Precalculus Examples

$lim_{x \to 0} {(1 - 3 x)}^{\frac{1}{2 x} + 4}$

Step 1

Combine terms.

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Step 1.1

To write $4$ as a fraction with a common denominator, multiply by $\frac{2 x}{2 x}$ .

$lim_{x \to 0} {(1 - 3 x)}^{\frac{1}{2 x} + 4 \cdot \frac{2 x}{2 x}}$

Step 1.2

Combine $4$ and $\frac{2 x}{2 x}$ .

$lim_{x \to 0} {(1 - 3 x)}^{\frac{1}{2 x} + \frac{4 (2 x)}{2 x}}$

Step 1.3

Combine the numerators over the common denominator.

$lim_{x \to 0} {(1 - 3 x)}^{\frac{1 + 4 (2 x)}{2 x}}$

Step 2

Multiply $2$ by $4$ .

$lim_{x \to 0} {(1 - 3 x)}^{\frac{1 + 8 x}{2 x}}$

Step 3

Use the properties of logarithms to simplify the limit.

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Step 3.1

Rewrite ${(1 - 3 x)}^{\frac{1 + 8 x}{2 x}}$ as $e^{\ln ({(1 - 3 x)}^{\frac{1 + 8 x}{2 x}})}$ .

$lim_{x \to 0} e^{\ln ({(1 - 3 x)}^{\frac{1 + 8 x}{2 x}})}$

Step 3.2

Expand $\ln ({(1 - 3 x)}^{\frac{1 + 8 x}{2 x}})$ by moving $\frac{1 + 8 x}{2 x}$ outside the logarithm.

$lim_{x \to 0} e^{\frac{1 + 8 x}{2 x} \ln (1 - 3 x)}$

Step 4

Evaluate the limit.

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Step 4.1

Move the limit into the exponent.

$e^{lim_{x \to 0} \frac{1 + 8 x}{2 x} \ln (1 - 3 x)}$

Step 4.2

Combine $\frac{1 + 8 x}{2 x}$ and $\ln (1 - 3 x)$ .

$e^{lim_{x \to 0} \frac{(1 + 8 x) \ln (1 - 3 x)}{2 x}}$

Step 4.3

Move the term $\frac{1}{2}$ outside of the limit because it is constant with respect to $x$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{(1 + 8 x) \ln (1 - 3 x)}{x}}$

Step 5

Apply L'Hospital's rule.

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Step 5.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 5.1.1

Take the limit of the numerator and the limit of the denominator.

$e^{\frac{1}{2} \cdot \frac{lim_{x \to 0} (1 + 8 x) \ln (1 - 3 x)}{lim_{x \to 0} x}}$

Step 5.1.2

Evaluate the limit of the numerator.

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Step 5.1.2.1

Split the limit using the Product of Limits Rule on the limit as $x$ approaches $0$ .

$e^{\frac{1}{2} \cdot \frac{lim_{x \to 0} 1 + 8 x \cdot lim_{x \to 0} \ln (1 - 3 x)}{lim_{x \to 0} x}}$

Step 5.1.2.2

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $0$ .

$e^{\frac{1}{2} \cdot \frac{(lim_{x \to 0} 1 + lim_{x \to 0} 8 x) \cdot lim_{x \to 0} \ln (1 - 3 x)}{lim_{x \to 0} x}}$

Step 5.1.2.3

Evaluate the limit of $1$ which is constant as $x$ approaches $0$ .

$e^{\frac{1}{2} \cdot \frac{(1 + lim_{x \to 0} 8 x) \cdot lim_{x \to 0} \ln (1 - 3 x)}{lim_{x \to 0} x}}$

Step 5.1.2.4

Move the term $8$ outside of the limit because it is constant with respect to $x$ .

$e^{\frac{1}{2} \cdot \frac{(1 + 8 lim_{x \to 0} x) \cdot lim_{x \to 0} \ln (1 - 3 x)}{lim_{x \to 0} x}}$

Step 5.1.2.5

Move the limit inside the logarithm.

