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有限数学例一次関数と点

xについて解く

$x - 3 = 2$

ステップ 1

方程式の両辺に $3$ を足します。

$x = 2 + 3$

ステップ 2

$2$ と $3$ をたし算します。

$x = 5$

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一次関数と点

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$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$