Calculus Examples

$y = \frac{4 x}{\sqrt{x + 1}}$

Step 1

Find the first derivative.

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Step 1.1

Differentiate using the Constant Multiple Rule.

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Step 1.1.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x + 1}$ as ${(x + 1)}^{\frac{1}{2}}$ .

$\frac{d}{d x} [\frac{4 x}{{(x + 1)}^{\frac{1}{2}}}]$

Step 1.1.2

Since $4$ is constant with respect to $x$ , the derivative of $\frac{4 x}{{(x + 1)}^{\frac{1}{2}}}$ with respect to $x$ is $4 \frac{d}{d x} [\frac{x}{{(x + 1)}^{\frac{1}{2}}}]$ .

$4 \frac{d}{d x} [\frac{x}{{(x + 1)}^{\frac{1}{2}}}]$

Step 1.2

Differentiate using the Quotient Rule which states that $\frac{d}{d x} [\frac{f (x)}{g (x)}]$ is $\frac{g (x) \frac{d}{d x} [f (x)] - f (x) \frac{d}{d x} [g (x)]}{{g (x)}^{2}}$ where $f (x) = x$ and $g (x) = {(x + 1)}^{\frac{1}{2}}$ .

$4 \frac{{(x + 1)}^{\frac{1}{2}} \frac{d}{d x} [x] - x \frac{d}{d x} [{(x + 1)}^{\frac{1}{2}}]}{{({(x + 1)}^{\frac{1}{2}})}^{2}}$

Step 1.3

Multiply the exponents in ${({(x + 1)}^{\frac{1}{2}})}^{2}$ .

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Step 1.3.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$4 \frac{{(x + 1)}^{\frac{1}{2}} \frac{d}{d x} [x] - x \frac{d}{d x} [{(x + 1)}^{\frac{1}{2}}]}{{(x + 1)}^{\frac{1}{2} \cdot 2}}$

Step 1.3.2

Cancel the common factor of $2$ .

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Step 1.3.2.1

Cancel the common factor.

$4 \frac{{(x + 1)}^{\frac{1}{2}} \frac{d}{d x} [x] - x \frac{d}{d x} [{(x + 1)}^{\frac{1}{2}}]}{{(x + 1)}^{\frac{1}{2} \cdot 2}}$

Step 1.3.2.2

Rewrite the expression.

$4 \frac{{(x + 1)}^{\frac{1}{2}} \frac{d}{d x} [x] - x \frac{d}{d x} [{(x + 1)}^{\frac{1}{2}}]}{{(x + 1)}^{1}}$

Step 1.4

Simplify.

$4 \frac{{(x + 1)}^{\frac{1}{2}} \frac{d}{d x} [x] - x \frac{d}{d x} [{(x + 1)}^{\frac{1}{2}}]}{x + 1}$

Step 1.5

Differentiate using the Power Rule.

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Step 1.5.1

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$4 \frac{{(x + 1)}^{\frac{1}{2}} \cdot 1 - x \frac{d}{d x} [{(x + 1)}^{\frac{1}{2}}]}{x + 1}$

Step 1.5.2

Multiply ${(x + 1)}^{\frac{1}{2}}$ by $1$ .

$4 \frac{{(x + 1)}^{\frac{1}{2}} - x \frac{d}{d x} [{(x + 1)}^{\frac{1}{2}}]}{x + 1}$

Step 1.6

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{1}{2}}$ and $g (x) = x + 1$ .

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Step 1.6.1

To apply the Chain Rule, set $u$ as $x + 1$ .

$4 \frac{{(x + 1)}^{\frac{1}{2}} - x (\frac{d}{d u} [u^{\frac{1}{2}}] \frac{d}{d x} [x + 1])}{x + 1}$

Step 1.6.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = \frac{1}{2}$ .

$4 \frac{{(x + 1)}^{\frac{1}{2}} - x (\frac{1}{2} u^{\frac{1}{2} - 1} \frac{d}{d x} [x + 1])}{x + 1}$

Step 1.6.3

Replace all occurrences of $u$ with $x + 1$ .

$4 \frac{{(x + 1)}^{\frac{1}{2}} - x (\frac{1}{2} {(x + 1)}^{\frac{1}{2} - 1} \frac{d}{d x} [x + 1])}{x + 1}$

Step 1.7

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$4 \frac{{(x + 1)}^{\frac{1}{2}} - x (\frac{1}{2} {(x + 1)}^{\frac{1}{2} - 1 \cdot \frac{2}{2}} \frac{d}{d x} [x + 1])}{x + 1}$

Step 1.8

Combine $- 1$ and $\frac{2}{2}$ .

$4 \frac{{(x + 1)}^{\frac{1}{2}} - x (\frac{1}{2} {(x + 1)}^{\frac{1}{2} + \frac{- 1 \cdot 2}{2}} \frac{d}{d x} [x + 1])}{x + 1}$

Step 1.9

Combine the numerators over the common denominator.

$4 \frac{{(x + 1)}^{\frac{1}{2}} - x (\frac{1}{2} {(x + 1)}^{\frac{1 - 1 \cdot 2}{2}} \frac{d}{d x} [x + 1])}{x + 1}$

Step 1.10

Simplify the numerator.

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Step 1.10.1

Multiply $- 1$ by $2$ .

$4 \frac{{(x + 1)}^{\frac{1}{2}} - x (\frac{1}{2} {(x + 1)}^{\frac{1 - 2}{2}} \frac{d}{d x} [x + 1])}{x + 1}$

Step 1.10.2

Subtract $2$ from $1$ .

$4 \frac{{(x + 1)}^{\frac{1}{2}} - x (\frac{1}{2} {(x + 1)}^{\frac{- 1}{2}} \frac{d}{d x} [x + 1])}{x + 1}$

Step 1.11

Combine fractions.

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Step 1.11.1

Move the negative in front of the fraction.

$4 \frac{{(x + 1)}^{\frac{1}{2}} - x (\frac{1}{2} {(x + 1)}^{- \frac{1}{2}} \frac{d}{d x} [x + 1])}{x + 1}$

Step 1.11.2

Combine $\frac{1}{2}$ and ${(x + 1)}^{- \frac{1}{2}}$ .

$4 \frac{{(x + 1)}^{\frac{1}{2}} - x (\frac{{(x + 1)}^{- \frac{1}{2}}}{2} \frac{d}{d x} [x + 1])}{x + 1}$

Step 1.11.3

Move ${(x + 1)}^{- \frac{1}{2}}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$4 \frac{{(x + 1)}^{\frac{1}{2}} - x (\frac{1}{2 {(x + 1)}^{\frac{1}{2}}} \frac{d}{d x} [x + 1])}{x + 1}$

Step 1.11.4

Combine $\frac{1}{2 {(x + 1)}^{\frac{1}{2}}}$ and $x$ .

$4 \frac{{(x + 1)}^{\frac{1}{2}} - \frac{x}{2 {(x + 1)}^{\frac{1}{2}}} \frac{d}{d x} [x + 1]}{x + 1}$

Step 1.12

By the Sum Rule, the derivative of $x + 1$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [1]$ .

$4 \frac{{(x + 1)}^{\frac{1}{2}} - \frac{x}{2 {(x + 1)}^{\frac{1}{2}}} (\frac{d}{d x} [x] + \frac{d}{d x} [1])}{x + 1}$

Step 1.13

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$4 \frac{{(x + 1)}^{\frac{1}{2}} - \frac{x}{2 {(x + 1)}^{\frac{1}{2}}} (1 + \frac{d}{d x} [1])}{x + 1}$

Step 1.14

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$4 \frac{{(x + 1)}^{\frac{1}{2}} - \frac{x}{2 {(x + 1)}^{\frac{1}{2}}} (1 + 0)}{x + 1}$

Step 1.15

Simplify the expression.

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Step 1.15.1

Add $1$ and $0$ .

$4 \frac{{(x + 1)}^{\frac{1}{2}} - \frac{x}{2 {(x + 1)}^{\frac{1}{2}}} \cdot 1}{x + 1}$

Step 1.15.2

Multiply $- 1$ by $1$ .

$4 \frac{{(x + 1)}^{\frac{1}{2}} - \frac{x}{2 {(x + 1)}^{\frac{1}{2}}}}{x + 1}$

Step 1.16

To write ${(x + 1)}^{\frac{1}{2}}$ as a fraction with a common denominator, multiply by $\frac{2 {(x + 1)}^{\frac{1}{2}}}{2 {(x + 1)}^{\frac{1}{2}}}$ .

$4 \frac{{(x + 1)}^{\frac{1}{2}} \cdot \frac{2 {(x + 1)}^{\frac{1}{2}}}{2 {(x + 1)}^{\frac{1}{2}}} - \frac{x}{2 {(x + 1)}^{\frac{1}{2}}}}{x + 1}$

Step 1.17

Combine ${(x + 1)}^{\frac{1}{2}}$ and $\frac{2 {(x + 1)}^{\frac{1}{2}}}{2 {(x + 1)}^{\frac{1}{2}}}$ .

$4 \frac{\frac{{(x + 1)}^{\frac{1}{2}} (2 {(x + 1)}^{\frac{1}{2}})}{2 {(x + 1)}^{\frac{1}{2}}} - \frac{x}{2 {(x + 1)}^{\frac{1}{2}}}}{x + 1}$

Step 1.18

Combine the numerators over the common denominator.

$4 \frac{\frac{{(x + 1)}^{\frac{1}{2}} (2 {(x + 1)}^{\frac{1}{2}}) - x}{2 {(x + 1)}^{\frac{1}{2}}}}{x + 1}$

Step 1.19

Multiply ${(x + 1)}^{\frac{1}{2}}$ by ${(x + 1)}^{\frac{1}{2}}$ by adding the exponents.

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Step 1.19.1

Move ${(x + 1)}^{\frac{1}{2}}$ .

$4 \frac{\frac{{(x + 1)}^{\frac{1}{2}} {(x + 1)}^{\frac{1}{2}} \cdot 2 - x}{2 {(x + 1)}^{\frac{1}{2}}}}{x + 1}$

Step 1.19.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$4 \frac{\frac{{(x + 1)}^{\frac{1}{2} + \frac{1}{2}} \cdot 2 - x}{2 {(x + 1)}^{\frac{1}{2}}}}{x + 1}$

Step 1.19.3

Combine the numerators over the common denominator.

$4 \frac{\frac{{(x + 1)}^{\frac{1 + 1}{2}} \cdot 2 - x}{2 {(x + 1)}^{\frac{1}{2}}}}{x + 1}$

Step 1.19.4

Add $1$ and $1$ .

$4 \frac{\frac{{(x + 1)}^{\frac{2}{2}} \cdot 2 - x}{2 {(x + 1)}^{\frac{1}{2}}}}{x + 1}$

Step 1.19.5

Divide $2$ by $2$ .

$4 \frac{\frac{{(x + 1)}^{1} \cdot 2 - x}{2 {(x + 1)}^{\frac{1}{2}}}}{x + 1}$

Step 1.20

Simplify ${(x + 1)}^{1} \cdot 2$ .

