Precalculus Examples

$\log_{2} (8) + \log_{2} (16)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{2} (8 \cdot 16)$

Step 2

Multiply $8$ by $16$ .

$\log_{2} (128)$

Step 3

Logarithm base $2$ of $128$ is $7$ .

$7$