Calculus Examples

$lim_{x \to \infty} \frac{\sin (2 x)}{x}$

Step 1

Since $\frac{- 1}{x} \leq \frac{\sin (2 x)}{x} \leq \frac{1}{x}$ and $lim_{x \to \infty} \frac{- 1}{x} = lim_{x \to \infty} \frac{1}{x} = 0$ , apply the squeeze theorem.

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