有限数学示例

$0.77 s \cdot 1 - 0.11 s \cdot 2 = 0$ , $s \cdot 1 + s \cdot 2 = 1$

解题步骤 1

Move variables to the left and constant terms to the right.

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解题步骤 1.1

化简每一项。

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解题步骤 1.1.1

将 $0.77$ 乘以 $1$ 。

$0.77 s - 0.11 s \cdot 2 = 0$

$s \cdot 1 + s \cdot 2 = 1$

解题步骤 1.1.2

将 $2$ 乘以 $- 0.11$ 。

$0.77 s - 0.22 s = 0$

$s \cdot 1 + s \cdot 2 = 1$

$0.77 s - 0.22 s = 0$

$s \cdot 1 + s \cdot 2 = 1$

解题步骤 1.2

从 $0.77 s$ 中减去 $0.22 s$ 。

$0.55 s = 0$

$s \cdot 1 + s \cdot 2 = 1$

解题步骤 1.3

化简每一项。

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解题步骤 1.3.1

将 $s$ 乘以 $1$ 。

$0.55 s = 0$

$s + s \cdot 2 = 1$

解题步骤 1.3.2

将 $2$ 移到 $s$ 的左侧。

$0.55 s = 0$

$s + 2 s = 1$

$0.55 s = 0$

$s + 2 s = 1$

解题步骤 1.4

将 $s$ 和 $2 s$ 相加。

$0.55 s = 0$

$3 s = 1$

$0.55 s = 0$

$3 s = 1$

解题步骤 2

Write the system as a matrix.

$[\begin{array}{c} 0.55 & 0 \\ 3 & 1 \end{array}]$

解题步骤 3

求行简化阶梯形矩阵。

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解题步骤 3.1

Multiply each element of $R_{1}$ by $\frac{1}{0.55}$ to make the entry at $1, 1$ a $1$ .

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解题步骤 3.1.1

Multiply each element of $R_{1}$ by $\frac{1}{0.55}$ to make the entry at $1, 1$ a $1$ .

$[\begin{array}{c} \frac{0.55}{0.55} & \frac{0}{0.55} \\ 3 & 1 \end{array}]$

解题步骤 3.1.2

化简 $R_{1}$ 。

$[\begin{array}{c} 1 & 0 \\ 3 & 1 \end{array}]$

解题步骤 3.2

Perform the row operation $R_{2} = R_{2} - 3 R_{1}$ to make the entry at $2, 1$ a $0$ .

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解题步骤 3.2.1

Perform the row operation $R_{2} = R_{2} - 3 R_{1}$ to make the entry at $2, 1$ a $0$ .

$[\begin{array}{c} 1 & 0 \\ 3 - 3 \cdot 1 & 1 - 3 \cdot 0 \end{array}]$

解题步骤 3.2.2

化简 $R_{2}$ 。

$[\begin{array}{c} 1 & 0 \\ 0 & 1 \end{array}]$

解题步骤 4

Use the result matrix to declare the final solution to the system of equations.

$s = 0$

$0 = 1$

解题步骤 5

The system is inconsistent so there is no solution.

$无解$

有限数学 示例

有限数学示例