Calculus Examples

$lim_{x \to \infty} \frac{x^{10}}{e^{x}}$

Step 1

Apply L'Hospital's rule.

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Step 1.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 1.1.1

Take the limit of the numerator and the limit of the denominator.

$\frac{lim_{x \to \infty} x^{10}}{lim_{x \to \infty} e^{x}}$

Step 1.1.2

The limit at infinity of a polynomial whose leading coefficient is positive is infinity.

$\frac{\infty}{lim_{x \to \infty} e^{x}}$

Step 1.1.3

Since the exponent $x$ approaches $\infty$ , the quantity $e^{x}$ approaches $\infty$ .

$\frac{\infty}{\infty}$

Step 1.1.4

Infinity divided by infinity is undefined.

Undefined

$\frac{\infty}{\infty}$

Step 1.2

Since $\frac{\infty}{\infty}$ is of indeterminate form, apply L'Hospital's Rule. L'Hospital's Rule states that the limit of a quotient of functions is equal to the limit of the quotient of their derivatives.

$lim_{x \to \infty} \frac{x^{10}}{e^{x}} = lim_{x \to \infty} \frac{\frac{d}{d x} [x^{10}]}{\frac{d}{d x} [e^{x}]}$

Step 1.3

Find the derivative of the numerator and denominator.

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Step 1.3.1

Differentiate the numerator and denominator.

$lim_{x \to \infty} \frac{\frac{d}{d x} [x^{10}]}{\frac{d}{d x} [e^{x}]}$

Step 1.3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 10$ .

$lim_{x \to \infty} \frac{10 x^{9}}{\frac{d}{d x} [e^{x}]}$

Step 1.3.3

Differentiate using the Exponential Rule which states that $\frac{d}{d x} [a^{x}]$ is $a^{x} \ln (a)$ where $a$ = $e$ .

$lim_{x \to \infty} \frac{10 x^{9}}{e^{x}}$

Step 2

Move the term $10$ outside of the limit because it is constant with respect to $x$ .

$10 lim_{x \to \infty} \frac{x^{9}}{e^{x}}$

Step 3

Apply L'Hospital's rule.

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Step 3.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 3.1.1

Take the limit of the numerator and the limit of the denominator.

$10 \frac{lim_{x \to \infty} x^{9}}{lim_{x \to \infty} e^{x}}$

Step 3.1.2

The limit at infinity of a polynomial whose leading coefficient is positive is infinity.

$10 \frac{\infty}{lim_{x \to \infty} e^{x}}$

Step 3.1.3

Since the exponent $x$ approaches $\infty$ , the quantity $e^{x}$ approaches $\infty$ .

$10 \frac{\infty}{\infty}$

Step 3.1.4

Infinity divided by infinity is undefined.

Undefined

$10 \frac{\infty}{\infty}$

Step 3.2

$lim_{x \to \infty} \frac{x^{9}}{e^{x}} = lim_{x \to \infty} \frac{\frac{d}{d x} [x^{9}]}{\frac{d}{d x} [e^{x}]}$

Step 3.3

Find the derivative of the numerator and denominator.

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Step 3.3.1

Differentiate the numerator and denominator.

$10 lim_{x \to \infty} \frac{\frac{d}{d x} [x^{9}]}{\frac{d}{d x} [e^{x}]}$

Step 3.3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 9$ .

$10 lim_{x \to \infty} \frac{9 x^{8}}{\frac{d}{d x} [e^{x}]}$

Step 3.3.3

Differentiate using the Exponential Rule which states that $\frac{d}{d x} [a^{x}]$ is $a^{x} \ln (a)$ where $a$ = $e$ .

$10 lim_{x \to \infty} \frac{9 x^{8}}{e^{x}}$

Step 4

Move the term $9$ outside of the limit because it is constant with respect to $x$ .

$10 \cdot 9 lim_{x \to \infty} \frac{x^{8}}{e^{x}}$

Step 5

Apply L'Hospital's rule.

