Algebra Examples

$(2, 3)$ $s l o p e = 2$

Step 1

Divide each term in $s l o p e = 2$ by $l o p e$ and simplify.

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Divide each term in $s l o p e = 2$ by $l o p e$ .

$\frac{s l o p e}{l o p e} = \frac{2}{l o p e}$

Simplify the left side.

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Cancel the common factor of $l$ .

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Cancel the common factor.

$\frac{s l o p e}{l o p e} = \frac{2}{l o p e}$

Rewrite the expression.

$\frac{s o p e}{o p e} = \frac{2}{l o p e}$

Cancel the common factor of $o$ .

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Cancel the common factor.

$\frac{s o p e}{o p e} = \frac{2}{l o p e}$

Rewrite the expression.

$\frac{s p e}{p e} = \frac{2}{l o p e}$

Cancel the common factor of $p$ .

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Cancel the common factor.

$\frac{s p e}{p e} = \frac{2}{l o p e}$

Rewrite the expression.

$\frac{s e}{e} = \frac{2}{l o p e}$

Cancel the common factor of $e$ .

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Cancel the common factor.

$\frac{s e}{e} = \frac{2}{l o p e}$

Divide $s$ by $1$ .

$s = \frac{2}{l o p e}$

Step 2

Find the value of $b$ using the formula for the equation of a line.

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Use the formula for the equation of a line to find $b$ .

$y = m x + b$

Substitute the value of $m$ into the equation.

$y = (\frac{2}{l o p e}) \cdot x + b$

Substitute the value of $x$ into the equation.

$y = (\frac{2}{l o p e}) \cdot (2) + b$

Substitute the value of $y$ into the equation.

$3 = (\frac{2}{l o p e}) \cdot (2) + b$

Find the value of $b$ .

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Rewrite the equation as $\frac{2}{l o p e} \cdot 2 + b = 3$ .

$\frac{2}{l o p e} \cdot 2 + b = 3$

Multiply $\frac{2}{l o p e} \cdot 2$ .

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Combine $\frac{2}{l o p e}$ and $2$ .

$\frac{2 \cdot 2}{l o p e} + b = 3$

Multiply $2$ by $2$ .

$\frac{4}{l o p e} + b = 3$

Subtract $\frac{4}{l o p e}$ from both sides of the equation.

$b = 3 - \frac{4}{l o p e}$

Step 3

Now that the values of $m$ (slope) and $b$ (y-intercept) are known, substitute them into $y = m x + b$ to find the equation of the line.

$y = \frac{2 x}{l o p e} + 3 - \frac{4}{l o p e}$

Step 4