$4 \frac{\frac{(x + 1) \cdot 2 - x}{2 {(x + 1)}^{\frac{1}{2}}}}{x + 1}$

Step 1.21

Move $2$ to the left of $x + 1$ .

$4 \frac{\frac{2 \cdot (x + 1) - x}{2 {(x + 1)}^{\frac{1}{2}}}}{x + 1}$

Step 1.22

Rewrite $\frac{\frac{2 (x + 1) - x}{2 {(x + 1)}^{\frac{1}{2}}}}{x + 1}$ as a product.

$4 (\frac{2 (x + 1) - x}{2 {(x + 1)}^{\frac{1}{2}}} \cdot \frac{1}{x + 1})$

Step 1.23

Multiply $\frac{2 (x + 1) - x}{2 {(x + 1)}^{\frac{1}{2}}}$ by $\frac{1}{x + 1}$ .

$4 \frac{2 (x + 1) - x}{2 {(x + 1)}^{\frac{1}{2}} (x + 1)}$

Step 1.24

Raise $x + 1$ to the power of $1$ .

$4 \frac{2 (x + 1) - x}{2 ({(x + 1)}^{1} {(x + 1)}^{\frac{1}{2}})}$

Step 1.25

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$4 \frac{2 (x + 1) - x}{2 {(x + 1)}^{1 + \frac{1}{2}}}$

Step 1.26

Simplify the expression.

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Step 1.26.1

Write $1$ as a fraction with a common denominator.

$4 \frac{2 (x + 1) - x}{2 {(x + 1)}^{\frac{2}{2} + \frac{1}{2}}}$

Step 1.26.2

Combine the numerators over the common denominator.

$4 \frac{2 (x + 1) - x}{2 {(x + 1)}^{\frac{2 + 1}{2}}}$

Step 1.26.3

Add $2$ and $1$ .

$4 \frac{2 (x + 1) - x}{2 {(x + 1)}^{\frac{3}{2}}}$

Step 1.27

Combine $4$ and $\frac{2 (x + 1) - x}{2 {(x + 1)}^{\frac{3}{2}}}$ .

$\frac{4 (2 (x + 1) - x)}{2 {(x + 1)}^{\frac{3}{2}}}$

Step 1.28

Factor $2$ out of $4 (2 (x + 1) - x)$ .

$\frac{2 (2 (2 (x + 1) - x))}{2 {(x + 1)}^{\frac{3}{2}}}$

Step 1.29

Cancel the common factors.

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Step 1.29.1

Factor $2$ out of $2 {(x + 1)}^{\frac{3}{2}}$ .

$\frac{2 (2 (2 (x + 1) - x))}{2 ({(x + 1)}^{\frac{3}{2}})}$

Step 1.29.2

Cancel the common factor.

$\frac{2 (2 (2 (x + 1) - x))}{2 {(x + 1)}^{\frac{3}{2}}}$

Step 1.29.3

Rewrite the expression.

$\frac{2 (2 (x + 1) - x)}{{(x + 1)}^{\frac{3}{2}}}$

Step 1.30

Simplify.

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Step 1.30.1

Apply the distributive property.

$\frac{2 (2 x + 2 \cdot 1 - x)}{{(x + 1)}^{\frac{3}{2}}}$

Step 1.30.2

Apply the distributive property.

$\frac{2 (2 x) + 2 (2 \cdot 1) + 2 (- x)}{{(x + 1)}^{\frac{3}{2}}}$

Step 1.30.3

Simplify the numerator.

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Step 1.30.3.1

Simplify each term.

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Step 1.30.3.1.1

Multiply $2$ by $2$ .

$\frac{4 x + 2 (2 \cdot 1) + 2 (- x)}{{(x + 1)}^{\frac{3}{2}}}$

Step 1.30.3.1.2

Multiply $2 (2 \cdot 1)$ .

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Step 1.30.3.1.2.1

Multiply $2$ by $1$ .

$\frac{4 x + 2 \cdot 2 + 2 (- x)}{{(x + 1)}^{\frac{3}{2}}}$

Step 1.30.3.1.2.2

Multiply $2$ by $2$ .

$\frac{4 x + 4 + 2 (- x)}{{(x + 1)}^{\frac{3}{2}}}$

Step 1.30.3.1.3

Multiply $- 1$ by $2$ .

$\frac{4 x + 4 - 2 x}{{(x + 1)}^{\frac{3}{2}}}$

Step 1.30.3.2

Subtract $2 x$ from $4 x$ .

$\frac{2 x + 4}{{(x + 1)}^{\frac{3}{2}}}$

Step 1.30.4

Factor $2$ out of $2 x + 4$ .

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Step 1.30.4.1

Factor $2$ out of $2 x$ .

$\frac{2 (x) + 4}{{(x + 1)}^{\frac{3}{2}}}$

Step 1.30.4.2

Factor $2$ out of $4$ .

$\frac{2 x + 2 \cdot 2}{{(x + 1)}^{\frac{3}{2}}}$

Step 1.30.4.3

Factor $2$ out of $2 x + 2 \cdot 2$ .

$f' (x) = \frac{2 (x + 2)}{{(x + 1)}^{\frac{3}{2}}}$

Step 2

Find the second derivative.

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Step 2.1

Since $2$ is constant with respect to $x$ , the derivative of $\frac{2 (x + 2)}{{(x + 1)}^{\frac{3}{2}}}$ with respect to $x$ is $2 \frac{d}{d x} [\frac{x + 2}{{(x + 1)}^{\frac{3}{2}}}]$ .

$2 \frac{d}{d x} [\frac{x + 2}{{(x + 1)}^{\frac{3}{2}}}]$

Step 2.2

$2 \frac{{(x + 1)}^{\frac{3}{2}} \frac{d}{d x} [x + 2] - (x + 2) \frac{d}{d x} [{(x + 1)}^{\frac{3}{2}}]}{{({(x + 1)}^{\frac{3}{2}})}^{2}}$

Step 2.3

Differentiate.

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Step 2.3.1

Multiply the exponents in ${({(x + 1)}^{\frac{3}{2}})}^{2}$ .

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Step 2.3.1.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$2 \frac{{(x + 1)}^{\frac{3}{2}} \frac{d}{d x} [x + 2] - (x + 2) \frac{d}{d x} [{(x + 1)}^{\frac{3}{2}}]}{{(x + 1)}^{\frac{3}{2} \cdot 2}}$

Step 2.3.1.2

Cancel the common factor of $2$ .

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Step 2.3.1.2.1

Cancel the common factor.

$2 \frac{{(x + 1)}^{\frac{3}{2}} \frac{d}{d x} [x + 2] - (x + 2) \frac{d}{d x} [{(x + 1)}^{\frac{3}{2}}]}{{(x + 1)}^{\frac{3}{2} \cdot 2}}$

Step 2.3.1.2.2

Rewrite the expression.

$2 \frac{{(x + 1)}^{\frac{3}{2}} \frac{d}{d x} [x + 2] - (x + 2) \frac{d}{d x} [{(x + 1)}^{\frac{3}{2}}]}{{(x + 1)}^{3}}$

Step 2.3.2

By the Sum Rule, the derivative of $x + 2$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [2]$ .

$2 \frac{{(x + 1)}^{\frac{3}{2}} (\frac{d}{d x} [x] + \frac{d}{d x} [2]) - (x + 2) \frac{d}{d x} [{(x + 1)}^{\frac{3}{2}}]}{{(x + 1)}^{3}}$

Step 2.3.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$2 \frac{{(x + 1)}^{\frac{3}{2}} (1 + \frac{d}{d x} [2]) - (x + 2) \frac{d}{d x} [{(x + 1)}^{\frac{3}{2}}]}{{(x + 1)}^{3}}$

Step 2.3.4

Since $2$ is constant with respect to $x$ , the derivative of $2$ with respect to $x$ is $0$ .

$2 \frac{{(x + 1)}^{\frac{3}{2}} (1 + 0) - (x + 2) \frac{d}{d x} [{(x + 1)}^{\frac{3}{2}}]}{{(x + 1)}^{3}}$

Step 2.3.5

Simplify the expression.

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Step 2.3.5.1

Add $1$ and $0$ .

$2 \frac{{(x + 1)}^{\frac{3}{2}} \cdot 1 - (x + 2) \frac{d}{d x} [{(x + 1)}^{\frac{3}{2}}]}{{(x + 1)}^{3}}$

Step 2.3.5.2

Multiply ${(x + 1)}^{\frac{3}{2}}$ by $1$ .

$2 \frac{{(x + 1)}^{\frac{3}{2}} - (x + 2) \frac{d}{d x} [{(x + 1)}^{\frac{3}{2}}]}{{(x + 1)}^{3}}$

Step 2.4

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{3}{2}}$ and $g (x) = x + 1$ .

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Step 2.4.1

To apply the Chain Rule, set $u$ as $x + 1$ .

$2 \frac{{(x + 1)}^{\frac{3}{2}} - (x + 2) (\frac{d}{d u} [u^{\frac{3}{2}}] \frac{d}{d x} [x + 1])}{{(x + 1)}^{3}}$

Step 2.4.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = \frac{3}{2}$ .

$2 \frac{{(x + 1)}^{\frac{3}{2}} - (x + 2) (\frac{3}{2} u^{\frac{3}{2} - 1} \frac{d}{d x} [x + 1])}{{(x + 1)}^{3}}$

Step 2.4.3

Replace all occurrences of $u$ with $x + 1$ .

$2 \frac{{(x + 1)}^{\frac{3}{2}} - (x + 2) (\frac{3}{2} {(x + 1)}^{\frac{3}{2} - 1} \frac{d}{d x} [x + 1])}{{(x + 1)}^{3}}$

Step 2.5

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$2 \frac{{(x + 1)}^{\frac{3}{2}} - (x + 2) (\frac{3}{2} {(x + 1)}^{\frac{3}{2} - 1 \cdot \frac{2}{2}} \frac{d}{d x} [x + 1])}{{(x + 1)}^{3}}$

Step 2.6

Combine $- 1$ and $\frac{2}{2}$ .

$2 \frac{{(x + 1)}^{\frac{3}{2}} - (x + 2) (\frac{3}{2} {(x + 1)}^{\frac{3}{2} + \frac{- 1 \cdot 2}{2}} \frac{d}{d x} [x + 1])}{{(x + 1)}^{3}}$

Step 2.7

Combine the numerators over the common denominator.

$2 \frac{{(x + 1)}^{\frac{3}{2}} - (x + 2) (\frac{3}{2} {(x + 1)}^{\frac{3 - 1 \cdot 2}{2}} \frac{d}{d x} [x + 1])}{{(x + 1)}^{3}}$

Step 2.8

Simplify the numerator.

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Step 2.8.1

Multiply $- 1$ by $2$ .

$2 \frac{{(x + 1)}^{\frac{3}{2}} - (x + 2) (\frac{3}{2} {(x + 1)}^{\frac{3 - 2}{2}} \frac{d}{d x} [x + 1])}{{(x + 1)}^{3}}$

Step 2.8.2

Subtract $2$ from $3$ .

