Precalculus Examples

$\log_{3} ({(81)}^{- 0.2})$

Step 1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\log_{3} (\frac{1}{81^{0.2}})$

Step 2

Raise $81$ to the power of $0.2$ .

$\log_{3} (\frac{1}{2.40822468})$

Step 3

Divide $1$ by $2.40822468$ .

$\log_{3} (0.41524364)$

Step 4

Log base $3$ of $0.41524364$ is approximately $- 0.7\overline{9}$ .

$- 0.7\overline{9}$