\frac{- 63}{2} + \frac{- 9 \cdot 2}{2} + 30 \sqrt[3]{36}}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.21

Combine the numerators over the common denominator.

$\frac{\frac{- 63 - 9 \cdot 2}{2} + 30 \sqrt[3]{36}}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.22

Simplify the numerator.

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Step 10.1.22.1

Multiply $- 9$ by $2$ .

$\frac{\frac{- 63 - 18}{2} + 30 \sqrt[3]{36}}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.22.2

Subtract $18$ from $- 63$ .

$\frac{\frac{- 81}{2} + 30 \sqrt[3]{36}}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.23

Move the negative in front of the fraction.

$\frac{- \frac{81}{2} + 30 \sqrt[3]{36}}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.24

To write $30 \sqrt[3]{36}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{- \frac{81}{2} + 30 \sqrt[3]{36} \cdot \frac{2}{2}}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.25

Combine $30 \sqrt[3]{36}$ and $\frac{2}{2}$ .

$\frac{- \frac{81}{2} + \frac{30 \sqrt[3]{36} \cdot 2}{2}}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.26

Combine the numerators over the common denominator.

$\frac{\frac{- 81 + 30 \sqrt[3]{36} \cdot 2}{2}}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.1.27

Multiply $2$ by $30$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {({(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.2

Simplify the denominator.

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Step 10.2.1

Simplify each term.

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Step 10.2.1.1

Apply the product rule to $\frac{\sqrt[3]{6}}{2}$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{{\sqrt[3]{6}}^{4}}{2^{4}} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.2.1.2

Simplify the numerator.

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Step 10.2.1.2.1

Rewrite ${\sqrt[3]{6}}^{4}$ as $\sqrt[3]{6^{4}}$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{\sqrt[3]{6^{4}}}{2^{4}} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.2.1.2.2

Raise $6$ to the power of $4$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{\sqrt[3]{1296}}{2^{4}} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.2.1.2.3

Rewrite $1296$ as $6^{3} \cdot 6$ .

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Step 10.2.1.2.3.1

Factor $216$ out of $1296$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{\sqrt[3]{216 (6)}}{2^{4}} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.2.1.2.3.2

Rewrite $216$ as $6^{3}$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{\sqrt[3]{6^{3} \cdot 6}}{2^{4}} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.2.1.2.4

Pull terms out from under the radical.

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{6 \sqrt[3]{6}}{2^{4}} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.2.1.3

Raise $2$ to the power of $4$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{6 \sqrt[3]{6}}{16} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.2.1.4

Cancel the common factor of $6$ and $16$ .

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Step 10.2.1.4.1

Factor $2$ out of $6 \sqrt[3]{6}$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{2 (3 \sqrt[3]{6})}{16} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.2.1.4.2

Cancel the common factors.

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Step 10.2.1.4.2.1

Factor $2$ out of $16$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{2 (3 \sqrt[3]{6})}{2 (8)} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.2.1.4.2.2

Cancel the common factor.

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{2 (3 \sqrt[3]{6})}{2 \cdot 8} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.2.1.4.2.3

Rewrite the expression.

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{3 \sqrt[3]{6}}{8} - 3 \frac{\sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.2.1.5

Combine $- 3$ and $\frac{\sqrt[3]{6}}{2}$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{3 \sqrt[3]{6}}{8} + \frac{- 3 \sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.2.1.6

Move the negative in front of the fraction.

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{3 \sqrt[3]{6}}{8} - \frac{3 \sqrt[3]{6}}{2} + 5)}^{\frac{3}{2}}}$

Step 10.2.2

Find the common denominator.