$2 \frac{{(x + 1)}^{\frac{3}{2}} - (x + 2) (\frac{3}{2} {(x + 1)}^{\frac{1}{2}} \frac{d}{d x} [x + 1])}{{(x + 1)}^{3}}$

Step 2.9

Combine $\frac{3}{2}$ and ${(x + 1)}^{\frac{1}{2}}$ .

$2 \frac{{(x + 1)}^{\frac{3}{2}} - (x + 2) (\frac{3 {(x + 1)}^{\frac{1}{2}}}{2} \frac{d}{d x} [x + 1])}{{(x + 1)}^{3}}$

Step 2.10

By the Sum Rule, the derivative of $x + 1$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [1]$ .

$2 \frac{{(x + 1)}^{\frac{3}{2}} - (x + 2) (\frac{3 {(x + 1)}^{\frac{1}{2}}}{2} (\frac{d}{d x} [x] + \frac{d}{d x} [1]))}{{(x + 1)}^{3}}$

Step 2.11

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$2 \frac{{(x + 1)}^{\frac{3}{2}} - (x + 2) (\frac{3 {(x + 1)}^{\frac{1}{2}}}{2} (1 + \frac{d}{d x} [1]))}{{(x + 1)}^{3}}$

Step 2.12

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$2 \frac{{(x + 1)}^{\frac{3}{2}} - (x + 2) (\frac{3 {(x + 1)}^{\frac{1}{2}}}{2} (1 + 0))}{{(x + 1)}^{3}}$

Step 2.13

Combine fractions.

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Step 2.13.1

Add $1$ and $0$ .

$2 \frac{{(x + 1)}^{\frac{3}{2}} - (x + 2) (\frac{3 {(x + 1)}^{\frac{1}{2}}}{2} \cdot 1)}{{(x + 1)}^{3}}$

Step 2.13.2

Multiply $\frac{3 {(x + 1)}^{\frac{1}{2}}}{2}$ by $1$ .

$2 \frac{{(x + 1)}^{\frac{3}{2}} - (x + 2) \frac{3 {(x + 1)}^{\frac{1}{2}}}{2}}{{(x + 1)}^{3}}$

Step 2.13.3

Combine $2$ and $\frac{{(x + 1)}^{\frac{3}{2}} - (x + 2) \frac{3 {(x + 1)}^{\frac{1}{2}}}{2}}{{(x + 1)}^{3}}$ .

$\frac{2 ({(x + 1)}^{\frac{3}{2}} - (x + 2) \frac{3 {(x + 1)}^{\frac{1}{2}}}{2})}{{(x + 1)}^{3}}$

Step 2.14

Simplify.

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Step 2.14.1

Apply the distributive property.

$\frac{2 ({(x + 1)}^{\frac{3}{2}} + (- x - 1 \cdot 2) \frac{3 {(x + 1)}^{\frac{1}{2}}}{2})}{{(x + 1)}^{3}}$

Step 2.14.2

Apply the distributive property.

$\frac{2 {(x + 1)}^{\frac{3}{2}} + 2 ((- x - 1 \cdot 2) \frac{3 {(x + 1)}^{\frac{1}{2}}}{2})}{{(x + 1)}^{3}}$

Step 2.14.3

Simplify the numerator.

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Step 2.14.3.1

Factor $2$ out of $2 {(x + 1)}^{\frac{3}{2}} + 2 (- x - 1 \cdot 2) \frac{3 {(x + 1)}^{\frac{1}{2}}}{2}$ .

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Step 2.14.3.1.1

Factor $2$ out of $2 {(x + 1)}^{\frac{3}{2}}$ .

$\frac{2 ({(x + 1)}^{\frac{3}{2}}) + 2 (- x - 1 \cdot 2) \frac{3 {(x + 1)}^{\frac{1}{2}}}{2}}{{(x + 1)}^{3}}$

Step 2.14.3.1.2

Factor $2$ out of $2 (- x - 1 \cdot 2) \frac{3 {(x + 1)}^{\frac{1}{2}}}{2}$ .

$\frac{2 ({(x + 1)}^{\frac{3}{2}}) + 2 ((- x - 1 \cdot 2) \frac{3 {(x + 1)}^{\frac{1}{2}}}{2})}{{(x + 1)}^{3}}$

Step 2.14.3.1.3

Factor $2$ out of $2 ({(x + 1)}^{\frac{3}{2}}) + 2 ((- x - 1 \cdot 2) \frac{3 {(x + 1)}^{\frac{1}{2}}}{2})$ .

$\frac{2 ({(x + 1)}^{\frac{3}{2}} + (- x - 1 \cdot 2) \frac{3 {(x + 1)}^{\frac{1}{2}}}{2})}{{(x + 1)}^{3}}$

Step 2.14.3.2

Multiply $- 1$ by $2$ .

$\frac{2 ({(x + 1)}^{\frac{3}{2}} + (- x - 2) \frac{3 {(x + 1)}^{\frac{1}{2}}}{2})}{{(x + 1)}^{3}}$

Step 2.14.3.3

Apply the distributive property.

$\frac{2 ({(x + 1)}^{\frac{3}{2}} - x \frac{3 {(x + 1)}^{\frac{1}{2}}}{2} - 2 \frac{3 {(x + 1)}^{\frac{1}{2}}}{2})}{{(x + 1)}^{3}}$

Step 2.14.3.4

Combine $\frac{3 {(x + 1)}^{\frac{1}{2}}}{2}$ and $x$ .

$\frac{2 ({(x + 1)}^{\frac{3}{2}} - \frac{3 {(x + 1)}^{\frac{1}{2}} x}{2} - 2 \frac{3 {(x + 1)}^{\frac{1}{2}}}{2})}{{(x + 1)}^{3}}$

Step 2.14.3.5

Cancel the common factor of $2$ .

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Step 2.14.3.5.1

Factor $2$ out of $- 2$ .

$\frac{2 ({(x + 1)}^{\frac{3}{2}} - \frac{3 {(x + 1)}^{\frac{1}{2}} x}{2} + 2 (- 1) \frac{3 {(x + 1)}^{\frac{1}{2}}}{2})}{{(x + 1)}^{3}}$

Step 2.14.3.5.2

Cancel the common factor.

$\frac{2 ({(x + 1)}^{\frac{3}{2}} - \frac{3 {(x + 1)}^{\frac{1}{2}} x}{2} + 2 \cdot - 1 \frac{3 {(x + 1)}^{\frac{1}{2}}}{2})}{{(x + 1)}^{3}}$

Step 2.14.3.5.3

Rewrite the expression.

$\frac{2 ({(x + 1)}^{\frac{3}{2}} - \frac{3 {(x + 1)}^{\frac{1}{2}} x}{2} - 1 (3 {(x + 1)}^{\frac{1}{2}}))}{{(x + 1)}^{3}}$

Step 2.14.3.6

Multiply $3$ by $- 1$ .

$\frac{2 ({(x + 1)}^{\frac{3}{2}} - \frac{3 {(x + 1)}^{\frac{1}{2}} x}{2} - 3 {(x + 1)}^{\frac{1}{2}})}{{(x + 1)}^{3}}$

Step 2.14.3.7

To write $- 3 {(x + 1)}^{\frac{1}{2}}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{2 ({(x + 1)}^{\frac{3}{2}} - \frac{3 {(x + 1)}^{\frac{1}{2}} x}{2} - 3 {(x + 1)}^{\frac{1}{2}} \cdot \frac{2}{2})}{{(x + 1)}^{3}}$

Step 2.14.3.8

Combine $- 3 {(x + 1)}^{\frac{1}{2}}$ and $\frac{2}{2}$ .

$\frac{2 ({(x + 1)}^{\frac{3}{2}} - \frac{3 {(x + 1)}^{\frac{1}{2}} x}{2} + \frac{- 3 {(x + 1)}^{\frac{1}{2}} \cdot 2}{2})}{{(x + 1)}^{3}}$

Step 2.14.3.9

Combine the numerators over the common denominator.

$\frac{2 ({(x + 1)}^{\frac{3}{2}} + \frac{- 3 {(x + 1)}^{\frac{1}{2}} x - 3 {(x + 1)}^{\frac{1}{2}} \cdot 2}{2})}{{(x + 1)}^{3}}$

Step 2.14.3.10

Simplify the numerator.

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Step 2.14.3.10.1

Factor $3 {(x + 1)}^{\frac{1}{2}}$ out of $- 3 {(x + 1)}^{\frac{1}{2}} x - 3 {(x + 1)}^{\frac{1}{2}} \cdot 2$ .

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Step 2.14.3.10.1.1

Reorder the expression.

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Step 2.14.3.10.1.1.1

Move ${(x + 1)}^{\frac{1}{2}}$ .

$\frac{2 ({(x + 1)}^{\frac{3}{2}} + \frac{- 3 x {(x + 1)}^{\frac{1}{2}} - 3 {(x + 1)}^{\frac{1}{2}} \cdot 2}{2})}{{(x + 1)}^{3}}$

Step 2.14.3.10.1.1.2

Move ${(x + 1)}^{\frac{1}{2}}$ .

$\frac{2 ({(x + 1)}^{\frac{3}{2}} + \frac{- 3 x {(x + 1)}^{\frac{1}{2}} - 3 \cdot 2 {(x + 1)}^{\frac{1}{2}}}{2})}{{(x + 1)}^{3}}$

Step 2.14.3.10.1.2

Factor $3 {(x + 1)}^{\frac{1}{2}}$ out of $- 3 x {(x + 1)}^{\frac{1}{2}}$ .

$\frac{2 ({(x + 1)}^{\frac{3}{2}} + \frac{3 {(x + 1)}^{\frac{1}{2}} (- x) - 3 \cdot 2 {(x + 1)}^{\frac{1}{2}}}{2})}{{(x + 1)}^{3}}$

Step 2.14.3.10.1.3

Factor $3 {(x + 1)}^{\frac{1}{2}}$ out of $- 3 \cdot 2 {(x + 1)}^{\frac{1}{2}}$ .

$\frac{2 ({(x + 1)}^{\frac{3}{2}} + \frac{3 {(x + 1)}^{\frac{1}{2}} (- x) + 3 {(x + 1)}^{\frac{1}{2}} (- 1 \cdot 2)}{2})}{{(x + 1)}^{3}}$

Step 2.14.3.10.1.4

Factor $3 {(x + 1)}^{\frac{1}{2}}$ out of $3 {(x + 1)}^{\frac{1}{2}} (- x) + 3 {(x + 1)}^{\frac{1}{2}} (- 1 \cdot 2)$ .

$\frac{2 ({(x + 1)}^{\frac{3}{2}} + \frac{3 {(x + 1)}^{\frac{1}{2}} (- x - 1 \cdot 2)}{2})}{{(x + 1)}^{3}}$

Step 2.14.3.10.2

Multiply $- 1$ by $2$ .

