Calculus Examples

$f (x) = x^{4} + \frac{1}{3} x^{3} - 2 x^{2} - x + 1$

Step 1

Find the first derivative of the function.

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Step 1.1

Differentiate.

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Step 1.1.1

By the Sum Rule, the derivative of $x^{4} + \frac{1}{3} x^{3} - 2 x^{2} - x + 1$ with respect to $x$ is $\frac{d}{d x} [x^{4}] + \frac{d}{d x} [\frac{1}{3} x^{3}] + \frac{d}{d x} [- 2 x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$ .

$\frac{d}{d x} [x^{4}] + \frac{d}{d x} [\frac{1}{3} x^{3}] + \frac{d}{d x} [- 2 x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 1.1.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 4$ .

$4 x^{3} + \frac{d}{d x} [\frac{1}{3} x^{3}] + \frac{d}{d x} [- 2 x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 1.2

Evaluate $\frac{d}{d x} [\frac{1}{3} x^{3}]$ .

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Step 1.2.1

Since $\frac{1}{3}$ is constant with respect to $x$ , the derivative of $\frac{1}{3} x^{3}$ with respect to $x$ is $\frac{1}{3} \frac{d}{d x} [x^{3}]$ .

$4 x^{3} + \frac{1}{3} \frac{d}{d x} [x^{3}] + \frac{d}{d x} [- 2 x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 1.2.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$4 x^{3} + \frac{1}{3} (3 x^{2}) + \frac{d}{d x} [- 2 x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 1.2.3

Combine $3$ and $\frac{1}{3}$ .

$4 x^{3} + \frac{3}{3} x^{2} + \frac{d}{d x} [- 2 x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 1.2.4

Combine $\frac{3}{3}$ and $x^{2}$ .

$4 x^{3} + \frac{3 x^{2}}{3} + \frac{d}{d x} [- 2 x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 1.2.5

Cancel the common factor of $3$ .

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Step 1.2.5.1

Cancel the common factor.

$4 x^{3} + \frac{3 x^{2}}{3} + \frac{d}{d x} [- 2 x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 1.2.5.2

Divide $x^{2}$ by $1$ .

$4 x^{3} + x^{2} + \frac{d}{d x} [- 2 x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 1.3

Evaluate $\frac{d}{d x} [- 2 x^{2}]$ .

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Step 1.3.1

Since $- 2$ is constant with respect to $x$ , the derivative of $- 2 x^{2}$ with respect to $x$ is $- 2 \frac{d}{d x} [x^{2}]$ .

$4 x^{3} + x^{2} - 2 \frac{d}{d x} [x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 1.3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$4 x^{3} + x^{2} - 2 (2 x) + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 1.3.3

Multiply $2$ by $- 2$ .

$4 x^{3} + x^{2} - 4 x + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 1.4

Evaluate $\frac{d}{d x} [- x]$ .

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Step 1.4.1

Since $- 1$ is constant with respect to $x$ , the derivative of $- x$ with respect to $x$ is $- \frac{d}{d x} [x]$ .

$4 x^{3} + x^{2} - 4 x - \frac{d}{d x} [x] + \frac{d}{d x} [1]$

Step 1.4.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$4 x^{3} + x^{2} - 4 x - 1 \cdot 1 + \frac{d}{d x} [1]$

Step 1.4.3

Multiply $- 1$ by $1$ .

$4 x^{3} + x^{2} - 4 x - 1 + \frac{d}{d x} [1]$

Step 1.5

Differentiate using the Constant Rule.

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Step 1.5.1

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$4 x^{3} + x^{2} - 4 x - 1 + 0$

Step 1.5.2

Add $4 x^{3} + x^{2} - 4 x - 1$ and $0$ .

$4 x^{3} + x^{2} - 4 x - 1$

Step 2

Find the second derivative of the function.

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Step 2.1

By the Sum Rule, the derivative of $4 x^{3} + x^{2} - 4 x - 1$ with respect to $x$ is $\frac{d}{d x} [4 x^{3}] + \frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 4 x] + \frac{d}{d x} [- 1]$ .

$f'' (x) = \frac{d}{d x} (4 x^{3}) + \frac{d}{d x} (x^{2}) + \frac{d}{d x} (- 4 x) + \frac{d}{d x} (- 1)$

Step 2.2

Evaluate $\frac{d}{d x} [4 x^{3}]$ .

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Step 2.2.1

Since $4$ is constant with respect to $x$ , the derivative of $4 x^{3}$ with respect to $x$ is $4 \frac{d}{d x} [x^{3}]$ .

$f'' (x) = 4 \frac{d}{d x} (x^{3}) + \frac{d}{d x} (x^{2}) + \frac{d}{d x} (- 4 x) + \frac{d}{d x} (- 1)$

Step 2.2.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$f'' (x) = 4 (3 x^{2}) + \frac{d}{d x} (x^{2}) + \frac{d}{d x} (- 4 x) + \frac{d}{d x} (- 1)$

Step 2.2.3

Multiply $3$ by $4$ .

$f'' (x) = 12 x^{2} + \frac{d}{d x} (x^{2}) + \frac{d}{d x} (- 4 x) + \frac{d}{d x} (- 1)$

Step 2.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$f'' (x) = 12 x^{2} + 2 x + \frac{d}{d x} (- 4 x) + \frac{d}{d x} (- 1)$

Step 2.4

Evaluate $\frac{d}{d x} [- 4 x]$ .

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Step 2.4.1

Since $- 4$ is constant with respect to $x$ , the derivative of $- 4 x$ with respect to $x$ is $- 4 \frac{d}{d x} [x]$ .

$f'' (x) = 12 x^{2} + 2 x - 4 \frac{d}{d x} x + \frac{d}{d x} (- 1)$

Step 2.4.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$f'' (x) = 12 x^{2} + 2 x - 4 \cdot 1 + \frac{d}{d x} (- 1)$

Step 2.4.3

Multiply $- 4$ by $1$ .

