三角学示例

$y = \frac{1}{2} \cdot \cos (\frac{1}{4} x - \frac{π}{16})$

解题步骤 1

$y = \frac{1}{2} \cdot \cos (\frac{1}{4} x - \frac{π}{16})$

解题步骤 2

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$