$\frac{2 ({(x + 1)}^{\frac{3}{2}} + \frac{3 {(x + 1)}^{\frac{1}{2}} (- x - 2)}{2})}{{(x + 1)}^{3}}$

Step 2.14.3.11

To write ${(x + 1)}^{\frac{3}{2}}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{2 ({(x + 1)}^{\frac{3}{2}} \cdot \frac{2}{2} + \frac{3 {(x + 1)}^{\frac{1}{2}} (- x - 2)}{2})}{{(x + 1)}^{3}}$

Step 2.14.3.12

Combine ${(x + 1)}^{\frac{3}{2}}$ and $\frac{2}{2}$ .

$\frac{2 (\frac{{(x + 1)}^{\frac{3}{2}} \cdot 2}{2} + \frac{3 {(x + 1)}^{\frac{1}{2}} (- x - 2)}{2})}{{(x + 1)}^{3}}$

Step 2.14.3.13

Combine the numerators over the common denominator.

$\frac{2 \frac{{(x + 1)}^{\frac{3}{2}} \cdot 2 + 3 {(x + 1)}^{\frac{1}{2}} (- x - 2)}{2}}{{(x + 1)}^{3}}$

Step 2.14.3.14

Rewrite $\frac{{(x + 1)}^{\frac{3}{2}} \cdot 2 + 3 {(x + 1)}^{\frac{1}{2}} (- x - 2)}{2}$ in a factored form.

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Step 2.14.3.14.1

Factor ${(x + 1)}^{\frac{1}{2}}$ out of ${(x + 1)}^{\frac{3}{2}} \cdot 2 + 3 {(x + 1)}^{\frac{1}{2}} (- x - 2)$ .

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Step 2.14.3.14.1.1

Reorder ${(x + 1)}^{\frac{3}{2}}$ and $2$ .

$\frac{2 \frac{2 \cdot {(x + 1)}^{\frac{3}{2}} + 3 {(x + 1)}^{\frac{1}{2}} (- x - 2)}{2}}{{(x + 1)}^{3}}$

Step 2.14.3.14.1.2

Factor ${(x + 1)}^{\frac{1}{2}}$ out of $2 \cdot {(x + 1)}^{\frac{3}{2}}$ .

$\frac{2 \frac{{(x + 1)}^{\frac{1}{2}} (2 \cdot {(x + 1)}^{\frac{2}{2}}) + 3 {(x + 1)}^{\frac{1}{2}} (- x - 2)}{2}}{{(x + 1)}^{3}}$

Step 2.14.3.14.1.3

Factor ${(x + 1)}^{\frac{1}{2}}$ out of $3 {(x + 1)}^{\frac{1}{2}} (- x - 2)$ .

$\frac{2 \frac{{(x + 1)}^{\frac{1}{2}} (2 \cdot {(x + 1)}^{\frac{2}{2}}) + {(x + 1)}^{\frac{1}{2}} (3 (- x - 2))}{2}}{{(x + 1)}^{3}}$

Step 2.14.3.14.1.4

Factor ${(x + 1)}^{\frac{1}{2}}$ out of ${(x + 1)}^{\frac{1}{2}} (2 \cdot {(x + 1)}^{\frac{2}{2}}) + {(x + 1)}^{\frac{1}{2}} (3 (- x - 2))$ .

$\frac{2 \frac{{(x + 1)}^{\frac{1}{2}} (2 \cdot {(x + 1)}^{\frac{2}{2}} + 3 (- x - 2))}{2}}{{(x + 1)}^{3}}$

Step 2.14.3.14.2

Divide $2$ by $2$ .

$\frac{2 \frac{{(x + 1)}^{\frac{1}{2}} (2 \cdot {(x + 1)}^{1} + 3 (- x - 2))}{2}}{{(x + 1)}^{3}}$

Step 2.14.3.14.3

Simplify.

$\frac{2 \frac{{(x + 1)}^{\frac{1}{2}} (2 \cdot (x + 1) + 3 (- x - 2))}{2}}{{(x + 1)}^{3}}$

Step 2.14.3.14.4

Apply the distributive property.

$\frac{2 \frac{{(x + 1)}^{\frac{1}{2}} (2 x + 2 \cdot 1 + 3 (- x - 2))}{2}}{{(x + 1)}^{3}}$

Step 2.14.3.14.5

Multiply $2$ by $1$ .

$\frac{2 \frac{{(x + 1)}^{\frac{1}{2}} (2 x + 2 + 3 (- x - 2))}{2}}{{(x + 1)}^{3}}$

Step 2.14.3.14.6

Apply the distributive property.

$\frac{2 \frac{{(x + 1)}^{\frac{1}{2}} (2 x + 2 + 3 (- x) + 3 \cdot - 2)}{2}}{{(x + 1)}^{3}}$

Step 2.14.3.14.7

Multiply $- 1$ by $3$ .

$\frac{2 \frac{{(x + 1)}^{\frac{1}{2}} (2 x + 2 - 3 x + 3 \cdot - 2)}{2}}{{(x + 1)}^{3}}$

Step 2.14.3.14.8

Multiply $3$ by $- 2$ .

$\frac{2 \frac{{(x + 1)}^{\frac{1}{2}} (2 x + 2 - 3 x - 6)}{2}}{{(x + 1)}^{3}}$

Step 2.14.3.14.9

Subtract $3 x$ from $2 x$ .

$\frac{2 \frac{{(x + 1)}^{\frac{1}{2}} (- x + 2 - 6)}{2}}{{(x + 1)}^{3}}$

Step 2.14.3.14.10

Subtract $6$ from $2$ .

$\frac{2 \frac{{(x + 1)}^{\frac{1}{2}} (- x - 4)}{2}}{{(x + 1)}^{3}}$

Step 2.14.4

Combine terms.

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Step 2.14.4.1

Combine $2$ and $\frac{{(x + 1)}^{\frac{1}{2}} (- x - 4)}{2}$ .

$\frac{\frac{2 ({(x + 1)}^{\frac{1}{2}} (- x - 4))}{2}}{{(x + 1)}^{3}}$

Step 2.14.4.2

Cancel the common factor.

$\frac{\frac{2 {(x + 1)}^{\frac{1}{2}} (- x - 4)}{2}}{{(x + 1)}^{3}}$

Step 2.14.4.3

Divide ${(x + 1)}^{\frac{1}{2}} (- x - 4)$ by $1$ .

$\frac{{(x + 1)}^{\frac{1}{2}} (- x - 4)}{{(x + 1)}^{3}}$

Step 2.14.4.4

Move ${(x + 1)}^{\frac{1}{2}}$ to the denominator using the negative exponent rule $b^{n} = \frac{1}{b^{- n}}$ .

$\frac{- x - 4}{{(x + 1)}^{3} {(x + 1)}^{- \frac{1}{2}}}$

Step 2.14.4.5

Multiply ${(x + 1)}^{3}$ by ${(x + 1)}^{- \frac{1}{2}}$ by adding the exponents.

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Step 2.14.4.5.1

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{- x - 4}{{(x + 1)}^{3 - \frac{1}{2}}}$

Step 2.14.4.5.2

To write $3$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{- x - 4}{{(x + 1)}^{3 \cdot \frac{2}{2} - \frac{1}{2}}}$

Step 2.14.4.5.3

Combine $3$ and $\frac{2}{2}$ .

$\frac{- x - 4}{{(x + 1)}^{\frac{3 \cdot 2}{2} - \frac{1}{2}}}$

Step 2.14.4.5.4

Combine the numerators over the common denominator.

$\frac{- x - 4}{{(x + 1)}^{\frac{3 \cdot 2 - 1}{2}}}$

Step 2.14.4.5.5

Simplify the numerator.

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Step 2.14.4.5.5.1

Multiply $3$ by $2$ .

$\frac{- x - 4}{{(x + 1)}^{\frac{6 - 1}{2}}}$

Step 2.14.4.5.5.2

Subtract $1$ from $6$ .

$\frac{- x - 4}{{(x + 1)}^{\frac{5}{2}}}$

Step 2.14.5

Factor $- 1$ out of $- x$ .

$\frac{- (x) - 4}{{(x + 1)}^{\frac{5}{2}}}$

Step 2.14.6

Rewrite $- 4$ as $- 1 (4)$ .

$\frac{- (x) - 1 (4)}{{(x + 1)}^{\frac{5}{2}}}$

Step 2.14.7

Factor $- 1$ out of $- (x) - 1 (4)$ .

$\frac{- (x + 4)}{{(x + 1)}^{\frac{5}{2}}}$

Step 2.14.8

Rewrite $- (x + 4)$ as $- 1 (x + 4)$ .

$\frac{- 1 (x + 4)}{{(x + 1)}^{\frac{5}{2}}}$

Step 2.14.9

Move the negative in front of the fraction.

$f'' (x) = - \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}}$

Step 3

Find the third derivative.

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Step 3.1

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = - 1$ and $g (x) = \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}}$ .

$- \frac{d}{d x} [\frac{x + 4}{{(x + 1)}^{\frac{5}{2}}}] + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.2

$- \frac{{(x + 1)}^{\frac{5}{2}} \frac{d}{d x} [x + 4] - (x + 4) \frac{d}{d x} [{(x + 1)}^{\frac{5}{2}}]}{{({(x + 1)}^{\frac{5}{2}})}^{2}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.3

Differentiate.

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Step 3.3.1

Multiply the exponents in ${({(x + 1)}^{\frac{5}{2}})}^{2}$ .

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Step 3.3.1.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} \frac{d}{d x} [x + 4] - (x + 4) \frac{d}{d x} [{(x + 1)}^{\frac{5}{2}}]}{{(x + 1)}^{\frac{5}{2} \cdot 2}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.3.1.2

Cancel the common factor of $2$ .

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Step 3.3.1.2.1

Cancel the common factor.

$- \frac{{(x + 1)}^{\frac{5}{2}} \frac{d}{d x} [x + 4] - (x + 4) \frac{d}{d x} [{(x + 1)}^{\frac{5}{2}}]}{{(x + 1)}^{\frac{5}{2} \cdot 2}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.3.1.2.2

Rewrite the expression.

$- \frac{{(x + 1)}^{\frac{5}{2}} \frac{d}{d x} [x + 4] - (x + 4) \frac{d}{d x} [{(x + 1)}^{\frac{5}{2}}]}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.3.2

By the Sum Rule, the derivative of $x + 4$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [4]$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} (\frac{d}{d x} [x] + \frac{d}{d x} [4]) - (x + 4) \frac{d}{d x} [{(x + 1)}^{\frac{5}{2}}]}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.3.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} (1 + \frac{d}{d x} [4]) - (x + 4) \frac{d}{d x} [{(x + 1)}^{\frac{5}{2}}]}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.3.4

Since $4$ is constant with respect to $x$ , the derivative of $4$ with respect to $x$ is $0$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} (1 + 0) - (x + 4) \frac{d}{d x} [{(x + 1)}^{\frac{5}{2}}]}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.3.5

Simplify the expression.

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Step 3.3.5.1

Add $1$ and $0$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} \cdot 1 - (x + 4) \frac{d}{d x} [{(x + 1)}^{\frac{5}{2}}]}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.3.5.2

Multiply ${(x + 1)}^{\frac{5}{2}}$ by $1$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - (x + 4) \frac{d}{d x} [{(x + 1)}^{\frac{5}{2}}]}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.4

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{5}{2}}$ and $g (x) = x + 1$ .