$f'' (x) = 12 x^{2} + 2 x - 4 + \frac{d}{d x} (- 1)$

Step 2.5

Differentiate using the Constant Rule.

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Step 2.5.1

Since $- 1$ is constant with respect to $x$ , the derivative of $- 1$ with respect to $x$ is $0$ .

$f'' (x) = 12 x^{2} + 2 x - 4 + 0$

Step 2.5.2

Add $12 x^{2} + 2 x - 4$ and $0$ .

$f'' (x) = 12 x^{2} + 2 x - 4$

Step 3

To find the local maximum and minimum values of the function, set the derivative equal to $0$ and solve.

$4 x^{3} + x^{2} - 4 x - 1 = 0$

Step 4

Find the first derivative.

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Step 4.1

Find the first derivative.

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Step 4.1.1

Differentiate.

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Step 4.1.1.1

$\frac{d}{d x} [x^{4}] + \frac{d}{d x} [\frac{1}{3} x^{3}] + \frac{d}{d x} [- 2 x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 4.1.1.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 4$ .

$4 x^{3} + \frac{d}{d x} [\frac{1}{3} x^{3}] + \frac{d}{d x} [- 2 x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 4.1.2

Evaluate $\frac{d}{d x} [\frac{1}{3} x^{3}]$ .

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Step 4.1.2.1

Since $\frac{1}{3}$ is constant with respect to $x$ , the derivative of $\frac{1}{3} x^{3}$ with respect to $x$ is $\frac{1}{3} \frac{d}{d x} [x^{3}]$ .

$4 x^{3} + \frac{1}{3} \frac{d}{d x} [x^{3}] + \frac{d}{d x} [- 2 x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 4.1.2.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$4 x^{3} + \frac{1}{3} (3 x^{2}) + \frac{d}{d x} [- 2 x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 4.1.2.3

Combine $3$ and $\frac{1}{3}$ .

$4 x^{3} + \frac{3}{3} x^{2} + \frac{d}{d x} [- 2 x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 4.1.2.4

Combine $\frac{3}{3}$ and $x^{2}$ .

$4 x^{3} + \frac{3 x^{2}}{3} + \frac{d}{d x} [- 2 x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 4.1.2.5

Cancel the common factor of $3$ .

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Step 4.1.2.5.1

Cancel the common factor.

$4 x^{3} + \frac{3 x^{2}}{3} + \frac{d}{d x} [- 2 x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 4.1.2.5.2

Divide $x^{2}$ by $1$ .

$4 x^{3} + x^{2} + \frac{d}{d x} [- 2 x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 4.1.3

Evaluate $\frac{d}{d x} [- 2 x^{2}]$ .

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Step 4.1.3.1

Since $- 2$ is constant with respect to $x$ , the derivative of $- 2 x^{2}$ with respect to $x$ is $- 2 \frac{d}{d x} [x^{2}]$ .

$4 x^{3} + x^{2} - 2 \frac{d}{d x} [x^{2}] + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 4.1.3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$4 x^{3} + x^{2} - 2 (2 x) + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 4.1.3.3

Multiply $2$ by $- 2$ .

$4 x^{3} + x^{2} - 4 x + \frac{d}{d x} [- x] + \frac{d}{d x} [1]$

Step 4.1.4

Evaluate $\frac{d}{d x} [- x]$ .

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Step 4.1.4.1

Since $- 1$ is constant with respect to $x$ , the derivative of $- x$ with respect to $x$ is $- \frac{d}{d x} [x]$ .

$4 x^{3} + x^{2} - 4 x - \frac{d}{d x} [x] + \frac{d}{d x} [1]$

Step 4.1.4.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$4 x^{3} + x^{2} - 4 x - 1 \cdot 1 + \frac{d}{d x} [1]$

Step 4.1.4.3

Multiply $- 1$ by $1$ .

$4 x^{3} + x^{2} - 4 x - 1 + \frac{d}{d x} [1]$

Step 4.1.5

Differentiate using the Constant Rule.

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Step 4.1.5.1

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$4 x^{3} + x^{2} - 4 x - 1 + 0$

Step 4.1.5.2

Add $4 x^{3} + x^{2} - 4 x - 1$ and $0$ .

$f' (x) = 4 x^{3} + x^{2} - 4 x - 1$

Step 4.2

The first derivative of $f (x)$ with respect to $x$ is $4 x^{3} + x^{2} - 4 x - 1$ .

$4 x^{3} + x^{2} - 4 x - 1$

Step 5

Set the first derivative equal to $0$ then solve the equation $4 x^{3} + x^{2} - 4 x - 1 = 0$ .

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Step 5.1

Set the first derivative equal to $0$ .

$4 x^{3} + x^{2} - 4 x - 1 = 0$

Step 5.2

Factor the left side of the equation.

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Step 5.2.1

Factor out the greatest common factor from each group.

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Step 5.2.1.1

Group the first two terms and the last two terms.

$(4 x^{3} + x^{2}) - 4 x - 1 = 0$

Step 5.2.1.2

Factor out the greatest common factor (GCF) from each group.

$x^{2} (4 x + 1) - (4 x + 1) = 0$

Step 5.2.2

Factor the polynomial by factoring out the greatest common factor, $4 x + 1$ .

$(4 x + 1) (x^{2} - 1) = 0$

Step 5.2.3

Rewrite $1$ as $1^{2}$ .

$(4 x + 1) (x^{2} - 1^{2}) = 0$

Step 5.2.4

Factor.

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Step 5.2.4.1

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 1$ .

$(4 x + 1) ((x + 1) (x - 1)) = 0$

Step 5.2.4.2

Remove unnecessary parentheses.

$(4 x + 1) (x + 1) (x - 1) = 0$

Step 5.3

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$4 x + 1 = 0$

$x + 1 = 0$

$x - 1 = 0$

Step 5.4

Set $4 x + 1$ equal to $0$ and solve for $x$ .

