Precalculus Examples

$\ln (\frac{5422}{4548}) = (12 t) \ln (1 + \frac{0.055}{12})$

Step 1

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = e$ , $x = \frac{5422}{4548}$ , and $y = (12 t) \ln (1 + \frac{0.055}{12})$ .

$b = e$

$x = \frac{5422}{4548}$

$y = (12 t) \ln (1 + \frac{0.055}{12})$

Step 2

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

$e^{(12 t) \ln (1 + \frac{0.055}{12})} = \frac{5422}{4548}$