Algebra Examples

$3 x - y = 1$ $- 2 x + y = 2$

Step 1

Add the two equations together to eliminate $y$ from the system.

Step 2

Substitute the value found for $x$ into one of the original equations, then solve for $y$ .

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Substitute the value found for $x$ into one of the original equations to solve for $y$ .

$3 (3) - y = 1$

Multiply $3$ by $3$ .

$9 - y = 1$

Move all terms not containing $y$ to the right side of the equation.

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Subtract $9$ from both sides of the equation.

$- y = 1 - 9$

Subtract $9$ from $1$ .

$- y = - 8$

Divide each term in $- y = - 8$ by $- 1$ and simplify.

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Divide each term in $- y = - 8$ by $- 1$ .

$\frac{- y}{- 1} = \frac{- 8}{- 1}$

Simplify the left side.

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Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{- 8}{- 1}$

Divide $y$ by $1$ .

$y = \frac{- 8}{- 1}$

Simplify the right side.

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Divide $- 8$ by $- 1$ .

$y = 8$

Step 3

The solution to the independent system of equations can be represented as a point.

$(3, 8)$

Step 4

The result can be shown in multiple forms.

Point Form:

$(3, 8)$

Equation Form:

$x = 3, y = 8$

Step 5