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Step 5.4.1

Set $4 x + 1$ equal to $0$ .

$4 x + 1 = 0$

Step 5.4.2

Solve $4 x + 1 = 0$ for $x$ .

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Step 5.4.2.1

Subtract $1$ from both sides of the equation.

$4 x = - 1$

Step 5.4.2.2

Divide each term in $4 x = - 1$ by $4$ and simplify.

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Step 5.4.2.2.1

Divide each term in $4 x = - 1$ by $4$ .

$\frac{4 x}{4} = \frac{- 1}{4}$

Step 5.4.2.2.2

Simplify the left side.

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Step 5.4.2.2.2.1

Cancel the common factor of $4$ .

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Step 5.4.2.2.2.1.1

Cancel the common factor.

$\frac{4 x}{4} = \frac{- 1}{4}$

Step 5.4.2.2.2.1.2

Divide $x$ by $1$ .

$x = \frac{- 1}{4}$

Step 5.4.2.2.3

Simplify the right side.

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Step 5.4.2.2.3.1

Move the negative in front of the fraction.

$x = - \frac{1}{4}$

Step 5.5

Set $x + 1$ equal to $0$ and solve for $x$ .

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Step 5.5.1

Set $x + 1$ equal to $0$ .

$x + 1 = 0$

Step 5.5.2

Subtract $1$ from both sides of the equation.

$x = - 1$

Step 5.6

Set $x - 1$ equal to $0$ and solve for $x$ .

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Step 5.6.1

Set $x - 1$ equal to $0$ .

$x - 1 = 0$

Step 5.6.2

Add $1$ to both sides of the equation.

$x = 1$

Step 5.7

The final solution is all the values that make $(4 x + 1) (x + 1) (x - 1) = 0$ true.

$x = - \frac{1}{4}, - 1, 1$

Step 6

Find the values where the derivative is undefined.

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Step 6.1

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Step 7

Critical points to evaluate.

$x = - \frac{1}{4}, - 1, 1$

Step 8

Evaluate the second derivative at $x = - \frac{1}{4}$ . If the second derivative is positive, then this is a local minimum. If it is negative, then this is a local maximum.

$12 {(- \frac{1}{4})}^{2} + 2 (- \frac{1}{4}) - 4$

Step 9

Evaluate the second derivative.

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Step 9.1

Simplify each term.

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Step 9.1.1

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

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Step 9.1.1.1

Apply the product rule to $- \frac{1}{4}$ .

$12 ({(- 1)}^{2} {(\frac{1}{4})}^{2}) + 2 (- \frac{1}{4}) - 4$

Step 9.1.1.2

Apply the product rule to $\frac{1}{4}$ .

$12 ({(- 1)}^{2} \frac{1^{2}}{4^{2}}) + 2 (- \frac{1}{4}) - 4$

Step 9.1.2

Raise $- 1$ to the power of $2$ .

$12 (1 \frac{1^{2}}{4^{2}}) + 2 (- \frac{1}{4}) - 4$

Step 9.1.3

Multiply $\frac{1^{2}}{4^{2}}$ by $1$ .

$12 \frac{1^{2}}{4^{2}} + 2 (- \frac{1}{4}) - 4$

Step 9.1.4

One to any power is one.

$12 \frac{1}{4^{2}} + 2 (- \frac{1}{4}) - 4$

Step 9.1.5

Raise $4$ to the power of $2$ .

$12 (\frac{1}{16}) + 2 (- \frac{1}{4}) - 4$

Step 9.1.6

Cancel the common factor of $4$ .

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Step 9.1.6.1

Factor $4$ out of $12$ .

$4 (3) \frac{1}{16} + 2 (- \frac{1}{4}) - 4$

Step 9.1.6.2

Factor $4$ out of $16$ .

$4 \cdot 3 \frac{1}{4 \cdot 4} + 2 (- \frac{1}{4}) - 4$

Step 9.1.6.3

Cancel the common factor.

$4 \cdot 3 \frac{1}{4 \cdot 4} + 2 (- \frac{1}{4}) - 4$

Step 9.1.6.4

Rewrite the expression.

$3 (\frac{1}{4}) + 2 (- \frac{1}{4}) - 4$

Step 9.1.7

Combine $3$ and $\frac{1}{4}$ .

$\frac{3}{4} + 2 (- \frac{1}{4}) - 4$

Step 9.1.8

Cancel the common factor of $2$ .

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Step 9.1.8.1

Move the leading negative in $- \frac{1}{4}$ into the numerator.

$\frac{3}{4} + 2 (\frac{- 1}{4}) - 4$

Step 9.1.8.2

Factor $2$ out of $4$ .

$\frac{3}{4} + 2 \frac{- 1}{2 (2)} - 4$

Step 9.1.8.3

Cancel the common factor.

$\frac{3}{4} + 2 \frac{- 1}{2 \cdot 2} - 4$

Step 9.1.8.4

Rewrite the expression.

$\frac{3}{4} + \frac{- 1}{2} - 4$

Step 9.1.9

Move the negative in front of the fraction.

$\frac{3}{4} - \frac{1}{2} - 4$

Step 9.2

Find the common denominator.

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Step 9.2.1

Multiply $\frac{1}{2}$ by $\frac{2}{2}$ .

$\frac{3}{4} - (\frac{1}{2} \cdot \frac{2}{2}) - 4$

Step 9.2.2

Multiply $\frac{1}{2}$ by $\frac{2}{2}$ .

$\frac{3}{4} - \frac{2}{2 \cdot 2} - 4$

Step 9.2.3

Write $- 4$ as a fraction with denominator $1$ .

$\frac{3}{4} - \frac{2}{2 \cdot 2} + \frac{- 4}{1}$

Step 9.2.4

Multiply $\frac{- 4}{1}$ by $\frac{4}{4}$ .

