Algebra Examples

$(15, - 3)$ , $(20, - 5)$ , $(25, - 7)$

Step 1

Use the standard form of a quadratic equation $y = a x^{2} + b x + c$ as the starting point for finding the equation through the three points.

$y = a x^{2} + b x + c$

Step 2

Create a system of equations by substituting the $x$ and $y$ values of each point into the standard formula of a quadratic equation to create the three equation system.

$- 3 = a {(15)}^{2} + b (15) + c$

$- 5 = a {(20)}^{2} + b (20) + c$

$- 7 = a {(25)}^{2} + b (25) + c$

Step 3

Solve the system of equations to find the values of $a$ , $b$ , and $c$ .

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Solve for $c$ in $- 3 = a \cdot 15^{2} + b (15) + c$ .

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Rewrite the equation as $a \cdot 15^{2} + b (15) + c = - 3$ .

$a \cdot 15^{2} + b (15) + c = - 3$

$- 5 = a \cdot 20^{2} + b (20) + c$

$- 7 = a \cdot 25^{2} + b (25) + c$

Simplify each term.

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Raise $15$ to the power of $2$ .

$a \cdot 225 + b (15) + c = - 3$

$- 5 = a \cdot 20^{2} + b (20) + c$

$- 7 = a \cdot 25^{2} + b (25) + c$

Move $225$ to the left of $a$ .

$225 \cdot a + b (15) + c = - 3$

$- 5 = a \cdot 20^{2} + b (20) + c$

$- 7 = a \cdot 25^{2} + b (25) + c$

Move $15$ to the left of $b$ .

$225 a + 15 b + c = - 3$

$- 5 = a \cdot 20^{2} + b (20) + c$

$- 7 = a \cdot 25^{2} + b (25) + c$

$225 a + 15 b + c = - 3$

$- 5 = a \cdot 20^{2} + b (20) + c$

$- 7 = a \cdot 25^{2} + b (25) + c$

Move all terms not containing $c$ to the right side of the equation.

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Subtract $225 a$ from both sides of the equation.

$15 b + c = - 3 - 225 a$

$- 5 = a \cdot 20^{2} + b (20) + c$

$- 7 = a \cdot 25^{2} + b (25) + c$

Subtract $15 b$ from both sides of the equation.

$c = - 3 - 225 a - 15 b$

$- 5 = a \cdot 20^{2} + b (20) + c$

$- 7 = a \cdot 25^{2} + b (25) + c$

$c = - 3 - 225 a - 15 b$

$- 5 = a \cdot 20^{2} + b (20) + c$

$- 7 = a \cdot 25^{2} + b (25) + c$

$c = - 3 - 225 a - 15 b$

$- 5 = a \cdot 20^{2} + b (20) + c$

$- 7 = a \cdot 25^{2} + b (25) + c$

Replace all occurrences of $c$ with $- 3 - 225 a - 15 b$ in each equation.

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Replace all occurrences of $c$ in $- 5 = a \cdot 20^{2} + b (20) + c$ with $- 3 - 225 a - 15 b$ .

$- 5 = a \cdot 20^{2} + b (20) - 3 - 225 a - 15 b$

$c = - 3 - 225 a - 15 b$

$- 7 = a \cdot 25^{2} + b (25) + c$

Simplify $- 5 = a \cdot 20^{2} + b (20) - 3 - 225 a - 15 b$ .

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Simplify the left side.

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Remove parentheses.

$- 5 = a \cdot 20^{2} + b (20) - 3 - 225 a - 15 b$

$c = - 3 - 225 a - 15 b$

$- 7 = a \cdot 25^{2} + b (25) + c$

$- 5 = a \cdot 20^{2} + b (20) - 3 - 225 a - 15 b$

$c = - 3 - 225 a - 15 b$

$- 7 = a \cdot 25^{2} + b (25) + c$

Simplify the right side.

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Simplify $a \cdot 20^{2} + b (20) - 3 - 225 a - 15 b$ .

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Simplify each term.

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Raise $20$ to the power of $2$ .