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Step 3.4.1

To apply the Chain Rule, set $u$ as $x + 1$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - (x + 4) (\frac{d}{d u} [u^{\frac{5}{2}}] \frac{d}{d x} [x + 1])}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.4.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = \frac{5}{2}$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - (x + 4) (\frac{5}{2} u^{\frac{5}{2} - 1} \frac{d}{d x} [x + 1])}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.4.3

Replace all occurrences of $u$ with $x + 1$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - (x + 4) (\frac{5}{2} {(x + 1)}^{\frac{5}{2} - 1} \frac{d}{d x} [x + 1])}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.5

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - (x + 4) (\frac{5}{2} {(x + 1)}^{\frac{5}{2} - 1 \cdot \frac{2}{2}} \frac{d}{d x} [x + 1])}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.6

Combine $- 1$ and $\frac{2}{2}$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - (x + 4) (\frac{5}{2} {(x + 1)}^{\frac{5}{2} + \frac{- 1 \cdot 2}{2}} \frac{d}{d x} [x + 1])}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.7

Combine the numerators over the common denominator.

$- \frac{{(x + 1)}^{\frac{5}{2}} - (x + 4) (\frac{5}{2} {(x + 1)}^{\frac{5 - 1 \cdot 2}{2}} \frac{d}{d x} [x + 1])}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.8

Simplify the numerator.

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Step 3.8.1

Multiply $- 1$ by $2$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - (x + 4) (\frac{5}{2} {(x + 1)}^{\frac{5 - 2}{2}} \frac{d}{d x} [x + 1])}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.8.2

Subtract $2$ from $5$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - (x + 4) (\frac{5}{2} {(x + 1)}^{\frac{3}{2}} \frac{d}{d x} [x + 1])}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.9

Combine $\frac{5}{2}$ and ${(x + 1)}^{\frac{3}{2}}$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - (x + 4) (\frac{5 {(x + 1)}^{\frac{3}{2}}}{2} \frac{d}{d x} [x + 1])}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.10

By the Sum Rule, the derivative of $x + 1$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [1]$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - (x + 4) (\frac{5 {(x + 1)}^{\frac{3}{2}}}{2} (\frac{d}{d x} [x] + \frac{d}{d x} [1]))}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.11

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - (x + 4) (\frac{5 {(x + 1)}^{\frac{3}{2}}}{2} (1 + \frac{d}{d x} [1]))}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.12

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - (x + 4) (\frac{5 {(x + 1)}^{\frac{3}{2}}}{2} (1 + 0))}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.13

Simplify the expression.

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Step 3.13.1

Add $1$ and $0$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - (x + 4) (\frac{5 {(x + 1)}^{\frac{3}{2}}}{2} \cdot 1)}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.13.2

Multiply $\frac{5 {(x + 1)}^{\frac{3}{2}}}{2}$ by $1$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - (x + 4) \frac{5 {(x + 1)}^{\frac{3}{2}}}{2}}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \frac{d}{d x} [- 1]$

Step 3.14

Since $- 1$ is constant with respect to $x$ , the derivative of $- 1$ with respect to $x$ is $0$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - (x + 4) \frac{5 {(x + 1)}^{\frac{3}{2}}}{2}}{{(x + 1)}^{5}} + \frac{x + 4}{{(x + 1)}^{\frac{5}{2}}} \cdot 0$

Step 3.15

Simplify the expression.

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Step 3.15.1

Multiply $\frac{x + 4}{{(x + 1)}^{\frac{5}{2}}}$ by $0$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - (x + 4) \frac{5 {(x + 1)}^{\frac{3}{2}}}{2}}{{(x + 1)}^{5}} + 0$

Step 3.15.2

Add $- \frac{{(x + 1)}^{\frac{5}{2}} - (x + 4) \frac{5 {(x + 1)}^{\frac{3}{2}}}{2}}{{(x + 1)}^{5}}$ and $0$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - (x + 4) \frac{5 {(x + 1)}^{\frac{3}{2}}}{2}}{{(x + 1)}^{5}}$

Step 3.16

Simplify.

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Step 3.16.1

Apply the distributive property.

$- \frac{{(x + 1)}^{\frac{5}{2}} + (- x - 1 \cdot 4) \frac{5 {(x + 1)}^{\frac{3}{2}}}{2}}{{(x + 1)}^{5}}$

Step 3.16.2

Simplify the numerator.

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Step 3.16.2.1

Multiply $- 1$ by $4$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} + (- x - 4) \frac{5 {(x + 1)}^{\frac{3}{2}}}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.2

Apply the distributive property.

$- \frac{{(x + 1)}^{\frac{5}{2}} - x \frac{5 {(x + 1)}^{\frac{3}{2}}}{2} - 4 \frac{5 {(x + 1)}^{\frac{3}{2}}}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.3

Combine $\frac{5 {(x + 1)}^{\frac{3}{2}}}{2}$ and $x$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - \frac{5 {(x + 1)}^{\frac{3}{2}} x}{2} - 4 \frac{5 {(x + 1)}^{\frac{3}{2}}}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.4

Cancel the common factor of $2$ .

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Step 3.16.2.4.1

Factor $2$ out of $- 4$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - \frac{5 {(x + 1)}^{\frac{3}{2}} x}{2} + 2 (- 2) \frac{5 {(x + 1)}^{\frac{3}{2}}}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.4.2

Cancel the common factor.

$- \frac{{(x + 1)}^{\frac{5}{2}} - \frac{5 {(x + 1)}^{\frac{3}{2}} x}{2} + 2 \cdot - 2 \frac{5 {(x + 1)}^{\frac{3}{2}}}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.4.3

Rewrite the expression.

$- \frac{{(x + 1)}^{\frac{5}{2}} - \frac{5 {(x + 1)}^{\frac{3}{2}} x}{2} - 2 (5 {(x + 1)}^{\frac{3}{2}})}{{(x + 1)}^{5}}$

Step 3.16.2.5

Multiply $5$ by $- 2$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - \frac{5 {(x + 1)}^{\frac{3}{2}} x}{2} - 10 {(x + 1)}^{\frac{3}{2}}}{{(x + 1)}^{5}}$

Step 3.16.2.6

To write $- 10 {(x + 1)}^{\frac{3}{2}}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - \frac{5 {(x + 1)}^{\frac{3}{2}} x}{2} - 10 {(x + 1)}^{\frac{3}{2}} \cdot \frac{2}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.7

Combine $- 10 {(x + 1)}^{\frac{3}{2}}$ and $\frac{2}{2}$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} - \frac{5 {(x + 1)}^{\frac{3}{2}} x}{2} + \frac{- 10 {(x + 1)}^{\frac{3}{2}} \cdot 2}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.8

Combine the numerators over the common denominator.

$- \frac{{(x + 1)}^{\frac{5}{2}} + \frac{- 5 {(x + 1)}^{\frac{3}{2}} x - 10 {(x + 1)}^{\frac{3}{2}} \cdot 2}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.9

Simplify the numerator.

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Step 3.16.2.9.1

Factor $5 {(x + 1)}^{\frac{3}{2}}$ out of $- 5 {(x + 1)}^{\frac{3}{2}} x - 10 {(x + 1)}^{\frac{3}{2}} \cdot 2$ .

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Step 3.16.2.9.1.1

Reorder the expression.

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Step 3.16.2.9.1.1.1

Move ${(x + 1)}^{\frac{3}{2}}$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} + \frac{- 5 x {(x + 1)}^{\frac{3}{2}} - 10 {(x + 1)}^{\frac{3}{2}} \cdot 2}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.9.1.1.2

Move ${(x + 1)}^{\frac{3}{2}}$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} + \frac{- 5 x {(x + 1)}^{\frac{3}{2}} - 10 \cdot 2 {(x + 1)}^{\frac{3}{2}}}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.9.1.2

Factor $5 {(x + 1)}^{\frac{3}{2}}$ out of $- 5 x {(x + 1)}^{\frac{3}{2}}$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} + \frac{5 {(x + 1)}^{\frac{3}{2}} (- x) - 10 \cdot 2 {(x + 1)}^{\frac{3}{2}}}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.9.1.3

Factor $5 {(x + 1)}^{\frac{3}{2}}$ out of $- 10 \cdot 2 {(x + 1)}^{\frac{3}{2}}$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} + \frac{5 {(x + 1)}^{\frac{3}{2}} (- x) + 5 {(x + 1)}^{\frac{3}{2}} (- 2 \cdot 2)}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.9.1.4

Factor $5 {(x + 1)}^{\frac{3}{2}}$ out of $5 {(x + 1)}^{\frac{3}{2}} (- x) + 5 {(x + 1)}^{\frac{3}{2}} (- 2 \cdot 2)$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} + \frac{5 {(x + 1)}^{\frac{3}{2}} (- x - 2 \cdot 2)}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.9.2

Multiply $- 2$ by $2$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} + \frac{5 {(x + 1)}^{\frac{3}{2}} (- x - 4)}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.10

To write ${(x + 1)}^{\frac{5}{2}}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$- \frac{{(x + 1)}^{\frac{5}{2}} \cdot \frac{2}{2} + \frac{5 {(x + 1)}^{\frac{3}{2}} (- x - 4)}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.11

Combine ${(x + 1)}^{\frac{5}{2}}$ and $\frac{2}{2}$ .

$- \frac{\frac{{(x + 1)}^{\frac{5}{2}} \cdot 2}{2} + \frac{5 {(x + 1)}^{\frac{3}{2}} (- x - 4)}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.12

Combine the numerators over the common denominator.

$- \frac{\frac{{(x + 1)}^{\frac{5}{2}} \cdot 2 + 5 {(x + 1)}^{\frac{3}{2}} (- x - 4)}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.13

Rewrite $\frac{{(x + 1)}^{\frac{5}{2}} \cdot 2 + 5 {(x + 1)}^{\frac{3}{2}} (- x - 4)}{2}$ in a factored form.

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Step 3.16.2.13.1

Factor ${(x + 1)}^{\frac{3}{2}}$ out of ${(x + 1)}^{\frac{5}{2}} \cdot 2 + 5 {(x + 1)}^{\frac{3}{2}} (- x - 4)$ .

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Step 3.16.2.13.1.1

Reorder ${(x + 1)}^{\frac{5}{2}}$ and $2$ .

$- \frac{\frac{2 \cdot {(x + 1)}^{\frac{5}{2}} + 5 {(x + 1)}^{\frac{3}{2}} (- x - 4)}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.13.1.2

Factor ${(x + 1)}^{\frac{3}{2}}$ out of $2 \cdot {(x + 1)}^{\frac{5}{2}}$ .

$- \frac{\frac{{(x + 1)}^{\frac{3}{2}} (2 \cdot {(x + 1)}^{\frac{2}{2}}) + 5 {(x + 1)}^{\frac{3}{2}} (- x - 4)}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.13.1.3

Factor ${(x + 1)}^{\frac{3}{2}}$ out of $5 {(x + 1)}^{\frac{3}{2}} (- x - 4)$ .