$e^{\frac{1}{2} \cdot \frac{(1 + 8 lim_{x \to 0} x) \cdot \ln (lim_{x \to 0} 1 - 3 x)}{lim_{x \to 0} x}}$

Step 5.1.2.6

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $0$ .

$e^{\frac{1}{2} \cdot \frac{(1 + 8 lim_{x \to 0} x) \cdot \ln (lim_{x \to 0} 1 - lim_{x \to 0} 3 x)}{lim_{x \to 0} x}}$

Step 5.1.2.7

Evaluate the limit of $1$ which is constant as $x$ approaches $0$ .

$e^{\frac{1}{2} \cdot \frac{(1 + 8 lim_{x \to 0} x) \cdot \ln (1 - lim_{x \to 0} 3 x)}{lim_{x \to 0} x}}$

Step 5.1.2.8

Move the term $3$ outside of the limit because it is constant with respect to $x$ .

$e^{\frac{1}{2} \cdot \frac{(1 + 8 lim_{x \to 0} x) \cdot \ln (1 - 3 lim_{x \to 0} x)}{lim_{x \to 0} x}}$

Step 5.1.2.9

Evaluate the limits by plugging in $0$ for all occurrences of $x$ .

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Step 5.1.2.9.1

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$e^{\frac{1}{2} \cdot \frac{(1 + 8 \cdot 0) \cdot \ln (1 - 3 lim_{x \to 0} x)}{lim_{x \to 0} x}}$

Step 5.1.2.9.2

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$e^{\frac{1}{2} \cdot \frac{(1 + 8 \cdot 0) \cdot \ln (1 - 3 \cdot 0)}{lim_{x \to 0} x}}$

Step 5.1.2.10

Simplify the answer.

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Step 5.1.2.10.1

Multiply $8$ by $0$ .

$e^{\frac{1}{2} \cdot \frac{(1 + 0) \cdot \ln (1 - 3 \cdot 0)}{lim_{x \to 0} x}}$

Step 5.1.2.10.2

Add $1$ and $0$ .

$e^{\frac{1}{2} \cdot \frac{1 \cdot \ln (1 - 3 \cdot 0)}{lim_{x \to 0} x}}$

Step 5.1.2.10.3

Multiply $\ln (1 - 3 \cdot 0)$ by $1$ .

$e^{\frac{1}{2} \cdot \frac{\ln (1 - 3 \cdot 0)}{lim_{x \to 0} x}}$

Step 5.1.2.10.4

Multiply $- 3$ by $0$ .

$e^{\frac{1}{2} \cdot \frac{\ln (1 + 0)}{lim_{x \to 0} x}}$

Step 5.1.2.10.5

Add $1$ and $0$ .

$e^{\frac{1}{2} \cdot \frac{\ln (1)}{lim_{x \to 0} x}}$

Step 5.1.2.10.6

The natural logarithm of $1$ is $0$ .

$e^{\frac{1}{2} \cdot \frac{0}{lim_{x \to 0} x}}$

Step 5.1.3

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$e^{\frac{1}{2} \cdot \frac{0}{0}}$

Step 5.1.4

The expression contains a division by $0$ . The expression is undefined.

Undefined

$e^{\frac{1}{2} \cdot \frac{0}{0}}$

Step 5.2

Since $\frac{0}{0}$ is of indeterminate form, apply L'Hospital's Rule. L'Hospital's Rule states that the limit of a quotient of functions is equal to the limit of the quotient of their derivatives.

$lim_{x \to 0} \frac{(1 + 8 x) \ln (1 - 3 x)}{x} = lim_{x \to 0} \frac{\frac{d}{d x} [(1 + 8 x) \ln (1 - 3 x)]}{\frac{d}{d x} [x]}$

Step 5.3

Find the derivative of the numerator and denominator.