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Step 10.2.2.1

Multiply $\frac{3 \sqrt[3]{6}}{2}$ by $\frac{4}{4}$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{3 \sqrt[3]{6}}{8} - (\frac{3 \sqrt[3]{6}}{2} \cdot \frac{4}{4}) + 5)}^{\frac{3}{2}}}$

Step 10.2.2.2

Multiply $\frac{3 \sqrt[3]{6}}{2}$ by $\frac{4}{4}$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{3 \sqrt[3]{6}}{8} - \frac{3 \sqrt[3]{6} \cdot 4}{2 \cdot 4} + 5)}^{\frac{3}{2}}}$

Step 10.2.2.3

Write $5$ as a fraction with denominator $1$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{3 \sqrt[3]{6}}{8} - \frac{3 \sqrt[3]{6} \cdot 4}{2 \cdot 4} + \frac{5}{1})}^{\frac{3}{2}}}$

Step 10.2.2.4

Multiply $\frac{5}{1}$ by $\frac{8}{8}$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{3 \sqrt[3]{6}}{8} - \frac{3 \sqrt[3]{6} \cdot 4}{2 \cdot 4} + \frac{5}{1} \cdot \frac{8}{8})}^{\frac{3}{2}}}$

Step 10.2.2.5

Multiply $\frac{5}{1}$ by $\frac{8}{8}$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{3 \sqrt[3]{6}}{8} - \frac{3 \sqrt[3]{6} \cdot 4}{2 \cdot 4} + \frac{5 \cdot 8}{8})}^{\frac{3}{2}}}$

Step 10.2.2.6

Multiply $2$ by $4$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{3 \sqrt[3]{6}}{8} - \frac{3 \sqrt[3]{6} \cdot 4}{8} + \frac{5 \cdot 8}{8})}^{\frac{3}{2}}}$

Step 10.2.3

Combine the numerators over the common denominator.

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{3 \sqrt[3]{6} - 3 \sqrt[3]{6} \cdot 4 + 5 \cdot 8}{8})}^{\frac{3}{2}}}$

Step 10.2.4

Simplify each term.

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Step 10.2.4.1

Multiply $4$ by $- 3$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{3 \sqrt[3]{6} - 12 \sqrt[3]{6} + 5 \cdot 8}{8})}^{\frac{3}{2}}}$

Step 10.2.4.2

Multiply $5$ by $8$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{3 \sqrt[3]{6} - 12 \sqrt[3]{6} + 40}{8})}^{\frac{3}{2}}}$

Step 10.2.5

Subtract $12 \sqrt[3]{6}$ from $3 \sqrt[3]{6}$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 {(\frac{- 9 \sqrt[3]{6} + 40}{8})}^{\frac{3}{2}}}$

Step 10.2.6

Apply the product rule to $\frac{- 9 \sqrt[3]{6} + 40}{8}$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{4 \frac{{(- 9 \sqrt[3]{6} + 40)}^{\frac{3}{2}}}{8^{\frac{3}{2}}}}$

Step 10.3

Combine $4$ and $\frac{{(- 9 \sqrt[3]{6} + 40)}^{\frac{3}{2}}}{8^{\frac{3}{2}}}$ .

$\frac{\frac{- 81 + 60 \sqrt[3]{36}}{2}}{\frac{4 {(- 9 \sqrt[3]{6} + 40)}^{\frac{3}{2}}}{8^{\frac{3}{2}}}}$

Step 10.4

Multiply the numerator by the reciprocal of the denominator.

$\frac{- 81 + 60 \sqrt[3]{36}}{2} \cdot \frac{8^{\frac{3}{2}}}{4 {(- 9 \sqrt[3]{6} + 40)}^{\frac{3}{2}}}$

Step 10.5

Multiply $\frac{- 81 + 60 \sqrt[3]{36}}{2} \cdot \frac{8^{\frac{3}{2}}}{4 {(- 9 \sqrt[3]{6} + 40)}^{\frac{3}{2}}}$ .

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Step 10.5.1

Multiply $\frac{- 81 + 60 \sqrt[3]{36}}{2}$ by $\frac{8^{\frac{3}{2}}}{4 {(- 9 \sqrt[3]{6} + 40)}^{\frac{3}{2}}}$ .

$\frac{(- 81 + 60 \sqrt[3]{36}) \cdot 8^{\frac{3}{2}}}{2 (4 {(- 9 \sqrt[3]{6} + 40)}^{\frac{3}{2}})}$

Step 10.5.2

Multiply $4$ by $2$ .