$- 5 = a \cdot 400 + b (20) - 3 - 225 a - 15 b$

$c = - 3 - 225 a - 15 b$

$- 7 = a \cdot 25^{2} + b (25) + c$

Move $400$ to the left of $a$ .

$- 5 = 400 \cdot a + b (20) - 3 - 225 a - 15 b$

$c = - 3 - 225 a - 15 b$

$- 7 = a \cdot 25^{2} + b (25) + c$

Move $20$ to the left of $b$ .

$- 5 = 400 a + 20 b - 3 - 225 a - 15 b$

$c = - 3 - 225 a - 15 b$

$- 7 = a \cdot 25^{2} + b (25) + c$

$- 5 = 400 a + 20 b - 3 - 225 a - 15 b$

$c = - 3 - 225 a - 15 b$

$- 7 = a \cdot 25^{2} + b (25) + c$

Simplify by adding terms.

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Subtract $225 a$ from $400 a$ .

$- 5 = 175 a + 20 b - 3 - 15 b$

$c = - 3 - 225 a - 15 b$

$- 7 = a \cdot 25^{2} + b (25) + c$

Subtract $15 b$ from $20 b$ .

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$- 7 = a \cdot 25^{2} + b (25) + c$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$- 7 = a \cdot 25^{2} + b (25) + c$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$- 7 = a \cdot 25^{2} + b (25) + c$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$- 7 = a \cdot 25^{2} + b (25) + c$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$- 7 = a \cdot 25^{2} + b (25) + c$

Replace all occurrences of $c$ in $- 7 = a \cdot 25^{2} + b (25) + c$ with $- 3 - 225 a - 15 b$ .

$- 7 = a \cdot 25^{2} + b (25) - 3 - 225 a - 15 b$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Simplify $- 7 = a \cdot 25^{2} + b (25) - 3 - 225 a - 15 b$ .

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Simplify the left side.

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Remove parentheses.

$- 7 = a \cdot 25^{2} + b (25) - 3 - 225 a - 15 b$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$- 7 = a \cdot 25^{2} + b (25) - 3 - 225 a - 15 b$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Simplify the right side.

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Simplify $a \cdot 25^{2} + b (25) - 3 - 225 a - 15 b$ .

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Simplify each term.

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Raise $25$ to the power of $2$ .

$- 7 = a \cdot 625 + b (25) - 3 - 225 a - 15 b$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Move $625$ to the left of $a$ .

$- 7 = 625 \cdot a + b (25) - 3 - 225 a - 15 b$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Move $25$ to the left of $b$ .

$- 7 = 625 a + 25 b - 3 - 225 a - 15 b$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$- 7 = 625 a + 25 b - 3 - 225 a - 15 b$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Simplify by adding terms.

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Subtract $225 a$ from $625 a$ .

$- 7 = 400 a + 25 b - 3 - 15 b$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Subtract $15 b$ from $25 b$ .

$- 7 = 400 a + 10 b - 3$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$- 7 = 400 a + 10 b - 3$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$- 7 = 400 a + 10 b - 3$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$- 7 = 400 a + 10 b - 3$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$- 7 = 400 a + 10 b - 3$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$- 7 = 400 a + 10 b - 3$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Solve for $a$ in $- 7 = 400 a + 10 b - 3$ .

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Rewrite the equation as $400 a + 10 b - 3 = - 7$ .

$400 a + 10 b - 3 = - 7$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Move all terms not containing $a$ to the right side of the equation.

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Subtract $10 b$ from both sides of the equation.

$400 a - 3 = - 7 - 10 b$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Add $3$ to both sides of the equation.

$400 a = - 7 - 10 b + 3$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Add $- 7$ and $3$ .

$400 a = - 10 b - 4$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$400 a = - 10 b - 4$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Divide each term in $400 a = - 10 b - 4$ by $400$ and simplify.

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Divide each term in $400 a = - 10 b - 4$ by $400$ .

$\frac{400 a}{400} = \frac{- 10 b}{400} + \frac{- 4}{400}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Simplify the left side.

