代数示例

$[\begin{array}{c} 5 & 11 & 3 \end{array}] - [\begin{array}{c} 2 & 0 & 2 \end{array}] = [\begin{array}{c} 3 & x & 1 \end{array}]$

解题步骤 1

减去相应的元素。

$[\begin{array}{c} 5 - 2 & 11 - 0 & 3 - 2 \end{array}] = [\begin{array}{c} 3 & x & 1 \end{array}]$

解题步骤 2

Simplify each element.

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解题步骤 2.1

从 $5$ 中减去 $2$ 。

$[\begin{array}{c} 3 & 11 - 0 & 3 - 2 \end{array}] = [\begin{array}{c} 3 & x & 1 \end{array}]$

解题步骤 2.2

从 $11$ 中减去 $0$ 。

$[\begin{array}{c} 3 & 11 & 3 - 2 \end{array}] = [\begin{array}{c} 3 & x & 1 \end{array}]$

解题步骤 2.3

从 $3$ 中减去 $2$ 。

$[\begin{array}{c} 3 & 11 & 1 \end{array}] = [\begin{array}{c} 3 & x & 1 \end{array}]$

解题步骤 3

Write as a linear system of equations.

$3 = 3$

$11 = x$

$1 = 1$

解题步骤 4

Since $1 = 1$ is always true, the matrix equation has infinite solutions.

Infinite solutions satisfying $11 = x$ .

代数 示例