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Step 5.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 5.1.1

Take the limit of the numerator and the limit of the denominator.

$10 \cdot 9 \frac{lim_{x \to \infty} x^{8}}{lim_{x \to \infty} e^{x}}$

Step 5.1.2

The limit at infinity of a polynomial whose leading coefficient is positive is infinity.

$10 \cdot 9 \frac{\infty}{lim_{x \to \infty} e^{x}}$

Step 5.1.3

Since the exponent $x$ approaches $\infty$ , the quantity $e^{x}$ approaches $\infty$ .

$10 \cdot 9 \frac{\infty}{\infty}$

Step 5.1.4

Infinity divided by infinity is undefined.

Undefined

$10 \cdot 9 \frac{\infty}{\infty}$

Step 5.2

$lim_{x \to \infty} \frac{x^{8}}{e^{x}} = lim_{x \to \infty} \frac{\frac{d}{d x} [x^{8}]}{\frac{d}{d x} [e^{x}]}$

Step 5.3

Find the derivative of the numerator and denominator.

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Step 5.3.1

Differentiate the numerator and denominator.

$10 \cdot 9 lim_{x \to \infty} \frac{\frac{d}{d x} [x^{8}]}{\frac{d}{d x} [e^{x}]}$

Step 5.3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 8$ .

$10 \cdot 9 lim_{x \to \infty} \frac{8 x^{7}}{\frac{d}{d x} [e^{x}]}$

Step 5.3.3

Differentiate using the Exponential Rule which states that $\frac{d}{d x} [a^{x}]$ is $a^{x} \ln (a)$ where $a$ = $e$ .

$10 \cdot 9 lim_{x \to \infty} \frac{8 x^{7}}{e^{x}}$

Step 6

Move the term $8$ outside of the limit because it is constant with respect to $x$ .

$10 \cdot 9 \cdot 8 lim_{x \to \infty} \frac{x^{7}}{e^{x}}$

Step 7

Apply L'Hospital's rule.

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Step 7.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 7.1.1

Take the limit of the numerator and the limit of the denominator.

$10 \cdot 9 \cdot 8 \frac{lim_{x \to \infty} x^{7}}{lim_{x \to \infty} e^{x}}$

Step 7.1.2

The limit at infinity of a polynomial whose leading coefficient is positive is infinity.

$10 \cdot 9 \cdot 8 \frac{\infty}{lim_{x \to \infty} e^{x}}$

Step 7.1.3

Since the exponent $x$ approaches $\infty$ , the quantity $e^{x}$ approaches $\infty$ .

$10 \cdot 9 \cdot 8 \frac{\infty}{\infty}$

Step 7.1.4

Infinity divided by infinity is undefined.

Undefined

$10 \cdot 9 \cdot 8 \frac{\infty}{\infty}$

Step 7.2

$lim_{x \to \infty} \frac{x^{7}}{e^{x}} = lim_{x \to \infty} \frac{\frac{d}{d x} [x^{7}]}{\frac{d}{d x} [e^{x}]}$

Step 7.3

Find the derivative of the numerator and denominator.

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Step 7.3.1

Differentiate the numerator and denominator.

$10 \cdot 9 \cdot 8 lim_{x \to \infty} \frac{\frac{d}{d x} [x^{7}]}{\frac{d}{d x} [e^{x}]}$

Step 7.3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 7$ .

$10 \cdot 9 \cdot 8 lim_{x \to \infty} \frac{7 x^{6}}{\frac{d}{d x} [e^{x}]}$

Step 7.3.3

Differentiate using the Exponential Rule which states that $\frac{d}{d x} [a^{x}]$ is $a^{x} \ln (a)$ where $a$ = $e$ .

$10 \cdot 9 \cdot 8 lim_{x \to \infty} \frac{7 x^{6}}{e^{x}}$

Step 8

Move the term $7$ outside of the limit because it is constant with respect to $x$ .

