Precalculus Examples

$- 4 \ln (2) + \frac{1}{2} \cdot \ln (24) - \ln (5) + 3 \ln (2) = \frac{\ln (\sqrt{6})}{5}$

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$- 4 \ln (2) + \frac{1}{2} \cdot \ln (24) - \ln (5) + 3 \ln (2) = \frac{\ln (\sqrt{6})}{5}$