Precalculus Examples

$\log_{140} (20) + \log_{140} (7)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{140} (20 \cdot 7)$

Step 2

Multiply $20$ by $7$ .

$\log_{140} (140)$

Step 3

Logarithm base $140$ of $140$ is $1$ .

$1$