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Step 5.3.1

Differentiate the numerator and denominator.

$e^{\frac{1}{2} lim_{x \to 0} \frac{\frac{d}{d x} [(1 + 8 x) \ln (1 - 3 x)]}{\frac{d}{d x} [x]}}$

Step 5.3.2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = 1 + 8 x$ and $g (x) = \ln (1 - 3 x)$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{(1 + 8 x) \frac{d}{d x} [\ln (1 - 3 x)] + \ln (1 - 3 x) \frac{d}{d x} [1 + 8 x]}{\frac{d}{d x} [x]}}$

Step 5.3.3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = \ln (x)$ and $g (x) = 1 - 3 x$ .

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Step 5.3.3.1

To apply the Chain Rule, set $u$ as $1 - 3 x$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{(1 + 8 x) \frac{d}{d u} [\ln (u)] \frac{d}{d x} [1 - 3 x] + \ln (1 - 3 x) \frac{d}{d x} [1 + 8 x]}{\frac{d}{d x} [x]}}$

Step 5.3.3.2

The derivative of $\ln (u)$ with respect to $u$ is $\frac{1}{u}$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{(1 + 8 x) \frac{1}{u} \frac{d}{d x} [1 - 3 x] + \ln (1 - 3 x) \frac{d}{d x} [1 + 8 x]}{\frac{d}{d x} [x]}}$

Step 5.3.3.3

Replace all occurrences of $u$ with $1 - 3 x$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{(1 + 8 x) \frac{1}{1 - 3 x} \frac{d}{d x} [1 - 3 x] + \ln (1 - 3 x) \frac{d}{d x} [1 + 8 x]}{\frac{d}{d x} [x]}}$

Step 5.3.4

By the Sum Rule, the derivative of $1 - 3 x$ with respect to $x$ is $\frac{d}{d x} [1] + \frac{d}{d x} [- 3 x]$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{(1 + 8 x) \frac{1}{1 - 3 x} (\frac{d}{d x} [1] + \frac{d}{d x} [- 3 x]) + \ln (1 - 3 x) \frac{d}{d x} [1 + 8 x]}{\frac{d}{d x} [x]}}$

Step 5.3.5

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{(1 + 8 x) \frac{1}{1 - 3 x} (0 + \frac{d}{d x} [- 3 x]) + \ln (1 - 3 x) \frac{d}{d x} [1 + 8 x]}{\frac{d}{d x} [x]}}$

Step 5.3.6

Add $0$ and $\frac{d}{d x} [- 3 x]$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{(1 + 8 x) \frac{1}{1 - 3 x} \frac{d}{d x} [- 3 x] + \ln (1 - 3 x) \frac{d}{d x} [1 + 8 x]}{\frac{d}{d x} [x]}}$

Step 5.3.7

Since $- 3$ is constant with respect to $x$ , the derivative of $- 3 x$ with respect to $x$ is $- 3 \frac{d}{d x} [x]$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{(1 + 8 x) \frac{1}{1 - 3 x} \cdot - 3 \frac{d}{d x} [x] + \ln (1 - 3 x) \frac{d}{d x} [1 + 8 x]}{\frac{d}{d x} [x]}}$

Step 5.3.8

Combine $- 3$ and $\frac{1}{1 - 3 x}$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{(1 + 8 x) \frac{- 3}{1 - 3 x} \frac{d}{d x} [x] + \ln (1 - 3 x) \frac{d}{d x} [1 + 8 x]}{\frac{d}{d x} [x]}}$

Step 5.3.9

Move the negative in front of the fraction.