$10 \cdot 9 \cdot 8 \cdot 7 lim_{x \to \infty} \frac{x^{6}}{e^{x}}$

Step 9

Apply L'Hospital's rule.

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Step 9.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 9.1.1

Take the limit of the numerator and the limit of the denominator.

$10 \cdot 9 \cdot 8 \cdot 7 \frac{lim_{x \to \infty} x^{6}}{lim_{x \to \infty} e^{x}}$

Step 9.1.2

The limit at infinity of a polynomial whose leading coefficient is positive is infinity.

$10 \cdot 9 \cdot 8 \cdot 7 \frac{\infty}{lim_{x \to \infty} e^{x}}$

Step 9.1.3

Since the exponent $x$ approaches $\infty$ , the quantity $e^{x}$ approaches $\infty$ .

$10 \cdot 9 \cdot 8 \cdot 7 \frac{\infty}{\infty}$

Step 9.1.4

Infinity divided by infinity is undefined.

Undefined

$10 \cdot 9 \cdot 8 \cdot 7 \frac{\infty}{\infty}$

Step 9.2

$lim_{x \to \infty} \frac{x^{6}}{e^{x}} = lim_{x \to \infty} \frac{\frac{d}{d x} [x^{6}]}{\frac{d}{d x} [e^{x}]}$

Step 9.3

Find the derivative of the numerator and denominator.

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Step 9.3.1

Differentiate the numerator and denominator.

$10 \cdot 9 \cdot 8 \cdot 7 lim_{x \to \infty} \frac{\frac{d}{d x} [x^{6}]}{\frac{d}{d x} [e^{x}]}$

Step 9.3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 6$ .

$10 \cdot 9 \cdot 8 \cdot 7 lim_{x \to \infty} \frac{6 x^{5}}{\frac{d}{d x} [e^{x}]}$

Step 9.3.3

Differentiate using the Exponential Rule which states that $\frac{d}{d x} [a^{x}]$ is $a^{x} \ln (a)$ where $a$ = $e$ .

$10 \cdot 9 \cdot 8 \cdot 7 lim_{x \to \infty} \frac{6 x^{5}}{e^{x}}$

Step 10

Move the term $6$ outside of the limit because it is constant with respect to $x$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 lim_{x \to \infty} \frac{x^{5}}{e^{x}}$

Step 11

Apply L'Hospital's rule.

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Step 11.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 11.1.1

Take the limit of the numerator and the limit of the denominator.

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \frac{lim_{x \to \infty} x^{5}}{lim_{x \to \infty} e^{x}}$

Step 11.1.2

The limit at infinity of a polynomial whose leading coefficient is positive is infinity.

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \frac{\infty}{lim_{x \to \infty} e^{x}}$

Step 11.1.3

Since the exponent $x$ approaches $\infty$ , the quantity $e^{x}$ approaches $\infty$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \frac{\infty}{\infty}$

Step 11.1.4

Infinity divided by infinity is undefined.

Undefined

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \frac{\infty}{\infty}$

Step 11.2

$lim_{x \to \infty} \frac{x^{5}}{e^{x}} = lim_{x \to \infty} \frac{\frac{d}{d x} [x^{5}]}{\frac{d}{d x} [e^{x}]}$

Step 11.3

Find the derivative of the numerator and denominator.

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Step 11.3.1

Differentiate the numerator and denominator.

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 lim_{x \to \infty} \frac{\frac{d}{d x} [x^{5}]}{\frac{d}{d x} [e^{x}]}$

Step 11.3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 5$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 lim_{x \to \infty} \frac{5 x^{4}}{\frac{d}{d x} [e^{x}]}$

Step 11.3.3

Differentiate using the Exponential Rule which states that $\frac{d}{d x} [a^{x}]$ is $a^{x} \ln (a)$ where $a$ = $e$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 lim_{x \to \infty} \frac{5 x^{4}}{e^{x}}$

Step 12

Move the term $5$ outside of the limit because it is constant with respect to $x$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 lim_{x \to \infty} \frac{x^{4}}{e^{x}}$

Step 13

Apply L'Hospital's rule.