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Cancel the common factor of $400$ .

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Cancel the common factor.

$\frac{400 a}{400} = \frac{- 10 b}{400} + \frac{- 4}{400}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Divide $a$ by $1$ .

$a = \frac{- 10 b}{400} + \frac{- 4}{400}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$a = \frac{- 10 b}{400} + \frac{- 4}{400}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$a = \frac{- 10 b}{400} + \frac{- 4}{400}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Simplify the right side.

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Simplify each term.

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Cancel the common factor of $- 10$ and $400$ .

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Factor $10$ out of $- 10 b$ .

$a = \frac{10 (- b)}{400} + \frac{- 4}{400}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Cancel the common factors.

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Factor $10$ out of $400$ .

$a = \frac{10 (- b)}{10 (40)} + \frac{- 4}{400}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Cancel the common factor.

$a = \frac{10 (- b)}{10 \cdot 40} + \frac{- 4}{400}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Rewrite the expression.

$a = \frac{- b}{40} + \frac{- 4}{400}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$a = \frac{- b}{40} + \frac{- 4}{400}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$a = \frac{- b}{40} + \frac{- 4}{400}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Move the negative in front of the fraction.

$a = - \frac{b}{40} + \frac{- 4}{400}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Cancel the common factor of $- 4$ and $400$ .

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Factor $4$ out of $- 4$ .

$a = - \frac{b}{40} + \frac{4 (- 1)}{400}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Cancel the common factors.

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Factor $4$ out of $400$ .

$a = - \frac{b}{40} + \frac{4 \cdot - 1}{4 \cdot 100}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Cancel the common factor.

$a = - \frac{b}{40} + \frac{4 \cdot - 1}{4 \cdot 100}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Rewrite the expression.

$a = - \frac{b}{40} + \frac{- 1}{100}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$a = - \frac{b}{40} + \frac{- 1}{100}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$a = - \frac{b}{40} + \frac{- 1}{100}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Move the negative in front of the fraction.

$a = - \frac{b}{40} - \frac{1}{100}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$a = - \frac{b}{40} - \frac{1}{100}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$a = - \frac{b}{40} - \frac{1}{100}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$a = - \frac{b}{40} - \frac{1}{100}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

$a = - \frac{b}{40} - \frac{1}{100}$

$- 5 = 175 a + 5 b - 3$

$c = - 3 - 225 a - 15 b$

Replace all occurrences of $a$ with $- \frac{b}{40} - \frac{1}{100}$ in each equation.

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Replace all occurrences of $a$ in $- 5 = 175 a + 5 b - 3$ with $- \frac{b}{40} - \frac{1}{100}$ .

$- 5 = 175 (- \frac{b}{40} - \frac{1}{100}) + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Simplify the right side.

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Simplify $175 (- \frac{b}{40} - \frac{1}{100}) + 5 b - 3$ .

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Simplify each term.

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Apply the distributive property.

$- 5 = 175 (- \frac{b}{40}) + 175 (- \frac{1}{100}) + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Cancel the common factor of $5$ .

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Move the leading negative in $- \frac{b}{40}$ into the numerator.

$- 5 = 175 (\frac{- b}{40}) + 175 (- \frac{1}{100}) + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Factor $5$ out of $175$ .

$- 5 = 5 (35) (\frac{- b}{40}) + 175 (- \frac{1}{100}) + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Factor $5$ out of $40$ .

$- 5 = 5 \cdot (35 (\frac{- b}{5 \cdot 8})) + 175 (- \frac{1}{100}) + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Cancel the common factor.

$- 5 = 5 \cdot (35 (\frac{- b}{5 \cdot 8})) + 175 (- \frac{1}{100}) + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Rewrite the expression.

$- 5 = 35 (\frac{- b}{8}) + 175 (- \frac{1}{100}) + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

$- 5 = 35 (\frac{- b}{8}) + 175 (- \frac{1}{100}) + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Combine $35$ and $\frac{- b}{8}$ .