$e^{\frac{1}{2} lim_{x \to 0} \frac{(1 + 8 x) \cdot - 1 \frac{3}{1 - 3 x} \frac{d}{d x} [x] + \ln (1 - 3 x) \frac{d}{d x} [1 + 8 x]}{\frac{d}{d x} [x]}}$

Step 5.3.10

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{(1 + 8 x) \cdot - 1 \frac{3}{1 - 3 x} \cdot 1 + \ln (1 - 3 x) \frac{d}{d x} [1 + 8 x]}{\frac{d}{d x} [x]}}$

Step 5.3.11

Multiply $1 + 8 x$ by $1$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{- \frac{3}{1 - 3 x} \cdot (1 + 8 x) + \ln (1 - 3 x) \frac{d}{d x} [1 + 8 x]}{\frac{d}{d x} [x]}}$

Step 5.3.12

By the Sum Rule, the derivative of $1 + 8 x$ with respect to $x$ is $\frac{d}{d x} [1] + \frac{d}{d x} [8 x]$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{- \frac{3}{1 - 3 x} (1 + 8 x) + \ln (1 - 3 x) (\frac{d}{d x} [1] + \frac{d}{d x} [8 x])}{\frac{d}{d x} [x]}}$

Step 5.3.13

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{- \frac{3}{1 - 3 x} (1 + 8 x) + \ln (1 - 3 x) (0 + \frac{d}{d x} [8 x])}{\frac{d}{d x} [x]}}$

Step 5.3.14

Add $0$ and $\frac{d}{d x} [8 x]$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{- \frac{3}{1 - 3 x} (1 + 8 x) + \ln (1 - 3 x) \frac{d}{d x} [8 x]}{\frac{d}{d x} [x]}}$

Step 5.3.15

Since $8$ is constant with respect to $x$ , the derivative of $8 x$ with respect to $x$ is $8 \frac{d}{d x} [x]$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{- \frac{3}{1 - 3 x} (1 + 8 x) + \ln (1 - 3 x) \cdot 8 \frac{d}{d x} [x]}{\frac{d}{d x} [x]}}$

Step 5.3.16

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{- \frac{3}{1 - 3 x} (1 + 8 x) + \ln (1 - 3 x) \cdot 8 \cdot 1}{\frac{d}{d x} [x]}}$

Step 5.3.17

Multiply $8$ by $1$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{- \frac{3}{1 - 3 x} (1 + 8 x) + \ln (1 - 3 x) \cdot 8}{\frac{d}{d x} [x]}}$

Step 5.3.18

Move $8$ to the left of $\ln (1 - 3 x)$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{- \frac{3}{1 - 3 x} (1 + 8 x) + 8 \cdot \ln (1 - 3 x)}{\frac{d}{d x} [x]}}$

Step 5.3.19

Reorder terms.

$e^{\frac{1}{2} lim_{x \to 0} \frac{- (1 + 8 x) \frac{3}{1 - 3 x} + 8 \ln (1 - 3 x)}{\frac{d}{d x} [x]}}$

Step 5.3.20

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{- (1 + 8 x) \frac{3}{1 - 3 x} + 8 \ln (1 - 3 x)}{1}}$

Step 5.4

Multiply $- (1 + 8 x)$ by $\frac{3}{1 - 3 x}$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{\frac{- (1 + 8 x) \cdot 3}{1 - 3 x} + 8 \ln (1 - 3 x)}{1}}$

Step 5.5

Combine terms.

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Step 5.5.1

To write $8 \ln (1 - 3 x)$ as a fraction with a common denominator, multiply by $\frac{1 - 3 x}{1 - 3 x}$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{\frac{- (1 + 8 x) \cdot 3}{1 - 3 x} + \frac{8 \ln (1 - 3 x) (1 - 3 x)}{1 - 3 x}}{1}}$

Step 5.5.2

Combine the numerators over the common denominator.

$e^{\frac{1}{2} lim_{x \to 0} \frac{\frac{- (1 + 8 x) \cdot 3 + 8 \ln (1 - 3 x) (1 - 3 x)}{1 - 3 x}}{1}}$

Step 5.6

Divide $\frac{- (1 + 8 x) \cdot 3 + 8 \ln (1 - 3 x) (1 - 3 x)}{1 - 3 x}$ by $1$ .