$\frac{3}{4} - \frac{2}{2 \cdot 2} + \frac{- 4}{1} \cdot \frac{4}{4}$

Step 9.2.5

Multiply $\frac{- 4}{1}$ by $\frac{4}{4}$ .

$\frac{3}{4} - \frac{2}{2 \cdot 2} + \frac{- 4 \cdot 4}{4}$

Step 9.2.6

Multiply $2$ by $2$ .

$\frac{3}{4} - \frac{2}{4} + \frac{- 4 \cdot 4}{4}$

Step 9.3

Combine the numerators over the common denominator.

$\frac{3 - 2 - 4 \cdot 4}{4}$

Step 9.4

Simplify the expression.

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Step 9.4.1

Multiply $- 4$ by $4$ .

$\frac{3 - 2 - 16}{4}$

Step 9.4.2

Subtract $2$ from $3$ .

$\frac{1 - 16}{4}$

Step 9.4.3

Subtract $16$ from $1$ .

$\frac{- 15}{4}$

Step 9.4.4

Move the negative in front of the fraction.

$- \frac{15}{4}$

Step 10

$x = - \frac{1}{4}$ is a local maximum because the value of the second derivative is negative. This is referred to as the second derivative test.

$x = - \frac{1}{4}$ is a local maximum

Step 11

Find the y-value when $x = - \frac{1}{4}$ .

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Step 11.1

Replace the variable $x$ with $- \frac{1}{4}$ in the expression.

$f (- \frac{1}{4}) = {(- \frac{1}{4})}^{4} + \frac{1}{3} \cdot {(- \frac{1}{4})}^{3} - 2 {(- \frac{1}{4})}^{2} - (- \frac{1}{4}) + 1$

Step 11.2

Simplify the result.

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Step 11.2.1

Simplify each term.

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Step 11.2.1.1

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

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Step 11.2.1.1.1

Apply the product rule to $- \frac{1}{4}$ .

$f (- \frac{1}{4}) = {(- 1)}^{4} {(\frac{1}{4})}^{4} + \frac{1}{3} \cdot {(- \frac{1}{4})}^{3} - 2 {(- \frac{1}{4})}^{2} - (- \frac{1}{4}) + 1$

Step 11.2.1.1.2

Apply the product rule to $\frac{1}{4}$ .

$f (- \frac{1}{4}) = {(- 1)}^{4} (\frac{1^{4}}{4^{4}}) + \frac{1}{3} \cdot {(- \frac{1}{4})}^{3} - 2 {(- \frac{1}{4})}^{2} - (- \frac{1}{4}) + 1$

Step 11.2.1.2

Raise $- 1$ to the power of $4$ .

$f (- \frac{1}{4}) = 1 (\frac{1^{4}}{4^{4}}) + \frac{1}{3} \cdot {(- \frac{1}{4})}^{3} - 2 {(- \frac{1}{4})}^{2} - (- \frac{1}{4}) + 1$

Step 11.2.1.3

Multiply $\frac{1^{4}}{4^{4}}$ by $1$ .

$f (- \frac{1}{4}) = \frac{1^{4}}{4^{4}} + \frac{1}{3} \cdot {(- \frac{1}{4})}^{3} - 2 {(- \frac{1}{4})}^{2} - (- \frac{1}{4}) + 1$

Step 11.2.1.4

One to any power is one.

$f (- \frac{1}{4}) = \frac{1}{4^{4}} + \frac{1}{3} \cdot {(- \frac{1}{4})}^{3} - 2 {(- \frac{1}{4})}^{2} - (- \frac{1}{4}) + 1$

Step 11.2.1.5

Raise $4$ to the power of $4$ .

$f (- \frac{1}{4}) = \frac{1}{256} + \frac{1}{3} \cdot {(- \frac{1}{4})}^{3} - 2 {(- \frac{1}{4})}^{2} - (- \frac{1}{4}) + 1$

Step 11.2.1.6

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

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Step 11.2.1.6.1

Apply the product rule to $- \frac{1}{4}$ .

$f (- \frac{1}{4}) = \frac{1}{256} + \frac{1}{3} \cdot ({(- 1)}^{3} {(\frac{1}{4})}^{3}) - 2 {(- \frac{1}{4})}^{2} - (- \frac{1}{4}) + 1$

Step 11.2.1.6.2

Apply the product rule to $\frac{1}{4}$ .

$f (- \frac{1}{4}) = \frac{1}{256} + \frac{1}{3} \cdot ({(- 1)}^{3} (\frac{1^{3}}{4^{3}})) - 2 {(- \frac{1}{4})}^{2} - (- \frac{1}{4}) + 1$

Step 11.2.1.7

Raise $- 1$ to the power of $3$ .

$f (- \frac{1}{4}) = \frac{1}{256} + \frac{1}{3} \cdot (- \frac{1^{3}}{4^{3}}) - 2 {(- \frac{1}{4})}^{2} - (- \frac{1}{4}) + 1$

Step 11.2.1.8

One to any power is one.

$f (- \frac{1}{4}) = \frac{1}{256} + \frac{1}{3} \cdot (- \frac{1}{4^{3}}) - 2 {(- \frac{1}{4})}^{2} - (- \frac{1}{4}) + 1$

Step 11.2.1.9

Raise $4$ to the power of $3$ .

$f (- \frac{1}{4}) = \frac{1}{256} + \frac{1}{3} \cdot (- \frac{1}{64}) - 2 {(- \frac{1}{4})}^{2} - (- \frac{1}{4}) + 1$

Step 11.2.1.10

Multiply $\frac{1}{3} (- \frac{1}{64})$ .

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Step 11.2.1.10.1

Multiply $\frac{1}{3}$ by $\frac{1}{64}$ .

$f (- \frac{1}{4}) = \frac{1}{256} - \frac{1}{3 \cdot 64} - 2 {(- \frac{1}{4})}^{2} - (- \frac{1}{4}) + 1$

Step 11.2.1.10.2

Multiply $3$ by $64$ .

