Calculus Examples

$\int 2 (2^{x}) d x$

Step 1

Multiply $2$ by $2^{x}$ .

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Step 1.1

Raise $2$ to the power of $1$ .

$\int 2^{1} \cdot 2^{x} d x$

Step 1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\int 2^{1 + x} d x$

Step 2

Let $u = 1 + x$ . Then $d u = d x$ . Rewrite using $u$ and $d$ $u$ .

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Step 2.1

Let $u = 1 + x$ . Find $\frac{d u}{d x}$ .

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Step 2.1.1

Differentiate $1 + x$ .

$\frac{d}{d x} [1 + x]$

Step 2.1.2

By the Sum Rule, the derivative of $1 + x$ with respect to $x$ is $\frac{d}{d x} [1] + \frac{d}{d x} [x]$ .

$\frac{d}{d x} [1] + \frac{d}{d x} [x]$

Step 2.1.3

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$0 + \frac{d}{d x} [x]$

Step 2.1.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$0 + 1$

Step 2.1.5

Add $0$ and $1$ .

$1$

Step 2.2

Rewrite the problem using $u$ and $d u$ .

$\int 2^{u} d u$

Step 3

The integral of $2^{u}$ with respect to $u$ is $\frac{2^{u}}{\ln (2)}$ .

$\frac{2^{u}}{\ln (2)} + C$

Step 4

Rewrite $\frac{2^{u}}{\ln (2)} + C$ as $\frac{1}{\ln (2)} \cdot 2^{u} + C$ .

$\frac{1}{\ln (2)} \cdot 2^{u} + C$

Step 5

Replace all occurrences of $u$ with $1 + x$ .

$\frac{1}{\ln (2)} \cdot 2^{1 + x} + C$