$\frac{(- 81 + 60 \sqrt[3]{36}) \cdot 8^{\frac{3}{2}}}{8 {(- 9 \sqrt[3]{6} + 40)}^{\frac{3}{2}}}$

Step 10.6

Move $8^{1}$ to the numerator using the negative exponent rule $\frac{1}{b^{n}} = b^{- n}$ .

$\frac{(- 81 + 60 \sqrt[3]{36}) \cdot 8^{\frac{3}{2}} \cdot 8^{- 1}}{{(- 9 \sqrt[3]{6} + 40)}^{\frac{3}{2}}}$

Step 10.7

Multiply $8^{\frac{3}{2}}$ by $8^{- 1}$ by adding the exponents.

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Step 10.7.1

Move $8^{- 1}$ .

$\frac{(- 81 + 60 \sqrt[3]{36}) \cdot (8^{- 1} \cdot 8^{\frac{3}{2}})}{{(- 9 \sqrt[3]{6} + 40)}^{\frac{3}{2}}}$

Step 10.7.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{(- 81 + 60 \sqrt[3]{36}) \cdot 8^{- 1 + \frac{3}{2}}}{{(- 9 \sqrt[3]{6} + 40)}^{\frac{3}{2}}}$

Step 10.7.3

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{(- 81 + 60 \sqrt[3]{36}) \cdot 8^{- 1 \cdot \frac{2}{2} + \frac{3}{2}}}{{(- 9 \sqrt[3]{6} + 40)}^{\frac{3}{2}}}$

Step 10.7.4

Combine $- 1$ and $\frac{2}{2}$ .

$\frac{(- 81 + 60 \sqrt[3]{36}) \cdot 8^{\frac{- 1 \cdot 2}{2} + \frac{3}{2}}}{{(- 9 \sqrt[3]{6} + 40)}^{\frac{3}{2}}}$

Step 10.7.5

Combine the numerators over the common denominator.

$\frac{(- 81 + 60 \sqrt[3]{36}) \cdot 8^{\frac{- 1 \cdot 2 + 3}{2}}}{{(- 9 \sqrt[3]{6} + 40)}^{\frac{3}{2}}}$

Step 10.7.6

Simplify the numerator.

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Step 10.7.6.1

Multiply $- 1$ by $2$ .

$\frac{(- 81 + 60 \sqrt[3]{36}) \cdot 8^{\frac{- 2 + 3}{2}}}{{(- 9 \sqrt[3]{6} + 40)}^{\frac{3}{2}}}$

Step 10.7.6.2

Add $- 2$ and $3$ .

$\frac{(- 81 + 60 \sqrt[3]{36}) \cdot 8^{\frac{1}{2}}}{{(- 9 \sqrt[3]{6} + 40)}^{\frac{3}{2}}}$

Step 10.8

Rewrite $- 81$ as $- 1 (81)$ .

$\frac{(- 1 (81) + 60 \sqrt[3]{36}) \cdot 8^{\frac{1}{2}}}{{(- 9 \sqrt[3]{6} + 40)}^{\frac{3}{2}}}$

Step 10.9

Factor $- 1$ out of $60 \sqrt[3]{36}$ .

$\frac{(- 1 (81) - (- 60 \sqrt[3]{36})) \cdot 8^{\frac{1}{2}}}{{(- 9 \sqrt[3]{6} + 40)}^{\frac{3}{2}}}$

Step 10.10

Factor $- 1$ out of $- 1 (81) - (- 60 \sqrt[3]{36})$ .

$\frac{- 1 (81 - 60 \sqrt[3]{36}) \cdot 8^{\frac{1}{2}}}{{(- 9 \sqrt[3]{6} + 40)}^{\frac{3}{2}}}$

Step 10.11

Move the negative in front of the fraction.

$- \frac{(81 - 60 \sqrt[3]{36}) \cdot 8^{\frac{1}{2}}}{{(- 9 \sqrt[3]{6} + 40)}^{\frac{3}{2}}}$

Step 11

$x = \frac{\sqrt[3]{6}}{2}$ is a local minimum because the value of the second derivative is positive. This is referred to as the second derivative test.

$x = \frac{\sqrt[3]{6}}{2}$ is a local minimum

Step 12

Find the y-value when $x = \frac{\sqrt[3]{6}}{2}$ .

