Calculus Examples

$y = - 8 x^{2} - 3$

Step 1

Differentiate both sides of the equation.

$\frac{d}{d x} (y) = \frac{d}{d x} (- 8 x^{2} - 3)$

Step 2

The derivative of $y$ with respect to $x$ is $y'$ .

$y'$

Step 3

Differentiate the right side of the equation.

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Step 3.1

By the Sum Rule, the derivative of $- 8 x^{2} - 3$ with respect to $x$ is $\frac{d}{d x} [- 8 x^{2}] + \frac{d}{d x} [- 3]$ .

$\frac{d}{d x} [- 8 x^{2}] + \frac{d}{d x} [- 3]$

Step 3.2

Evaluate $\frac{d}{d x} [- 8 x^{2}]$ .

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Step 3.2.1

Since $- 8$ is constant with respect to $x$ , the derivative of $- 8 x^{2}$ with respect to $x$ is $- 8 \frac{d}{d x} [x^{2}]$ .

$- 8 \frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 3]$

Step 3.2.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$- 8 (2 x) + \frac{d}{d x} [- 3]$

Step 3.2.3

Multiply $2$ by $- 8$ .

$- 16 x + \frac{d}{d x} [- 3]$

Step 3.3

Differentiate using the Constant Rule.

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Step 3.3.1

Since $- 3$ is constant with respect to $x$ , the derivative of $- 3$ with respect to $x$ is $0$ .

$- 16 x + 0$

Step 3.3.2

Add $- 16 x$ and $0$ .

$- 16 x$

Step 4

Reform the equation by setting the left side equal to the right side.

$y' = - 16 x$

Step 5

Replace $y'$ with $\frac{d y}{d x}$ .

$\frac{d y}{d x} = - 16 x$

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