$f (- \frac{1}{4}) = \frac{1}{256} - \frac{1}{192} - 2 {(- \frac{1}{4})}^{2} - (- \frac{1}{4}) + 1$

Step 11.2.1.11

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

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Step 11.2.1.11.1

Apply the product rule to $- \frac{1}{4}$ .

$f (- \frac{1}{4}) = \frac{1}{256} - \frac{1}{192} - 2 ({(- 1)}^{2} {(\frac{1}{4})}^{2}) - (- \frac{1}{4}) + 1$

Step 11.2.1.11.2

Apply the product rule to $\frac{1}{4}$ .

$f (- \frac{1}{4}) = \frac{1}{256} - \frac{1}{192} - 2 ({(- 1)}^{2} (\frac{1^{2}}{4^{2}})) - (- \frac{1}{4}) + 1$

Step 11.2.1.12

Raise $- 1$ to the power of $2$ .

$f (- \frac{1}{4}) = \frac{1}{256} - \frac{1}{192} - 2 (1 (\frac{1^{2}}{4^{2}})) - (- \frac{1}{4}) + 1$

Step 11.2.1.13

Multiply $\frac{1^{2}}{4^{2}}$ by $1$ .

$f (- \frac{1}{4}) = \frac{1}{256} - \frac{1}{192} - 2 \frac{1^{2}}{4^{2}} - (- \frac{1}{4}) + 1$

Step 11.2.1.14

One to any power is one.

$f (- \frac{1}{4}) = \frac{1}{256} - \frac{1}{192} - 2 \frac{1}{4^{2}} - (- \frac{1}{4}) + 1$

Step 11.2.1.15

Raise $4$ to the power of $2$ .

$f (- \frac{1}{4}) = \frac{1}{256} - \frac{1}{192} - 2 (\frac{1}{16}) - (- \frac{1}{4}) + 1$

Step 11.2.1.16

Cancel the common factor of $2$ .

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Step 11.2.1.16.1

Factor $2$ out of $- 2$ .

$f (- \frac{1}{4}) = \frac{1}{256} - \frac{1}{192} + 2 (- 1) (\frac{1}{16}) - (- \frac{1}{4}) + 1$

Step 11.2.1.16.2

Factor $2$ out of $16$ .

$f (- \frac{1}{4}) = \frac{1}{256} - \frac{1}{192} + 2 \cdot (- 1 \frac{1}{2 \cdot 8}) - (- \frac{1}{4}) + 1$

Step 11.2.1.16.3

Cancel the common factor.

$f (- \frac{1}{4}) = \frac{1}{256} - \frac{1}{192} + 2 \cdot (- 1 \frac{1}{2 \cdot 8}) - (- \frac{1}{4}) + 1$

Step 11.2.1.16.4

Rewrite the expression.

$f (- \frac{1}{4}) = \frac{1}{256} - \frac{1}{192} - 1 (\frac{1}{8}) - (- \frac{1}{4}) + 1$

Step 11.2.1.17

Rewrite $- 1 (\frac{1}{8})$ as $- (\frac{1}{8})$ .

$f (- \frac{1}{4}) = \frac{1}{256} - \frac{1}{192} - (\frac{1}{8}) - (- \frac{1}{4}) + 1$

Step 11.2.1.18

Multiply $- (- \frac{1}{4})$ .

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Step 11.2.1.18.1

Multiply $- 1$ by $- 1$ .

$f (- \frac{1}{4}) = \frac{1}{256} - \frac{1}{192} - \frac{1}{8} + 1 (\frac{1}{4}) + 1$

Step 11.2.1.18.2

Multiply $\frac{1}{4}$ by $1$ .

$f (- \frac{1}{4}) = \frac{1}{256} - \frac{1}{192} - \frac{1}{8} + \frac{1}{4} + 1$

Step 11.2.2

Find the common denominator.

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Step 11.2.2.1

Multiply $\frac{1}{256}$ by $\frac{3}{3}$ .

$f (- \frac{1}{4}) = \frac{1}{256} \cdot \frac{3}{3} - \frac{1}{192} - \frac{1}{8} + \frac{1}{4} + 1$

Step 11.2.2.2

Multiply $\frac{1}{256}$ by $\frac{3}{3}$ .

$f (- \frac{1}{4}) = \frac{3}{256 \cdot 3} - \frac{1}{192} - \frac{1}{8} + \frac{1}{4} + 1$

Step 11.2.2.3

Multiply $\frac{1}{192}$ by $\frac{4}{4}$ .

$f (- \frac{1}{4}) = \frac{3}{256 \cdot 3} - (\frac{1}{192} \cdot \frac{4}{4}) - \frac{1}{8} + \frac{1}{4} + 1$

Step 11.2.2.4

Multiply $\frac{1}{192}$ by $\frac{4}{4}$ .

$f (- \frac{1}{4}) = \frac{3}{256 \cdot 3} - \frac{4}{192 \cdot 4} - \frac{1}{8} + \frac{1}{4} + 1$

Step 11.2.2.5

Multiply $\frac{1}{8}$ by $\frac{96}{96}$ .

$f (- \frac{1}{4}) = \frac{3}{256 \cdot 3} - \frac{4}{192 \cdot 4} - (\frac{1}{8} \cdot \frac{96}{96}) + \frac{1}{4} + 1$

Step 11.2.2.6

Multiply $\frac{1}{8}$ by $\frac{96}{96}$ .

$f (- \frac{1}{4}) = \frac{3}{256 \cdot 3} - \frac{4}{192 \cdot 4} - \frac{96}{8 \cdot 96} + \frac{1}{4} + 1$

Step 11.2.2.7

Multiply $\frac{1}{4}$ by $\frac{192}{192}$ .

