Algèbre Exemples

$(3, 4)$ , $(2, 5)$

Step 1

Find the radius $r$ for the circle. The radius is any line segment from the center of the circle to any point on its circumference. In this case, $r$ is the distance between $(3, 4)$ and $(2, 5)$ .

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Step 1.1

Use the distance formula to determine the distance between the two points.

$Distance = \sqrt{{(x_{2} - x_{1})}^{2} + {(y_{2} - y_{1})}^{2}}$

Step 1.2

Substitute the actual values of the points into the distance formula.

$r = \sqrt{{(2 - 3)}^{2} + {(5 - 4)}^{2}}$

Step 1.3

Simplify.

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Step 1.3.1

Subtract $3$ from $2$ .

$r = \sqrt{{(- 1)}^{2} + {(5 - 4)}^{2}}$

Step 1.3.2

Raise $- 1$ to the power of $2$ .

$r = \sqrt{1 + {(5 - 4)}^{2}}$

Step 1.3.3

Subtract $4$ from $5$ .

$r = \sqrt{1 + 1^{2}}$

Step 1.3.4

One to any power is one.

$r = \sqrt{1 + 1}$

Step 1.3.5

Add $1$ and $1$ .

$r = \sqrt{2}$

Step 2

${(x - h)}^{2} + {(y - k)}^{2} = r^{2}$ is the equation form for a circle with $r$ radius and $(h, k)$ as the center point. In this case, $r = \sqrt{2}$ and the center point is $(3, 4)$ . The equation for the circle is ${(x - (3))}^{2} + {(y - (4))}^{2} = {(\sqrt{2})}^{2}$ .

${(x - (3))}^{2} + {(y - (4))}^{2} = {(\sqrt{2})}^{2}$

Step 3

The circle equation is ${(x - 3)}^{2} + {(y - 4)}^{2} = 2$ .

${(x - 3)}^{2} + {(y - 4)}^{2} = 2$

Step 4

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