Precalculus Examples

$\log_{12} (81) + \log_{12} (256)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{12} (81 \cdot 256)$

Step 2

Multiply $81$ by $256$ .

$\log_{12} (20736)$

Step 3

Logarithm base $12$ of $20736$ is $4$ .

$4$