Calculus Examples

$lim_{x \to 0} (x^{2}) \cdot {2.71828}^{\sin (\frac{1}{x})}$

Step 1

Since $x^{2} \cdot {2.71828}^{- 1} \leq (x^{2}) \cdot {2.71828}^{\sin (\frac{1}{x})} \leq x^{2} \cdot {2.71828}^{1}$ and $lim_{x \to 0} x^{2} \cdot {2.71828}^{- 1} = lim_{x \to 0} x^{2} \cdot {2.71828}^{1} = 0$ , apply the squeeze theorem.

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