Calculus Examples

$lim_{x \to 0} (\sqrt{16 h + 1} - 1) {(h)}^{- 1}$

Step 1

Evaluate the limit of $(\sqrt{16 h + 1} - 1) {(h)}^{- 1}$ which is constant as $x$ approaches $0$ .

$(\sqrt{16 h + 1} - 1) {(h)}^{- 1}$

Step 2

Simplify the answer.

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Step 2.1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$(\sqrt{16 h + 1} - 1) \frac{1}{h}$

Step 2.2

Multiply $\sqrt{16 h + 1} - 1$ by $\frac{1}{h}$ .

$\frac{\sqrt{16 h + 1} - 1}{h}$