$f (- \frac{1}{4}) = \frac{3}{256 \cdot 3} - \frac{4}{192 \cdot 4} - \frac{96}{8 \cdot 96} + \frac{1}{4} \cdot \frac{192}{192} + 1$

Step 11.2.2.8

Multiply $\frac{1}{4}$ by $\frac{192}{192}$ .

$f (- \frac{1}{4}) = \frac{3}{256 \cdot 3} - \frac{4}{192 \cdot 4} - \frac{96}{8 \cdot 96} + \frac{192}{4 \cdot 192} + 1$

Step 11.2.2.9

Write $1$ as a fraction with denominator $1$ .

$f (- \frac{1}{4}) = \frac{3}{256 \cdot 3} - \frac{4}{192 \cdot 4} - \frac{96}{8 \cdot 96} + \frac{192}{4 \cdot 192} + \frac{1}{1}$

Step 11.2.2.10

Multiply $\frac{1}{1}$ by $\frac{768}{768}$ .

$f (- \frac{1}{4}) = \frac{3}{256 \cdot 3} - \frac{4}{192 \cdot 4} - \frac{96}{8 \cdot 96} + \frac{192}{4 \cdot 192} + \frac{1}{1} \cdot \frac{768}{768}$

Step 11.2.2.11

Multiply $\frac{1}{1}$ by $\frac{768}{768}$ .

$f (- \frac{1}{4}) = \frac{3}{256 \cdot 3} - \frac{4}{192 \cdot 4} - \frac{96}{8 \cdot 96} + \frac{192}{4 \cdot 192} + \frac{768}{768}$

Step 11.2.2.12

Reorder the factors of $256 \cdot 3$ .

$f (- \frac{1}{4}) = \frac{3}{3 \cdot 256} - \frac{4}{192 \cdot 4} - \frac{96}{8 \cdot 96} + \frac{192}{4 \cdot 192} + \frac{768}{768}$

Step 11.2.2.13

Multiply $3$ by $256$ .

$f (- \frac{1}{4}) = \frac{3}{768} - \frac{4}{192 \cdot 4} - \frac{96}{8 \cdot 96} + \frac{192}{4 \cdot 192} + \frac{768}{768}$

Step 11.2.2.14

Reorder the factors of $192 \cdot 4$ .

$f (- \frac{1}{4}) = \frac{3}{768} - \frac{4}{4 \cdot 192} - \frac{96}{8 \cdot 96} + \frac{192}{4 \cdot 192} + \frac{768}{768}$

Step 11.2.2.15

Multiply $4$ by $192$ .

$f (- \frac{1}{4}) = \frac{3}{768} - \frac{4}{768} - \frac{96}{8 \cdot 96} + \frac{192}{4 \cdot 192} + \frac{768}{768}$

Step 11.2.2.16

Multiply $8$ by $96$ .

$f (- \frac{1}{4}) = \frac{3}{768} - \frac{4}{768} - \frac{96}{768} + \frac{192}{4 \cdot 192} + \frac{768}{768}$

Step 11.2.2.17

Multiply $4$ by $192$ .

$f (- \frac{1}{4}) = \frac{3}{768} - \frac{4}{768} - \frac{96}{768} + \frac{192}{768} + \frac{768}{768}$

Step 11.2.3

Combine the numerators over the common denominator.

$f (- \frac{1}{4}) = \frac{3 - 4 - 96 + 192 + 768}{768}$

Step 11.2.4

Simplify by adding and subtracting.

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Step 11.2.4.1

Subtract $4$ from $3$ .

$f (- \frac{1}{4}) = \frac{- 1 - 96 + 192 + 768}{768}$

Step 11.2.4.2

Subtract $96$ from $- 1$ .

$f (- \frac{1}{4}) = \frac{- 97 + 192 + 768}{768}$

Step 11.2.4.3

Add $- 97$ and $192$ .

$f (- \frac{1}{4}) = \frac{95 + 768}{768}$

Step 11.2.4.4

Add $95$ and $768$ .

$f (- \frac{1}{4}) = \frac{863}{768}$

Step 11.2.5

The final answer is $\frac{863}{768}$ .

$y = \frac{863}{768}$

Step 12

Evaluate the second derivative at $x = - 1$ . If the second derivative is positive, then this is a local minimum. If it is negative, then this is a local maximum.

$12 {(- 1)}^{2} + 2 (- 1) - 4$

Step 13

Evaluate the second derivative.

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Step 13.1

Simplify each term.

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Step 13.1.1

Raise $- 1$ to the power of $2$ .

$12 \cdot 1 + 2 (- 1) - 4$

Step 13.1.2

Multiply $12$ by $1$ .

$12 + 2 (- 1) - 4$

Step 13.1.3

Multiply $2$ by $- 1$ .

$12 - 2 - 4$

Step 13.2

Simplify by subtracting numbers.

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Step 13.2.1

Subtract $2$ from $12$ .

$10 - 4$

Step 13.2.2

Subtract $4$ from $10$ .

$6$

Step 14

$x = - 1$ is a local minimum because the value of the second derivative is positive. This is referred to as the second derivative test.

$x = - 1$ is a local minimum

Step 15

Find the y-value when $x = - 1$ .

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Step 15.1

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = {(- 1)}^{4} + \frac{1}{3} \cdot {(- 1)}^{3} - 2 {(- 1)}^{2} - (- 1) + 1$

Step 15.2

Simplify the result.

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Step 15.2.1

Simplify each term.

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Step 15.2.1.1

Raise $- 1$ to the power of $4$ .

$f (- 1) = 1 + \frac{1}{3} \cdot {(- 1)}^{3} - 2 {(- 1)}^{2} - (- 1) + 1$

Step 15.2.1.2

Raise $- 1$ to the power of $3$ .

$f (- 1) = 1 + \frac{1}{3} \cdot - 1 - 2 {(- 1)}^{2} - (- 1) + 1$

Step 15.2.1.3

Combine $\frac{1}{3}$ and $- 1$ .