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Step 13.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 13.1.1

Take the limit of the numerator and the limit of the denominator.

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \frac{lim_{x \to \infty} x^{4}}{lim_{x \to \infty} e^{x}}$

Step 13.1.2

The limit at infinity of a polynomial whose leading coefficient is positive is infinity.

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \frac{\infty}{lim_{x \to \infty} e^{x}}$

Step 13.1.3

Since the exponent $x$ approaches $\infty$ , the quantity $e^{x}$ approaches $\infty$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \frac{\infty}{\infty}$

Step 13.1.4

Infinity divided by infinity is undefined.

Undefined

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \frac{\infty}{\infty}$

Step 13.2

$lim_{x \to \infty} \frac{x^{4}}{e^{x}} = lim_{x \to \infty} \frac{\frac{d}{d x} [x^{4}]}{\frac{d}{d x} [e^{x}]}$

Step 13.3

Find the derivative of the numerator and denominator.

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Step 13.3.1

Differentiate the numerator and denominator.

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 lim_{x \to \infty} \frac{\frac{d}{d x} [x^{4}]}{\frac{d}{d x} [e^{x}]}$

Step 13.3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 4$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 lim_{x \to \infty} \frac{4 x^{3}}{\frac{d}{d x} [e^{x}]}$

Step 13.3.3

Differentiate using the Exponential Rule which states that $\frac{d}{d x} [a^{x}]$ is $a^{x} \ln (a)$ where $a$ = $e$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 lim_{x \to \infty} \frac{4 x^{3}}{e^{x}}$

Step 14

Move the term $4$ outside of the limit because it is constant with respect to $x$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 lim_{x \to \infty} \frac{x^{3}}{e^{x}}$

Step 15

Apply L'Hospital's rule.

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Step 15.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 15.1.1

Take the limit of the numerator and the limit of the denominator.

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \frac{lim_{x \to \infty} x^{3}}{lim_{x \to \infty} e^{x}}$

Step 15.1.2

The limit at infinity of a polynomial whose leading coefficient is positive is infinity.

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \frac{\infty}{lim_{x \to \infty} e^{x}}$

Step 15.1.3

Since the exponent $x$ approaches $\infty$ , the quantity $e^{x}$ approaches $\infty$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \frac{\infty}{\infty}$

Step 15.1.4

Infinity divided by infinity is undefined.

Undefined

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \frac{\infty}{\infty}$

Step 15.2

$lim_{x \to \infty} \frac{x^{3}}{e^{x}} = lim_{x \to \infty} \frac{\frac{d}{d x} [x^{3}]}{\frac{d}{d x} [e^{x}]}$

Step 15.3

Find the derivative of the numerator and denominator.

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Step 15.3.1

Differentiate the numerator and denominator.

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 lim_{x \to \infty} \frac{\frac{d}{d x} [x^{3}]}{\frac{d}{d x} [e^{x}]}$

Step 15.3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 lim_{x \to \infty} \frac{3 x^{2}}{\frac{d}{d x} [e^{x}]}$

Step 15.3.3

Differentiate using the Exponential Rule which states that $\frac{d}{d x} [a^{x}]$ is $a^{x} \ln (a)$ where $a$ = $e$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 lim_{x \to \infty} \frac{3 x^{2}}{e^{x}}$

Step 16

Move the term $3$ outside of the limit because it is constant with respect to $x$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 lim_{x \to \infty} \frac{x^{2}}{e^{x}}$

Step 17

Apply L'Hospital's rule.

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Step 17.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 17.1.1

Take the limit of the numerator and the limit of the denominator.

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \frac{lim_{x \to \infty} x^{2}}{lim_{x \to \infty} e^{x}}$

Step 17.1.2

The limit at infinity of a polynomial whose leading coefficient is positive is infinity.