$- \frac{\frac{{(x + 1)}^{\frac{3}{2}} (2 \cdot {(x + 1)}^{\frac{2}{2}}) + {(x + 1)}^{\frac{3}{2}} (5 (- x - 4))}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.13.1.4

Factor ${(x + 1)}^{\frac{3}{2}}$ out of ${(x + 1)}^{\frac{3}{2}} (2 \cdot {(x + 1)}^{\frac{2}{2}}) + {(x + 1)}^{\frac{3}{2}} (5 (- x - 4))$ .

$- \frac{\frac{{(x + 1)}^{\frac{3}{2}} (2 \cdot {(x + 1)}^{\frac{2}{2}} + 5 (- x - 4))}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.13.2

Divide $2$ by $2$ .

$- \frac{\frac{{(x + 1)}^{\frac{3}{2}} (2 \cdot {(x + 1)}^{1} + 5 (- x - 4))}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.13.3

Simplify.

$- \frac{\frac{{(x + 1)}^{\frac{3}{2}} (2 \cdot (x + 1) + 5 (- x - 4))}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.13.4

Apply the distributive property.

$- \frac{\frac{{(x + 1)}^{\frac{3}{2}} (2 x + 2 \cdot 1 + 5 (- x - 4))}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.13.5

Multiply $2$ by $1$ .

$- \frac{\frac{{(x + 1)}^{\frac{3}{2}} (2 x + 2 + 5 (- x - 4))}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.13.6

Apply the distributive property.

$- \frac{\frac{{(x + 1)}^{\frac{3}{2}} (2 x + 2 + 5 (- x) + 5 \cdot - 4)}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.13.7

Multiply $- 1$ by $5$ .

$- \frac{\frac{{(x + 1)}^{\frac{3}{2}} (2 x + 2 - 5 x + 5 \cdot - 4)}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.13.8

Multiply $5$ by $- 4$ .

$- \frac{\frac{{(x + 1)}^{\frac{3}{2}} (2 x + 2 - 5 x - 20)}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.13.9

Subtract $5 x$ from $2 x$ .

$- \frac{\frac{{(x + 1)}^{\frac{3}{2}} (- 3 x + 2 - 20)}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.13.10

Subtract $20$ from $2$ .

$- \frac{\frac{{(x + 1)}^{\frac{3}{2}} (- 3 x - 18)}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.13.11

Factor $3$ out of $- 3 x - 18$ .

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Step 3.16.2.13.11.1

Factor $3$ out of $- 3 x$ .

$- \frac{\frac{{(x + 1)}^{\frac{3}{2}} (3 (- x) - 18)}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.13.11.2

Factor $3$ out of $- 18$ .

$- \frac{\frac{{(x + 1)}^{\frac{3}{2}} (3 (- x) + 3 (- 6))}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.13.11.3

Factor $3$ out of $3 (- x) + 3 (- 6)$ .

$- \frac{\frac{{(x + 1)}^{\frac{3}{2}} (3 (- x - 6))}{2}}{{(x + 1)}^{5}}$

$- \frac{\frac{{(x + 1)}^{\frac{3}{2}} \cdot 3 (- x - 6)}{2}}{{(x + 1)}^{5}}$

Step 3.16.2.14

Move $3$ to the left of ${(x + 1)}^{\frac{3}{2}}$ .

$- \frac{\frac{3 {(x + 1)}^{\frac{3}{2}} (- x - 6)}{2}}{{(x + 1)}^{5}}$

Step 3.16.3

Combine terms.

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Step 3.16.3.1

Rewrite $\frac{\frac{3 {(x + 1)}^{\frac{3}{2}} (- x - 6)}{2}}{{(x + 1)}^{5}}$ as a product.

$- (\frac{3 {(x + 1)}^{\frac{3}{2}} (- x - 6)}{2} \cdot \frac{1}{{(x + 1)}^{5}})$

Step 3.16.3.2

Multiply $\frac{3 {(x + 1)}^{\frac{3}{2}} (- x - 6)}{2}$ by $\frac{1}{{(x + 1)}^{5}}$ .

$- \frac{3 {(x + 1)}^{\frac{3}{2}} (- x - 6)}{2 {(x + 1)}^{5}}$

Step 3.16.3.3

Move ${(x + 1)}^{\frac{3}{2}}$ to the denominator using the negative exponent rule $b^{n} = \frac{1}{b^{- n}}$ .

$- \frac{3 (- x - 6)}{2 {(x + 1)}^{5} {(x + 1)}^{- \frac{3}{2}}}$

Step 3.16.3.4

Multiply ${(x + 1)}^{5}$ by ${(x + 1)}^{- \frac{3}{2}}$ by adding the exponents.

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Step 3.16.3.4.1

Move ${(x + 1)}^{- \frac{3}{2}}$ .

$- \frac{3 (- x - 6)}{2 ({(x + 1)}^{- \frac{3}{2}} {(x + 1)}^{5})}$

Step 3.16.3.4.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$- \frac{3 (- x - 6)}{2 {(x + 1)}^{- \frac{3}{2} + 5}}$

Step 3.16.3.4.3

To write $5$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$- \frac{3 (- x - 6)}{2 {(x + 1)}^{- \frac{3}{2} + 5 \cdot \frac{2}{2}}}$

Step 3.16.3.4.4

Combine $5$ and $\frac{2}{2}$ .

$- \frac{3 (- x - 6)}{2 {(x + 1)}^{- \frac{3}{2} + \frac{5 \cdot 2}{2}}}$

Step 3.16.3.4.5

Combine the numerators over the common denominator.

$- \frac{3 (- x - 6)}{2 {(x + 1)}^{\frac{- 3 + 5 \cdot 2}{2}}}$

Step 3.16.3.4.6

Simplify the numerator.

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Step 3.16.3.4.6.1

Multiply $5$ by $2$ .

$- \frac{3 (- x - 6)}{2 {(x + 1)}^{\frac{- 3 + 10}{2}}}$

Step 3.16.3.4.6.2

Add $- 3$ and $10$ .

$- \frac{3 (- x - 6)}{2 {(x + 1)}^{\frac{7}{2}}}$

Step 3.16.4

Factor $- 1$ out of $- x$ .

$- \frac{3 (- (x) - 6)}{2 {(x + 1)}^{\frac{7}{2}}}$

Step 3.16.5

Rewrite $- 6$ as $- 1 (6)$ .

$- \frac{3 (- (x) - 1 (6))}{2 {(x + 1)}^{\frac{7}{2}}}$

Step 3.16.6

Factor $- 1$ out of $- (x) - 1 (6)$ .

$- \frac{3 (- (x + 6))}{2 {(x + 1)}^{\frac{7}{2}}}$

Step 3.16.7

Rewrite $- (x + 6)$ as $- 1 (x + 6)$ .

$- \frac{3 (- 1 (x + 6))}{2 {(x + 1)}^{\frac{7}{2}}}$

Step 3.16.8

Move the negative in front of the fraction.

$- - \frac{3 (x + 6)}{2 {(x + 1)}^{\frac{7}{2}}}$

Step 3.16.9

Multiply $- 1$ by $- 1$ .

$1 \frac{3 (x + 6)}{2 {(x + 1)}^{\frac{7}{2}}}$

Step 3.16.10

Multiply $\frac{3 (x + 6)}{2 {(x + 1)}^{\frac{7}{2}}}$ by $1$ .

$f''' (x) = \frac{3 (x + 6)}{2 {(x + 1)}^{\frac{7}{2}}}$

Step 4

Find the fourth derivative.

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Step 4.1

Since $\frac{3}{2}$ is constant with respect to $x$ , the derivative of $\frac{3 (x + 6)}{2 {(x + 1)}^{\frac{7}{2}}}$ with respect to $x$ is $\frac{3}{2} \frac{d}{d x} [\frac{x + 6}{{(x + 1)}^{\frac{7}{2}}}]$ .

$\frac{3}{2} \frac{d}{d x} [\frac{x + 6}{{(x + 1)}^{\frac{7}{2}}}]$

Step 4.2

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} \frac{d}{d x} [x + 6] - (x + 6) \frac{d}{d x} [{(x + 1)}^{\frac{7}{2}}]}{{({(x + 1)}^{\frac{7}{2}})}^{2}}$

Step 4.3

Differentiate.

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Step 4.3.1

Multiply the exponents in ${({(x + 1)}^{\frac{7}{2}})}^{2}$ .

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Step 4.3.1.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} \frac{d}{d x} [x + 6] - (x + 6) \frac{d}{d x} [{(x + 1)}^{\frac{7}{2}}]}{{(x + 1)}^{\frac{7}{2} \cdot 2}}$

Step 4.3.1.2

Cancel the common factor of $2$ .

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Step 4.3.1.2.1

Cancel the common factor.

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} \frac{d}{d x} [x + 6] - (x + 6) \frac{d}{d x} [{(x + 1)}^{\frac{7}{2}}]}{{(x + 1)}^{\frac{7}{2} \cdot 2}}$

Step 4.3.1.2.2

Rewrite the expression.

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} \frac{d}{d x} [x + 6] - (x + 6) \frac{d}{d x} [{(x + 1)}^{\frac{7}{2}}]}{{(x + 1)}^{7}}$

Step 4.3.2

By the Sum Rule, the derivative of $x + 6$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [6]$ .

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} (\frac{d}{d x} [x] + \frac{d}{d x} [6]) - (x + 6) \frac{d}{d x} [{(x + 1)}^{\frac{7}{2}}]}{{(x + 1)}^{7}}$

Step 4.3.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} (1 + \frac{d}{d x} [6]) - (x + 6) \frac{d}{d x} [{(x + 1)}^{\frac{7}{2}}]}{{(x + 1)}^{7}}$

Step 4.3.4

Since $6$ is constant with respect to $x$ , the derivative of $6$ with respect to $x$ is $0$ .

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} (1 + 0) - (x + 6) \frac{d}{d x} [{(x + 1)}^{\frac{7}{2}}]}{{(x + 1)}^{7}}$

Step 4.3.5

Simplify the expression.

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Step 4.3.5.1

Add $1$ and $0$ .

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} \cdot 1 - (x + 6) \frac{d}{d x} [{(x + 1)}^{\frac{7}{2}}]}{{(x + 1)}^{7}}$

Step 4.3.5.2

Multiply ${(x + 1)}^{\frac{7}{2}}$ by $1$ .

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} - (x + 6) \frac{d}{d x} [{(x + 1)}^{\frac{7}{2}}]}{{(x + 1)}^{7}}$

Step 4.4

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{\frac{7}{2}}$ and $g (x) = x + 1$ .

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Step 4.4.1

To apply the Chain Rule, set $u$ as $x + 1$ .

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} - (x + 6) (\frac{d}{d u} [u^{\frac{7}{2}}] \frac{d}{d x} [x + 1])}{{(x + 1)}^{7}}$

Step 4.4.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = \frac{7}{2}$ .

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} - (x + 6) (\frac{7}{2} u^{\frac{7}{2} - 1} \frac{d}{d x} [x + 1])}{{(x + 1)}^{7}}$

Step 4.4.3

Replace all occurrences of $u$ with $x + 1$ .