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Step 12.1

Replace the variable $x$ with $\frac{\sqrt[3]{6}}{2}$ in the expression.

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{{(\frac{\sqrt[3]{6}}{2})}^{4} - 3 \frac{\sqrt[3]{6}}{2} + 5}$

Step 12.2

Simplify the result.

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Step 12.2.1

Apply the product rule to $\frac{\sqrt[3]{6}}{2}$ .

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{{\sqrt[3]{6}}^{4}}{2^{4}} - 3 \frac{\sqrt[3]{6}}{2} + 5}$

Step 12.2.2

Simplify the numerator.

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Step 12.2.2.1

Rewrite ${\sqrt[3]{6}}^{4}$ as $\sqrt[3]{6^{4}}$ .

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{\sqrt[3]{6^{4}}}{2^{4}} - 3 \frac{\sqrt[3]{6}}{2} + 5}$

Step 12.2.2.2

Raise $6$ to the power of $4$ .

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{\sqrt[3]{1296}}{2^{4}} - 3 \frac{\sqrt[3]{6}}{2} + 5}$

Step 12.2.2.3

Rewrite $1296$ as $6^{3} \cdot 6$ .

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Step 12.2.2.3.1

Factor $216$ out of $1296$ .

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{\sqrt[3]{216 (6)}}{2^{4}} - 3 \frac{\sqrt[3]{6}}{2} + 5}$

Step 12.2.2.3.2

Rewrite $216$ as $6^{3}$ .

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{\sqrt[3]{6^{3} \cdot 6}}{2^{4}} - 3 \frac{\sqrt[3]{6}}{2} + 5}$

Step 12.2.2.4

Pull terms out from under the radical.

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{6 \sqrt[3]{6}}{2^{4}} - 3 \frac{\sqrt[3]{6}}{2} + 5}$

Step 12.2.3

Simplify terms.

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Step 12.2.3.1

Raise $2$ to the power of $4$ .

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{6 \sqrt[3]{6}}{16} - 3 \frac{\sqrt[3]{6}}{2} + 5}$

Step 12.2.3.2

Cancel the common factor of $6$ and $16$ .

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Step 12.2.3.2.1

Factor $2$ out of $6 \sqrt[3]{6}$ .

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{2 (3 \sqrt[3]{6})}{16} - 3 \frac{\sqrt[3]{6}}{2} + 5}$

Step 12.2.3.2.2

Cancel the common factors.

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Step 12.2.3.2.2.1

Factor $2$ out of $16$ .

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{2 (3 \sqrt[3]{6})}{2 (8)} - 3 \frac{\sqrt[3]{6}}{2} + 5}$

Step 12.2.3.2.2.2

Cancel the common factor.

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{2 (3 \sqrt[3]{6})}{2 \cdot 8} - 3 \frac{\sqrt[3]{6}}{2} + 5}$

Step 12.2.3.2.2.3

Rewrite the expression.

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{3 \sqrt[3]{6}}{8} - 3 \frac{\sqrt[3]{6}}{2} + 5}$

Step 12.2.3.3

Combine $- 3$ and $\frac{\sqrt[3]{6}}{2}$ .

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{3 \sqrt[3]{6}}{8} + \frac{- 3 \sqrt[3]{6}}{2} + 5}$

Step 12.2.3.4

Move the negative in front of the fraction.

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{3 \sqrt[3]{6}}{8} - \frac{3 \sqrt[3]{6}}{2} + 5}$

Step 12.2.4

To write $- \frac{3 \sqrt[3]{6}}{2}$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{3 \sqrt[3]{6}}{8} - \frac{3 \sqrt[3]{6}}{2} \cdot \frac{4}{4} + 5}$

Step 12.2.5

Write each expression with a common denominator of $8$ , by multiplying each by an appropriate factor of $1$ .

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Step 12.2.5.1

Multiply $\frac{3 \sqrt[3]{6}}{2}$ by $\frac{4}{4}$ .

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{3 \sqrt[3]{6}}{8} - \frac{3 \sqrt[3]{6} \cdot 4}{2 \cdot 4} + 5}$

Step 12.2.5.2

Multiply $2$ by $4$ .