$e^{\frac{1}{2} lim_{x \to 0} \frac{- (1 + 8 x) \cdot 3 + 8 \ln (1 - 3 x) (1 - 3 x)}{1 - 3 x}}$

Step 6

Evaluate the limit.

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Step 6.1

Split the limit using the Limits Quotient Rule on the limit as $x$ approaches $0$ .

$e^{\frac{1}{2} \cdot \frac{lim_{x \to 0} - (1 + 8 x) \cdot 3 + 8 \ln (1 - 3 x) (1 - 3 x)}{lim_{x \to 0} 1 - 3 x}}$

Step 6.2

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $0$ .

$e^{\frac{1}{2} \cdot \frac{- lim_{x \to 0} (1 + 8 x) \cdot 3 + lim_{x \to 0} 8 \ln (1 - 3 x) (1 - 3 x)}{lim_{x \to 0} 1 - 3 x}}$

Step 6.3

Move the term $3$ outside of the limit because it is constant with respect to $x$ .

$e^{\frac{1}{2} \cdot \frac{- 3 lim_{x \to 0} 1 + 8 x + lim_{x \to 0} 8 \ln (1 - 3 x) (1 - 3 x)}{lim_{x \to 0} 1 - 3 x}}$

Step 6.4

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $0$ .

$e^{\frac{1}{2} \cdot \frac{- 3 (lim_{x \to 0} 1 + lim_{x \to 0} 8 x) + lim_{x \to 0} 8 \ln (1 - 3 x) (1 - 3 x)}{lim_{x \to 0} 1 - 3 x}}$

Step 6.5

Evaluate the limit of $1$ which is constant as $x$ approaches $0$ .

$e^{\frac{1}{2} \cdot \frac{- 3 (1 + lim_{x \to 0} 8 x) + lim_{x \to 0} 8 \ln (1 - 3 x) (1 - 3 x)}{lim_{x \to 0} 1 - 3 x}}$

Step 6.6

Move the term $8$ outside of the limit because it is constant with respect to $x$ .

$e^{\frac{1}{2} \cdot \frac{- 3 (1 + 8 lim_{x \to 0} x) + lim_{x \to 0} 8 \ln (1 - 3 x) (1 - 3 x)}{lim_{x \to 0} 1 - 3 x}}$

Step 6.7

Move the term $8$ outside of the limit because it is constant with respect to $x$ .

$e^{\frac{1}{2} \cdot \frac{- 3 (1 + 8 lim_{x \to 0} x) + 8 lim_{x \to 0} \ln (1 - 3 x) (1 - 3 x)}{lim_{x \to 0} 1 - 3 x}}$

Step 6.8

Split the limit using the Product of Limits Rule on the limit as $x$ approaches $0$ .

$e^{\frac{1}{2} \cdot \frac{- 3 (1 + 8 lim_{x \to 0} x) + 8 lim_{x \to 0} \ln (1 - 3 x) \cdot lim_{x \to 0} 1 - 3 x}{lim_{x \to 0} 1 - 3 x}}$

Step 6.9

Move the limit inside the logarithm.

$e^{\frac{1}{2} \cdot \frac{- 3 (1 + 8 lim_{x \to 0} x) + 8 \ln (lim_{x \to 0} 1 - 3 x) \cdot lim_{x \to 0} 1 - 3 x}{lim_{x \to 0} 1 - 3 x}}$

Step 6.10

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $0$ .

$e^{\frac{1}{2} \cdot \frac{- 3 (1 + 8 lim_{x \to 0} x) + 8 \ln (lim_{x \to 0} 1 - lim_{x \to 0} 3 x) \cdot lim_{x \to 0} 1 - 3 x}{lim_{x \to 0} 1 - 3 x}}$

Step 6.11

Evaluate the limit of $1$ which is constant as $x$ approaches $0$ .