$- 5 = \frac{35 (- b)}{8} + 175 (- \frac{1}{100}) + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Multiply $- 1$ by $35$ .

$- 5 = \frac{- 35 b}{8} + 175 (- \frac{1}{100}) + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Cancel the common factor of $25$ .

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Move the leading negative in $- \frac{1}{100}$ into the numerator.

$- 5 = \frac{- 35 b}{8} + 175 (\frac{- 1}{100}) + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Factor $25$ out of $175$ .

$- 5 = \frac{- 35 b}{8} + 25 (7) (\frac{- 1}{100}) + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Factor $25$ out of $100$ .

$- 5 = \frac{- 35 b}{8} + 25 \cdot (7 (\frac{- 1}{25 \cdot 4})) + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Cancel the common factor.

$- 5 = \frac{- 35 b}{8} + 25 \cdot (7 (\frac{- 1}{25 \cdot 4})) + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Rewrite the expression.

$- 5 = \frac{- 35 b}{8} + 7 (\frac{- 1}{4}) + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

$- 5 = \frac{- 35 b}{8} + 7 (\frac{- 1}{4}) + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Combine $7$ and $\frac{- 1}{4}$ .

$- 5 = \frac{- 35 b}{8} + \frac{7 \cdot - 1}{4} + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Multiply $7$ by $- 1$ .

$- 5 = \frac{- 35 b}{8} + \frac{- 7}{4} + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Simplify each term.

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Move the negative in front of the fraction.

$- 5 = - \frac{(35) b}{8} + \frac{- 7}{4} + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Move the negative in front of the fraction.

$- 5 = - \frac{35 b}{8} - \frac{7}{4} + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

$- 5 = - \frac{35 b}{8} - \frac{7}{4} + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

$- 5 = - \frac{35 b}{8} - \frac{7}{4} + 5 b - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

To write $5 b$ as a fraction with a common denominator, multiply by $\frac{8}{8}$ .

$- 5 = - \frac{35 b}{8} + 5 b \cdot \frac{8}{8} - \frac{7}{4} - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Combine $5 b$ and $\frac{8}{8}$ .

$- 5 = - \frac{35 b}{8} + \frac{5 b \cdot 8}{8} - \frac{7}{4} - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Combine the numerators over the common denominator.

$- 5 = \frac{- 35 b + 5 b \cdot 8}{8} - \frac{7}{4} - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Find the common denominator.

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Multiply $\frac{7}{4}$ by $\frac{2}{2}$ .

$- 5 = \frac{- 35 b + 5 b \cdot 8}{8} - (\frac{7}{4} \cdot \frac{2}{2}) - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Multiply $\frac{7}{4}$ by $\frac{2}{2}$ .

$- 5 = \frac{- 35 b + 5 b \cdot 8}{8} - \frac{7 \cdot 2}{4 \cdot 2} - 3$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Write $- 3$ as a fraction with denominator $1$ .

$- 5 = \frac{- 35 b + 5 b \cdot 8}{8} - \frac{7 \cdot 2}{4 \cdot 2} + \frac{- 3}{1}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Multiply $\frac{- 3}{1}$ by $\frac{8}{8}$ .

$- 5 = \frac{- 35 b + 5 b \cdot 8}{8} - \frac{7 \cdot 2}{4 \cdot 2} + \frac{- 3}{1} \cdot \frac{8}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Multiply $\frac{- 3}{1}$ by $\frac{8}{8}$ .

$- 5 = \frac{- 35 b + 5 b \cdot 8}{8} - \frac{7 \cdot 2}{4 \cdot 2} + \frac{- 3 \cdot 8}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Reorder the factors of $4 \cdot 2$ .

$- 5 = \frac{- 35 b + 5 b \cdot 8}{8} - \frac{7 \cdot 2}{2 \cdot 4} + \frac{- 3 \cdot 8}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Multiply $2$ by $4$ .