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{3 \sqrt[3]{6}}{8} - \frac{3 \sqrt[3]{6} \cdot 4}{8} + 5}$

Step 12.2.6

Combine the numerators over the common denominator.

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{3 \sqrt[3]{6} - 3 \sqrt[3]{6} \cdot 4}{8} + 5}$

Step 12.2.7

To write $5$ as a fraction with a common denominator, multiply by $\frac{8}{8}$ .

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{3 \sqrt[3]{6} - 3 \sqrt[3]{6} \cdot 4}{8} + 5 \cdot \frac{8}{8}}$

Step 12.2.8

Combine $5$ and $\frac{8}{8}$ .

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{3 \sqrt[3]{6} - 3 \sqrt[3]{6} \cdot 4}{8} + \frac{5 \cdot 8}{8}}$

Step 12.2.9

Combine the numerators over the common denominator.

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{3 \sqrt[3]{6} - 3 \sqrt[3]{6} \cdot 4 + 5 \cdot 8}{8}}$

Step 12.2.10

Rewrite $\frac{3 \sqrt[3]{6} - 3 \sqrt[3]{6} \cdot 4 + 5 \cdot 8}{8}$ in a factored form.

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Step 12.2.10.1

Multiply $4$ by $- 3$ .

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{3 \sqrt[3]{6} - 12 \sqrt[3]{6} + 5 \cdot 8}{8}}$

Step 12.2.10.2

Multiply $5$ by $8$ .

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{3 \sqrt[3]{6} - 12 \sqrt[3]{6} + 40}{8}}$

Step 12.2.10.3

Subtract $12 \sqrt[3]{6}$ from $3 \sqrt[3]{6}$ .

$f (\frac{\sqrt[3]{6}}{2}) = \sqrt{\frac{- 9 \sqrt[3]{6} + 40}{8}}$

Step 12.2.11

Rewrite $\sqrt{\frac{- 9 \sqrt[3]{6} + 40}{8}}$ as $\frac{\sqrt{- 9 \sqrt[3]{6} + 40}}{\sqrt{8}}$ .

$f (\frac{\sqrt[3]{6}}{2}) = \frac{\sqrt{- 9 \sqrt[3]{6} + 40}}{\sqrt{8}}$

Step 12.2.12

Simplify the denominator.

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Step 12.2.12.1

Rewrite $8$ as $2^{2} \cdot 2$ .

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Step 12.2.12.1.1

Factor $4$ out of $8$ .

$f (\frac{\sqrt[3]{6}}{2}) = \frac{\sqrt{- 9 \sqrt[3]{6} + 40}}{\sqrt{4 (2)}}$

Step 12.2.12.1.2

Rewrite $4$ as $2^{2}$ .

$f (\frac{\sqrt[3]{6}}{2}) = \frac{\sqrt{- 9 \sqrt[3]{6} + 40}}{\sqrt{2^{2} \cdot 2}}$

Step 12.2.12.2

Pull terms out from under the radical.

$f (\frac{\sqrt[3]{6}}{2}) = \frac{\sqrt{- 9 \sqrt[3]{6} + 40}}{2 \sqrt{2}}$

Step 12.2.13

Multiply $\frac{\sqrt{- 9 \sqrt[3]{6} + 40}}{2 \sqrt{2}}$ by $\frac{\sqrt{2}}{\sqrt{2}}$ .

$f (\frac{\sqrt[3]{6}}{2}) = \frac{\sqrt{- 9 \sqrt[3]{6} + 40}}{2 \sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}}$

Step 12.2.14

Combine and simplify the denominator.

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Step 12.2.14.1

Multiply $\frac{\sqrt{- 9 \sqrt[3]{6} + 40}}{2 \sqrt{2}}$ by $\frac{\sqrt{2}}{\sqrt{2}}$ .

$f (\frac{\sqrt[3]{6}}{2}) = \frac{\sqrt{- 9 \sqrt[3]{6} + 40} \sqrt{2}}{2 \sqrt{2} \sqrt{2}}$

Step 12.2.14.2

Move $\sqrt{2}$ .

