Precalculus Examples

$\log_{190} (10) + \log_{190} (19)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{190} (10 \cdot 19)$

Step 2

Multiply $10$ by $19$ .

$\log_{190} (190)$

Step 3

Logarithm base $190$ of $190$ is $1$ .

$1$