$f (- 1) = 1 + \frac{- 1}{3} - 2 {(- 1)}^{2} - (- 1) + 1$

Step 15.2.1.4

Move the negative in front of the fraction.

$f (- 1) = 1 - \frac{1}{3} - 2 {(- 1)}^{2} - (- 1) + 1$

Step 15.2.1.5

Raise $- 1$ to the power of $2$ .

$f (- 1) = 1 - \frac{1}{3} - 2 \cdot 1 - (- 1) + 1$

Step 15.2.1.6

Multiply $- 2$ by $1$ .

$f (- 1) = 1 - \frac{1}{3} - 2 - (- 1) + 1$

Step 15.2.1.7

Multiply $- 1$ by $- 1$ .

$f (- 1) = 1 - \frac{1}{3} - 2 + 1 + 1$

Step 15.2.2

Find the common denominator.

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Step 15.2.2.1

Write $1$ as a fraction with denominator $1$ .

$f (- 1) = \frac{1}{1} - \frac{1}{3} - 2 + 1 + 1$

Step 15.2.2.2

Multiply $\frac{1}{1}$ by $\frac{3}{3}$ .

$f (- 1) = \frac{1}{1} \cdot \frac{3}{3} - \frac{1}{3} - 2 + 1 + 1$

Step 15.2.2.3

Multiply $\frac{1}{1}$ by $\frac{3}{3}$ .

$f (- 1) = \frac{3}{3} - \frac{1}{3} - 2 + 1 + 1$

Step 15.2.2.4

Write $- 2$ as a fraction with denominator $1$ .

$f (- 1) = \frac{3}{3} - \frac{1}{3} + \frac{- 2}{1} + 1 + 1$

Step 15.2.2.5

Multiply $\frac{- 2}{1}$ by $\frac{3}{3}$ .

$f (- 1) = \frac{3}{3} - \frac{1}{3} + \frac{- 2}{1} \cdot \frac{3}{3} + 1 + 1$

Step 15.2.2.6

Multiply $\frac{- 2}{1}$ by $\frac{3}{3}$ .

$f (- 1) = \frac{3}{3} - \frac{1}{3} + \frac{- 2 \cdot 3}{3} + 1 + 1$

Step 15.2.2.7

Write $1$ as a fraction with denominator $1$ .

$f (- 1) = \frac{3}{3} - \frac{1}{3} + \frac{- 2 \cdot 3}{3} + \frac{1}{1} + 1$

Step 15.2.2.8

Multiply $\frac{1}{1}$ by $\frac{3}{3}$ .

$f (- 1) = \frac{3}{3} - \frac{1}{3} + \frac{- 2 \cdot 3}{3} + \frac{1}{1} \cdot \frac{3}{3} + 1$

Step 15.2.2.9

Multiply $\frac{1}{1}$ by $\frac{3}{3}$ .

$f (- 1) = \frac{3}{3} - \frac{1}{3} + \frac{- 2 \cdot 3}{3} + \frac{3}{3} + 1$

Step 15.2.2.10

Write $1$ as a fraction with denominator $1$ .

$f (- 1) = \frac{3}{3} - \frac{1}{3} + \frac{- 2 \cdot 3}{3} + \frac{3}{3} + \frac{1}{1}$

Step 15.2.2.11

Multiply $\frac{1}{1}$ by $\frac{3}{3}$ .

$f (- 1) = \frac{3}{3} - \frac{1}{3} + \frac{- 2 \cdot 3}{3} + \frac{3}{3} + \frac{1}{1} \cdot \frac{3}{3}$

Step 15.2.2.12

Multiply $\frac{1}{1}$ by $\frac{3}{3}$ .

$f (- 1) = \frac{3}{3} - \frac{1}{3} + \frac{- 2 \cdot 3}{3} + \frac{3}{3} + \frac{3}{3}$

Step 15.2.3

Combine the numerators over the common denominator.

$f (- 1) = \frac{3 - 1 - 2 \cdot 3 + 3 + 3}{3}$

Step 15.2.4

Simplify the expression.

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Step 15.2.4.1

Multiply $- 2$ by $3$ .

$f (- 1) = \frac{3 - 1 - 6 + 3 + 3}{3}$

Step 15.2.4.2

Subtract $1$ from $3$ .

$f (- 1) = \frac{2 - 6 + 3 + 3}{3}$

Step 15.2.4.3

Subtract $6$ from $2$ .

$f (- 1) = \frac{- 4 + 3 + 3}{3}$

Step 15.2.4.4

Add $- 4$ and $3$ .

$f (- 1) = \frac{- 1 + 3}{3}$

Step 15.2.4.5

Add $- 1$ and $3$ .

$f (- 1) = \frac{2}{3}$

Step 15.2.5

The final answer is $\frac{2}{3}$ .

$y = \frac{2}{3}$

Step 16

Evaluate the second derivative at $x = 1$ . If the second derivative is positive, then this is a local minimum. If it is negative, then this is a local maximum.

$12 {(1)}^{2} + 2 (1) - 4$

Step 17

Evaluate the second derivative.

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Step 17.1

Simplify each term.

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Step 17.1.1

One to any power is one.

$12 \cdot 1 + 2 (1) - 4$

Step 17.1.2

Multiply $12$ by $1$ .

$12 + 2 (1) - 4$

Step 17.1.3

Multiply $2$ by $1$ .

$12 + 2 - 4$

Step 17.2

Simplify by adding and subtracting.

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Step 17.2.1

Add $12$ and $2$ .

$14 - 4$

Step 17.2.2

Subtract $4$ from $14$ .

$10$

Step 18

$x = 1$ is a local minimum because the value of the second derivative is positive. This is referred to as the second derivative test.

$x = 1$ is a local minimum

Step 19

Find the y-value when $x = 1$ .

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Step 19.1

Replace the variable $x$ with $1$ in the expression.