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} - (x + 6) (\frac{7}{2} {(x + 1)}^{\frac{7}{2} - 1} \frac{d}{d x} [x + 1])}{{(x + 1)}^{7}}$

Step 4.5

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} - (x + 6) (\frac{7}{2} {(x + 1)}^{\frac{7}{2} - 1 \cdot \frac{2}{2}} \frac{d}{d x} [x + 1])}{{(x + 1)}^{7}}$

Step 4.6

Combine $- 1$ and $\frac{2}{2}$ .

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} - (x + 6) (\frac{7}{2} {(x + 1)}^{\frac{7}{2} + \frac{- 1 \cdot 2}{2}} \frac{d}{d x} [x + 1])}{{(x + 1)}^{7}}$

Step 4.7

Combine the numerators over the common denominator.

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} - (x + 6) (\frac{7}{2} {(x + 1)}^{\frac{7 - 1 \cdot 2}{2}} \frac{d}{d x} [x + 1])}{{(x + 1)}^{7}}$

Step 4.8

Simplify the numerator.

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Step 4.8.1

Multiply $- 1$ by $2$ .

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} - (x + 6) (\frac{7}{2} {(x + 1)}^{\frac{7 - 2}{2}} \frac{d}{d x} [x + 1])}{{(x + 1)}^{7}}$

Step 4.8.2

Subtract $2$ from $7$ .

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} - (x + 6) (\frac{7}{2} {(x + 1)}^{\frac{5}{2}} \frac{d}{d x} [x + 1])}{{(x + 1)}^{7}}$

Step 4.9

Combine $\frac{7}{2}$ and ${(x + 1)}^{\frac{5}{2}}$ .

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} - (x + 6) (\frac{7 {(x + 1)}^{\frac{5}{2}}}{2} \frac{d}{d x} [x + 1])}{{(x + 1)}^{7}}$

Step 4.10

By the Sum Rule, the derivative of $x + 1$ with respect to $x$ is $\frac{d}{d x} [x] + \frac{d}{d x} [1]$ .

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} - (x + 6) (\frac{7 {(x + 1)}^{\frac{5}{2}}}{2} (\frac{d}{d x} [x] + \frac{d}{d x} [1]))}{{(x + 1)}^{7}}$

Step 4.11

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} - (x + 6) (\frac{7 {(x + 1)}^{\frac{5}{2}}}{2} (1 + \frac{d}{d x} [1]))}{{(x + 1)}^{7}}$

Step 4.12

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} - (x + 6) (\frac{7 {(x + 1)}^{\frac{5}{2}}}{2} (1 + 0))}{{(x + 1)}^{7}}$

Step 4.13

Combine fractions.

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Step 4.13.1

Add $1$ and $0$ .

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} - (x + 6) (\frac{7 {(x + 1)}^{\frac{5}{2}}}{2} \cdot 1)}{{(x + 1)}^{7}}$

Step 4.13.2

Multiply $\frac{7 {(x + 1)}^{\frac{5}{2}}}{2}$ by $1$ .

$\frac{3}{2} \cdot \frac{{(x + 1)}^{\frac{7}{2}} - (x + 6) \frac{7 {(x + 1)}^{\frac{5}{2}}}{2}}{{(x + 1)}^{7}}$

Step 4.13.3

Multiply $\frac{3}{2}$ by $\frac{{(x + 1)}^{\frac{7}{2}} - (x + 6) \frac{7 {(x + 1)}^{\frac{5}{2}}}{2}}{{(x + 1)}^{7}}$ .

$\frac{3 ({(x + 1)}^{\frac{7}{2}} - (x + 6) \frac{7 {(x + 1)}^{\frac{5}{2}}}{2})}{2 {(x + 1)}^{7}}$

Step 4.14

Simplify.

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Step 4.14.1

Apply the distributive property.

$\frac{3 ({(x + 1)}^{\frac{7}{2}} + (- x - 1 \cdot 6) \frac{7 {(x + 1)}^{\frac{5}{2}}}{2})}{2 {(x + 1)}^{7}}$

Step 4.14.2

Apply the distributive property.

$\frac{3 {(x + 1)}^{\frac{7}{2}} + 3 ((- x - 1 \cdot 6) \frac{7 {(x + 1)}^{\frac{5}{2}}}{2})}{2 {(x + 1)}^{7}}$

Step 4.14.3

Simplify the numerator.

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Step 4.14.3.1

Factor $3$ out of $3 {(x + 1)}^{\frac{7}{2}} + 3 (- x - 1 \cdot 6) \frac{7 {(x + 1)}^{\frac{5}{2}}}{2}$ .

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Step 4.14.3.1.1

Factor $3$ out of $3 {(x + 1)}^{\frac{7}{2}}$ .

$\frac{3 ({(x + 1)}^{\frac{7}{2}}) + 3 (- x - 1 \cdot 6) \frac{7 {(x + 1)}^{\frac{5}{2}}}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.3.1.2

Factor $3$ out of $3 (- x - 1 \cdot 6) \frac{7 {(x + 1)}^{\frac{5}{2}}}{2}$ .

$\frac{3 ({(x + 1)}^{\frac{7}{2}}) + 3 ((- x - 1 \cdot 6) \frac{7 {(x + 1)}^{\frac{5}{2}}}{2})}{2 {(x + 1)}^{7}}$

Step 4.14.3.1.3

Factor $3$ out of $3 ({(x + 1)}^{\frac{7}{2}}) + 3 ((- x - 1 \cdot 6) \frac{7 {(x + 1)}^{\frac{5}{2}}}{2})$ .

$\frac{3 ({(x + 1)}^{\frac{7}{2}} + (- x - 1 \cdot 6) \frac{7 {(x + 1)}^{\frac{5}{2}}}{2})}{2 {(x + 1)}^{7}}$

Step 4.14.3.2

Multiply $- 1$ by $6$ .

$\frac{3 ({(x + 1)}^{\frac{7}{2}} + (- x - 6) \frac{7 {(x + 1)}^{\frac{5}{2}}}{2})}{2 {(x + 1)}^{7}}$

Step 4.14.3.3

Apply the distributive property.

$\frac{3 ({(x + 1)}^{\frac{7}{2}} - x \frac{7 {(x + 1)}^{\frac{5}{2}}}{2} - 6 \frac{7 {(x + 1)}^{\frac{5}{2}}}{2})}{2 {(x + 1)}^{7}}$

Step 4.14.3.4

Combine $\frac{7 {(x + 1)}^{\frac{5}{2}}}{2}$ and $x$ .

$\frac{3 ({(x + 1)}^{\frac{7}{2}} - \frac{7 {(x + 1)}^{\frac{5}{2}} x}{2} - 6 \frac{7 {(x + 1)}^{\frac{5}{2}}}{2})}{2 {(x + 1)}^{7}}$

Step 4.14.3.5

Cancel the common factor of $2$ .

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Step 4.14.3.5.1

Factor $2$ out of $- 6$ .

$\frac{3 ({(x + 1)}^{\frac{7}{2}} - \frac{7 {(x + 1)}^{\frac{5}{2}} x}{2} + 2 (- 3) \frac{7 {(x + 1)}^{\frac{5}{2}}}{2})}{2 {(x + 1)}^{7}}$

Step 4.14.3.5.2

Cancel the common factor.

$\frac{3 ({(x + 1)}^{\frac{7}{2}} - \frac{7 {(x + 1)}^{\frac{5}{2}} x}{2} + 2 \cdot - 3 \frac{7 {(x + 1)}^{\frac{5}{2}}}{2})}{2 {(x + 1)}^{7}}$

Step 4.14.3.5.3

Rewrite the expression.

$\frac{3 ({(x + 1)}^{\frac{7}{2}} - \frac{7 {(x + 1)}^{\frac{5}{2}} x}{2} - 3 (7 {(x + 1)}^{\frac{5}{2}}))}{2 {(x + 1)}^{7}}$

Step 4.14.3.6

Multiply $7$ by $- 3$ .

$\frac{3 ({(x + 1)}^{\frac{7}{2}} - \frac{7 {(x + 1)}^{\frac{5}{2}} x}{2} - 21 {(x + 1)}^{\frac{5}{2}})}{2 {(x + 1)}^{7}}$

Step 4.14.3.7

To write $- 21 {(x + 1)}^{\frac{5}{2}}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{3 ({(x + 1)}^{\frac{7}{2}} - \frac{7 {(x + 1)}^{\frac{5}{2}} x}{2} - 21 {(x + 1)}^{\frac{5}{2}} \cdot \frac{2}{2})}{2 {(x + 1)}^{7}}$

Step 4.14.3.8

Combine $- 21 {(x + 1)}^{\frac{5}{2}}$ and $\frac{2}{2}$ .

$\frac{3 ({(x + 1)}^{\frac{7}{2}} - \frac{7 {(x + 1)}^{\frac{5}{2}} x}{2} + \frac{- 21 {(x + 1)}^{\frac{5}{2}} \cdot 2}{2})}{2 {(x + 1)}^{7}}$

Step 4.14.3.9

Combine the numerators over the common denominator.

$\frac{3 ({(x + 1)}^{\frac{7}{2}} + \frac{- 7 {(x + 1)}^{\frac{5}{2}} x - 21 {(x + 1)}^{\frac{5}{2}} \cdot 2}{2})}{2 {(x + 1)}^{7}}$

Step 4.14.3.10

Simplify the numerator.

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Step 4.14.3.10.1

Factor $7 {(x + 1)}^{\frac{5}{2}}$ out of $- 7 {(x + 1)}^{\frac{5}{2}} x - 21 {(x + 1)}^{\frac{5}{2}} \cdot 2$ .

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Step 4.14.3.10.1.1

Reorder the expression.

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Step 4.14.3.10.1.1.1

Move ${(x + 1)}^{\frac{5}{2}}$ .

$\frac{3 ({(x + 1)}^{\frac{7}{2}} + \frac{- 7 x {(x + 1)}^{\frac{5}{2}} - 21 {(x + 1)}^{\frac{5}{2}} \cdot 2}{2})}{2 {(x + 1)}^{7}}$

Step 4.14.3.10.1.1.2

Move ${(x + 1)}^{\frac{5}{2}}$ .

$\frac{3 ({(x + 1)}^{\frac{7}{2}} + \frac{- 7 x {(x + 1)}^{\frac{5}{2}} - 21 \cdot 2 {(x + 1)}^{\frac{5}{2}}}{2})}{2 {(x + 1)}^{7}}$

Step 4.14.3.10.1.2

Factor $7 {(x + 1)}^{\frac{5}{2}}$ out of $- 7 x {(x + 1)}^{\frac{5}{2}}$ .

$\frac{3 ({(x + 1)}^{\frac{7}{2}} + \frac{7 {(x + 1)}^{\frac{5}{2}} (- x) - 21 \cdot 2 {(x + 1)}^{\frac{5}{2}}}{2})}{2 {(x + 1)}^{7}}$

Step 4.14.3.10.1.3

Factor $7 {(x + 1)}^{\frac{5}{2}}$ out of $- 21 \cdot 2 {(x + 1)}^{\frac{5}{2}}$ .

