Precalculus Examples

$\frac{\ln (\frac{25}{6})}{12.77}$

Step 1

Replace $e$ with an approximation.

$\frac{\log_{2.71828182} (\frac{25}{6})}{12.77}$

Step 2

Divide $25$ by $6$ .

$\frac{\log_{2.71828182} (4.1\overline{6})}{12.77}$

Step 3

Log base $2.71828182$ of $4.1\overline{6}$ is approximately $1.42711635$ .

$\frac{1.42711635}{12.77}$

Step 4

Divide $1.42711635$ by $12.77$ .

$0.11175539$