$f (1) = {(1)}^{4} + \frac{1}{3} \cdot {(1)}^{3} - 2 {(1)}^{2} - (1) + 1$

Step 19.2

Simplify the result.

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Step 19.2.1

Simplify each term.

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Step 19.2.1.1

One to any power is one.

$f (1) = 1 + \frac{1}{3} \cdot {(1)}^{3} - 2 {(1)}^{2} - (1) + 1$

Step 19.2.1.2

One to any power is one.

$f (1) = 1 + \frac{1}{3} \cdot 1 - 2 {(1)}^{2} - (1) + 1$

Step 19.2.1.3

Multiply $\frac{1}{3}$ by $1$ .

$f (1) = 1 + \frac{1}{3} - 2 {(1)}^{2} - (1) + 1$

Step 19.2.1.4

One to any power is one.

$f (1) = 1 + \frac{1}{3} - 2 \cdot 1 - (1) + 1$

Step 19.2.1.5

Multiply $- 2$ by $1$ .

$f (1) = 1 + \frac{1}{3} - 2 - (1) + 1$

Step 19.2.1.6

Multiply $- 1$ by $1$ .

$f (1) = 1 + \frac{1}{3} - 2 - 1 + 1$

Step 19.2.2

Find the common denominator.

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Step 19.2.2.1

Write $1$ as a fraction with denominator $1$ .

$f (1) = \frac{1}{1} + \frac{1}{3} - 2 - 1 + 1$

Step 19.2.2.2

Multiply $\frac{1}{1}$ by $\frac{3}{3}$ .

$f (1) = \frac{1}{1} \cdot \frac{3}{3} + \frac{1}{3} - 2 - 1 + 1$

Step 19.2.2.3

Multiply $\frac{1}{1}$ by $\frac{3}{3}$ .

$f (1) = \frac{3}{3} + \frac{1}{3} - 2 - 1 + 1$

Step 19.2.2.4

Write $- 2$ as a fraction with denominator $1$ .

$f (1) = \frac{3}{3} + \frac{1}{3} + \frac{- 2}{1} - 1 + 1$

Step 19.2.2.5

Multiply $\frac{- 2}{1}$ by $\frac{3}{3}$ .

$f (1) = \frac{3}{3} + \frac{1}{3} + \frac{- 2}{1} \cdot \frac{3}{3} - 1 + 1$

Step 19.2.2.6

Multiply $\frac{- 2}{1}$ by $\frac{3}{3}$ .

$f (1) = \frac{3}{3} + \frac{1}{3} + \frac{- 2 \cdot 3}{3} - 1 + 1$

Step 19.2.2.7

Write $- 1$ as a fraction with denominator $1$ .

$f (1) = \frac{3}{3} + \frac{1}{3} + \frac{- 2 \cdot 3}{3} + \frac{- 1}{1} + 1$

Step 19.2.2.8

Multiply $\frac{- 1}{1}$ by $\frac{3}{3}$ .

$f (1) = \frac{3}{3} + \frac{1}{3} + \frac{- 2 \cdot 3}{3} + \frac{- 1}{1} \cdot \frac{3}{3} + 1$

Step 19.2.2.9

Multiply $\frac{- 1}{1}$ by $\frac{3}{3}$ .

$f (1) = \frac{3}{3} + \frac{1}{3} + \frac{- 2 \cdot 3}{3} + \frac{- 1 \cdot 3}{3} + 1$

Step 19.2.2.10

Write $1$ as a fraction with denominator $1$ .

$f (1) = \frac{3}{3} + \frac{1}{3} + \frac{- 2 \cdot 3}{3} + \frac{- 1 \cdot 3}{3} + \frac{1}{1}$

Step 19.2.2.11

Multiply $\frac{1}{1}$ by $\frac{3}{3}$ .

$f (1) = \frac{3}{3} + \frac{1}{3} + \frac{- 2 \cdot 3}{3} + \frac{- 1 \cdot 3}{3} + \frac{1}{1} \cdot \frac{3}{3}$

Step 19.2.2.12

Multiply $\frac{1}{1}$ by $\frac{3}{3}$ .

$f (1) = \frac{3}{3} + \frac{1}{3} + \frac{- 2 \cdot 3}{3} + \frac{- 1 \cdot 3}{3} + \frac{3}{3}$

Step 19.2.3

Combine the numerators over the common denominator.

$f (1) = \frac{3 + 1 - 2 \cdot 3 - 1 \cdot 3 + 3}{3}$

Step 19.2.4

Simplify each term.

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Step 19.2.4.1

Multiply $- 2$ by $3$ .

$f (1) = \frac{3 + 1 - 6 - 1 \cdot 3 + 3}{3}$

Step 19.2.4.2

Multiply $- 1$ by $3$ .

$f (1) = \frac{3 + 1 - 6 - 3 + 3}{3}$

Step 19.2.5

Simplify the expression.

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Step 19.2.5.1

Add $3$ and $1$ .

$f (1) = \frac{4 - 6 - 3 + 3}{3}$

Step 19.2.5.2

Subtract $6$ from $4$ .

$f (1) = \frac{- 2 - 3 + 3}{3}$

Step 19.2.5.3

Subtract $3$ from $- 2$ .

$f (1) = \frac{- 5 + 3}{3}$

Step 19.2.5.4

Add $- 5$ and $3$ .

$f (1) = \frac{- 2}{3}$

Step 19.2.5.5

Move the negative in front of the fraction.

$f (1) = - \frac{2}{3}$

Step 19.2.6

The final answer is $- \frac{2}{3}$ .

$y = - \frac{2}{3}$

Step 20

These are the local extrema for $f (x) = x^{4} + \frac{1}{3} x^{3} - 2 x^{2} - x + 1$ .

$(- \frac{1}{4}, \frac{863}{768})$ is a local maxima

$(- 1, \frac{2}{3})$ is a local minima

$(1, - \frac{2}{3})$ is a local minima

Step 21