$f (\frac{\sqrt[3]{6}}{2}) = \frac{\sqrt{- 9 \sqrt[3]{6} + 40} \sqrt{2}}{2 (\sqrt{2} \sqrt{2})}$

Step 12.2.14.3

Raise $\sqrt{2}$ to the power of $1$ .

$f (\frac{\sqrt[3]{6}}{2}) = \frac{\sqrt{- 9 \sqrt[3]{6} + 40} \sqrt{2}}{2 (\sqrt{2} \sqrt{2})}$

Step 12.2.14.4

Raise $\sqrt{2}$ to the power of $1$ .

$f (\frac{\sqrt[3]{6}}{2}) = \frac{\sqrt{- 9 \sqrt[3]{6} + 40} \sqrt{2}}{2 (\sqrt{2} \sqrt{2})}$

Step 12.2.14.5

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f (\frac{\sqrt[3]{6}}{2}) = \frac{\sqrt{- 9 \sqrt[3]{6} + 40} \sqrt{2}}{2 {\sqrt{2}}^{1 + 1}}$

Step 12.2.14.6

Add $1$ and $1$ .

$f (\frac{\sqrt[3]{6}}{2}) = \frac{\sqrt{- 9 \sqrt[3]{6} + 40} \sqrt{2}}{2 {\sqrt{2}}^{2}}$

Step 12.2.14.7

Rewrite ${\sqrt{2}}^{2}$ as $2$ .

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Step 12.2.14.7.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$f (\frac{\sqrt[3]{6}}{2}) = \frac{\sqrt{- 9 \sqrt[3]{6} + 40} \sqrt{2}}{2 {(2^{\frac{1}{2}})}^{2}}$

Step 12.2.14.7.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$f (\frac{\sqrt[3]{6}}{2}) = \frac{\sqrt{- 9 \sqrt[3]{6} + 40} \sqrt{2}}{2 \cdot 2^{\frac{1}{2} \cdot 2}}$

Step 12.2.14.7.3

Combine $\frac{1}{2}$ and $2$ .

$f (\frac{\sqrt[3]{6}}{2}) = \frac{\sqrt{- 9 \sqrt[3]{6} + 40} \sqrt{2}}{2 \cdot 2^{\frac{2}{2}}}$

Step 12.2.14.7.4

Cancel the common factor of $2$ .

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Step 12.2.14.7.4.1

Cancel the common factor.

$f (\frac{\sqrt[3]{6}}{2}) = \frac{\sqrt{- 9 \sqrt[3]{6} + 40} \sqrt{2}}{2 \cdot 2^{\frac{2}{2}}}$

Step 12.2.14.7.4.2

Rewrite the expression.

$f (\frac{\sqrt[3]{6}}{2}) = \frac{\sqrt{- 9 \sqrt[3]{6} + 40} \sqrt{2}}{2 \cdot 2}$

Step 12.2.14.7.5

Evaluate the exponent.

$f (\frac{\sqrt[3]{6}}{2}) = \frac{\sqrt{- 9 \sqrt[3]{6} + 40} \sqrt{2}}{2 \cdot 2}$

Step 12.2.15

Combine using the product rule for radicals.

$f (\frac{\sqrt[3]{6}}{2}) = \frac{\sqrt{(- 9 \sqrt[3]{6} + 40) \cdot 2}}{2 \cdot 2}$

Step 12.2.16

Multiply $2$ by $2$ .

$f (\frac{\sqrt[3]{6}}{2}) = \frac{\sqrt{(- 9 \sqrt[3]{6} + 40) \cdot 2}}{4}$

Step 12.2.17

The final answer is $\frac{\sqrt{(- 9 \sqrt[3]{6} + 40) \cdot 2}}{4}$ .

$y = \frac{\sqrt{(- 9 \sqrt[3]{6} + 40) \cdot 2}}{4}$

Step 13

These are the local extrema for $f (x) = \sqrt{x^{4} - 3 x + 5}$ .

$(\frac{\sqrt[3]{6}}{2}, \frac{\sqrt{(- 9 \sqrt[3]{6} + 40) \cdot 2}}{4})$ is a local minima

Step 14