$e^{\frac{1}{2} \cdot \frac{- 3 (1 + 8 lim_{x \to 0} x) + 8 \ln (1 - lim_{x \to 0} 3 x) \cdot lim_{x \to 0} 1 - 3 x}{lim_{x \to 0} 1 - 3 x}}$

Step 6.12

Move the term $3$ outside of the limit because it is constant with respect to $x$ .

$e^{\frac{1}{2} \cdot \frac{- 3 (1 + 8 lim_{x \to 0} x) + 8 \ln (1 - 3 lim_{x \to 0} x) \cdot lim_{x \to 0} 1 - 3 x}{lim_{x \to 0} 1 - 3 x}}$

Step 6.13

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $0$ .

$e^{\frac{1}{2} \cdot \frac{- 3 (1 + 8 lim_{x \to 0} x) + 8 \ln (1 - 3 lim_{x \to 0} x) \cdot (lim_{x \to 0} 1 - lim_{x \to 0} 3 x)}{lim_{x \to 0} 1 - 3 x}}$

Step 6.14

Evaluate the limit of $1$ which is constant as $x$ approaches $0$ .

$e^{\frac{1}{2} \cdot \frac{- 3 (1 + 8 lim_{x \to 0} x) + 8 \ln (1 - 3 lim_{x \to 0} x) \cdot (1 - lim_{x \to 0} 3 x)}{lim_{x \to 0} 1 - 3 x}}$

Step 6.15

Move the term $3$ outside of the limit because it is constant with respect to $x$ .

$e^{\frac{1}{2} \cdot \frac{- 3 (1 + 8 lim_{x \to 0} x) + 8 \ln (1 - 3 lim_{x \to 0} x) \cdot (1 - 3 lim_{x \to 0} x)}{lim_{x \to 0} 1 - 3 x}}$

Step 6.16

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $0$ .

$e^{\frac{1}{2} \cdot \frac{- 3 (1 + 8 lim_{x \to 0} x) + 8 \ln (1 - 3 lim_{x \to 0} x) \cdot (1 - 3 lim_{x \to 0} x)}{lim_{x \to 0} 1 - lim_{x \to 0} 3 x}}$

Step 6.17

Evaluate the limit of $1$ which is constant as $x$ approaches $0$ .

$e^{\frac{1}{2} \cdot \frac{- 3 (1 + 8 lim_{x \to 0} x) + 8 \ln (1 - 3 lim_{x \to 0} x) \cdot (1 - 3 lim_{x \to 0} x)}{1 - lim_{x \to 0} 3 x}}$

Step 6.18

Move the term $3$ outside of the limit because it is constant with respect to $x$ .

$e^{\frac{1}{2} \cdot \frac{- 3 (1 + 8 lim_{x \to 0} x) + 8 \ln (1 - 3 lim_{x \to 0} x) \cdot (1 - 3 lim_{x \to 0} x)}{1 - 3 lim_{x \to 0} x}}$

Step 7

Evaluate the limits by plugging in $0$ for all occurrences of $x$ .

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Step 7.1

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$e^{\frac{1}{2} \cdot \frac{- 3 (1 + 8 \cdot 0) + 8 \ln (1 - 3 lim_{x \to 0} x) \cdot (1 - 3 lim_{x \to 0} x)}{1 - 3 lim_{x \to 0} x}}$

Step 7.2

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$e^{\frac{1}{2} \cdot \frac{- 3 (1 + 8 \cdot 0) + 8 \ln (1 - 3 \cdot 0) \cdot (1 - 3 lim_{x \to 0} x)}{1 - 3 lim_{x \to 0} x}}$

Step 7.3

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$e^{\frac{1}{2} \cdot \frac{- 3 (1 + 8 \cdot 0) + 8 \ln (1 - 3 \cdot 0) \cdot (1 - 3 \cdot 0)}{1 - 3 lim_{x \to 0} x}}$

Step 7.4

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$e^{\frac{1}{2} \cdot \frac{- 3 (1 + 8 \cdot 0) + 8 \ln (1 - 3 \cdot 0) \cdot (1 - 3 \cdot 0)}{1 - 3 \cdot 0}}$

Step 8

Simplify the answer.

