Calculus Examples

$lim_{x \to 5} \frac{{(3.99)}^{2} + 4 (3.99) - 32}{{(3.99)}^{2} - 16}$

Step 1

Evaluate the limit of $\frac{{(3.99)}^{2} + 4 (3.99) - 32}{{(3.99)}^{2} - 16}$ which is constant as $x$ approaches $5$ .

$\frac{{(3.99)}^{2} + 4 (3.99) - 32}{{(3.99)}^{2} - 16}$

Step 2

Simplify the answer.

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Step 2.1

Simplify the numerator.

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Step 2.1.1

Raise $3.99$ to the power of $2$ .

$\frac{15.9201 + 4 (3.99) - 32}{{3.99}^{2} - 16}$

Step 2.1.2

Multiply $4$ by $3.99$ .

$\frac{15.9201 + 15.96 - 32}{{3.99}^{2} - 16}$

Step 2.1.3

Add $15.9201$ and $15.96$ .

$\frac{31.8801 - 32}{{3.99}^{2} - 16}$

Step 2.1.4

Subtract $32$ from $31.8801$ .

$\frac{- 0.1199}{{3.99}^{2} - 16}$

Step 2.2

Simplify the denominator.

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Step 2.2.1

Raise $3.99$ to the power of $2$ .

$\frac{- 0.1199}{15.9201 - 16}$

Step 2.2.2

Subtract $16$ from $15.9201$ .

$\frac{- 0.1199}{- 0.0799}$

Step 2.3

Divide $- 0.1199$ by $- 0.0799$ .

$1.50062578$