$\frac{3 ({(x + 1)}^{\frac{7}{2}} + \frac{7 {(x + 1)}^{\frac{5}{2}} (- x) + 7 {(x + 1)}^{\frac{5}{2}} (- 3 \cdot 2)}{2})}{2 {(x + 1)}^{7}}$

Step 4.14.3.10.1.4

Factor $7 {(x + 1)}^{\frac{5}{2}}$ out of $7 {(x + 1)}^{\frac{5}{2}} (- x) + 7 {(x + 1)}^{\frac{5}{2}} (- 3 \cdot 2)$ .

$\frac{3 ({(x + 1)}^{\frac{7}{2}} + \frac{7 {(x + 1)}^{\frac{5}{2}} (- x - 3 \cdot 2)}{2})}{2 {(x + 1)}^{7}}$

Step 4.14.3.10.2

Multiply $- 3$ by $2$ .

$\frac{3 ({(x + 1)}^{\frac{7}{2}} + \frac{7 {(x + 1)}^{\frac{5}{2}} (- x - 6)}{2})}{2 {(x + 1)}^{7}}$

Step 4.14.3.11

To write ${(x + 1)}^{\frac{7}{2}}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{3 ({(x + 1)}^{\frac{7}{2}} \cdot \frac{2}{2} + \frac{7 {(x + 1)}^{\frac{5}{2}} (- x - 6)}{2})}{2 {(x + 1)}^{7}}$

Step 4.14.3.12

Combine ${(x + 1)}^{\frac{7}{2}}$ and $\frac{2}{2}$ .

$\frac{3 (\frac{{(x + 1)}^{\frac{7}{2}} \cdot 2}{2} + \frac{7 {(x + 1)}^{\frac{5}{2}} (- x - 6)}{2})}{2 {(x + 1)}^{7}}$

Step 4.14.3.13

Combine the numerators over the common denominator.

$\frac{3 \frac{{(x + 1)}^{\frac{7}{2}} \cdot 2 + 7 {(x + 1)}^{\frac{5}{2}} (- x - 6)}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.3.14

Rewrite $\frac{{(x + 1)}^{\frac{7}{2}} \cdot 2 + 7 {(x + 1)}^{\frac{5}{2}} (- x - 6)}{2}$ in a factored form.

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Step 4.14.3.14.1

Factor ${(x + 1)}^{\frac{5}{2}}$ out of ${(x + 1)}^{\frac{7}{2}} \cdot 2 + 7 {(x + 1)}^{\frac{5}{2}} (- x - 6)$ .

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Step 4.14.3.14.1.1

Reorder ${(x + 1)}^{\frac{7}{2}}$ and $2$ .

$\frac{3 \frac{2 \cdot {(x + 1)}^{\frac{7}{2}} + 7 {(x + 1)}^{\frac{5}{2}} (- x - 6)}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.3.14.1.2

Factor ${(x + 1)}^{\frac{5}{2}}$ out of $2 \cdot {(x + 1)}^{\frac{7}{2}}$ .

$\frac{3 \frac{{(x + 1)}^{\frac{5}{2}} (2 \cdot {(x + 1)}^{\frac{2}{2}}) + 7 {(x + 1)}^{\frac{5}{2}} (- x - 6)}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.3.14.1.3

Factor ${(x + 1)}^{\frac{5}{2}}$ out of $7 {(x + 1)}^{\frac{5}{2}} (- x - 6)$ .

$\frac{3 \frac{{(x + 1)}^{\frac{5}{2}} (2 \cdot {(x + 1)}^{\frac{2}{2}}) + {(x + 1)}^{\frac{5}{2}} (7 (- x - 6))}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.3.14.1.4

Factor ${(x + 1)}^{\frac{5}{2}}$ out of ${(x + 1)}^{\frac{5}{2}} (2 \cdot {(x + 1)}^{\frac{2}{2}}) + {(x + 1)}^{\frac{5}{2}} (7 (- x - 6))$ .

$\frac{3 \frac{{(x + 1)}^{\frac{5}{2}} (2 \cdot {(x + 1)}^{\frac{2}{2}} + 7 (- x - 6))}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.3.14.2

Divide $2$ by $2$ .

$\frac{3 \frac{{(x + 1)}^{\frac{5}{2}} (2 \cdot {(x + 1)}^{1} + 7 (- x - 6))}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.3.14.3

Simplify.

$\frac{3 \frac{{(x + 1)}^{\frac{5}{2}} (2 \cdot (x + 1) + 7 (- x - 6))}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.3.14.4

Apply the distributive property.

$\frac{3 \frac{{(x + 1)}^{\frac{5}{2}} (2 x + 2 \cdot 1 + 7 (- x - 6))}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.3.14.5

Multiply $2$ by $1$ .

$\frac{3 \frac{{(x + 1)}^{\frac{5}{2}} (2 x + 2 + 7 (- x - 6))}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.3.14.6

Apply the distributive property.

$\frac{3 \frac{{(x + 1)}^{\frac{5}{2}} (2 x + 2 + 7 (- x) + 7 \cdot - 6)}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.3.14.7

Multiply $- 1$ by $7$ .

$\frac{3 \frac{{(x + 1)}^{\frac{5}{2}} (2 x + 2 - 7 x + 7 \cdot - 6)}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.3.14.8

Multiply $7$ by $- 6$ .

$\frac{3 \frac{{(x + 1)}^{\frac{5}{2}} (2 x + 2 - 7 x - 42)}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.3.14.9

Subtract $7 x$ from $2 x$ .

$\frac{3 \frac{{(x + 1)}^{\frac{5}{2}} (- 5 x + 2 - 42)}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.3.14.10

Subtract $42$ from $2$ .

$\frac{3 \frac{{(x + 1)}^{\frac{5}{2}} (- 5 x - 40)}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.3.14.11

Factor $5$ out of $- 5 x - 40$ .

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Step 4.14.3.14.11.1

Factor $5$ out of $- 5 x$ .

$\frac{3 \frac{{(x + 1)}^{\frac{5}{2}} (5 (- x) - 40)}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.3.14.11.2

Factor $5$ out of $- 40$ .

$\frac{3 \frac{{(x + 1)}^{\frac{5}{2}} (5 (- x) + 5 (- 8))}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.3.14.11.3

Factor $5$ out of $5 (- x) + 5 (- 8)$ .

$\frac{3 \frac{{(x + 1)}^{\frac{5}{2}} (5 (- x - 8))}{2}}{2 {(x + 1)}^{7}}$

$\frac{3 \frac{{(x + 1)}^{\frac{5}{2}} \cdot 5 (- x - 8)}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.3.15

Move $5$ to the left of ${(x + 1)}^{\frac{5}{2}}$ .

$\frac{3 \frac{5 {(x + 1)}^{\frac{5}{2}} (- x - 8)}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.4

Combine terms.

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Step 4.14.4.1

Combine $3$ and $\frac{5 {(x + 1)}^{\frac{5}{2}} (- x - 8)}{2}$ .

$\frac{\frac{3 (5 {(x + 1)}^{\frac{5}{2}} (- x - 8))}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.4.2

Multiply $5$ by $3$ .

$\frac{\frac{15 ({(x + 1)}^{\frac{5}{2}} (- x - 8))}{2}}{2 {(x + 1)}^{7}}$

Step 4.14.4.3

Rewrite $\frac{\frac{15 {(x + 1)}^{\frac{5}{2}} (- x - 8)}{2}}{2 {(x + 1)}^{7}}$ as a product.

$\frac{15 {(x + 1)}^{\frac{5}{2}} (- x - 8)}{2} \cdot \frac{1}{2 {(x + 1)}^{7}}$

Step 4.14.4.4

Multiply $\frac{15 {(x + 1)}^{\frac{5}{2}} (- x - 8)}{2}$ by $\frac{1}{2 {(x + 1)}^{7}}$ .

$\frac{15 {(x + 1)}^{\frac{5}{2}} (- x - 8)}{2 (2 {(x + 1)}^{7})}$

Step 4.14.4.5

Multiply $2$ by $2$ .

$\frac{15 {(x + 1)}^{\frac{5}{2}} (- x - 8)}{4 {(x + 1)}^{7}}$

Step 4.14.4.6

Move ${(x + 1)}^{\frac{5}{2}}$ to the denominator using the negative exponent rule $b^{n} = \frac{1}{b^{- n}}$ .

$\frac{15 (- x - 8)}{4 {(x + 1)}^{7} {(x + 1)}^{- \frac{5}{2}}}$

Step 4.14.4.7

Multiply ${(x + 1)}^{7}$ by ${(x + 1)}^{- \frac{5}{2}}$ by adding the exponents.

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Step 4.14.4.7.1

Move ${(x + 1)}^{- \frac{5}{2}}$ .

$\frac{15 (- x - 8)}{4 ({(x + 1)}^{- \frac{5}{2}} {(x + 1)}^{7})}$

Step 4.14.4.7.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{15 (- x - 8)}{4 {(x + 1)}^{- \frac{5}{2} + 7}}$

Step 4.14.4.7.3

To write $7$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{15 (- x - 8)}{4 {(x + 1)}^{- \frac{5}{2} + 7 \cdot \frac{2}{2}}}$

Step 4.14.4.7.4

Combine $7$ and $\frac{2}{2}$ .

$\frac{15 (- x - 8)}{4 {(x + 1)}^{- \frac{5}{2} + \frac{7 \cdot 2}{2}}}$

Step 4.14.4.7.5

Combine the numerators over the common denominator.

$\frac{15 (- x - 8)}{4 {(x + 1)}^{\frac{- 5 + 7 \cdot 2}{2}}}$

Step 4.14.4.7.6

Simplify the numerator.

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Step 4.14.4.7.6.1

Multiply $7$ by $2$ .

$\frac{15 (- x - 8)}{4 {(x + 1)}^{\frac{- 5 + 14}{2}}}$

Step 4.14.4.7.6.2

Add $- 5$ and $14$ .

$\frac{15 (- x - 8)}{4 {(x + 1)}^{\frac{9}{2}}}$

Step 4.14.5

Factor $- 1$ out of $- x$ .

$\frac{15 (- (x) - 8)}{4 {(x + 1)}^{\frac{9}{2}}}$

Step 4.14.6

Rewrite $- 8$ as $- 1 (8)$ .

$\frac{15 (- (x) - 1 (8))}{4 {(x + 1)}^{\frac{9}{2}}}$

Step 4.14.7

Factor $- 1$ out of $- (x) - 1 (8)$ .

$\frac{15 (- (x + 8))}{4 {(x + 1)}^{\frac{9}{2}}}$

Step 4.14.8

Rewrite $- (x + 8)$ as $- 1 (x + 8)$ .

$\frac{15 (- 1 (x + 8))}{4 {(x + 1)}^{\frac{9}{2}}}$

Step 4.14.9

Move the negative in front of the fraction.

$f^{4} (x) = - \frac{15 (x + 8)}{4 {(x + 1)}^{\frac{9}{2}}}$