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \frac{\infty}{lim_{x \to \infty} e^{x}}$

Step 17.1.3

Since the exponent $x$ approaches $\infty$ , the quantity $e^{x}$ approaches $\infty$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \frac{\infty}{\infty}$

Step 17.1.4

Infinity divided by infinity is undefined.

Undefined

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \frac{\infty}{\infty}$

Step 17.2

$lim_{x \to \infty} \frac{x^{2}}{e^{x}} = lim_{x \to \infty} \frac{\frac{d}{d x} [x^{2}]}{\frac{d}{d x} [e^{x}]}$

Step 17.3

Find the derivative of the numerator and denominator.

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Step 17.3.1

Differentiate the numerator and denominator.

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 lim_{x \to \infty} \frac{\frac{d}{d x} [x^{2}]}{\frac{d}{d x} [e^{x}]}$

Step 17.3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 lim_{x \to \infty} \frac{2 x}{\frac{d}{d x} [e^{x}]}$

Step 17.3.3

Differentiate using the Exponential Rule which states that $\frac{d}{d x} [a^{x}]$ is $a^{x} \ln (a)$ where $a$ = $e$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 lim_{x \to \infty} \frac{2 x}{e^{x}}$

Step 18

Move the term $2$ outside of the limit because it is constant with respect to $x$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 lim_{x \to \infty} \frac{x}{e^{x}}$

Step 19

Apply L'Hospital's rule.

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Step 19.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 19.1.1

Take the limit of the numerator and the limit of the denominator.

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \frac{lim_{x \to \infty} x}{lim_{x \to \infty} e^{x}}$

Step 19.1.2

The limit at infinity of a polynomial whose leading coefficient is positive is infinity.

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \frac{\infty}{lim_{x \to \infty} e^{x}}$

Step 19.1.3

Since the exponent $x$ approaches $\infty$ , the quantity $e^{x}$ approaches $\infty$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \frac{\infty}{\infty}$

Step 19.1.4

Infinity divided by infinity is undefined.

Undefined

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \frac{\infty}{\infty}$

Step 19.2

$lim_{x \to \infty} \frac{x}{e^{x}} = lim_{x \to \infty} \frac{\frac{d}{d x} [x]}{\frac{d}{d x} [e^{x}]}$

Step 19.3

Find the derivative of the numerator and denominator.

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Step 19.3.1

Differentiate the numerator and denominator.

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 lim_{x \to \infty} \frac{\frac{d}{d x} [x]}{\frac{d}{d x} [e^{x}]}$

Step 19.3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 lim_{x \to \infty} \frac{1}{\frac{d}{d x} [e^{x}]}$

Step 19.3.3

Differentiate using the Exponential Rule which states that $\frac{d}{d x} [a^{x}]$ is $a^{x} \ln (a)$ where $a$ = $e$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 lim_{x \to \infty} \frac{1}{e^{x}}$

Step 20

Since its numerator approaches a real number while its denominator is unbounded, the fraction $\frac{1}{e^{x}}$ approaches $0$ .

$10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 0$

Step 21

Multiply $10 \cdot 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 0$ .

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Step 21.1

Multiply $10$ by $9$ .

$90 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 0$

Step 21.2

Multiply $90$ by $8$ .

$720 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 0$

Step 21.3

Multiply $720$ by $7$ .

$5040 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 0$

Step 21.4

Multiply $5040$ by $6$ .

$30240 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 0$

Step 21.5

Multiply $30240$ by $5$ .

$151200 \cdot 4 \cdot 3 \cdot 2 \cdot 0$

Step 21.6

Multiply $151200$ by $4$ .

$604800 \cdot 3 \cdot 2 \cdot 0$

Step 21.7

Multiply $604800$ by $3$ .

$1814400 \cdot 2 \cdot 0$

Step 21.8

Multiply $1814400$ by $2$ .

$3628800 \cdot 0$

Step 21.9

Multiply $3628800$ by $0$ .

$0$