Kalkulus Contoh

$lim_{x \to - \infty} e^{x} \sin (x)$

Step 1

Karena $e^{x} \cdot - 1 \leq e^{x} \sin (x) \leq e^{x} \cdot 1$ dan $lim_{x \to - \infty} e^{x} \cdot - 1 = lim_{x \to - \infty} e^{x} \cdot 1 = 0$ , terapkan Teorema Apit.

$0$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$