$- 5 = \frac{- 35 b + 5 b \cdot 8}{8} - \frac{7 \cdot 2}{8} + \frac{- 3 \cdot 8}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

$- 5 = \frac{- 35 b + 5 b \cdot 8}{8} - \frac{7 \cdot 2}{8} + \frac{- 3 \cdot 8}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Combine the numerators over the common denominator.

$- 5 = \frac{- 35 b + 5 b \cdot 8 - 7 \cdot 2 - 3 \cdot 8}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Simplify each term.

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Multiply $8$ by $5$ .

$- 5 = \frac{- 35 b + 40 b - 7 \cdot 2 - 3 \cdot 8}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Multiply $- 7$ by $2$ .

$- 5 = \frac{- 35 b + 40 b - 14 - 3 \cdot 8}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Multiply $- 3$ by $8$ .

$- 5 = \frac{- 35 b + 40 b - 14 - 24}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

$- 5 = \frac{- 35 b + 40 b - 14 - 24}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Simplify by adding terms.

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Add $- 35 b$ and $40 b$ .

$- 5 = \frac{5 b - 14 - 24}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Subtract $24$ from $- 14$ .

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 225 a - 15 b$

Replace all occurrences of $a$ in $c = - 3 - 225 a - 15 b$ with $- \frac{b}{40} - \frac{1}{100}$ .

$c = - 3 - 225 (- \frac{b}{40} - \frac{1}{100}) - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Simplify the right side.

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Simplify $- 3 - 225 (- \frac{b}{40} - \frac{1}{100}) - 15 b$ .

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Simplify each term.

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Apply the distributive property.

$c = - 3 - 225 (- \frac{b}{40}) - 225 (- \frac{1}{100}) - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Cancel the common factor of $5$ .

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Move the leading negative in $- \frac{b}{40}$ into the numerator.

$c = - 3 - 225 \frac{- b}{40} - 225 (- \frac{1}{100}) - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Factor $5$ out of $- 225$ .

$c = - 3 + 5 (- 45) (\frac{- b}{40}) - 225 (- \frac{1}{100}) - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Factor $5$ out of $40$ .

$c = - 3 + 5 \cdot (- 45 \frac{- b}{5 \cdot 8}) - 225 (- \frac{1}{100}) - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Cancel the common factor.

$c = - 3 + 5 \cdot (- 45 \frac{- b}{5 \cdot 8}) - 225 (- \frac{1}{100}) - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Rewrite the expression.

$c = - 3 - 45 \frac{- b}{8} - 225 (- \frac{1}{100}) - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 - 45 \frac{- b}{8} - 225 (- \frac{1}{100}) - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Combine $- 45$ and $\frac{- b}{8}$ .

$c = - 3 + \frac{- 45 (- b)}{8} - 225 (- \frac{1}{100}) - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Multiply $- 1$ by $- 45$ .

$c = - 3 + \frac{45 b}{8} - 225 (- \frac{1}{100}) - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Cancel the common factor of $25$ .

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Move the leading negative in $- \frac{1}{100}$ into the numerator.

$c = - 3 + \frac{45 b}{8} - 225 (\frac{- 1}{100}) - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Factor $25$ out of $- 225$ .

$c = - 3 + \frac{45 b}{8} + 25 (- 9) (\frac{- 1}{100}) - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Factor $25$ out of $100$ .

$c = - 3 + \frac{45 b}{8} + 25 \cdot (- 9 \frac{- 1}{25 \cdot 4}) - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Cancel the common factor.

$c = - 3 + \frac{45 b}{8} + 25 \cdot (- 9 \frac{- 1}{25 \cdot 4}) - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Rewrite the expression.

$c = - 3 + \frac{45 b}{8} - 9 (\frac{- 1}{4}) - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 + \frac{45 b}{8} - 9 (\frac{- 1}{4}) - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Combine $- 9$ and $\frac{- 1}{4}$ .

$c = - 3 + \frac{45 b}{8} + \frac{- 9 \cdot - 1}{4} - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Multiply $- 9$ by $- 1$ .

