Algebra Examples

$3 y = x - 1$ $x - 2 y = 2$

Move all terms containing variables to the left side of the equation.

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Subtract $x$ from both sides of the equation.

$3 y - x = - 1$

$x - 2 y = 2$

Reorder $3 y$ and $- x$ .

$- x + 3 y = - 1$

$x - 2 y = 2$

$- x + 3 y = - 1$

$x - 2 y = 2$

Add the two equations together to eliminate $x$ from the system.

Substitute the value found for $y$ into one of the original equations, then solve for $x$ .

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Substitute the value found for $y$ into one of the original equations to solve for $x$ .

$- x + 3 (1) = - 1$

Multiply $3$ by $1$ .

$- x + 3 = - 1$

Move all terms not containing $x$ to the right side of the equation.

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Subtract $3$ from both sides of the equation.

$- x = - 1 - 3$

Subtract $3$ from $- 1$ .

$- x = - 4$

Divide each term in $- x = - 4$ by $- 1$ and simplify.

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Divide each term in $- x = - 4$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 4}{- 1}$

Simplify the left side.

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Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 4}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- 4}{- 1}$

Simplify the right side.

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Divide $- 4$ by $- 1$ .

$x = 4$

The solution to the independent system of equations can be represented as a point.

$(4, 1)$

The result can be shown in multiple forms.

Point Form:

$(4, 1)$

Equation Form:

$x = 4, y = 1$