Algebra Examples

$\sin (x) = - \frac{12}{13}$

To find the value of $\csc (x)$ , use the fact that $\frac{1}{\sin (x)}$ then substitute in the known values.

$\csc (x) = \frac{1}{\sin (x)} = \frac{1}{- \frac{12}{13}}$

Simplify the result.

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Cancel the common factor of $1$ and $- 1$ .

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Rewrite $1$ as $- 1 (- 1)$ .

$\csc (x) = \frac{1}{\sin (x)} = \frac{- 1 \cdot - 1}{- \frac{12}{13}}$

Move the negative in front of the fraction.

$\csc (x) = \frac{1}{\sin (x)} = - \frac{1}{\frac{12}{13}}$

Multiply the numerator by the reciprocal of the denominator.

$\csc (x) = \frac{1}{\sin (x)} = - (1 (\frac{13}{12}))$

Multiply $\frac{13}{12}$ by $1$ .

$\csc (x) = \frac{1}{\sin (x)} = - \frac{13}{12}$