$c = - 3 + \frac{45 b}{8} + \frac{9}{4} - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - 3 + \frac{45 b}{8} + \frac{9}{4} - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

To write $- 3$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$c = \frac{45 b}{8} - 3 \cdot \frac{4}{4} + \frac{9}{4} - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Combine $- 3$ and $\frac{4}{4}$ .

$c = \frac{45 b}{8} + \frac{- 3 \cdot 4}{4} + \frac{9}{4} - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Combine the numerators over the common denominator.

$c = \frac{45 b}{8} + \frac{- 3 \cdot 4 + 9}{4} - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Simplify the numerator.

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Multiply $- 3$ by $4$ .

$c = \frac{45 b}{8} + \frac{- 12 + 9}{4} - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Add $- 12$ and $9$ .

$c = \frac{45 b}{8} + \frac{- 3}{4} - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = \frac{45 b}{8} + \frac{- 3}{4} - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Move the negative in front of the fraction.

$c = \frac{45 b}{8} - \frac{3}{4} - 15 b$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

To write $- 15 b$ as a fraction with a common denominator, multiply by $\frac{8}{8}$ .

$c = \frac{45 b}{8} - 15 b \cdot \frac{8}{8} - \frac{3}{4}$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Simplify terms.

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Combine $- 15 b$ and $\frac{8}{8}$ .

$c = \frac{45 b}{8} + \frac{- 15 b \cdot 8}{8} - \frac{3}{4}$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Combine the numerators over the common denominator.

$c = \frac{45 b - 15 b \cdot 8}{8} - \frac{3}{4}$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = \frac{45 b - 15 b \cdot 8}{8} - \frac{3}{4}$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Simplify each term.

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Simplify the numerator.

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Factor $15 b$ out of $45 b - 15 b \cdot 8$ .

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Factor $15 b$ out of $45 b$ .

$c = \frac{15 b (3) - 15 b \cdot 8}{8} - \frac{3}{4}$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Factor $15 b$ out of $- 15 b \cdot 8$ .

$c = \frac{15 b (3) + 15 b (- 1 \cdot 8)}{8} - \frac{3}{4}$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Factor $15 b$ out of $15 b (3) + 15 b (- 1 \cdot 8)$ .

$c = \frac{15 b (3 - 1 \cdot 8)}{8} - \frac{3}{4}$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = \frac{15 b (3 - 1 \cdot 8)}{8} - \frac{3}{4}$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Multiply $- 1$ by $8$ .

$c = \frac{15 b (3 - 8)}{8} - \frac{3}{4}$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Subtract $8$ from $3$ .

$c = \frac{15 b \cdot - 5}{8} - \frac{3}{4}$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Multiply $- 5$ by $15$ .

$c = \frac{- 75 b}{8} - \frac{3}{4}$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = \frac{- 75 b}{8} - \frac{3}{4}$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Move the negative in front of the fraction.

$c = - \frac{75 b}{8} - \frac{3}{4}$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$- 5 = \frac{5 b - 38}{8}$

$a = - \frac{b}{40} - \frac{1}{100}$

Solve for $b$ in $- 5 = \frac{5 b - 38}{8}$ .

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Rewrite the equation as $\frac{5 b - 38}{8} = - 5$ .

$\frac{5 b - 38}{8} = - 5$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

Multiply both sides by $8$ .

$\frac{5 b - 38}{8} \cdot 8 = - 5 \cdot 8$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

Simplify.

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Simplify the left side.

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Cancel the common factor of $8$ .

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Cancel the common factor.

$\frac{5 b - 38}{8} \cdot 8 = - 5 \cdot 8$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

Rewrite the expression.

$5 b - 38 = - 5 \cdot 8$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

$5 b - 38 = - 5 \cdot 8$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

$5 b - 38 = - 5 \cdot 8$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

Simplify the right side.

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Multiply $- 5$ by $8$ .

$5 b - 38 = - 40$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

$5 b - 38 = - 40$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

$5 b - 38 = - 40$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

Solve for $b$ .

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Move all terms not containing $b$ to the right side of the equation.

