代数示例

$- 2 [\begin{array}{c} x & - 1 \\ 3 & 5 \end{array}] + [\begin{array}{c} 3 & 8 \\ - 1 & 6 \end{array}] = [\begin{array}{c} x & 10 \\ - 7 & - 4 \end{array}]$

解题步骤 1

化简每一项。

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解题步骤 1.1

将 $- 2$ 乘以矩阵中的每一个元素。

$[\begin{array}{c} - 2 x & - 2 \cdot - 1 \\ - 2 \cdot 3 & - 2 \cdot 5 \end{array}] + [\begin{array}{c} 3 & 8 \\ - 1 & 6 \end{array}] = [\begin{array}{c} x & 10 \\ - 7 & - 4 \end{array}]$

解题步骤 1.2

化简矩阵中的每一个元素。

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解题步骤 1.2.1

将 $- 2$ 乘以 $- 1$ 。

$[\begin{array}{c} - 2 x & 2 \\ - 2 \cdot 3 & - 2 \cdot 5 \end{array}] + [\begin{array}{c} 3 & 8 \\ - 1 & 6 \end{array}] = [\begin{array}{c} x & 10 \\ - 7 & - 4 \end{array}]$

解题步骤 1.2.2

将 $- 2$ 乘以 $3$ 。

$[\begin{array}{c} - 2 x & 2 \\ - 6 & - 2 \cdot 5 \end{array}] + [\begin{array}{c} 3 & 8 \\ - 1 & 6 \end{array}] = [\begin{array}{c} x & 10 \\ - 7 & - 4 \end{array}]$

解题步骤 1.2.3

将 $- 2$ 乘以 $5$ 。

$[\begin{array}{c} - 2 x & 2 \\ - 6 & - 10 \end{array}] + [\begin{array}{c} 3 & 8 \\ - 1 & 6 \end{array}] = [\begin{array}{c} x & 10 \\ - 7 & - 4 \end{array}]$

解题步骤 2

加上相应元素。

$[\begin{array}{c} - 2 x + 3 & 2 + 8 \\ - 6 - 1 & - 10 + 6 \end{array}] = [\begin{array}{c} x & 10 \\ - 7 & - 4 \end{array}]$

解题步骤 3

Simplify each element.

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解题步骤 3.1

将 $2$ 和 $8$ 相加。

$[\begin{array}{c} - 2 x + 3 & 10 \\ - 6 - 1 & - 10 + 6 \end{array}] = [\begin{array}{c} x & 10 \\ - 7 & - 4 \end{array}]$

解题步骤 3.2

从 $- 6$ 中减去 $1$ 。

$[\begin{array}{c} - 2 x + 3 & 10 \\ - 7 & - 10 + 6 \end{array}] = [\begin{array}{c} x & 10 \\ - 7 & - 4 \end{array}]$

解题步骤 3.3

将 $- 10$ 和 $6$ 相加。

$[\begin{array}{c} - 2 x + 3 & 10 \\ - 7 & - 4 \end{array}] = [\begin{array}{c} x & 10 \\ - 7 & - 4 \end{array}]$

解题步骤 4

Write as a linear system of equations.

$- 2 x + 3 = x$

$10 = 10$

$- 7 = - 7$

$- 4 = - 4$

解题步骤 5

Since $- 4 = - 4$ is always true, the matrix equation has infinite solutions.

Infinite solutions satisfying $- 2 x + 3 = x$ .

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