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Step 8.1

Simplify the numerator.

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Step 8.1.1

Multiply $8$ by $0$ .

$e^{\frac{1}{2} \cdot \frac{- 3 (1 + 0) + 8 \ln (1 - 3 \cdot 0) \cdot (1 - 3 \cdot 0)}{1 - 3 \cdot 0}}$

Step 8.1.2

Add $1$ and $0$ .

$e^{\frac{1}{2} \cdot \frac{- 3 \cdot 1 + 8 \ln (1 - 3 \cdot 0) \cdot (1 - 3 \cdot 0)}{1 - 3 \cdot 0}}$

Step 8.1.3

Multiply $- 3$ by $1$ .

$e^{\frac{1}{2} \cdot \frac{- 3 + 8 \ln (1 - 3 \cdot 0) \cdot (1 - 3 \cdot 0)}{1 - 3 \cdot 0}}$

Step 8.1.4

Multiply $- 3$ by $0$ .

$e^{\frac{1}{2} \cdot \frac{- 3 + 8 \ln (1 + 0) \cdot (1 - 3 \cdot 0)}{1 - 3 \cdot 0}}$

Step 8.1.5

Add $1$ and $0$ .

$e^{\frac{1}{2} \cdot \frac{- 3 + 8 \ln (1) \cdot (1 - 3 \cdot 0)}{1 - 3 \cdot 0}}$

Step 8.1.6

The natural logarithm of $1$ is $0$ .

$e^{\frac{1}{2} \cdot \frac{- 3 + 8 \cdot 0 \cdot (1 - 3 \cdot 0)}{1 - 3 \cdot 0}}$

Step 8.1.7

Multiply $8$ by $0$ .

$e^{\frac{1}{2} \cdot \frac{- 3 + 0 \cdot (1 - 3 \cdot 0)}{1 - 3 \cdot 0}}$

Step 8.1.8

Multiply $- 3$ by $0$ .

$e^{\frac{1}{2} \cdot \frac{- 3 + 0 \cdot (1 + 0)}{1 - 3 \cdot 0}}$

Step 8.1.9

Add $1$ and $0$ .

$e^{\frac{1}{2} \cdot \frac{- 3 + 0 \cdot 1}{1 - 3 \cdot 0}}$

Step 8.1.10

Multiply $0$ by $1$ .

$e^{\frac{1}{2} \cdot \frac{- 3 + 0}{1 - 3 \cdot 0}}$

Step 8.1.11

Add $- 3$ and $0$ .

$e^{\frac{1}{2} \cdot \frac{- 3}{1 - 3 \cdot 0}}$

Step 8.2

Simplify the denominator.

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Step 8.2.1

Multiply $- 3$ by $0$ .

$e^{\frac{1}{2} \cdot \frac{- 3}{1 + 0}}$

Step 8.2.2

Add $1$ and $0$ .

$e^{\frac{1}{2} \cdot \frac{- 3}{1}}$

Step 8.3

Divide $- 3$ by $1$ .

$e^{\frac{1}{2} \cdot - 3}$

Step 8.4

Combine $\frac{1}{2}$ and $- 3$ .

$e^{\frac{- 3}{2}}$

Step 8.5

Move the negative in front of the fraction.

$e^{- \frac{3}{2}}$

Step 8.6

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{e^{\frac{3}{2}}}$

Step 9

The result can be shown in multiple forms.

Exact Form:

$\frac{1}{e^{\frac{3}{2}}}$

Decimal Form:

$0.22313016 \dots$