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Add $38$ to both sides of the equation.

$5 b = - 40 + 38$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

Add $- 40$ and $38$ .

$5 b = - 2$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

$5 b = - 2$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

Divide each term in $5 b = - 2$ by $5$ and simplify.

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Divide each term in $5 b = - 2$ by $5$ .

$\frac{5 b}{5} = \frac{- 2}{5}$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

Simplify the left side.

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Cancel the common factor of $5$ .

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Cancel the common factor.

$\frac{5 b}{5} = \frac{- 2}{5}$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

Divide $b$ by $1$ .

$b = \frac{- 2}{5}$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

$b = \frac{- 2}{5}$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

$b = \frac{- 2}{5}$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

Simplify the right side.

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Move the negative in front of the fraction.

$b = - \frac{2}{5}$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

$b = - \frac{2}{5}$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

$b = - \frac{2}{5}$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

$b = - \frac{2}{5}$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

$b = - \frac{2}{5}$

$c = - \frac{75 b}{8} - \frac{3}{4}$

$a = - \frac{b}{40} - \frac{1}{100}$

Replace all occurrences of $b$ with $- \frac{2}{5}$ in each equation.

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Replace all occurrences of $b$ in $c = - \frac{75 b}{8} - \frac{3}{4}$ with $- \frac{2}{5}$ .

$c = - \frac{75 (- \frac{2}{5})}{8} - \frac{3}{4}$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

Simplify the right side.

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Simplify $- \frac{75 (- \frac{2}{5})}{8} - \frac{3}{4}$ .

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Simplify each term.

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Simplify the numerator.

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Multiply $- 1$ by $75$ .

$c = - \frac{- 75 (\frac{2}{5})}{8} - \frac{3}{4}$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

Combine $- 75$ and $\frac{2}{5}$ .

$c = - \frac{\frac{- 75 \cdot 2}{5}}{8} - \frac{3}{4}$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - \frac{\frac{- 75 \cdot 2}{5}}{8} - \frac{3}{4}$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

Multiply $- 75$ by $2$ .

$c = - \frac{\frac{- 150}{5}}{8} - \frac{3}{4}$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

Divide $- 150$ by $5$ .

$c = - \frac{- 30}{8} - \frac{3}{4}$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

Cancel the common factor of $- 30$ and $8$ .

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Factor $2$ out of $- 30$ .

$c = - \frac{2 (- 15)}{8} - \frac{3}{4}$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

Cancel the common factors.

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Factor $2$ out of $8$ .

$c = - \frac{2 \cdot - 15}{2 \cdot 4} - \frac{3}{4}$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

Cancel the common factor.

$c = - \frac{2 \cdot - 15}{2 \cdot 4} - \frac{3}{4}$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

Rewrite the expression.

$c = - \frac{- 15}{4} - \frac{3}{4}$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - \frac{- 15}{4} - \frac{3}{4}$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = - \frac{- 15}{4} - \frac{3}{4}$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

Move the negative in front of the fraction.

$c = \frac{15}{4} - \frac{3}{4}$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

Multiply $- - \frac{15}{4}$ .

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Multiply $- 1$ by $- 1$ .

$c = 1 (\frac{15}{4}) - \frac{3}{4}$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

Multiply $\frac{15}{4}$ by $1$ .

$c = \frac{15}{4} - \frac{3}{4}$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = \frac{15}{4} - \frac{3}{4}$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = \frac{15}{4} - \frac{3}{4}$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

Combine fractions.

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Combine the numerators over the common denominator.

$c = \frac{15 - 3}{4}$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

Simplify the expression.

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Subtract $3$ from $15$ .

$c = \frac{12}{4}$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

Divide $12$ by $4$ .

$c = 3$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = 3$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = 3$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = 3$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

$c = 3$

$b = - \frac{2}{5}$

$a = - \frac{b}{40} - \frac{1}{100}$

Replace all occurrences of $b$ in $a = - \frac{b}{40} - \frac{1}{100}$ with $- \frac{2}{5}$ .

$a = - \frac{- \frac{2}{5}}{40} - \frac{1}{100}$

$c = 3$

$b = - \frac{2}{5}$

Simplify the right side.

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Simplify $- \frac{- \frac{2}{5}}{40} - \frac{1}{100}$ .

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Simplify each term.

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Multiply the numerator by the reciprocal of the denominator.

$a = - (- \frac{2}{5} \cdot \frac{1}{40}) - \frac{1}{100}$

$c = 3$

$b = - \frac{2}{5}$

Cancel the common factor of $2$ .

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Move the leading negative in $- \frac{2}{5}$ into the numerator.

$a = - (\frac{- 2}{5} \cdot \frac{1}{40}) - \frac{1}{100}$

$c = 3$

$b = - \frac{2}{5}$

Factor $2$ out of $- 2$ .

$a = - (\frac{2 (- 1)}{5} \cdot \frac{1}{40}) - \frac{1}{100}$

$c = 3$

$b = - \frac{2}{5}$

Factor $2$ out of $40$ .

$a = - (\frac{2 \cdot - 1}{5} \cdot \frac{1}{2 \cdot 20}) - \frac{1}{100}$

$c = 3$

$b = - \frac{2}{5}$

Cancel the common factor.

$a = - (\frac{2 \cdot - 1}{5} \cdot \frac{1}{2 \cdot 20}) - \frac{1}{100}$

$c = 3$

$b = - \frac{2}{5}$

Rewrite the expression.

$a = - (\frac{- 1}{5} \cdot \frac{1}{20}) - \frac{1}{100}$

$c = 3$

$b = - \frac{2}{5}$

$a = - (\frac{- 1}{5} \cdot \frac{1}{20}) - \frac{1}{100}$

$c = 3$

$b = - \frac{2}{5}$

Multiply $\frac{- 1}{5}$ by $\frac{1}{20}$ .

$a = - \frac{- 1}{5 \cdot 20} - \frac{1}{100}$

$c = 3$

$b = - \frac{2}{5}$

Multiply $5$ by $20$ .

$a = - \frac{- 1}{100} - \frac{1}{100}$

$c = 3$

$b = - \frac{2}{5}$

Move the negative in front of the fraction.

$a = \frac{1}{100} - \frac{1}{100}$

$c = 3$

$b = - \frac{2}{5}$

Multiply $- - \frac{1}{100}$ .

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Multiply $- 1$ by $- 1$ .

$a = 1 (\frac{1}{100}) - \frac{1}{100}$

$c = 3$

$b = - \frac{2}{5}$

Multiply $\frac{1}{100}$ by $1$ .

$a = \frac{1}{100} - \frac{1}{100}$

$c = 3$

$b = - \frac{2}{5}$

$a = \frac{1}{100} - \frac{1}{100}$

$c = 3$

$b = - \frac{2}{5}$

$a = \frac{1}{100} - \frac{1}{100}$

$c = 3$

$b = - \frac{2}{5}$

Combine fractions.

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Combine the numerators over the common denominator.

$a = \frac{1 - 1}{100}$

$c = 3$

$b = - \frac{2}{5}$

Simplify the expression.

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Subtract $1$ from $1$ .

$a = \frac{0}{100}$

$c = 3$

$b = - \frac{2}{5}$

Divide $0$ by $100$ .

$a = 0$

$c = 3$

$b = - \frac{2}{5}$

$a = 0$

$c = 3$

$b = - \frac{2}{5}$

$a = 0$

$c = 3$

$b = - \frac{2}{5}$

$a = 0$

$c = 3$

$b = - \frac{2}{5}$

$a = 0$

$c = 3$

$b = - \frac{2}{5}$

$a = 0$

$c = 3$

$b = - \frac{2}{5}$

List all of the solutions.

$a = 0, c = 3, b = - \frac{2}{5}$

Step 4

Substitute the actual values of $a$ , $b$ , and $c$ into the formula for a quadratic equation to find the resulting equation.

$y = - \frac{2 x}{5} + 3$

Step 5